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What is wrong with my Python code and how can I fix it?

-1

Here is my code

import requests
ping = requests.get('http://example.com')
ping.status_code

if ping.status_code==200:
 print ("Online")
else:
 print ("Offline")

It pings http://example.com. When the website is online it successfully prints Online. when the website is offline, I want it to print Offline but instead it is showing me a huge error message ends with this line

Max retries exceeded with url: / (Caused by NewConnectionError('<urllib3.connection.HTTPConnection object at 0x7fd3f17372e8>: Failed to establish a new connection: [Errno -2] Name or service not known',))

How can I fix it to successfully print Offline if the website is offline?

python python-requests ping

share|improve this question

asked Mar 6 at 14:44

SadieSadie

215

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I would think you need to use a try catch, and if you catch an exception you know it is offline, otherwise it is online
  
  – Bentaye
  Mar 6 at 14:46
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Possible duplicate of Correct way to try/except using Python requests module?
  
  – meowgoesthedog
  Mar 6 at 14:46
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  what about try/catch?
  
  – deathangel908
  Mar 6 at 14:46
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You might want to wrap your call to the get function inside a try-except block to handle this case.
  
  – Thomas Lang
  Mar 6 at 14:46
  

  
  
  
  

add a comment | 

-1

Here is my code

import requests
ping = requests.get('http://example.com')
ping.status_code

if ping.status_code==200:
 print ("Online")
else:
 print ("Offline")

It pings http://example.com. When the website is online it successfully prints Online. when the website is offline, I want it to print Offline but instead it is showing me a huge error message ends with this line

Max retries exceeded with url: / (Caused by NewConnectionError('<urllib3.connection.HTTPConnection object at 0x7fd3f17372e8>: Failed to establish a new connection: [Errno -2] Name or service not known',))

How can I fix it to successfully print Offline if the website is offline?

python python-requests ping

share|improve this question

asked Mar 6 at 14:44

SadieSadie

215

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I would think you need to use a try catch, and if you catch an exception you know it is offline, otherwise it is online
  
  – Bentaye
  Mar 6 at 14:46
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Possible duplicate of Correct way to try/except using Python requests module?
  
  – meowgoesthedog
  Mar 6 at 14:46
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  what about try/catch?
  
  – deathangel908
  Mar 6 at 14:46
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You might want to wrap your call to the get function inside a try-except block to handle this case.
  
  – Thomas Lang
  Mar 6 at 14:46
  

  
  
  
  

add a comment | 

Here is my code

import requests
ping = requests.get('http://example.com')
ping.status_code

if ping.status_code==200:
 print ("Online")
else:
 print ("Offline")

It pings http://example.com. When the website is online it successfully prints Online. when the website is offline, I want it to print Offline but instead it is showing me a huge error message ends with this line

Max retries exceeded with url: / (Caused by NewConnectionError('<urllib3.connection.HTTPConnection object at 0x7fd3f17372e8>: Failed to establish a new connection: [Errno -2] Name or service not known',))

How can I fix it to successfully print Offline if the website is offline?

python python-requests ping

share|improve this question

asked Mar 6 at 14:44

SadieSadie

215

import requests
ping = requests.get('http://example.com')
ping.status_code

if ping.status_code==200:
 print ("Online")
else:
 print ("Offline")

Max retries exceeded with url: / (Caused by NewConnectionError('<urllib3.connection.HTTPConnection object at 0x7fd3f17372e8>: Failed to establish a new connection: [Errno -2] Name or service not known',))

share|improve this question

asked Mar 6 at 14:44

SadieSadie

215

share|improve this question

asked Mar 6 at 14:44

SadieSadie

215

asked Mar 6 at 14:44

SadieSadie

215

asked Mar 6 at 14:44

SadieSadie

215

2 Answers
2

active

oldest

votes

1

You're getting an error on request itself.

ping = requests.get('http://example.com')

So you don't get a status code if server didn't respond you.
If you want to check if host is down it's worth using exception handling so when request fails your script doesn't go down with an error. Following code should work.

import requests
try:
 ping = requests.get('http://example.com')
 print ("Online")
except:
 print ("Offline")

share|improve this answer

answered Mar 6 at 14:50

Vladimir VishnevskyiVladimir Vishnevskyi

1526

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you. It worked!
  
  – Sadie
  Mar 6 at 14:58
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  always welcome. worth saying that with this particular script - if website responds with any error (like 500, 404 etc) script will still respond with "Online". So you probably should still include your status_code checks.
  
  – Vladimir Vishnevskyi
  Mar 6 at 15:03
  

  
  
  
  

add a comment | 

1

You can do this by modifying your code as below:

Adding try and except mechanism.

import requests
try:
 ping = requests.get('http://example.com')
 ping.status_code

 if ping.status_code==200:
 print ("Online")
 else:
 print ("Offline")
except requests.exceptions.ConnectionError as e:
 print("Offline")

share|improve this answer

answered Mar 6 at 14:55

Devang PadhiyarDevang Padhiyar

430119

add a comment | 

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1

You're getting an error on request itself.

ping = requests.get('http://example.com')

So you don't get a status code if server didn't respond you.
If you want to check if host is down it's worth using exception handling so when request fails your script doesn't go down with an error. Following code should work.

import requests
try:
 ping = requests.get('http://example.com')
 print ("Online")
except:
 print ("Offline")

share|improve this answer

answered Mar 6 at 14:50

Vladimir VishnevskyiVladimir Vishnevskyi

1526

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you. It worked!
  
  – Sadie
  Mar 6 at 14:58
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  always welcome. worth saying that with this particular script - if website responds with any error (like 500, 404 etc) script will still respond with "Online". So you probably should still include your status_code checks.
  
  – Vladimir Vishnevskyi
  Mar 6 at 15:03
  

  
  
  
  

add a comment | 

1

You're getting an error on request itself.

ping = requests.get('http://example.com')

So you don't get a status code if server didn't respond you.
If you want to check if host is down it's worth using exception handling so when request fails your script doesn't go down with an error. Following code should work.

import requests
try:
 ping = requests.get('http://example.com')
 print ("Online")
except:
 print ("Offline")

share|improve this answer

answered Mar 6 at 14:50

Vladimir VishnevskyiVladimir Vishnevskyi

1526

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you. It worked!
  
  – Sadie
  Mar 6 at 14:58
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  always welcome. worth saying that with this particular script - if website responds with any error (like 500, 404 etc) script will still respond with "Online". So you probably should still include your status_code checks.
  
  – Vladimir Vishnevskyi
  Mar 6 at 15:03
  

  
  
  
  

add a comment | 

You're getting an error on request itself.

ping = requests.get('http://example.com')

So you don't get a status code if server didn't respond you.
If you want to check if host is down it's worth using exception handling so when request fails your script doesn't go down with an error. Following code should work.

import requests
try:
 ping = requests.get('http://example.com')
 print ("Online")
except:
 print ("Offline")

share|improve this answer

answered Mar 6 at 14:50

Vladimir VishnevskyiVladimir Vishnevskyi

1526

ping = requests.get('http://example.com')

import requests
try:
 ping = requests.get('http://example.com')
 print ("Online")
except:
 print ("Offline")

share|improve this answer

answered Mar 6 at 14:50

Vladimir VishnevskyiVladimir Vishnevskyi

1526

answered Mar 6 at 14:50

Vladimir VishnevskyiVladimir Vishnevskyi

1526

answered Mar 6 at 14:50

Vladimir VishnevskyiVladimir Vishnevskyi

1526

1

You can do this by modifying your code as below:

Adding try and except mechanism.

import requests
try:
 ping = requests.get('http://example.com')
 ping.status_code

 if ping.status_code==200:
 print ("Online")
 else:
 print ("Offline")
except requests.exceptions.ConnectionError as e:
 print("Offline")

share|improve this answer

answered Mar 6 at 14:55

Devang PadhiyarDevang Padhiyar

430119

add a comment | 

1

You can do this by modifying your code as below:

Adding try and except mechanism.

import requests
try:
 ping = requests.get('http://example.com')
 ping.status_code

 if ping.status_code==200:
 print ("Online")
 else:
 print ("Offline")
except requests.exceptions.ConnectionError as e:
 print("Offline")

share|improve this answer

answered Mar 6 at 14:55

Devang PadhiyarDevang Padhiyar

430119

add a comment | 

You can do this by modifying your code as below:

Adding try and except mechanism.

import requests
try:
 ping = requests.get('http://example.com')
 ping.status_code

 if ping.status_code==200:
 print ("Online")
 else:
 print ("Offline")
except requests.exceptions.ConnectionError as e:
 print("Offline")

share|improve this answer

answered Mar 6 at 14:55

Devang PadhiyarDevang Padhiyar

430119

import requests
try:
 ping = requests.get('http://example.com')
 ping.status_code

 if ping.status_code==200:
 print ("Online")
 else:
 print ("Offline")
except requests.exceptions.ConnectionError as e:
 print("Offline")

share|improve this answer

answered Mar 6 at 14:55

Devang PadhiyarDevang Padhiyar

430119

answered Mar 6 at 14:55

Devang PadhiyarDevang Padhiyar

430119

answered Mar 6 at 14:55

Devang PadhiyarDevang Padhiyar

430119