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Convert binary String to hexadecimal String
2019 Community Moderator ElectionHow to convert decimal to hex in JavaScript?Converting an integer to a hexadecimal string in RubyConvert hex string to int in PythonHow do you convert a byte array to a hexadecimal string, and vice versa?Decimal/Hexadecimal/Binary ConversionHow to convert a byte array to a hex string in Java?Bitwise Operators and Binary string evaluationsMoving between hexadecimal and binary notationHexadecimal to binary to decimal GUIWithout format specifiers, converting binary int number to hexadecimal in C
I have this conversion in my Kotlin class for Android:
val binary = "01000100000111001011011011100010111000110011010111010110"
val hexadecimal = BigInteger(binary, 2).toString(16)
Which is producing the expected value of 441CB6E2E335D6.
Now I want to reproduce this in Visual Basic and I am doing something like this:
Dim binary = "01000100000111001011011011100010111000110011010111010110"
Dim hexadecimal = BigInteger.Parse(binary, 2).ToString("X")
Which is producing 0A7108304A751AFEC876F740BC1F2CB59772FB7C6C753E.
I am not an expert in Visual Basic, but from what I researched, I think this is the right way to convert a binary to hexadecimal. What I am doing wrong?
vb.net kotlin binary hex
add a comment |
I have this conversion in my Kotlin class for Android:
val binary = "01000100000111001011011011100010111000110011010111010110"
val hexadecimal = BigInteger(binary, 2).toString(16)
Which is producing the expected value of 441CB6E2E335D6.
Now I want to reproduce this in Visual Basic and I am doing something like this:
Dim binary = "01000100000111001011011011100010111000110011010111010110"
Dim hexadecimal = BigInteger.Parse(binary, 2).ToString("X")
Which is producing 0A7108304A751AFEC876F740BC1F2CB59772FB7C6C753E.
I am not an expert in Visual Basic, but from what I researched, I think this is the right way to convert a binary to hexadecimal. What I am doing wrong?
vb.net kotlin binary hex
1
Just a note: the second parameter inParseis not the base, but the enumNumberStyleswhere 2 isAllowTrailingWhite. You are simply parsing it as a decimal.
– ZorgoZ
Mar 6 at 17:01
@ZorgoZ alright. So doing only BigInteger.Parse(binary) should do the work, right?
– Ravers
Mar 6 at 17:12
No. Have you seen anywhere in the documentation, that it can parse binary?
– ZorgoZ
Mar 6 at 17:14
add a comment |
I have this conversion in my Kotlin class for Android:
val binary = "01000100000111001011011011100010111000110011010111010110"
val hexadecimal = BigInteger(binary, 2).toString(16)
Which is producing the expected value of 441CB6E2E335D6.
Now I want to reproduce this in Visual Basic and I am doing something like this:
Dim binary = "01000100000111001011011011100010111000110011010111010110"
Dim hexadecimal = BigInteger.Parse(binary, 2).ToString("X")
Which is producing 0A7108304A751AFEC876F740BC1F2CB59772FB7C6C753E.
I am not an expert in Visual Basic, but from what I researched, I think this is the right way to convert a binary to hexadecimal. What I am doing wrong?
vb.net kotlin binary hex
I have this conversion in my Kotlin class for Android:
val binary = "01000100000111001011011011100010111000110011010111010110"
val hexadecimal = BigInteger(binary, 2).toString(16)
Which is producing the expected value of 441CB6E2E335D6.
Now I want to reproduce this in Visual Basic and I am doing something like this:
Dim binary = "01000100000111001011011011100010111000110011010111010110"
Dim hexadecimal = BigInteger.Parse(binary, 2).ToString("X")
Which is producing 0A7108304A751AFEC876F740BC1F2CB59772FB7C6C753E.
I am not an expert in Visual Basic, but from what I researched, I think this is the right way to convert a binary to hexadecimal. What I am doing wrong?
vb.net kotlin binary hex
vb.net kotlin binary hex
edited Mar 7 at 8:08
Jimi
9,43242035
9,43242035
asked Mar 6 at 16:50
RaversRavers
283523
283523
1
Just a note: the second parameter inParseis not the base, but the enumNumberStyleswhere 2 isAllowTrailingWhite. You are simply parsing it as a decimal.
– ZorgoZ
Mar 6 at 17:01
@ZorgoZ alright. So doing only BigInteger.Parse(binary) should do the work, right?
– Ravers
Mar 6 at 17:12
No. Have you seen anywhere in the documentation, that it can parse binary?
– ZorgoZ
Mar 6 at 17:14
add a comment |
1
Just a note: the second parameter inParseis not the base, but the enumNumberStyleswhere 2 isAllowTrailingWhite. You are simply parsing it as a decimal.
– ZorgoZ
Mar 6 at 17:01
@ZorgoZ alright. So doing only BigInteger.Parse(binary) should do the work, right?
– Ravers
Mar 6 at 17:12
No. Have you seen anywhere in the documentation, that it can parse binary?
– ZorgoZ
Mar 6 at 17:14
1
1
Just a note: the second parameter in
Parse is not the base, but the enum NumberStyles where 2 is AllowTrailingWhite. You are simply parsing it as a decimal.– ZorgoZ
Mar 6 at 17:01
Just a note: the second parameter in
Parse is not the base, but the enum NumberStyles where 2 is AllowTrailingWhite. You are simply parsing it as a decimal.– ZorgoZ
Mar 6 at 17:01
@ZorgoZ alright. So doing only BigInteger.Parse(binary) should do the work, right?
– Ravers
Mar 6 at 17:12
@ZorgoZ alright. So doing only BigInteger.Parse(binary) should do the work, right?
– Ravers
Mar 6 at 17:12
No. Have you seen anywhere in the documentation, that it can parse binary?
– ZorgoZ
Mar 6 at 17:14
No. Have you seen anywhere in the documentation, that it can parse binary?
– ZorgoZ
Mar 6 at 17:14
add a comment |
2 Answers
2
active
oldest
votes
You can write a simple parser for the string representing the bits:
Dim sb As StringBuilder = New StringBuilder()
For pos As Integer = 0 To binary.Length - 8 Step 8
sb.Append(Convert.ToByte(binary.Substring(pos, 8), 2).ToString("X2"))
Next
Console.WriteLine(sb) will print "441CB6E2E335D6"
Or use a Module to add an extension method to the string data type:
Imports System.Runtime.CompilerServices
Imports System.Text
Module modStringExtensions
<Extension()>
Public Function ToHexFromBits(ByVal Value As String) As String
If (Not (Value.Length Mod 8 = 0)) Then Throw New FormatException("Invalid string length")
Dim sb As StringBuilder = New StringBuilder()
For pos As Integer = 0 To Value.Length - 8 Step 8
sb.Append(Convert.ToByte(Value.Substring(pos, 8), 2).ToString("X2"))
Next
Return sb.ToString()
End Function
End Module
Then use the extension to convert the bits string to a HEX representation:
Dim result As String = binary.ToHexFromBits()
add a comment |
Following code is c#, but might not be too hard to translate it to vb.net.
string BinToHex(string value)
var res = new char[(int)(value.Length / 4)];
int j = res.Length-1;
for (int i = value.Length - 1; i > 0; i -= 4)
int x = ((int)value[i]-48)
+((int)value[i-1]-48)*2
+((int)value[i-2]-48)*4
+((int)value[i-3]-48)*8;
res[j--] = x.ToString("X")[0];
return new string(res);
Beware: it won't handle input that has not the proper number of bits (multiple of 4). Anyway, the idea is that you can translate between base 2 and base 16 without the use of base 10. You could even step from left to right.
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can write a simple parser for the string representing the bits:
Dim sb As StringBuilder = New StringBuilder()
For pos As Integer = 0 To binary.Length - 8 Step 8
sb.Append(Convert.ToByte(binary.Substring(pos, 8), 2).ToString("X2"))
Next
Console.WriteLine(sb) will print "441CB6E2E335D6"
Or use a Module to add an extension method to the string data type:
Imports System.Runtime.CompilerServices
Imports System.Text
Module modStringExtensions
<Extension()>
Public Function ToHexFromBits(ByVal Value As String) As String
If (Not (Value.Length Mod 8 = 0)) Then Throw New FormatException("Invalid string length")
Dim sb As StringBuilder = New StringBuilder()
For pos As Integer = 0 To Value.Length - 8 Step 8
sb.Append(Convert.ToByte(Value.Substring(pos, 8), 2).ToString("X2"))
Next
Return sb.ToString()
End Function
End Module
Then use the extension to convert the bits string to a HEX representation:
Dim result As String = binary.ToHexFromBits()
add a comment |
You can write a simple parser for the string representing the bits:
Dim sb As StringBuilder = New StringBuilder()
For pos As Integer = 0 To binary.Length - 8 Step 8
sb.Append(Convert.ToByte(binary.Substring(pos, 8), 2).ToString("X2"))
Next
Console.WriteLine(sb) will print "441CB6E2E335D6"
Or use a Module to add an extension method to the string data type:
Imports System.Runtime.CompilerServices
Imports System.Text
Module modStringExtensions
<Extension()>
Public Function ToHexFromBits(ByVal Value As String) As String
If (Not (Value.Length Mod 8 = 0)) Then Throw New FormatException("Invalid string length")
Dim sb As StringBuilder = New StringBuilder()
For pos As Integer = 0 To Value.Length - 8 Step 8
sb.Append(Convert.ToByte(Value.Substring(pos, 8), 2).ToString("X2"))
Next
Return sb.ToString()
End Function
End Module
Then use the extension to convert the bits string to a HEX representation:
Dim result As String = binary.ToHexFromBits()
add a comment |
You can write a simple parser for the string representing the bits:
Dim sb As StringBuilder = New StringBuilder()
For pos As Integer = 0 To binary.Length - 8 Step 8
sb.Append(Convert.ToByte(binary.Substring(pos, 8), 2).ToString("X2"))
Next
Console.WriteLine(sb) will print "441CB6E2E335D6"
Or use a Module to add an extension method to the string data type:
Imports System.Runtime.CompilerServices
Imports System.Text
Module modStringExtensions
<Extension()>
Public Function ToHexFromBits(ByVal Value As String) As String
If (Not (Value.Length Mod 8 = 0)) Then Throw New FormatException("Invalid string length")
Dim sb As StringBuilder = New StringBuilder()
For pos As Integer = 0 To Value.Length - 8 Step 8
sb.Append(Convert.ToByte(Value.Substring(pos, 8), 2).ToString("X2"))
Next
Return sb.ToString()
End Function
End Module
Then use the extension to convert the bits string to a HEX representation:
Dim result As String = binary.ToHexFromBits()
You can write a simple parser for the string representing the bits:
Dim sb As StringBuilder = New StringBuilder()
For pos As Integer = 0 To binary.Length - 8 Step 8
sb.Append(Convert.ToByte(binary.Substring(pos, 8), 2).ToString("X2"))
Next
Console.WriteLine(sb) will print "441CB6E2E335D6"
Or use a Module to add an extension method to the string data type:
Imports System.Runtime.CompilerServices
Imports System.Text
Module modStringExtensions
<Extension()>
Public Function ToHexFromBits(ByVal Value As String) As String
If (Not (Value.Length Mod 8 = 0)) Then Throw New FormatException("Invalid string length")
Dim sb As StringBuilder = New StringBuilder()
For pos As Integer = 0 To Value.Length - 8 Step 8
sb.Append(Convert.ToByte(Value.Substring(pos, 8), 2).ToString("X2"))
Next
Return sb.ToString()
End Function
End Module
Then use the extension to convert the bits string to a HEX representation:
Dim result As String = binary.ToHexFromBits()
answered Mar 6 at 20:34
JimiJimi
9,43242035
9,43242035
add a comment |
add a comment |
Following code is c#, but might not be too hard to translate it to vb.net.
string BinToHex(string value)
var res = new char[(int)(value.Length / 4)];
int j = res.Length-1;
for (int i = value.Length - 1; i > 0; i -= 4)
int x = ((int)value[i]-48)
+((int)value[i-1]-48)*2
+((int)value[i-2]-48)*4
+((int)value[i-3]-48)*8;
res[j--] = x.ToString("X")[0];
return new string(res);
Beware: it won't handle input that has not the proper number of bits (multiple of 4). Anyway, the idea is that you can translate between base 2 and base 16 without the use of base 10. You could even step from left to right.
add a comment |
Following code is c#, but might not be too hard to translate it to vb.net.
string BinToHex(string value)
var res = new char[(int)(value.Length / 4)];
int j = res.Length-1;
for (int i = value.Length - 1; i > 0; i -= 4)
int x = ((int)value[i]-48)
+((int)value[i-1]-48)*2
+((int)value[i-2]-48)*4
+((int)value[i-3]-48)*8;
res[j--] = x.ToString("X")[0];
return new string(res);
Beware: it won't handle input that has not the proper number of bits (multiple of 4). Anyway, the idea is that you can translate between base 2 and base 16 without the use of base 10. You could even step from left to right.
add a comment |
Following code is c#, but might not be too hard to translate it to vb.net.
string BinToHex(string value)
var res = new char[(int)(value.Length / 4)];
int j = res.Length-1;
for (int i = value.Length - 1; i > 0; i -= 4)
int x = ((int)value[i]-48)
+((int)value[i-1]-48)*2
+((int)value[i-2]-48)*4
+((int)value[i-3]-48)*8;
res[j--] = x.ToString("X")[0];
return new string(res);
Beware: it won't handle input that has not the proper number of bits (multiple of 4). Anyway, the idea is that you can translate between base 2 and base 16 without the use of base 10. You could even step from left to right.
Following code is c#, but might not be too hard to translate it to vb.net.
string BinToHex(string value)
var res = new char[(int)(value.Length / 4)];
int j = res.Length-1;
for (int i = value.Length - 1; i > 0; i -= 4)
int x = ((int)value[i]-48)
+((int)value[i-1]-48)*2
+((int)value[i-2]-48)*4
+((int)value[i-3]-48)*8;
res[j--] = x.ToString("X")[0];
return new string(res);
Beware: it won't handle input that has not the proper number of bits (multiple of 4). Anyway, the idea is that you can translate between base 2 and base 16 without the use of base 10. You could even step from left to right.
edited Mar 6 at 17:28
answered Mar 6 at 17:16
ZorgoZZorgoZ
1,2841417
1,2841417
add a comment |
add a comment |
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1
Just a note: the second parameter in
Parseis not the base, but the enumNumberStyleswhere 2 isAllowTrailingWhite. You are simply parsing it as a decimal.– ZorgoZ
Mar 6 at 17:01
@ZorgoZ alright. So doing only BigInteger.Parse(binary) should do the work, right?
– Ravers
Mar 6 at 17:12
No. Have you seen anywhere in the documentation, that it can parse binary?
– ZorgoZ
Mar 6 at 17:14