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Polar histogram in Python for given r, theta and z values



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1















I have a dataframe consisting of measurements from a particular magnetometer station over time, with columns corresponding to:



  • its latitude (which I think of as a radius)

  • its azimuthal angle

  • a measured quantity at this specific time

I was wondering of a way to plot this dataframe as a polar histogram for the measured variable: ie something like this:



Shi et al, 2018, doi:10.1029/2017JA025033



I have looked at the special histogram in physt but this allows me to only put in x,y values and I'm quite confused by it all.



Could anybody help?










share|improve this question
























  • Just wanted to say that is a very cool chart

    – rgk
    Mar 8 at 13:38











  • Seconding on the cool chart. The closest I've ever encountered is matplotlib.org/basemap/users/paeqd.html but I'm not sure it can be stretched for this kind of output

    – roganjosh
    Mar 8 at 13:39











  • Are you sure you want a histogram? That seems to contradict the third requirement "a measured quantity at this specific time". Can you clarify what exactly you need?

    – ImportanceOfBeingErnest
    Mar 8 at 13:53











  • Essential what I want to show is a certain characteristic of the measured quantity at a specific radius-azimuth bin. So with histogram what I mean is an occurrence number in the specific radius-azimuth bin. Does that help?

    – R Thompson
    Mar 8 at 14:20











  • No, it doesn't. It's easy: Do you have 2 columns, radius and azimut? Then you can plot occurance as histogram. Do you have 3 columns, radius and azimut, measured quantity, then you cannot plot a histogram, but rather the measured quantity as a function of the other two. Which one is it?

    – ImportanceOfBeingErnest
    Mar 8 at 17:16

















1















I have a dataframe consisting of measurements from a particular magnetometer station over time, with columns corresponding to:



  • its latitude (which I think of as a radius)

  • its azimuthal angle

  • a measured quantity at this specific time

I was wondering of a way to plot this dataframe as a polar histogram for the measured variable: ie something like this:



Shi et al, 2018, doi:10.1029/2017JA025033



I have looked at the special histogram in physt but this allows me to only put in x,y values and I'm quite confused by it all.



Could anybody help?










share|improve this question
























  • Just wanted to say that is a very cool chart

    – rgk
    Mar 8 at 13:38











  • Seconding on the cool chart. The closest I've ever encountered is matplotlib.org/basemap/users/paeqd.html but I'm not sure it can be stretched for this kind of output

    – roganjosh
    Mar 8 at 13:39











  • Are you sure you want a histogram? That seems to contradict the third requirement "a measured quantity at this specific time". Can you clarify what exactly you need?

    – ImportanceOfBeingErnest
    Mar 8 at 13:53











  • Essential what I want to show is a certain characteristic of the measured quantity at a specific radius-azimuth bin. So with histogram what I mean is an occurrence number in the specific radius-azimuth bin. Does that help?

    – R Thompson
    Mar 8 at 14:20











  • No, it doesn't. It's easy: Do you have 2 columns, radius and azimut? Then you can plot occurance as histogram. Do you have 3 columns, radius and azimut, measured quantity, then you cannot plot a histogram, but rather the measured quantity as a function of the other two. Which one is it?

    – ImportanceOfBeingErnest
    Mar 8 at 17:16













1












1








1








I have a dataframe consisting of measurements from a particular magnetometer station over time, with columns corresponding to:



  • its latitude (which I think of as a radius)

  • its azimuthal angle

  • a measured quantity at this specific time

I was wondering of a way to plot this dataframe as a polar histogram for the measured variable: ie something like this:



Shi et al, 2018, doi:10.1029/2017JA025033



I have looked at the special histogram in physt but this allows me to only put in x,y values and I'm quite confused by it all.



Could anybody help?










share|improve this question
















I have a dataframe consisting of measurements from a particular magnetometer station over time, with columns corresponding to:



  • its latitude (which I think of as a radius)

  • its azimuthal angle

  • a measured quantity at this specific time

I was wondering of a way to plot this dataframe as a polar histogram for the measured variable: ie something like this:



Shi et al, 2018, doi:10.1029/2017JA025033



I have looked at the special histogram in physt but this allows me to only put in x,y values and I'm quite confused by it all.



Could anybody help?







python matplotlib polar-coordinates






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 8 at 13:38







R Thompson

















asked Mar 8 at 13:35









R ThompsonR Thompson

7318




7318












  • Just wanted to say that is a very cool chart

    – rgk
    Mar 8 at 13:38











  • Seconding on the cool chart. The closest I've ever encountered is matplotlib.org/basemap/users/paeqd.html but I'm not sure it can be stretched for this kind of output

    – roganjosh
    Mar 8 at 13:39











  • Are you sure you want a histogram? That seems to contradict the third requirement "a measured quantity at this specific time". Can you clarify what exactly you need?

    – ImportanceOfBeingErnest
    Mar 8 at 13:53











  • Essential what I want to show is a certain characteristic of the measured quantity at a specific radius-azimuth bin. So with histogram what I mean is an occurrence number in the specific radius-azimuth bin. Does that help?

    – R Thompson
    Mar 8 at 14:20











  • No, it doesn't. It's easy: Do you have 2 columns, radius and azimut? Then you can plot occurance as histogram. Do you have 3 columns, radius and azimut, measured quantity, then you cannot plot a histogram, but rather the measured quantity as a function of the other two. Which one is it?

    – ImportanceOfBeingErnest
    Mar 8 at 17:16

















  • Just wanted to say that is a very cool chart

    – rgk
    Mar 8 at 13:38











  • Seconding on the cool chart. The closest I've ever encountered is matplotlib.org/basemap/users/paeqd.html but I'm not sure it can be stretched for this kind of output

    – roganjosh
    Mar 8 at 13:39











  • Are you sure you want a histogram? That seems to contradict the third requirement "a measured quantity at this specific time". Can you clarify what exactly you need?

    – ImportanceOfBeingErnest
    Mar 8 at 13:53











  • Essential what I want to show is a certain characteristic of the measured quantity at a specific radius-azimuth bin. So with histogram what I mean is an occurrence number in the specific radius-azimuth bin. Does that help?

    – R Thompson
    Mar 8 at 14:20











  • No, it doesn't. It's easy: Do you have 2 columns, radius and azimut? Then you can plot occurance as histogram. Do you have 3 columns, radius and azimut, measured quantity, then you cannot plot a histogram, but rather the measured quantity as a function of the other two. Which one is it?

    – ImportanceOfBeingErnest
    Mar 8 at 17:16
















Just wanted to say that is a very cool chart

– rgk
Mar 8 at 13:38





Just wanted to say that is a very cool chart

– rgk
Mar 8 at 13:38













Seconding on the cool chart. The closest I've ever encountered is matplotlib.org/basemap/users/paeqd.html but I'm not sure it can be stretched for this kind of output

– roganjosh
Mar 8 at 13:39





Seconding on the cool chart. The closest I've ever encountered is matplotlib.org/basemap/users/paeqd.html but I'm not sure it can be stretched for this kind of output

– roganjosh
Mar 8 at 13:39













Are you sure you want a histogram? That seems to contradict the third requirement "a measured quantity at this specific time". Can you clarify what exactly you need?

– ImportanceOfBeingErnest
Mar 8 at 13:53





Are you sure you want a histogram? That seems to contradict the third requirement "a measured quantity at this specific time". Can you clarify what exactly you need?

– ImportanceOfBeingErnest
Mar 8 at 13:53













Essential what I want to show is a certain characteristic of the measured quantity at a specific radius-azimuth bin. So with histogram what I mean is an occurrence number in the specific radius-azimuth bin. Does that help?

– R Thompson
Mar 8 at 14:20





Essential what I want to show is a certain characteristic of the measured quantity at a specific radius-azimuth bin. So with histogram what I mean is an occurrence number in the specific radius-azimuth bin. Does that help?

– R Thompson
Mar 8 at 14:20













No, it doesn't. It's easy: Do you have 2 columns, radius and azimut? Then you can plot occurance as histogram. Do you have 3 columns, radius and azimut, measured quantity, then you cannot plot a histogram, but rather the measured quantity as a function of the other two. Which one is it?

– ImportanceOfBeingErnest
Mar 8 at 17:16





No, it doesn't. It's easy: Do you have 2 columns, radius and azimut? Then you can plot occurance as histogram. Do you have 3 columns, radius and azimut, measured quantity, then you cannot plot a histogram, but rather the measured quantity as a function of the other two. Which one is it?

– ImportanceOfBeingErnest
Mar 8 at 17:16












3 Answers
3






active

oldest

votes


















1














Calculating a histogram is easily done with numpy.histogram2d. Plotting the resulting 2D array can be done with matplotlib's pcolormesh.



import numpy as np; np.random.seed(42)
import matplotlib.pyplot as plt

# two input arrays
azimut = np.random.rand(3000)*2*np.pi
radius = np.random.rayleigh(29, size=3000)

# define binning
rbins = np.linspace(0,radius.max(), 30)
abins = np.linspace(0,2*np.pi, 60)

#calculate histogram
hist, _, _ = np.histogram2d(azimut, radius, bins=(abins, rbins))
A, R = np.meshgrid(abins, rbins)

# plot
fig, ax = plt.subplots(subplot_kw=dict(projection="polar"))

pc = ax.pcolormesh(A, R, hist.T, cmap="magma_r")
fig.colorbar(pc)

plt.show()


enter image description here






share|improve this answer























  • Thanks this was exactly what I wanted!

    – R Thompson
    Mar 8 at 18:48


















2














This appears to be what you're looking for: https://physt.readthedocs.io/en/latest/special_histograms.html#Polar-histogram



from physt import histogram, binnings, special
import numpy as np
import matplotlib.pyplot as plt

# Generate some points in the Cartesian coordinates
np.random.seed(42)

x = np.random.rand(1000)
y = np.random.rand(1000)
z = np.random.rand(1000)

# Create a polar histogram with default parameters
hist = special.polar_histogram(x, y)
ax = hist.plot.polar_map()


Polar histogram created with physt



The docs linked include more examples with colors, bin sizing etc.



Edit: I think this is going to take a bit of munging to get your data into the right shape, but I think this example illustrates the library's capabilities and can be adjusted to your use case:



import random
import numpy as np
import matplotlib.pyplot as plt
from physt import special

# Generate some points in the Cartesian coordinates
np.random.seed(42)

gen = lambda l, h, s = 3000: np.asarray([random.random() * (h - l) + l for _ in range(s)])

X = gen(-100, 100)
Y = gen(-1000, 1000)
Z = gen(0, 1400)

hist = special.polar_histogram(X, Y, weights=Z, radial_bins=40)
# ax = hist.plot.polar_map()

hist.plot.polar_map(density=True, show_zero=False, cmap="inferno", lw=0.5, figsize=(5, 5))
plt.show()


Example with color & custom coordinates






share|improve this answer

























  • This is what I originally tried, but it doesn't allow for any z information as far as I could figure out

    – R Thompson
    Mar 8 at 13:40











  • z information as in magnitude? Isn't that just the values in the data? Forgive me if I'm not fully understanding your question

    – rgk
    Mar 8 at 13:44











  • I guess for now the values in the data of the measured quantity might not be the most relevant. So forget that apart for now. So I have effectively a time series for r and theta, how would I put that into the function above to get the histogram over the whole azimuthal space?

    – R Thompson
    Mar 8 at 13:54











  • Edited my example above - the package receives X & Y as cartesian coordinates, and your polar coodinate data can be transformed to fit the function and produce the chart you want (see more: math.uh.edu/~mmsosa/Math1330/Calendar/1330Day28.pdf). I used extreme values for Y to illustrate the point, but symmetrically scaled X & Y inputs would produce a radially symmetric chart.

    – rgk
    Mar 8 at 15:05



















0














This is not the full answer but you could find some ideas hear :
https://github.com/TronSkywalker/Visuals/blob/master/Circular_bar_charts.py



let me know how far you came!:)






share|improve this answer























  • Technically you would need to replace the zip(..)-loop with a double for-loop over r and the angles. The colors can be intuitively coupled more or less to your z direction.

    – Richard Lenkiewicz
    Mar 8 at 13:45











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3 Answers
3






active

oldest

votes








3 Answers
3






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














Calculating a histogram is easily done with numpy.histogram2d. Plotting the resulting 2D array can be done with matplotlib's pcolormesh.



import numpy as np; np.random.seed(42)
import matplotlib.pyplot as plt

# two input arrays
azimut = np.random.rand(3000)*2*np.pi
radius = np.random.rayleigh(29, size=3000)

# define binning
rbins = np.linspace(0,radius.max(), 30)
abins = np.linspace(0,2*np.pi, 60)

#calculate histogram
hist, _, _ = np.histogram2d(azimut, radius, bins=(abins, rbins))
A, R = np.meshgrid(abins, rbins)

# plot
fig, ax = plt.subplots(subplot_kw=dict(projection="polar"))

pc = ax.pcolormesh(A, R, hist.T, cmap="magma_r")
fig.colorbar(pc)

plt.show()


enter image description here






share|improve this answer























  • Thanks this was exactly what I wanted!

    – R Thompson
    Mar 8 at 18:48















1














Calculating a histogram is easily done with numpy.histogram2d. Plotting the resulting 2D array can be done with matplotlib's pcolormesh.



import numpy as np; np.random.seed(42)
import matplotlib.pyplot as plt

# two input arrays
azimut = np.random.rand(3000)*2*np.pi
radius = np.random.rayleigh(29, size=3000)

# define binning
rbins = np.linspace(0,radius.max(), 30)
abins = np.linspace(0,2*np.pi, 60)

#calculate histogram
hist, _, _ = np.histogram2d(azimut, radius, bins=(abins, rbins))
A, R = np.meshgrid(abins, rbins)

# plot
fig, ax = plt.subplots(subplot_kw=dict(projection="polar"))

pc = ax.pcolormesh(A, R, hist.T, cmap="magma_r")
fig.colorbar(pc)

plt.show()


enter image description here






share|improve this answer























  • Thanks this was exactly what I wanted!

    – R Thompson
    Mar 8 at 18:48













1












1








1







Calculating a histogram is easily done with numpy.histogram2d. Plotting the resulting 2D array can be done with matplotlib's pcolormesh.



import numpy as np; np.random.seed(42)
import matplotlib.pyplot as plt

# two input arrays
azimut = np.random.rand(3000)*2*np.pi
radius = np.random.rayleigh(29, size=3000)

# define binning
rbins = np.linspace(0,radius.max(), 30)
abins = np.linspace(0,2*np.pi, 60)

#calculate histogram
hist, _, _ = np.histogram2d(azimut, radius, bins=(abins, rbins))
A, R = np.meshgrid(abins, rbins)

# plot
fig, ax = plt.subplots(subplot_kw=dict(projection="polar"))

pc = ax.pcolormesh(A, R, hist.T, cmap="magma_r")
fig.colorbar(pc)

plt.show()


enter image description here






share|improve this answer













Calculating a histogram is easily done with numpy.histogram2d. Plotting the resulting 2D array can be done with matplotlib's pcolormesh.



import numpy as np; np.random.seed(42)
import matplotlib.pyplot as plt

# two input arrays
azimut = np.random.rand(3000)*2*np.pi
radius = np.random.rayleigh(29, size=3000)

# define binning
rbins = np.linspace(0,radius.max(), 30)
abins = np.linspace(0,2*np.pi, 60)

#calculate histogram
hist, _, _ = np.histogram2d(azimut, radius, bins=(abins, rbins))
A, R = np.meshgrid(abins, rbins)

# plot
fig, ax = plt.subplots(subplot_kw=dict(projection="polar"))

pc = ax.pcolormesh(A, R, hist.T, cmap="magma_r")
fig.colorbar(pc)

plt.show()


enter image description here







share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 8 at 17:46









ImportanceOfBeingErnestImportanceOfBeingErnest

142k13169248




142k13169248












  • Thanks this was exactly what I wanted!

    – R Thompson
    Mar 8 at 18:48

















  • Thanks this was exactly what I wanted!

    – R Thompson
    Mar 8 at 18:48
















Thanks this was exactly what I wanted!

– R Thompson
Mar 8 at 18:48





Thanks this was exactly what I wanted!

– R Thompson
Mar 8 at 18:48













2














This appears to be what you're looking for: https://physt.readthedocs.io/en/latest/special_histograms.html#Polar-histogram



from physt import histogram, binnings, special
import numpy as np
import matplotlib.pyplot as plt

# Generate some points in the Cartesian coordinates
np.random.seed(42)

x = np.random.rand(1000)
y = np.random.rand(1000)
z = np.random.rand(1000)

# Create a polar histogram with default parameters
hist = special.polar_histogram(x, y)
ax = hist.plot.polar_map()


Polar histogram created with physt



The docs linked include more examples with colors, bin sizing etc.



Edit: I think this is going to take a bit of munging to get your data into the right shape, but I think this example illustrates the library's capabilities and can be adjusted to your use case:



import random
import numpy as np
import matplotlib.pyplot as plt
from physt import special

# Generate some points in the Cartesian coordinates
np.random.seed(42)

gen = lambda l, h, s = 3000: np.asarray([random.random() * (h - l) + l for _ in range(s)])

X = gen(-100, 100)
Y = gen(-1000, 1000)
Z = gen(0, 1400)

hist = special.polar_histogram(X, Y, weights=Z, radial_bins=40)
# ax = hist.plot.polar_map()

hist.plot.polar_map(density=True, show_zero=False, cmap="inferno", lw=0.5, figsize=(5, 5))
plt.show()


Example with color & custom coordinates






share|improve this answer

























  • This is what I originally tried, but it doesn't allow for any z information as far as I could figure out

    – R Thompson
    Mar 8 at 13:40











  • z information as in magnitude? Isn't that just the values in the data? Forgive me if I'm not fully understanding your question

    – rgk
    Mar 8 at 13:44











  • I guess for now the values in the data of the measured quantity might not be the most relevant. So forget that apart for now. So I have effectively a time series for r and theta, how would I put that into the function above to get the histogram over the whole azimuthal space?

    – R Thompson
    Mar 8 at 13:54











  • Edited my example above - the package receives X & Y as cartesian coordinates, and your polar coodinate data can be transformed to fit the function and produce the chart you want (see more: math.uh.edu/~mmsosa/Math1330/Calendar/1330Day28.pdf). I used extreme values for Y to illustrate the point, but symmetrically scaled X & Y inputs would produce a radially symmetric chart.

    – rgk
    Mar 8 at 15:05
















2














This appears to be what you're looking for: https://physt.readthedocs.io/en/latest/special_histograms.html#Polar-histogram



from physt import histogram, binnings, special
import numpy as np
import matplotlib.pyplot as plt

# Generate some points in the Cartesian coordinates
np.random.seed(42)

x = np.random.rand(1000)
y = np.random.rand(1000)
z = np.random.rand(1000)

# Create a polar histogram with default parameters
hist = special.polar_histogram(x, y)
ax = hist.plot.polar_map()


Polar histogram created with physt



The docs linked include more examples with colors, bin sizing etc.



Edit: I think this is going to take a bit of munging to get your data into the right shape, but I think this example illustrates the library's capabilities and can be adjusted to your use case:



import random
import numpy as np
import matplotlib.pyplot as plt
from physt import special

# Generate some points in the Cartesian coordinates
np.random.seed(42)

gen = lambda l, h, s = 3000: np.asarray([random.random() * (h - l) + l for _ in range(s)])

X = gen(-100, 100)
Y = gen(-1000, 1000)
Z = gen(0, 1400)

hist = special.polar_histogram(X, Y, weights=Z, radial_bins=40)
# ax = hist.plot.polar_map()

hist.plot.polar_map(density=True, show_zero=False, cmap="inferno", lw=0.5, figsize=(5, 5))
plt.show()


Example with color & custom coordinates






share|improve this answer

























  • This is what I originally tried, but it doesn't allow for any z information as far as I could figure out

    – R Thompson
    Mar 8 at 13:40











  • z information as in magnitude? Isn't that just the values in the data? Forgive me if I'm not fully understanding your question

    – rgk
    Mar 8 at 13:44











  • I guess for now the values in the data of the measured quantity might not be the most relevant. So forget that apart for now. So I have effectively a time series for r and theta, how would I put that into the function above to get the histogram over the whole azimuthal space?

    – R Thompson
    Mar 8 at 13:54











  • Edited my example above - the package receives X & Y as cartesian coordinates, and your polar coodinate data can be transformed to fit the function and produce the chart you want (see more: math.uh.edu/~mmsosa/Math1330/Calendar/1330Day28.pdf). I used extreme values for Y to illustrate the point, but symmetrically scaled X & Y inputs would produce a radially symmetric chart.

    – rgk
    Mar 8 at 15:05














2












2








2







This appears to be what you're looking for: https://physt.readthedocs.io/en/latest/special_histograms.html#Polar-histogram



from physt import histogram, binnings, special
import numpy as np
import matplotlib.pyplot as plt

# Generate some points in the Cartesian coordinates
np.random.seed(42)

x = np.random.rand(1000)
y = np.random.rand(1000)
z = np.random.rand(1000)

# Create a polar histogram with default parameters
hist = special.polar_histogram(x, y)
ax = hist.plot.polar_map()


Polar histogram created with physt



The docs linked include more examples with colors, bin sizing etc.



Edit: I think this is going to take a bit of munging to get your data into the right shape, but I think this example illustrates the library's capabilities and can be adjusted to your use case:



import random
import numpy as np
import matplotlib.pyplot as plt
from physt import special

# Generate some points in the Cartesian coordinates
np.random.seed(42)

gen = lambda l, h, s = 3000: np.asarray([random.random() * (h - l) + l for _ in range(s)])

X = gen(-100, 100)
Y = gen(-1000, 1000)
Z = gen(0, 1400)

hist = special.polar_histogram(X, Y, weights=Z, radial_bins=40)
# ax = hist.plot.polar_map()

hist.plot.polar_map(density=True, show_zero=False, cmap="inferno", lw=0.5, figsize=(5, 5))
plt.show()


Example with color & custom coordinates






share|improve this answer















This appears to be what you're looking for: https://physt.readthedocs.io/en/latest/special_histograms.html#Polar-histogram



from physt import histogram, binnings, special
import numpy as np
import matplotlib.pyplot as plt

# Generate some points in the Cartesian coordinates
np.random.seed(42)

x = np.random.rand(1000)
y = np.random.rand(1000)
z = np.random.rand(1000)

# Create a polar histogram with default parameters
hist = special.polar_histogram(x, y)
ax = hist.plot.polar_map()


Polar histogram created with physt



The docs linked include more examples with colors, bin sizing etc.



Edit: I think this is going to take a bit of munging to get your data into the right shape, but I think this example illustrates the library's capabilities and can be adjusted to your use case:



import random
import numpy as np
import matplotlib.pyplot as plt
from physt import special

# Generate some points in the Cartesian coordinates
np.random.seed(42)

gen = lambda l, h, s = 3000: np.asarray([random.random() * (h - l) + l for _ in range(s)])

X = gen(-100, 100)
Y = gen(-1000, 1000)
Z = gen(0, 1400)

hist = special.polar_histogram(X, Y, weights=Z, radial_bins=40)
# ax = hist.plot.polar_map()

hist.plot.polar_map(density=True, show_zero=False, cmap="inferno", lw=0.5, figsize=(5, 5))
plt.show()


Example with color & custom coordinates







share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 8 at 14:57

























answered Mar 8 at 13:39









rgkrgk

420510




420510












  • This is what I originally tried, but it doesn't allow for any z information as far as I could figure out

    – R Thompson
    Mar 8 at 13:40











  • z information as in magnitude? Isn't that just the values in the data? Forgive me if I'm not fully understanding your question

    – rgk
    Mar 8 at 13:44











  • I guess for now the values in the data of the measured quantity might not be the most relevant. So forget that apart for now. So I have effectively a time series for r and theta, how would I put that into the function above to get the histogram over the whole azimuthal space?

    – R Thompson
    Mar 8 at 13:54











  • Edited my example above - the package receives X & Y as cartesian coordinates, and your polar coodinate data can be transformed to fit the function and produce the chart you want (see more: math.uh.edu/~mmsosa/Math1330/Calendar/1330Day28.pdf). I used extreme values for Y to illustrate the point, but symmetrically scaled X & Y inputs would produce a radially symmetric chart.

    – rgk
    Mar 8 at 15:05


















  • This is what I originally tried, but it doesn't allow for any z information as far as I could figure out

    – R Thompson
    Mar 8 at 13:40











  • z information as in magnitude? Isn't that just the values in the data? Forgive me if I'm not fully understanding your question

    – rgk
    Mar 8 at 13:44











  • I guess for now the values in the data of the measured quantity might not be the most relevant. So forget that apart for now. So I have effectively a time series for r and theta, how would I put that into the function above to get the histogram over the whole azimuthal space?

    – R Thompson
    Mar 8 at 13:54











  • Edited my example above - the package receives X & Y as cartesian coordinates, and your polar coodinate data can be transformed to fit the function and produce the chart you want (see more: math.uh.edu/~mmsosa/Math1330/Calendar/1330Day28.pdf). I used extreme values for Y to illustrate the point, but symmetrically scaled X & Y inputs would produce a radially symmetric chart.

    – rgk
    Mar 8 at 15:05

















This is what I originally tried, but it doesn't allow for any z information as far as I could figure out

– R Thompson
Mar 8 at 13:40





This is what I originally tried, but it doesn't allow for any z information as far as I could figure out

– R Thompson
Mar 8 at 13:40













z information as in magnitude? Isn't that just the values in the data? Forgive me if I'm not fully understanding your question

– rgk
Mar 8 at 13:44





z information as in magnitude? Isn't that just the values in the data? Forgive me if I'm not fully understanding your question

– rgk
Mar 8 at 13:44













I guess for now the values in the data of the measured quantity might not be the most relevant. So forget that apart for now. So I have effectively a time series for r and theta, how would I put that into the function above to get the histogram over the whole azimuthal space?

– R Thompson
Mar 8 at 13:54





I guess for now the values in the data of the measured quantity might not be the most relevant. So forget that apart for now. So I have effectively a time series for r and theta, how would I put that into the function above to get the histogram over the whole azimuthal space?

– R Thompson
Mar 8 at 13:54













Edited my example above - the package receives X & Y as cartesian coordinates, and your polar coodinate data can be transformed to fit the function and produce the chart you want (see more: math.uh.edu/~mmsosa/Math1330/Calendar/1330Day28.pdf). I used extreme values for Y to illustrate the point, but symmetrically scaled X & Y inputs would produce a radially symmetric chart.

– rgk
Mar 8 at 15:05






Edited my example above - the package receives X & Y as cartesian coordinates, and your polar coodinate data can be transformed to fit the function and produce the chart you want (see more: math.uh.edu/~mmsosa/Math1330/Calendar/1330Day28.pdf). I used extreme values for Y to illustrate the point, but symmetrically scaled X & Y inputs would produce a radially symmetric chart.

– rgk
Mar 8 at 15:05












0














This is not the full answer but you could find some ideas hear :
https://github.com/TronSkywalker/Visuals/blob/master/Circular_bar_charts.py



let me know how far you came!:)






share|improve this answer























  • Technically you would need to replace the zip(..)-loop with a double for-loop over r and the angles. The colors can be intuitively coupled more or less to your z direction.

    – Richard Lenkiewicz
    Mar 8 at 13:45















0














This is not the full answer but you could find some ideas hear :
https://github.com/TronSkywalker/Visuals/blob/master/Circular_bar_charts.py



let me know how far you came!:)






share|improve this answer























  • Technically you would need to replace the zip(..)-loop with a double for-loop over r and the angles. The colors can be intuitively coupled more or less to your z direction.

    – Richard Lenkiewicz
    Mar 8 at 13:45













0












0








0







This is not the full answer but you could find some ideas hear :
https://github.com/TronSkywalker/Visuals/blob/master/Circular_bar_charts.py



let me know how far you came!:)






share|improve this answer













This is not the full answer but you could find some ideas hear :
https://github.com/TronSkywalker/Visuals/blob/master/Circular_bar_charts.py



let me know how far you came!:)







share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 8 at 13:40









Richard LenkiewiczRichard Lenkiewicz

594




594












  • Technically you would need to replace the zip(..)-loop with a double for-loop over r and the angles. The colors can be intuitively coupled more or less to your z direction.

    – Richard Lenkiewicz
    Mar 8 at 13:45

















  • Technically you would need to replace the zip(..)-loop with a double for-loop over r and the angles. The colors can be intuitively coupled more or less to your z direction.

    – Richard Lenkiewicz
    Mar 8 at 13:45
















Technically you would need to replace the zip(..)-loop with a double for-loop over r and the angles. The colors can be intuitively coupled more or less to your z direction.

– Richard Lenkiewicz
Mar 8 at 13:45





Technically you would need to replace the zip(..)-loop with a double for-loop over r and the angles. The colors can be intuitively coupled more or less to your z direction.

– Richard Lenkiewicz
Mar 8 at 13:45

















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