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How can I check whether a column contains strings in pandas
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The codes are below. I want to create a new column "value_c" based on simple operation on column "value".
frame['value_c'] = frame['value'].apply(lambda x: (x-32) / (5/9))
However, I got an error message like below.
TypeError: unsupported operand type(s) for -: 'str' and 'int'
How can I check whether the column has strings and how can I delete them?
Thank you!!!
python pandas
edited Mar 9 at 3:02
U9-Forward
18.6k51744
asked Mar 9 at 2:49
Yabin DaYabin Da
133
add a comment |
The codes are below. I want to create a new column "value_c" based on simple operation on column "value".
frame['value_c'] = frame['value'].apply(lambda x: (x-32) / (5/9))
However, I got an error message like below.
TypeError: unsupported operand type(s) for -: 'str' and 'int'
How can I check whether the column has strings and how can I delete them?
Thank you!!!
python pandas
edited Mar 9 at 3:02
U9-Forward
18.6k51744
asked Mar 9 at 2:49
Yabin DaYabin Da
133
add a comment |
The codes are below. I want to create a new column "value_c" based on simple operation on column "value".
frame['value_c'] = frame['value'].apply(lambda x: (x-32) / (5/9))
However, I got an error message like below.
TypeError: unsupported operand type(s) for -: 'str' and 'int'
How can I check whether the column has strings and how can I delete them?
Thank you!!!
python pandas
edited Mar 9 at 3:02
U9-Forward
18.6k51744
asked Mar 9 at 2:49
Yabin DaYabin Da
133
The codes are below. I want to create a new column "value_c" based on simple operation on column "value".
frame['value_c'] = frame['value'].apply(lambda x: (x-32) / (5/9))
However, I got an error message like below.
TypeError: unsupported operand type(s) for -: 'str' and 'int'
How can I check whether the column has strings and how can I delete them?
Thank you!!!
python pandas
python pandas
edited Mar 9 at 3:02
U9-Forward
18.6k51744
asked Mar 9 at 2:49
Yabin DaYabin Da
133
edited Mar 9 at 3:02
U9-Forward
18.6k51744
asked Mar 9 at 2:49
Yabin DaYabin Da
133
edited Mar 9 at 3:02
U9-Forward
18.6k51744
edited Mar 9 at 3:02
U9-Forward
18.6k51744
edited Mar 9 at 3:02
U9-Forward
18.6k51744
18.6k51744
asked Mar 9 at 2:49
Yabin DaYabin Da
133
asked Mar 9 at 2:49
Yabin DaYabin Da
133
asked Mar 9 at 2:49
Yabin DaYabin Da
133
133
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Use pd.to_numeric then dropna:
frame['value_c'] = pd.to_numeric(frame['value'],errors='coerce').dropna().apply(lambda x: (x-32) / (5/9))
Then it will work as expected.
answered Mar 9 at 2:55
U9-ForwardU9-Forward
18.6k51744
or we can use.astype(int)to convert thendropna()andapply..
– hacker315
Mar 9 at 4:30
2
@hacker315 there are few cases where you cannot.astype(int)check this: stackoverflow.com/questions/38918653/…
– anky_91
Mar 9 at 4:44
@hacker315 Yeah, anky_91 is correct, you only can doastype(int)to string integers
– U9-Forward
Mar 9 at 5:38
1
Yeap. This code works for me.
– Yabin Da
Mar 9 at 15:07
@YabinDa Happy to help :-)
– U9-Forward
Mar 10 at 1:31
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use pd.to_numeric then dropna:
frame['value_c'] = pd.to_numeric(frame['value'],errors='coerce').dropna().apply(lambda x: (x-32) / (5/9))
Then it will work as expected.
answered Mar 9 at 2:55
U9-ForwardU9-Forward
18.6k51744
or we can use.astype(int)to convert thendropna()andapply..
– hacker315
Mar 9 at 4:30
2
@hacker315 there are few cases where you cannot.astype(int)check this: stackoverflow.com/questions/38918653/…
– anky_91
Mar 9 at 4:44
@hacker315 Yeah, anky_91 is correct, you only can doastype(int)to string integers
– U9-Forward
Mar 9 at 5:38
1
Yeap. This code works for me.
– Yabin Da
Mar 9 at 15:07
@YabinDa Happy to help :-)
– U9-Forward
Mar 10 at 1:31
add a comment |
Use pd.to_numeric then dropna:
frame['value_c'] = pd.to_numeric(frame['value'],errors='coerce').dropna().apply(lambda x: (x-32) / (5/9))
Then it will work as expected.
answered Mar 9 at 2:55
U9-ForwardU9-Forward
18.6k51744
or we can use.astype(int)to convert thendropna()andapply..
– hacker315
Mar 9 at 4:30
2
@hacker315 there are few cases where you cannot.astype(int)check this: stackoverflow.com/questions/38918653/…
– anky_91
Mar 9 at 4:44
@hacker315 Yeah, anky_91 is correct, you only can doastype(int)to string integers
– U9-Forward
Mar 9 at 5:38
1
Yeap. This code works for me.
– Yabin Da
Mar 9 at 15:07
@YabinDa Happy to help :-)
– U9-Forward
Mar 10 at 1:31
add a comment |
Use pd.to_numeric then dropna:
frame['value_c'] = pd.to_numeric(frame['value'],errors='coerce').dropna().apply(lambda x: (x-32) / (5/9))
Then it will work as expected.
answered Mar 9 at 2:55
U9-ForwardU9-Forward
18.6k51744
Use pd.to_numeric then dropna:
frame['value_c'] = pd.to_numeric(frame['value'],errors='coerce').dropna().apply(lambda x: (x-32) / (5/9))
Then it will work as expected.
answered Mar 9 at 2:55
U9-ForwardU9-Forward
18.6k51744
answered Mar 9 at 2:55
U9-ForwardU9-Forward
18.6k51744
answered Mar 9 at 2:55
U9-ForwardU9-Forward
18.6k51744
answered Mar 9 at 2:55
U9-ForwardU9-Forward
18.6k51744
18.6k51744
or we can use.astype(int)to convert thendropna()andapply..
– hacker315
Mar 9 at 4:30
2
@hacker315 there are few cases where you cannot.astype(int)check this: stackoverflow.com/questions/38918653/…
– anky_91
Mar 9 at 4:44
@hacker315 Yeah, anky_91 is correct, you only can doastype(int)to string integers
– U9-Forward
Mar 9 at 5:38
1
Yeap. This code works for me.
– Yabin Da
Mar 9 at 15:07
@YabinDa Happy to help :-)
– U9-Forward
Mar 10 at 1:31
add a comment |
or we can use.astype(int)to convert thendropna()andapply..
– hacker315
Mar 9 at 4:30
2
@hacker315 there are few cases where you cannot.astype(int)check this: stackoverflow.com/questions/38918653/…
– anky_91
Mar 9 at 4:44
@hacker315 Yeah, anky_91 is correct, you only can doastype(int)to string integers
– U9-Forward
Mar 9 at 5:38
1
Yeap. This code works for me.
– Yabin Da
Mar 9 at 15:07
@YabinDa Happy to help :-)
– U9-Forward
Mar 10 at 1:31
or we can use
.astype(int) to convert then dropna() and apply..– hacker315
Mar 9 at 4:30
or we can use
.astype(int) to convert then dropna() and apply..– hacker315
Mar 9 at 4:30
2
2
@hacker315 there are few cases where you cannot
.astype(int) check this: stackoverflow.com/questions/38918653/…– anky_91
Mar 9 at 4:44
@hacker315 there are few cases where you cannot
.astype(int) check this: stackoverflow.com/questions/38918653/…– anky_91
Mar 9 at 4:44
@hacker315 Yeah, anky_91 is correct, you only can do
astype(int) to string integers– U9-Forward
Mar 9 at 5:38
@hacker315 Yeah, anky_91 is correct, you only can do
astype(int) to string integers– U9-Forward
Mar 9 at 5:38
1
1
Yeap. This code works for me.
– Yabin Da
Mar 9 at 15:07
Yeap. This code works for me.
– Yabin Da
Mar 9 at 15:07
@YabinDa Happy to help :-)
– U9-Forward
Mar 10 at 1:31
@YabinDa Happy to help :-)
– U9-Forward
Mar 10 at 1:31
add a comment |
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