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How to extract specific fields recursively from json output?



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Data science time! April 2019 and salary with experience
The Ask Question Wizard is Live!How do I format a Microsoft JSON date?How can I pretty-print JSON in a shell script?Extracting extension from filename in PythonHow to parse JSON in JavaWhy can't Python parse this JSON data?How can I pretty-print JSON using JavaScript?How to parse JSON using Node.js?How do I POST JSON data with Curl from a terminal/commandline to Test Spring REST?How do I write JSON data to a file?How to prettyprint a JSON file?



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-2















Below is the sample json document or json variable I have. I'm using python for extracting the required fields as mentioned int the output section.



Can someone help on how to do this?



json_variable = 

"server01":
"address":"server01:5454",
"options": ,
"state":"online"
,
"server02":
"address":"server02:5454",
"options": ,
"state":"online"
,
"server03":
"address":"server03:5454",
"options": ,
"state":"online"



for x in json_variable:
print(x["address"])

Error:
Traceback (most recent call last):
File "<string>", line 30, in <module>
File "<string>", line 18, in getServerStatus
TypeError: 'shell.Dict' object is not iterable


I can get the required output by hard coding the fields as below, but i would like to do it dynamically as the number of servers vary depending upon the system queried and json returned.



print(json_variable["server01"]["address"])
print(json_variable["server02"]["address"])
print(json_variable["server03"]["address"])


Required Output:



server01:5454 --> online 
server02:5454 --> online
server03:5454 --> online









share|improve this question
























  • To do this generically, you're going to have to at least hardcode the patterns to look for so the code has a clue as to what you're interested in retrieving. Not sure why you seem to think it needs to be done recursively, however.

    – martineau
    Mar 9 at 1:00






  • 2





    What have you tried so far?

    – Klaus D.
    Mar 9 at 1:00






  • 1





    for server in json_variable.values(): print(f"server['address'] --> server['status']")

    – Jab
    Mar 9 at 1:02












  • @KlausD. I added the code that I tried.

    – sqlcheckpoint
    Mar 9 at 1:17

















-2















Below is the sample json document or json variable I have. I'm using python for extracting the required fields as mentioned int the output section.



Can someone help on how to do this?



json_variable = 

"server01":
"address":"server01:5454",
"options": ,
"state":"online"
,
"server02":
"address":"server02:5454",
"options": ,
"state":"online"
,
"server03":
"address":"server03:5454",
"options": ,
"state":"online"



for x in json_variable:
print(x["address"])

Error:
Traceback (most recent call last):
File "<string>", line 30, in <module>
File "<string>", line 18, in getServerStatus
TypeError: 'shell.Dict' object is not iterable


I can get the required output by hard coding the fields as below, but i would like to do it dynamically as the number of servers vary depending upon the system queried and json returned.



print(json_variable["server01"]["address"])
print(json_variable["server02"]["address"])
print(json_variable["server03"]["address"])


Required Output:



server01:5454 --> online 
server02:5454 --> online
server03:5454 --> online









share|improve this question
























  • To do this generically, you're going to have to at least hardcode the patterns to look for so the code has a clue as to what you're interested in retrieving. Not sure why you seem to think it needs to be done recursively, however.

    – martineau
    Mar 9 at 1:00






  • 2





    What have you tried so far?

    – Klaus D.
    Mar 9 at 1:00






  • 1





    for server in json_variable.values(): print(f"server['address'] --> server['status']")

    – Jab
    Mar 9 at 1:02












  • @KlausD. I added the code that I tried.

    – sqlcheckpoint
    Mar 9 at 1:17













-2












-2








-2


1






Below is the sample json document or json variable I have. I'm using python for extracting the required fields as mentioned int the output section.



Can someone help on how to do this?



json_variable = 

"server01":
"address":"server01:5454",
"options": ,
"state":"online"
,
"server02":
"address":"server02:5454",
"options": ,
"state":"online"
,
"server03":
"address":"server03:5454",
"options": ,
"state":"online"



for x in json_variable:
print(x["address"])

Error:
Traceback (most recent call last):
File "<string>", line 30, in <module>
File "<string>", line 18, in getServerStatus
TypeError: 'shell.Dict' object is not iterable


I can get the required output by hard coding the fields as below, but i would like to do it dynamically as the number of servers vary depending upon the system queried and json returned.



print(json_variable["server01"]["address"])
print(json_variable["server02"]["address"])
print(json_variable["server03"]["address"])


Required Output:



server01:5454 --> online 
server02:5454 --> online
server03:5454 --> online









share|improve this question
















Below is the sample json document or json variable I have. I'm using python for extracting the required fields as mentioned int the output section.



Can someone help on how to do this?



json_variable = 

"server01":
"address":"server01:5454",
"options": ,
"state":"online"
,
"server02":
"address":"server02:5454",
"options": ,
"state":"online"
,
"server03":
"address":"server03:5454",
"options": ,
"state":"online"



for x in json_variable:
print(x["address"])

Error:
Traceback (most recent call last):
File "<string>", line 30, in <module>
File "<string>", line 18, in getServerStatus
TypeError: 'shell.Dict' object is not iterable


I can get the required output by hard coding the fields as below, but i would like to do it dynamically as the number of servers vary depending upon the system queried and json returned.



print(json_variable["server01"]["address"])
print(json_variable["server02"]["address"])
print(json_variable["server03"]["address"])


Required Output:



server01:5454 --> online 
server02:5454 --> online
server03:5454 --> online






python json python-2.7






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 9 at 4:18







sqlcheckpoint

















asked Mar 9 at 0:54









sqlcheckpointsqlcheckpoint

353520




353520












  • To do this generically, you're going to have to at least hardcode the patterns to look for so the code has a clue as to what you're interested in retrieving. Not sure why you seem to think it needs to be done recursively, however.

    – martineau
    Mar 9 at 1:00






  • 2





    What have you tried so far?

    – Klaus D.
    Mar 9 at 1:00






  • 1





    for server in json_variable.values(): print(f"server['address'] --> server['status']")

    – Jab
    Mar 9 at 1:02












  • @KlausD. I added the code that I tried.

    – sqlcheckpoint
    Mar 9 at 1:17

















  • To do this generically, you're going to have to at least hardcode the patterns to look for so the code has a clue as to what you're interested in retrieving. Not sure why you seem to think it needs to be done recursively, however.

    – martineau
    Mar 9 at 1:00






  • 2





    What have you tried so far?

    – Klaus D.
    Mar 9 at 1:00






  • 1





    for server in json_variable.values(): print(f"server['address'] --> server['status']")

    – Jab
    Mar 9 at 1:02












  • @KlausD. I added the code that I tried.

    – sqlcheckpoint
    Mar 9 at 1:17
















To do this generically, you're going to have to at least hardcode the patterns to look for so the code has a clue as to what you're interested in retrieving. Not sure why you seem to think it needs to be done recursively, however.

– martineau
Mar 9 at 1:00





To do this generically, you're going to have to at least hardcode the patterns to look for so the code has a clue as to what you're interested in retrieving. Not sure why you seem to think it needs to be done recursively, however.

– martineau
Mar 9 at 1:00




2




2





What have you tried so far?

– Klaus D.
Mar 9 at 1:00





What have you tried so far?

– Klaus D.
Mar 9 at 1:00




1




1





for server in json_variable.values(): print(f"server['address'] --> server['status']")

– Jab
Mar 9 at 1:02






for server in json_variable.values(): print(f"server['address'] --> server['status']")

– Jab
Mar 9 at 1:02














@KlausD. I added the code that I tried.

– sqlcheckpoint
Mar 9 at 1:17





@KlausD. I added the code that I tried.

– sqlcheckpoint
Mar 9 at 1:17












2 Answers
2






active

oldest

votes


















1














Here's another way to get the server status from the JSON.



json_info = 
"server01":
"address":"server01:5454",
"options": ,
"state":"online"
,
"server02":
"address":"server02:5454",
"options": ,
"state":"online"
,
"server03":
"address":"server03:5454",
"options": ,
"state":"online"



for server in json_info.values():
server_status = server['state']
if 'online' in server_status:
server_name = server.get('address')
print (' is online'.format(server_name.split(':')[0]))
# output
# server01 is online
# server02 is online
# server03 is online
#
# print (' --> online'.format(server_name))
# output
# server01:5454 --> online
# server02:5454 --> online
# server03:5454 --> online
else:
server_name = server.get('address')
print(' is offline'.format(server_name.split(':')[0]))





share|improve this answer
































    1














    Treat it as a dictionary:



    for k, v in sample.items():
    print(v['address'] + "-->" + v['state'])





    share|improve this answer























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      2 Answers
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      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      Here's another way to get the server status from the JSON.



      json_info = 
      "server01":
      "address":"server01:5454",
      "options": ,
      "state":"online"
      ,
      "server02":
      "address":"server02:5454",
      "options": ,
      "state":"online"
      ,
      "server03":
      "address":"server03:5454",
      "options": ,
      "state":"online"



      for server in json_info.values():
      server_status = server['state']
      if 'online' in server_status:
      server_name = server.get('address')
      print (' is online'.format(server_name.split(':')[0]))
      # output
      # server01 is online
      # server02 is online
      # server03 is online
      #
      # print (' --> online'.format(server_name))
      # output
      # server01:5454 --> online
      # server02:5454 --> online
      # server03:5454 --> online
      else:
      server_name = server.get('address')
      print(' is offline'.format(server_name.split(':')[0]))





      share|improve this answer





























        1














        Here's another way to get the server status from the JSON.



        json_info = 
        "server01":
        "address":"server01:5454",
        "options": ,
        "state":"online"
        ,
        "server02":
        "address":"server02:5454",
        "options": ,
        "state":"online"
        ,
        "server03":
        "address":"server03:5454",
        "options": ,
        "state":"online"



        for server in json_info.values():
        server_status = server['state']
        if 'online' in server_status:
        server_name = server.get('address')
        print (' is online'.format(server_name.split(':')[0]))
        # output
        # server01 is online
        # server02 is online
        # server03 is online
        #
        # print (' --> online'.format(server_name))
        # output
        # server01:5454 --> online
        # server02:5454 --> online
        # server03:5454 --> online
        else:
        server_name = server.get('address')
        print(' is offline'.format(server_name.split(':')[0]))





        share|improve this answer



























          1












          1








          1







          Here's another way to get the server status from the JSON.



          json_info = 
          "server01":
          "address":"server01:5454",
          "options": ,
          "state":"online"
          ,
          "server02":
          "address":"server02:5454",
          "options": ,
          "state":"online"
          ,
          "server03":
          "address":"server03:5454",
          "options": ,
          "state":"online"



          for server in json_info.values():
          server_status = server['state']
          if 'online' in server_status:
          server_name = server.get('address')
          print (' is online'.format(server_name.split(':')[0]))
          # output
          # server01 is online
          # server02 is online
          # server03 is online
          #
          # print (' --> online'.format(server_name))
          # output
          # server01:5454 --> online
          # server02:5454 --> online
          # server03:5454 --> online
          else:
          server_name = server.get('address')
          print(' is offline'.format(server_name.split(':')[0]))





          share|improve this answer















          Here's another way to get the server status from the JSON.



          json_info = 
          "server01":
          "address":"server01:5454",
          "options": ,
          "state":"online"
          ,
          "server02":
          "address":"server02:5454",
          "options": ,
          "state":"online"
          ,
          "server03":
          "address":"server03:5454",
          "options": ,
          "state":"online"



          for server in json_info.values():
          server_status = server['state']
          if 'online' in server_status:
          server_name = server.get('address')
          print (' is online'.format(server_name.split(':')[0]))
          # output
          # server01 is online
          # server02 is online
          # server03 is online
          #
          # print (' --> online'.format(server_name))
          # output
          # server01:5454 --> online
          # server02:5454 --> online
          # server03:5454 --> online
          else:
          server_name = server.get('address')
          print(' is offline'.format(server_name.split(':')[0]))






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 9 at 2:44

























          answered Mar 9 at 2:14









          Life is complexLife is complex

          809518




          809518























              1














              Treat it as a dictionary:



              for k, v in sample.items():
              print(v['address'] + "-->" + v['state'])





              share|improve this answer



























                1














                Treat it as a dictionary:



                for k, v in sample.items():
                print(v['address'] + "-->" + v['state'])





                share|improve this answer

























                  1












                  1








                  1







                  Treat it as a dictionary:



                  for k, v in sample.items():
                  print(v['address'] + "-->" + v['state'])





                  share|improve this answer













                  Treat it as a dictionary:



                  for k, v in sample.items():
                  print(v['address'] + "-->" + v['state'])






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Mar 9 at 2:05









                  S. WangS. Wang

                  112




                  112



























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