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stating that a property is not only “keyof” of a type but also an array of something
Keyof that is also of type TClass extended from built-in Array in Typescript 1.6.2 does not update length while using [] operatorHow to type nested properties with keyof?Travel in PreOrder on a BinTree in typescriptTypescript recursively mapping object property types: object and array element typesKeyof that is also of type TWhy Vuex state return array as an objectRemove properties of a type from another typeFind in array with different typesTypescript - Ensure Generic Property Exists On Generic Type With Descriptive ErrorAllow arbitrary properties in class Typescript types
I have the following function:
export function listMutations<S, M extends Model>(postfix: keyof S): MutationTree<S>
return
ADD(state, payload)
state[postfix].push(payload.value)
,
CHANGED(state, payload) ,
REMOVED(state, payload) ,
RELATIONSHIP_ADDED(state, payload) ,
RELATIONSHIP_REMOVED(state, payload) ,
Where S represents a particular "state tree" and M is a given data model. The "model" is meant to fit into the state tree. For example, imagine that the state tree looked like this:
export interface StateTree<M>
all: M[],
byId: ...
the postfix value passed into the function determines whether the property is "all" or something else but it is assumed that -- given the postfix property -- that:
postfixis a keyof of the state tree- and the value of the
postfixproperty is an array ofM
I have typed for the first condition but because this typing doesn't tell the type system that the value is always an array I get a type error on the .push() call.
I then looked at this question for reference: keyof-that-is-also-of-type-t. This helped somewhat and led to this attempt:
export type ListPropertyCandidates<T> = Pick<T, [K in keyof T]: T[K] extends Model[] ? K : never [keyof T]>
export function listMutations<T>(postfix: keyof ListPropertyCandidates<T>): MutationTree<T>
return
ADD(state, payload)
state[postfix].push(payload.value)
,
CHANGED(state, payload) ,
REMOVED(state, payload) ,
RELATIONSHIP_ADDED(state, payload) ,
RELATIONSHIP_REMOVED(state, payload) ,
I'd thought that inclusion of T[K] extends Model[] in the ListPropertyCandidates might get me there but the typing error persists in that it doesn't recognize the state[postfix] as always being an array.
Anyone have any ideas?
typescript
asked Mar 7 at 5:05
kenken
3,63974289
add a comment |
I have the following function:
export function listMutations<S, M extends Model>(postfix: keyof S): MutationTree<S>
return
ADD(state, payload)
state[postfix].push(payload.value)
,
CHANGED(state, payload) ,
REMOVED(state, payload) ,
RELATIONSHIP_ADDED(state, payload) ,
RELATIONSHIP_REMOVED(state, payload) ,
Where S represents a particular "state tree" and M is a given data model. The "model" is meant to fit into the state tree. For example, imagine that the state tree looked like this:
export interface StateTree<M>
all: M[],
byId: ...
the postfix value passed into the function determines whether the property is "all" or something else but it is assumed that -- given the postfix property -- that:
postfixis a keyof of the state tree- and the value of the
postfixproperty is an array ofM
I have typed for the first condition but because this typing doesn't tell the type system that the value is always an array I get a type error on the .push() call.
I then looked at this question for reference: keyof-that-is-also-of-type-t. This helped somewhat and led to this attempt:
export type ListPropertyCandidates<T> = Pick<T, [K in keyof T]: T[K] extends Model[] ? K : never [keyof T]>
export function listMutations<T>(postfix: keyof ListPropertyCandidates<T>): MutationTree<T>
return
ADD(state, payload)
state[postfix].push(payload.value)
,
CHANGED(state, payload) ,
REMOVED(state, payload) ,
RELATIONSHIP_ADDED(state, payload) ,
RELATIONSHIP_REMOVED(state, payload) ,
I'd thought that inclusion of T[K] extends Model[] in the ListPropertyCandidates might get me there but the typing error persists in that it doesn't recognize the state[postfix] as always being an array.
Anyone have any ideas?
typescript
asked Mar 7 at 5:05
kenken
3,63974289
You refer it asprefixoutside the code, but name itpostfixinside the code, are they supposed to be the same?
– paibamboo
Mar 7 at 7:35
If I understand you correctly, you could define the type ofstatelike soADD<V>(state: postfix: V[], payload: value: V) state.postfix.push(payload.value);
– paibamboo
Mar 7 at 7:42
Sorry it should saypostfixeverywhere; will update
– ken
Mar 7 at 19:50
add a comment |
I have the following function:
export function listMutations<S, M extends Model>(postfix: keyof S): MutationTree<S>
return
ADD(state, payload)
state[postfix].push(payload.value)
,
CHANGED(state, payload) ,
REMOVED(state, payload) ,
RELATIONSHIP_ADDED(state, payload) ,
RELATIONSHIP_REMOVED(state, payload) ,
Where S represents a particular "state tree" and M is a given data model. The "model" is meant to fit into the state tree. For example, imagine that the state tree looked like this:
export interface StateTree<M>
all: M[],
byId: ...
the postfix value passed into the function determines whether the property is "all" or something else but it is assumed that -- given the postfix property -- that:
postfixis a keyof of the state tree- and the value of the
postfixproperty is an array ofM
I have typed for the first condition but because this typing doesn't tell the type system that the value is always an array I get a type error on the .push() call.
I then looked at this question for reference: keyof-that-is-also-of-type-t. This helped somewhat and led to this attempt:
export type ListPropertyCandidates<T> = Pick<T, [K in keyof T]: T[K] extends Model[] ? K : never [keyof T]>
export function listMutations<T>(postfix: keyof ListPropertyCandidates<T>): MutationTree<T>
return
ADD(state, payload)
state[postfix].push(payload.value)
,
CHANGED(state, payload) ,
REMOVED(state, payload) ,
RELATIONSHIP_ADDED(state, payload) ,
RELATIONSHIP_REMOVED(state, payload) ,
I'd thought that inclusion of T[K] extends Model[] in the ListPropertyCandidates might get me there but the typing error persists in that it doesn't recognize the state[postfix] as always being an array.
Anyone have any ideas?
typescript
asked Mar 7 at 5:05
kenken
3,63974289
I have the following function:
export function listMutations<S, M extends Model>(postfix: keyof S): MutationTree<S>
return
ADD(state, payload)
state[postfix].push(payload.value)
,
CHANGED(state, payload) ,
REMOVED(state, payload) ,
RELATIONSHIP_ADDED(state, payload) ,
RELATIONSHIP_REMOVED(state, payload) ,
Where S represents a particular "state tree" and M is a given data model. The "model" is meant to fit into the state tree. For example, imagine that the state tree looked like this:
export interface StateTree<M>
all: M[],
byId: ...
the postfix value passed into the function determines whether the property is "all" or something else but it is assumed that -- given the postfix property -- that:
postfixis a keyof of the state tree- and the value of the
postfixproperty is an array ofM
I have typed for the first condition but because this typing doesn't tell the type system that the value is always an array I get a type error on the .push() call.
I then looked at this question for reference: keyof-that-is-also-of-type-t. This helped somewhat and led to this attempt:
export type ListPropertyCandidates<T> = Pick<T, [K in keyof T]: T[K] extends Model[] ? K : never [keyof T]>
export function listMutations<T>(postfix: keyof ListPropertyCandidates<T>): MutationTree<T>
return
ADD(state, payload)
state[postfix].push(payload.value)
,
CHANGED(state, payload) ,
REMOVED(state, payload) ,
RELATIONSHIP_ADDED(state, payload) ,
RELATIONSHIP_REMOVED(state, payload) ,
I'd thought that inclusion of T[K] extends Model[] in the ListPropertyCandidates might get me there but the typing error persists in that it doesn't recognize the state[postfix] as always being an array.
Anyone have any ideas?
typescript
typescript
asked Mar 7 at 5:05
kenken
3,63974289
asked Mar 7 at 5:05
kenken
3,63974289
edited Mar 7 at 19:51
ken
asked Mar 7 at 5:05
kenken
3,63974289
asked Mar 7 at 5:05
kenken
3,63974289
asked Mar 7 at 5:05
kenken
3,63974289
3,63974289
You refer it asprefixoutside the code, but name itpostfixinside the code, are they supposed to be the same?
– paibamboo
Mar 7 at 7:35
If I understand you correctly, you could define the type ofstatelike soADD<V>(state: postfix: V[], payload: value: V) state.postfix.push(payload.value);
– paibamboo
Mar 7 at 7:42
Sorry it should saypostfixeverywhere; will update
– ken
Mar 7 at 19:50
add a comment |
You refer it asprefixoutside the code, but name itpostfixinside the code, are they supposed to be the same?
– paibamboo
Mar 7 at 7:35
If I understand you correctly, you could define the type ofstatelike soADD<V>(state: postfix: V[], payload: value: V) state.postfix.push(payload.value);
– paibamboo
Mar 7 at 7:42
Sorry it should saypostfixeverywhere; will update
– ken
Mar 7 at 19:50
You refer it as
prefix outside the code, but name it postfix inside the code, are they supposed to be the same?– paibamboo
Mar 7 at 7:35
You refer it as
prefix outside the code, but name it postfix inside the code, are they supposed to be the same?– paibamboo
Mar 7 at 7:35
If I understand you correctly, you could define the type of
state like so ADD<V>(state: postfix: V[], payload: value: V) state.postfix.push(payload.value);– paibamboo
Mar 7 at 7:42
If I understand you correctly, you could define the type of
state like so ADD<V>(state: postfix: V[], payload: value: V) state.postfix.push(payload.value);– paibamboo
Mar 7 at 7:42
Sorry it should say
postfix everywhere; will update– ken
Mar 7 at 19:50
Sorry it should say
postfix everywhere; will update– ken
Mar 7 at 19:50
add a comment |
1 Answer
1
active
oldest
votes
I don't think it's possible without defining the type of state itself
function listMutations<S, M extends Model>(postfix: keyof S): MutationTree<S>
return
ADD(state: Record<keyof S, M[]>, payload: value: M)
state[postfix].push(payload.value);
,
...
answered Mar 8 at 1:52
paibamboopaibamboo
1,5311113
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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active
oldest
votes
active
oldest
votes
I don't think it's possible without defining the type of state itself
function listMutations<S, M extends Model>(postfix: keyof S): MutationTree<S>
return
ADD(state: Record<keyof S, M[]>, payload: value: M)
state[postfix].push(payload.value);
,
...
answered Mar 8 at 1:52
paibamboopaibamboo
1,5311113
add a comment |
I don't think it's possible without defining the type of state itself
function listMutations<S, M extends Model>(postfix: keyof S): MutationTree<S>
return
ADD(state: Record<keyof S, M[]>, payload: value: M)
state[postfix].push(payload.value);
,
...
answered Mar 8 at 1:52
paibamboopaibamboo
1,5311113
add a comment |
I don't think it's possible without defining the type of state itself
function listMutations<S, M extends Model>(postfix: keyof S): MutationTree<S>
return
ADD(state: Record<keyof S, M[]>, payload: value: M)
state[postfix].push(payload.value);
,
...
answered Mar 8 at 1:52
paibamboopaibamboo
1,5311113
I don't think it's possible without defining the type of state itself
function listMutations<S, M extends Model>(postfix: keyof S): MutationTree<S>
return
ADD(state: Record<keyof S, M[]>, payload: value: M)
state[postfix].push(payload.value);
,
...
answered Mar 8 at 1:52
paibamboopaibamboo
1,5311113
answered Mar 8 at 1:52
paibamboopaibamboo
1,5311113
answered Mar 8 at 1:52
paibamboopaibamboo
1,5311113
answered Mar 8 at 1:52
paibamboopaibamboo
1,5311113
1,5311113
add a comment |
add a comment |
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You refer it as
prefixoutside the code, but name itpostfixinside the code, are they supposed to be the same?– paibamboo
Mar 7 at 7:35
If I understand you correctly, you could define the type of
statelike soADD<V>(state: postfix: V[], payload: value: V) state.postfix.push(payload.value);– paibamboo
Mar 7 at 7:42
Sorry it should say
postfixeverywhere; will update– ken
Mar 7 at 19:50