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How to create an express Application with import instead of require



2019 Community Moderator ElectionExpressJS How to structure an application?Bad Request: SendStream.error while sending file as responsenode.js and express : how to wait for udp responsenode JS client vs servernodejs oauth2 token regeneration help neededAngularJs + Typescript: error TS2307: Cannot find module 'angular'How nginx proxy to express(node.js)?Why res.data is index.html?How do I connect a react frontend and express backend?solving the error 'Unexpected token < in JSON at position 0 at JSON.parse'How to send github OAuth data to client?










2















This is what works with require. We instead want it to use import.



import Request, Response, Application from 'express';

// TODO Figure out how NOT to use require here.
const express = require('express');
var app: Application = express();

app.get('/', function (req: Request, res: Response)
res.send('Hello World')
);

app.listen(3000);


What we have tried



Our tsconfig.json has "esModuleInterop": true.



Attempt # 1



import express from 'express';


That gives this error:




"node_modules/@types/express/index"' has no default export.ts




Attempt # 2



import * as express from 'express';
var app = express();


That gives a different error:




Cannot invoke an expression whose type lacks a call signature. Type 'typeof e' has no compatible call signatures.ts(2349)
index.ts(1, 1): Type originates at this import. A namespace-style import cannot be called or constructed, and will cause a failure at runtime. Consider using a default import or import require here instead.











share|improve this question






















  • I can tell you why Attempt #2 didn't work: You asked for a module namespace object, then tried to run it as a function.

    – T.J. Crowder
    Mar 6 at 18:30











  • Looks like @types/express is missing the fact that Express provides a default export that's a function. (I just double-checked that it does, and that import express from "express"; correctly retrieves it in JavaScript code with --experimental-modules enabled.) So definitely a types thing (as the error suggests). Looking in node_modules/@types/express/index.d.ts, I see that it at least tries to define an export for the express function: "Creates an Express application. The express() function is a top-level function exported by the express module."

    – T.J. Crowder
    Mar 6 at 18:35







  • 1





    @T.J.Crowder Doing a forced cast to a Function works: const app = (express as unknown as Function)();. It's certainly an ugly hack, though.

    – Shaun Luttin
    Mar 6 at 19:02







  • 1





    (Speaking of hacks: import * as mno from 'express'; const express = mno.default as unknown as Function;) But the real solution (which sadly I can't help with) is to sort out the types in @types/express/index.d.ts and/or TypeScript's use of them.

    – T.J. Crowder
    Mar 6 at 19:14







  • 1





    Sorting out the types would be a worthwhile pull request. I can add that to my "maybe someday" list of things to do.

    – Shaun Luttin
    Mar 6 at 21:00















2















This is what works with require. We instead want it to use import.



import Request, Response, Application from 'express';

// TODO Figure out how NOT to use require here.
const express = require('express');
var app: Application = express();

app.get('/', function (req: Request, res: Response)
res.send('Hello World')
);

app.listen(3000);


What we have tried



Our tsconfig.json has "esModuleInterop": true.



Attempt # 1



import express from 'express';


That gives this error:




"node_modules/@types/express/index"' has no default export.ts




Attempt # 2



import * as express from 'express';
var app = express();


That gives a different error:




Cannot invoke an expression whose type lacks a call signature. Type 'typeof e' has no compatible call signatures.ts(2349)
index.ts(1, 1): Type originates at this import. A namespace-style import cannot be called or constructed, and will cause a failure at runtime. Consider using a default import or import require here instead.











share|improve this question






















  • I can tell you why Attempt #2 didn't work: You asked for a module namespace object, then tried to run it as a function.

    – T.J. Crowder
    Mar 6 at 18:30











  • Looks like @types/express is missing the fact that Express provides a default export that's a function. (I just double-checked that it does, and that import express from "express"; correctly retrieves it in JavaScript code with --experimental-modules enabled.) So definitely a types thing (as the error suggests). Looking in node_modules/@types/express/index.d.ts, I see that it at least tries to define an export for the express function: "Creates an Express application. The express() function is a top-level function exported by the express module."

    – T.J. Crowder
    Mar 6 at 18:35







  • 1





    @T.J.Crowder Doing a forced cast to a Function works: const app = (express as unknown as Function)();. It's certainly an ugly hack, though.

    – Shaun Luttin
    Mar 6 at 19:02







  • 1





    (Speaking of hacks: import * as mno from 'express'; const express = mno.default as unknown as Function;) But the real solution (which sadly I can't help with) is to sort out the types in @types/express/index.d.ts and/or TypeScript's use of them.

    – T.J. Crowder
    Mar 6 at 19:14







  • 1





    Sorting out the types would be a worthwhile pull request. I can add that to my "maybe someday" list of things to do.

    – Shaun Luttin
    Mar 6 at 21:00













2












2








2








This is what works with require. We instead want it to use import.



import Request, Response, Application from 'express';

// TODO Figure out how NOT to use require here.
const express = require('express');
var app: Application = express();

app.get('/', function (req: Request, res: Response)
res.send('Hello World')
);

app.listen(3000);


What we have tried



Our tsconfig.json has "esModuleInterop": true.



Attempt # 1



import express from 'express';


That gives this error:




"node_modules/@types/express/index"' has no default export.ts




Attempt # 2



import * as express from 'express';
var app = express();


That gives a different error:




Cannot invoke an expression whose type lacks a call signature. Type 'typeof e' has no compatible call signatures.ts(2349)
index.ts(1, 1): Type originates at this import. A namespace-style import cannot be called or constructed, and will cause a failure at runtime. Consider using a default import or import require here instead.











share|improve this question














This is what works with require. We instead want it to use import.



import Request, Response, Application from 'express';

// TODO Figure out how NOT to use require here.
const express = require('express');
var app: Application = express();

app.get('/', function (req: Request, res: Response)
res.send('Hello World')
);

app.listen(3000);


What we have tried



Our tsconfig.json has "esModuleInterop": true.



Attempt # 1



import express from 'express';


That gives this error:




"node_modules/@types/express/index"' has no default export.ts




Attempt # 2



import * as express from 'express';
var app = express();


That gives a different error:




Cannot invoke an expression whose type lacks a call signature. Type 'typeof e' has no compatible call signatures.ts(2349)
index.ts(1, 1): Type originates at this import. A namespace-style import cannot be called or constructed, and will cause a failure at runtime. Consider using a default import or import require here instead.








typescript express






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 6 at 18:21









Shaun LuttinShaun Luttin

61.5k34233292




61.5k34233292












  • I can tell you why Attempt #2 didn't work: You asked for a module namespace object, then tried to run it as a function.

    – T.J. Crowder
    Mar 6 at 18:30











  • Looks like @types/express is missing the fact that Express provides a default export that's a function. (I just double-checked that it does, and that import express from "express"; correctly retrieves it in JavaScript code with --experimental-modules enabled.) So definitely a types thing (as the error suggests). Looking in node_modules/@types/express/index.d.ts, I see that it at least tries to define an export for the express function: "Creates an Express application. The express() function is a top-level function exported by the express module."

    – T.J. Crowder
    Mar 6 at 18:35







  • 1





    @T.J.Crowder Doing a forced cast to a Function works: const app = (express as unknown as Function)();. It's certainly an ugly hack, though.

    – Shaun Luttin
    Mar 6 at 19:02







  • 1





    (Speaking of hacks: import * as mno from 'express'; const express = mno.default as unknown as Function;) But the real solution (which sadly I can't help with) is to sort out the types in @types/express/index.d.ts and/or TypeScript's use of them.

    – T.J. Crowder
    Mar 6 at 19:14







  • 1





    Sorting out the types would be a worthwhile pull request. I can add that to my "maybe someday" list of things to do.

    – Shaun Luttin
    Mar 6 at 21:00

















  • I can tell you why Attempt #2 didn't work: You asked for a module namespace object, then tried to run it as a function.

    – T.J. Crowder
    Mar 6 at 18:30











  • Looks like @types/express is missing the fact that Express provides a default export that's a function. (I just double-checked that it does, and that import express from "express"; correctly retrieves it in JavaScript code with --experimental-modules enabled.) So definitely a types thing (as the error suggests). Looking in node_modules/@types/express/index.d.ts, I see that it at least tries to define an export for the express function: "Creates an Express application. The express() function is a top-level function exported by the express module."

    – T.J. Crowder
    Mar 6 at 18:35







  • 1





    @T.J.Crowder Doing a forced cast to a Function works: const app = (express as unknown as Function)();. It's certainly an ugly hack, though.

    – Shaun Luttin
    Mar 6 at 19:02







  • 1





    (Speaking of hacks: import * as mno from 'express'; const express = mno.default as unknown as Function;) But the real solution (which sadly I can't help with) is to sort out the types in @types/express/index.d.ts and/or TypeScript's use of them.

    – T.J. Crowder
    Mar 6 at 19:14







  • 1





    Sorting out the types would be a worthwhile pull request. I can add that to my "maybe someday" list of things to do.

    – Shaun Luttin
    Mar 6 at 21:00
















I can tell you why Attempt #2 didn't work: You asked for a module namespace object, then tried to run it as a function.

– T.J. Crowder
Mar 6 at 18:30





I can tell you why Attempt #2 didn't work: You asked for a module namespace object, then tried to run it as a function.

– T.J. Crowder
Mar 6 at 18:30













Looks like @types/express is missing the fact that Express provides a default export that's a function. (I just double-checked that it does, and that import express from "express"; correctly retrieves it in JavaScript code with --experimental-modules enabled.) So definitely a types thing (as the error suggests). Looking in node_modules/@types/express/index.d.ts, I see that it at least tries to define an export for the express function: "Creates an Express application. The express() function is a top-level function exported by the express module."

– T.J. Crowder
Mar 6 at 18:35






Looks like @types/express is missing the fact that Express provides a default export that's a function. (I just double-checked that it does, and that import express from "express"; correctly retrieves it in JavaScript code with --experimental-modules enabled.) So definitely a types thing (as the error suggests). Looking in node_modules/@types/express/index.d.ts, I see that it at least tries to define an export for the express function: "Creates an Express application. The express() function is a top-level function exported by the express module."

– T.J. Crowder
Mar 6 at 18:35





1




1





@T.J.Crowder Doing a forced cast to a Function works: const app = (express as unknown as Function)();. It's certainly an ugly hack, though.

– Shaun Luttin
Mar 6 at 19:02






@T.J.Crowder Doing a forced cast to a Function works: const app = (express as unknown as Function)();. It's certainly an ugly hack, though.

– Shaun Luttin
Mar 6 at 19:02





1




1





(Speaking of hacks: import * as mno from 'express'; const express = mno.default as unknown as Function;) But the real solution (which sadly I can't help with) is to sort out the types in @types/express/index.d.ts and/or TypeScript's use of them.

– T.J. Crowder
Mar 6 at 19:14






(Speaking of hacks: import * as mno from 'express'; const express = mno.default as unknown as Function;) But the real solution (which sadly I can't help with) is to sort out the types in @types/express/index.d.ts and/or TypeScript's use of them.

– T.J. Crowder
Mar 6 at 19:14





1




1





Sorting out the types would be a worthwhile pull request. I can add that to my "maybe someday" list of things to do.

– Shaun Luttin
Mar 6 at 21:00





Sorting out the types would be a worthwhile pull request. I can add that to my "maybe someday" list of things to do.

– Shaun Luttin
Mar 6 at 21:00












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