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Flutter : Not getting code while Instagram login (Instagram login not working)
The 2019 Stack Overflow Developer Survey Results Are In
Unicorn Meta Zoo #1: Why another podcast?
Announcing the arrival of Valued Associate #679: Cesar Manara
The Ask Question Wizard is Live!
Data science time! April 2019 and salary with experienceHow to POST API URL with parameters to Instagram APIHow can I get a user's media from Instagram without authenticating as a user?Instagram iOS API Error Domain=WebKitErrorDomain Code=102 “Frame load interrupted”Unable to get code paramteter in redirect uri for instagramRedirect URI not passing variableNo redirect to callback URL when authenticating to InstagramInstagram php laravel access tokenApache Oltu Instragram integration doesn't return access_token… why?Android Instagram login integrationInstagram API call to retrieve authorization code with CURL returns empty
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I am using flutter and I want to achieve log in with Instagram in my app.
So I am following this tutorial for Instagram login,
I am getting success to log in but not getting user details, it is opening Redirect URI (https://www.google.com/) and not getting the code and access token.
Please help me if you know anything.
Note: I am using flutter_webview_plugin for load webview in
flutter.
Here is the code which is opening webview for Instagram login ->
My log print("Code ========== Code"); is not going to print anymore
Future<Token> getToken(String appId, String appSecret) async
Stream<String> onCode = await _server();
print("_server ========== _server");
String url =
"https://api.instagram.com/oauth/authorize?client_id=$appId&redirect_uri=https://www.google.com/&response_type=code";
final flutterWebviewPlugin = new FlutterWebviewPlugin();
flutterWebviewPlugin.launch(url);
final String code = await onCode.first;
print("Code ========== Code");
print("Code -> "+code);
final http.Response response = await http.post(
"https://api.instagram.com/oauth/access_token",
body: "client_id": appId, "redirect_uri": "https://www.google.com/", "client_secret": appSecret,
"code": code, "grant_type": "authorization_code");
flutterWebviewPlugin.close();
return new Token.fromMap(json.decode(response.body));
Future<Stream<String>> _server() async
final StreamController<String> onCode = new StreamController();
HttpServer server =
await HttpServer.bind(InternetAddress.LOOPBACK_IP_V4, 8585);
server.listen((HttpRequest request) async
final String code = request.uri.queryParameters["code"];
request.response
..statusCode = 200
..headers.set("Content-Type", ContentType.HTML.mimeType)
..write("<html><h1>You can now close this window</h1></html>");
await request.response.close();
await server.close(force: true);
onCode.add(code);
await onCode.close();
);
return onCode.stream;
flutter instagram instagram-api flutterwebviewplugin asked Mar 8 at 12:13
Mohit SutharMohit Suthar
2,77431841
add a comment |
I am using flutter and I want to achieve log in with Instagram in my app.
So I am following this tutorial for Instagram login,
I am getting success to log in but not getting user details, it is opening Redirect URI (https://www.google.com/) and not getting the code and access token.
Please help me if you know anything.
Note: I am using flutter_webview_plugin for load webview in
flutter.
Here is the code which is opening webview for Instagram login ->
My log print("Code ========== Code"); is not going to print anymore
Future<Token> getToken(String appId, String appSecret) async
Stream<String> onCode = await _server();
print("_server ========== _server");
String url =
"https://api.instagram.com/oauth/authorize?client_id=$appId&redirect_uri=https://www.google.com/&response_type=code";
final flutterWebviewPlugin = new FlutterWebviewPlugin();
flutterWebviewPlugin.launch(url);
final String code = await onCode.first;
print("Code ========== Code");
print("Code -> "+code);
final http.Response response = await http.post(
"https://api.instagram.com/oauth/access_token",
body: "client_id": appId, "redirect_uri": "https://www.google.com/", "client_secret": appSecret,
"code": code, "grant_type": "authorization_code");
flutterWebviewPlugin.close();
return new Token.fromMap(json.decode(response.body));
Future<Stream<String>> _server() async
final StreamController<String> onCode = new StreamController();
HttpServer server =
await HttpServer.bind(InternetAddress.LOOPBACK_IP_V4, 8585);
server.listen((HttpRequest request) async
final String code = request.uri.queryParameters["code"];
request.response
..statusCode = 200
..headers.set("Content-Type", ContentType.HTML.mimeType)
..write("<html><h1>You can now close this window</h1></html>");
await request.response.close();
await server.close(force: true);
onCode.add(code);
await onCode.close();
);
return onCode.stream;
asked Mar 8 at 12:13
Mohit SutharMohit Suthar
2,77431841
add a comment |
I am using flutter and I want to achieve log in with Instagram in my app.
So I am following this tutorial for Instagram login,
I am getting success to log in but not getting user details, it is opening Redirect URI (https://www.google.com/) and not getting the code and access token.
Please help me if you know anything.
Note: I am using flutter_webview_plugin for load webview in
flutter.
Here is the code which is opening webview for Instagram login ->
My log print("Code ========== Code"); is not going to print anymore
Future<Token> getToken(String appId, String appSecret) async
Stream<String> onCode = await _server();
print("_server ========== _server");
String url =
"https://api.instagram.com/oauth/authorize?client_id=$appId&redirect_uri=https://www.google.com/&response_type=code";
final flutterWebviewPlugin = new FlutterWebviewPlugin();
flutterWebviewPlugin.launch(url);
final String code = await onCode.first;
print("Code ========== Code");
print("Code -> "+code);
final http.Response response = await http.post(
"https://api.instagram.com/oauth/access_token",
body: "client_id": appId, "redirect_uri": "https://www.google.com/", "client_secret": appSecret,
"code": code, "grant_type": "authorization_code");
flutterWebviewPlugin.close();
return new Token.fromMap(json.decode(response.body));
Future<Stream<String>> _server() async
final StreamController<String> onCode = new StreamController();
HttpServer server =
await HttpServer.bind(InternetAddress.LOOPBACK_IP_V4, 8585);
server.listen((HttpRequest request) async
final String code = request.uri.queryParameters["code"];
request.response
..statusCode = 200
..headers.set("Content-Type", ContentType.HTML.mimeType)
..write("<html><h1>You can now close this window</h1></html>");
await request.response.close();
await server.close(force: true);
onCode.add(code);
await onCode.close();
);
return onCode.stream;
asked Mar 8 at 12:13
Mohit SutharMohit Suthar
2,77431841
I am using flutter and I want to achieve log in with Instagram in my app.
So I am following this tutorial for Instagram login,
I am getting success to log in but not getting user details, it is opening Redirect URI (https://www.google.com/) and not getting the code and access token.
Please help me if you know anything.
Note: I am using flutter_webview_plugin for load webview in
flutter.
Here is the code which is opening webview for Instagram login ->
My log print("Code ========== Code"); is not going to print anymore
Future<Token> getToken(String appId, String appSecret) async
Stream<String> onCode = await _server();
print("_server ========== _server");
String url =
"https://api.instagram.com/oauth/authorize?client_id=$appId&redirect_uri=https://www.google.com/&response_type=code";
final flutterWebviewPlugin = new FlutterWebviewPlugin();
flutterWebviewPlugin.launch(url);
final String code = await onCode.first;
print("Code ========== Code");
print("Code -> "+code);
final http.Response response = await http.post(
"https://api.instagram.com/oauth/access_token",
body: "client_id": appId, "redirect_uri": "https://www.google.com/", "client_secret": appSecret,
"code": code, "grant_type": "authorization_code");
flutterWebviewPlugin.close();
return new Token.fromMap(json.decode(response.body));
Future<Stream<String>> _server() async
final StreamController<String> onCode = new StreamController();
HttpServer server =
await HttpServer.bind(InternetAddress.LOOPBACK_IP_V4, 8585);
server.listen((HttpRequest request) async
final String code = request.uri.queryParameters["code"];
request.response
..statusCode = 200
..headers.set("Content-Type", ContentType.HTML.mimeType)
..write("<html><h1>You can now close this window</h1></html>");
await request.response.close();
await server.close(force: true);
onCode.add(code);
await onCode.close();
);
return onCode.stream;
asked Mar 8 at 12:13
Mohit SutharMohit Suthar
2,77431841
asked Mar 8 at 12:13
Mohit SutharMohit Suthar
2,77431841
asked Mar 8 at 12:13
Mohit SutharMohit Suthar
2,77431841
asked Mar 8 at 12:13
Mohit SutharMohit Suthar
2,77431841
asked Mar 8 at 12:13
Mohit SutharMohit Suthar
2,77431841
2,77431841
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Finally, I found the answer actually, This blog was right,
My mistake is changing Redirect URI
so i have change Redirect URI https://www.google.com/ to http://localhost:8585 and instagram login works.
Use http://localhost:8585 this Redirect URI for Instagram login
answered Mar 11 at 5:11
Mohit SutharMohit Suthar
2,77431841
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Finally, I found the answer actually, This blog was right,
My mistake is changing Redirect URI
so i have change Redirect URI https://www.google.com/ to http://localhost:8585 and instagram login works.
Use http://localhost:8585 this Redirect URI for Instagram login
answered Mar 11 at 5:11
Mohit SutharMohit Suthar
2,77431841
add a comment |
Finally, I found the answer actually, This blog was right,
My mistake is changing Redirect URI
so i have change Redirect URI https://www.google.com/ to http://localhost:8585 and instagram login works.
Use http://localhost:8585 this Redirect URI for Instagram login
answered Mar 11 at 5:11
Mohit SutharMohit Suthar
2,77431841
add a comment |
Finally, I found the answer actually, This blog was right,
My mistake is changing Redirect URI
so i have change Redirect URI https://www.google.com/ to http://localhost:8585 and instagram login works.
Use http://localhost:8585 this Redirect URI for Instagram login
answered Mar 11 at 5:11
Mohit SutharMohit Suthar
2,77431841
Finally, I found the answer actually, This blog was right,
My mistake is changing Redirect URI
so i have change Redirect URI https://www.google.com/ to http://localhost:8585 and instagram login works.
Use http://localhost:8585 this Redirect URI for Instagram login
answered Mar 11 at 5:11
Mohit SutharMohit Suthar
2,77431841
answered Mar 11 at 5:11
Mohit SutharMohit Suthar
2,77431841
answered Mar 11 at 5:11
Mohit SutharMohit Suthar
2,77431841
answered Mar 11 at 5:11
Mohit SutharMohit Suthar
2,77431841
2,77431841
add a comment |
add a comment |
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