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Too few arguments in function call

-4

I want to call the void getInput function in the main scope. But when I do this, it tells me:

too few argument in function call.

How do I fix this?

The first void function prints the exercises. Then I call it in the next void function called getInput. After that I just want to call it in the main() function.

#include <iostream>;
#include <string>;

using namespace std;

void Exercices()

 double speed;
 int minutes;

 cout << "walking: ";
 cin >> speed >> minutes;
 cout << "running: ";
 cin >> speed >> minutes;
 cout << "cycling: ";
 cin >> speed >> minutes;


void getInput(string username)

 double weight, goal;
 string walking, running, cycling;

 cout << "Please enter your name: ";
 cin >> username;
 cout << "Welcome " << username << ", please enter your weight(kg): ";
 cin >> weight;
 cout << username << ", please enter speed(km/h) and minutes spent in a week for the activities below." << endl;
 Exercices();
 cout << username << ", please enter your weekly calorie burn goal: ";
 cin >> goal;


int main()

//string user_info;
 getInput();

 Exercices();

 cout << endl;

 return 0;

c++ visual-c++

share|improve this question

edited Mar 7 at 0:05

Kingsley

3,14821328

asked Mar 6 at 19:54

Yassine EzzaimYassine Ezzaim

11

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  getInput has 1 argument (username) but you gave 0 arguments when calling it (getInput();).
  
  – François Andrieux
  Mar 6 at 19:55
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  What's unclear about the error message? You declared the function as void getInput(string username) (i.e. taking a string as an argument), but are trying to call it as getInput(); (i.e. taking no arguments).
  
  – Algirdas Preidžius
  Mar 6 at 19:56
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please read the error message properly and try to understand it. It is a very straightforward error message you have got
  
  – Dulvin Witharane
  Mar 6 at 20:02
  

  
  
  
  

add a comment | 

-4

I want to call the void getInput function in the main scope. But when I do this, it tells me:

too few argument in function call.

How do I fix this?

The first void function prints the exercises. Then I call it in the next void function called getInput. After that I just want to call it in the main() function.

#include <iostream>;
#include <string>;

using namespace std;

void Exercices()

 double speed;
 int minutes;

 cout << "walking: ";
 cin >> speed >> minutes;
 cout << "running: ";
 cin >> speed >> minutes;
 cout << "cycling: ";
 cin >> speed >> minutes;


void getInput(string username)

 double weight, goal;
 string walking, running, cycling;

 cout << "Please enter your name: ";
 cin >> username;
 cout << "Welcome " << username << ", please enter your weight(kg): ";
 cin >> weight;
 cout << username << ", please enter speed(km/h) and minutes spent in a week for the activities below." << endl;
 Exercices();
 cout << username << ", please enter your weekly calorie burn goal: ";
 cin >> goal;


int main()

//string user_info;
 getInput();

 Exercices();

 cout << endl;

 return 0;

c++ visual-c++

share|improve this question

edited Mar 7 at 0:05

Kingsley

3,14821328

asked Mar 6 at 19:54

Yassine EzzaimYassine Ezzaim

11

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  getInput has 1 argument (username) but you gave 0 arguments when calling it (getInput();).
  
  – François Andrieux
  Mar 6 at 19:55
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  What's unclear about the error message? You declared the function as void getInput(string username) (i.e. taking a string as an argument), but are trying to call it as getInput(); (i.e. taking no arguments).
  
  – Algirdas Preidžius
  Mar 6 at 19:56
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please read the error message properly and try to understand it. It is a very straightforward error message you have got
  
  – Dulvin Witharane
  Mar 6 at 20:02
  

  
  
  
  

add a comment | 

I want to call the void getInput function in the main scope. But when I do this, it tells me:

too few argument in function call.

How do I fix this?

The first void function prints the exercises. Then I call it in the next void function called getInput. After that I just want to call it in the main() function.

#include <iostream>;
#include <string>;

using namespace std;

void Exercices()

 double speed;
 int minutes;

 cout << "walking: ";
 cin >> speed >> minutes;
 cout << "running: ";
 cin >> speed >> minutes;
 cout << "cycling: ";
 cin >> speed >> minutes;


void getInput(string username)

 double weight, goal;
 string walking, running, cycling;

 cout << "Please enter your name: ";
 cin >> username;
 cout << "Welcome " << username << ", please enter your weight(kg): ";
 cin >> weight;
 cout << username << ", please enter speed(km/h) and minutes spent in a week for the activities below." << endl;
 Exercices();
 cout << username << ", please enter your weekly calorie burn goal: ";
 cin >> goal;


int main()

//string user_info;
 getInput();

 Exercices();

 cout << endl;

 return 0;

c++ visual-c++

share|improve this question

edited Mar 7 at 0:05

Kingsley

3,14821328

asked Mar 6 at 19:54

Yassine EzzaimYassine Ezzaim

11

#include <iostream>;
#include <string>;

using namespace std;

void Exercices()

 double speed;
 int minutes;

 cout << "walking: ";
 cin >> speed >> minutes;
 cout << "running: ";
 cin >> speed >> minutes;
 cout << "cycling: ";
 cin >> speed >> minutes;


void getInput(string username)

 double weight, goal;
 string walking, running, cycling;

 cout << "Please enter your name: ";
 cin >> username;
 cout << "Welcome " << username << ", please enter your weight(kg): ";
 cin >> weight;
 cout << username << ", please enter speed(km/h) and minutes spent in a week for the activities below." << endl;
 Exercices();
 cout << username << ", please enter your weekly calorie burn goal: ";
 cin >> goal;


int main()

//string user_info;
 getInput();

 Exercices();

 cout << endl;

 return 0;

share|improve this question

edited Mar 7 at 0:05

Kingsley

3,14821328

asked Mar 6 at 19:54

Yassine EzzaimYassine Ezzaim

11

share|improve this question

edited Mar 7 at 0:05

Kingsley

3,14821328

asked Mar 6 at 19:54

Yassine EzzaimYassine Ezzaim

11

edited Mar 7 at 0:05

Kingsley

3,14821328

edited Mar 7 at 0:05

Kingsley

3,14821328

asked Mar 6 at 19:54

Yassine EzzaimYassine Ezzaim

11

asked Mar 6 at 19:54

Yassine EzzaimYassine Ezzaim

11

1 Answer
1

active

oldest

votes

4

As the error suggests,

int main()

 string user_info;
 getInput(user_info);

 Exercices();

 cout << endl;

 return 0;

You have to pass a string to the function getInput(string username) since the function definition says it needs one. I hope you will read and try to understand the error message before everything else in the future

share|improve this answer

edited Mar 6 at 20:09

answered Mar 6 at 20:01

Dulvin WitharaneDulvin Witharane

3041211

add a comment | 

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4

As the error suggests,

int main()

 string user_info;
 getInput(user_info);

 Exercices();

 cout << endl;

 return 0;

You have to pass a string to the function getInput(string username) since the function definition says it needs one. I hope you will read and try to understand the error message before everything else in the future

share|improve this answer

edited Mar 6 at 20:09

answered Mar 6 at 20:01

Dulvin WitharaneDulvin Witharane

3041211

add a comment | 

4

As the error suggests,

int main()

 string user_info;
 getInput(user_info);

 Exercices();

 cout << endl;

 return 0;

You have to pass a string to the function getInput(string username) since the function definition says it needs one. I hope you will read and try to understand the error message before everything else in the future

share|improve this answer

edited Mar 6 at 20:09

answered Mar 6 at 20:01

Dulvin WitharaneDulvin Witharane

3041211

add a comment | 

As the error suggests,

int main()

 string user_info;
 getInput(user_info);

 Exercices();

 cout << endl;

 return 0;

You have to pass a string to the function getInput(string username) since the function definition says it needs one. I hope you will read and try to understand the error message before everything else in the future

share|improve this answer

edited Mar 6 at 20:09

answered Mar 6 at 20:01

Dulvin WitharaneDulvin Witharane

3041211

int main()

 string user_info;
 getInput(user_info);

 Exercices();

 cout << endl;

 return 0;

share|improve this answer

edited Mar 6 at 20:09

answered Mar 6 at 20:01

Dulvin WitharaneDulvin Witharane

3041211

answered Mar 6 at 20:01

Dulvin WitharaneDulvin Witharane

3041211

answered Mar 6 at 20:01

Dulvin WitharaneDulvin Witharane

3041211