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How to detect specific subwords in text
How to validate an email address in JavaScript?Is there a regular expression to detect a valid regular expression?How to validate an email address using a regular expression?How do you access the matched groups in a JavaScript regular expression?How do you use a variable in a regular expression?How do I make the first letter of a string uppercase in JavaScript?How to replace all occurrences of a string in JavaScriptHow to negate specific word in regex?Bash command in php script, get some lines of a file according values of a specific columnRegEx match sequence of three strings along with text inbetween
I have a column as a string with no spaces:
clear
input str100 var
"ihaveanewspaper"
"watchingthenewsonthetv"
"watchthenewsandreadthenewspaper"
end
I am using the following command:
gen = regex,(var, "(news)")
This outputs 1 1 1 because it finds that the 3 rows in the column var contain the word news.
I'm trying to alter the regular expression "(news)" to create two columns. One for news and one for newspaper. regexm(var, "(newspaper)") makes sure that the row contains a newspaper, but I need a command to make sure characters after news are not "paper" as I'm trying to quantify the two.
EDIT:
Is there a way to count the third entry as 1, because it has a news occurrence without however being a newspaper?
regex stata
edited Mar 7 at 20:24
Pearly Spencer
12k173968
asked Mar 7 at 10:18
sammyramzsammyramz
13619
add a comment |
I have a column as a string with no spaces:
clear
input str100 var
"ihaveanewspaper"
"watchingthenewsonthetv"
"watchthenewsandreadthenewspaper"
end
I am using the following command:
gen = regex,(var, "(news)")
This outputs 1 1 1 because it finds that the 3 rows in the column var contain the word news.
I'm trying to alter the regular expression "(news)" to create two columns. One for news and one for newspaper. regexm(var, "(newspaper)") makes sure that the row contains a newspaper, but I need a command to make sure characters after news are not "paper" as I'm trying to quantify the two.
EDIT:
Is there a way to count the third entry as 1, because it has a news occurrence without however being a newspaper?
regex stata
edited Mar 7 at 20:24
Pearly Spencer
12k173968
asked Mar 7 at 10:18
sammyramzsammyramz
13619
1
The "following command" is illegal. Few users of Stata will not realise that, but it's not good practice to give illegal commands as examples.
– Nick Cox
Mar 7 at 13:27
add a comment |
I have a column as a string with no spaces:
clear
input str100 var
"ihaveanewspaper"
"watchingthenewsonthetv"
"watchthenewsandreadthenewspaper"
end
I am using the following command:
gen = regex,(var, "(news)")
This outputs 1 1 1 because it finds that the 3 rows in the column var contain the word news.
I'm trying to alter the regular expression "(news)" to create two columns. One for news and one for newspaper. regexm(var, "(newspaper)") makes sure that the row contains a newspaper, but I need a command to make sure characters after news are not "paper" as I'm trying to quantify the two.
EDIT:
Is there a way to count the third entry as 1, because it has a news occurrence without however being a newspaper?
regex stata
edited Mar 7 at 20:24
Pearly Spencer
12k173968
asked Mar 7 at 10:18
sammyramzsammyramz
13619
I have a column as a string with no spaces:
clear
input str100 var
"ihaveanewspaper"
"watchingthenewsonthetv"
"watchthenewsandreadthenewspaper"
end
I am using the following command:
gen = regex,(var, "(news)")
This outputs 1 1 1 because it finds that the 3 rows in the column var contain the word news.
I'm trying to alter the regular expression "(news)" to create two columns. One for news and one for newspaper. regexm(var, "(newspaper)") makes sure that the row contains a newspaper, but I need a command to make sure characters after news are not "paper" as I'm trying to quantify the two.
EDIT:
Is there a way to count the third entry as 1, because it has a news occurrence without however being a newspaper?
regex stata
regex stata
edited Mar 7 at 20:24
Pearly Spencer
12k173968
asked Mar 7 at 10:18
sammyramzsammyramz
13619
edited Mar 7 at 20:24
Pearly Spencer
12k173968
asked Mar 7 at 10:18
sammyramzsammyramz
13619
edited Mar 7 at 20:24
Pearly Spencer
12k173968
edited Mar 7 at 20:24
Pearly Spencer
12k173968
edited Mar 7 at 20:24
Pearly Spencer
12k173968
12k173968
asked Mar 7 at 10:18
sammyramzsammyramz
13619
asked Mar 7 at 10:18
sammyramzsammyramz
13619
asked Mar 7 at 10:18
sammyramzsammyramz
13619
13619
1
The "following command" is illegal. Few users of Stata will not realise that, but it's not good practice to give illegal commands as examples.
– Nick Cox
Mar 7 at 13:27
add a comment |
1
The "following command" is illegal. Few users of Stata will not realise that, but it's not good practice to give illegal commands as examples.
– Nick Cox
Mar 7 at 13:27
1
1
The "following command" is illegal. Few users of Stata will not realise that, but it's not good practice to give illegal commands as examples.
– Nick Cox
Mar 7 at 13:27
The "following command" is illegal. Few users of Stata will not realise that, but it's not good practice to give illegal commands as examples.
– Nick Cox
Mar 7 at 13:27
add a comment |
1 Answer
1
active
oldest
votes
You can quantify as follows without a regular expression:
clear
input str100 var
"ihaveanewspaper"
"watchingthenewsonthetv"
"watchthenewsandreadthenewspaper"
"fdgdnews"
"fgogodigjhoigjnewspaper"
"fgeogeionnewsfgdgfpaper"
"45pap9358newsfjfgni"
end
generate news = strmatch(var, "*news*") & !strmatch(var, "*newspaper*")
list, separator(0)
+----------------------------------------+
| var news |
|----------------------------------------|
1. | ihaveanewspaper 0 |
2. | watchingthenewsonthetv 1 |
3. | watchthenewsandreadthenewspaper 0 |
4. | fdgdnews 1 |
5. | fgogodigjhoigjnewspaper 0 |
6. | fgeogeionnewsfgdgfpaper 1 |
7. | 45pap9358newsfjfgni 1 |
+----------------------------------------+
count if news
4
count if !news
3
EDIT:
One way to do this is to eliminate all instances of the word newspaper and repeat the process:
generate var2 = subinstr(var, "newspaper", "", .)
replace news = 1 if strmatch(var2, "*news*")
list, separator(0)
+------------------------------------------------------------------+
| var news var2 |
|------------------------------------------------------------------|
1. | ihaveanewspaper 0 ihavea |
2. | watchingthenewsonthetv 1 watchingthenewsonthetv |
3. | watchthenewsandreadthenewspaper 1 watchthenewsandreadthe |
4. | fdgdnews 1 fdgdnews |
5. | fgogodigjhoigjnewspaper 0 fgogodigjhoigj |
6. | fgeogeionnewsfgdgfpaper 1 fgeogeionnewsfgdgfpaper |
7. | 45pap9358newsfjfgni 1 45pap9358newsfjfgni |
+------------------------------------------------------------------+
count if news
5
count if !news
2
answered Mar 7 at 10:50
Pearly SpencerPearly Spencer
12k173968
add a comment |
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1 Answer
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oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can quantify as follows without a regular expression:
clear
input str100 var
"ihaveanewspaper"
"watchingthenewsonthetv"
"watchthenewsandreadthenewspaper"
"fdgdnews"
"fgogodigjhoigjnewspaper"
"fgeogeionnewsfgdgfpaper"
"45pap9358newsfjfgni"
end
generate news = strmatch(var, "*news*") & !strmatch(var, "*newspaper*")
list, separator(0)
+----------------------------------------+
| var news |
|----------------------------------------|
1. | ihaveanewspaper 0 |
2. | watchingthenewsonthetv 1 |
3. | watchthenewsandreadthenewspaper 0 |
4. | fdgdnews 1 |
5. | fgogodigjhoigjnewspaper 0 |
6. | fgeogeionnewsfgdgfpaper 1 |
7. | 45pap9358newsfjfgni 1 |
+----------------------------------------+
count if news
4
count if !news
3
EDIT:
One way to do this is to eliminate all instances of the word newspaper and repeat the process:
generate var2 = subinstr(var, "newspaper", "", .)
replace news = 1 if strmatch(var2, "*news*")
list, separator(0)
+------------------------------------------------------------------+
| var news var2 |
|------------------------------------------------------------------|
1. | ihaveanewspaper 0 ihavea |
2. | watchingthenewsonthetv 1 watchingthenewsonthetv |
3. | watchthenewsandreadthenewspaper 1 watchthenewsandreadthe |
4. | fdgdnews 1 fdgdnews |
5. | fgogodigjhoigjnewspaper 0 fgogodigjhoigj |
6. | fgeogeionnewsfgdgfpaper 1 fgeogeionnewsfgdgfpaper |
7. | 45pap9358newsfjfgni 1 45pap9358newsfjfgni |
+------------------------------------------------------------------+
count if news
5
count if !news
2
answered Mar 7 at 10:50
Pearly SpencerPearly Spencer
12k173968
add a comment |
You can quantify as follows without a regular expression:
clear
input str100 var
"ihaveanewspaper"
"watchingthenewsonthetv"
"watchthenewsandreadthenewspaper"
"fdgdnews"
"fgogodigjhoigjnewspaper"
"fgeogeionnewsfgdgfpaper"
"45pap9358newsfjfgni"
end
generate news = strmatch(var, "*news*") & !strmatch(var, "*newspaper*")
list, separator(0)
+----------------------------------------+
| var news |
|----------------------------------------|
1. | ihaveanewspaper 0 |
2. | watchingthenewsonthetv 1 |
3. | watchthenewsandreadthenewspaper 0 |
4. | fdgdnews 1 |
5. | fgogodigjhoigjnewspaper 0 |
6. | fgeogeionnewsfgdgfpaper 1 |
7. | 45pap9358newsfjfgni 1 |
+----------------------------------------+
count if news
4
count if !news
3
EDIT:
One way to do this is to eliminate all instances of the word newspaper and repeat the process:
generate var2 = subinstr(var, "newspaper", "", .)
replace news = 1 if strmatch(var2, "*news*")
list, separator(0)
+------------------------------------------------------------------+
| var news var2 |
|------------------------------------------------------------------|
1. | ihaveanewspaper 0 ihavea |
2. | watchingthenewsonthetv 1 watchingthenewsonthetv |
3. | watchthenewsandreadthenewspaper 1 watchthenewsandreadthe |
4. | fdgdnews 1 fdgdnews |
5. | fgogodigjhoigjnewspaper 0 fgogodigjhoigj |
6. | fgeogeionnewsfgdgfpaper 1 fgeogeionnewsfgdgfpaper |
7. | 45pap9358newsfjfgni 1 45pap9358newsfjfgni |
+------------------------------------------------------------------+
count if news
5
count if !news
2
answered Mar 7 at 10:50
Pearly SpencerPearly Spencer
12k173968
add a comment |
You can quantify as follows without a regular expression:
clear
input str100 var
"ihaveanewspaper"
"watchingthenewsonthetv"
"watchthenewsandreadthenewspaper"
"fdgdnews"
"fgogodigjhoigjnewspaper"
"fgeogeionnewsfgdgfpaper"
"45pap9358newsfjfgni"
end
generate news = strmatch(var, "*news*") & !strmatch(var, "*newspaper*")
list, separator(0)
+----------------------------------------+
| var news |
|----------------------------------------|
1. | ihaveanewspaper 0 |
2. | watchingthenewsonthetv 1 |
3. | watchthenewsandreadthenewspaper 0 |
4. | fdgdnews 1 |
5. | fgogodigjhoigjnewspaper 0 |
6. | fgeogeionnewsfgdgfpaper 1 |
7. | 45pap9358newsfjfgni 1 |
+----------------------------------------+
count if news
4
count if !news
3
EDIT:
One way to do this is to eliminate all instances of the word newspaper and repeat the process:
generate var2 = subinstr(var, "newspaper", "", .)
replace news = 1 if strmatch(var2, "*news*")
list, separator(0)
+------------------------------------------------------------------+
| var news var2 |
|------------------------------------------------------------------|
1. | ihaveanewspaper 0 ihavea |
2. | watchingthenewsonthetv 1 watchingthenewsonthetv |
3. | watchthenewsandreadthenewspaper 1 watchthenewsandreadthe |
4. | fdgdnews 1 fdgdnews |
5. | fgogodigjhoigjnewspaper 0 fgogodigjhoigj |
6. | fgeogeionnewsfgdgfpaper 1 fgeogeionnewsfgdgfpaper |
7. | 45pap9358newsfjfgni 1 45pap9358newsfjfgni |
+------------------------------------------------------------------+
count if news
5
count if !news
2
answered Mar 7 at 10:50
Pearly SpencerPearly Spencer
12k173968
You can quantify as follows without a regular expression:
clear
input str100 var
"ihaveanewspaper"
"watchingthenewsonthetv"
"watchthenewsandreadthenewspaper"
"fdgdnews"
"fgogodigjhoigjnewspaper"
"fgeogeionnewsfgdgfpaper"
"45pap9358newsfjfgni"
end
generate news = strmatch(var, "*news*") & !strmatch(var, "*newspaper*")
list, separator(0)
+----------------------------------------+
| var news |
|----------------------------------------|
1. | ihaveanewspaper 0 |
2. | watchingthenewsonthetv 1 |
3. | watchthenewsandreadthenewspaper 0 |
4. | fdgdnews 1 |
5. | fgogodigjhoigjnewspaper 0 |
6. | fgeogeionnewsfgdgfpaper 1 |
7. | 45pap9358newsfjfgni 1 |
+----------------------------------------+
count if news
4
count if !news
3
EDIT:
One way to do this is to eliminate all instances of the word newspaper and repeat the process:
generate var2 = subinstr(var, "newspaper", "", .)
replace news = 1 if strmatch(var2, "*news*")
list, separator(0)
+------------------------------------------------------------------+
| var news var2 |
|------------------------------------------------------------------|
1. | ihaveanewspaper 0 ihavea |
2. | watchingthenewsonthetv 1 watchingthenewsonthetv |
3. | watchthenewsandreadthenewspaper 1 watchthenewsandreadthe |
4. | fdgdnews 1 fdgdnews |
5. | fgogodigjhoigjnewspaper 0 fgogodigjhoigj |
6. | fgeogeionnewsfgdgfpaper 1 fgeogeionnewsfgdgfpaper |
7. | 45pap9358newsfjfgni 1 45pap9358newsfjfgni |
+------------------------------------------------------------------+
count if news
5
count if !news
2
answered Mar 7 at 10:50
Pearly SpencerPearly Spencer
12k173968
edited Mar 7 at 20:22
answered Mar 7 at 10:50
Pearly SpencerPearly Spencer
12k173968
answered Mar 7 at 10:50
Pearly SpencerPearly Spencer
12k173968
answered Mar 7 at 10:50
Pearly SpencerPearly Spencer
12k173968
12k173968
add a comment |
add a comment |
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1
The "following command" is illegal. Few users of Stata will not realise that, but it's not good practice to give illegal commands as examples.
– Nick Cox
Mar 7 at 13:27