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how to get Model “values” without a foreach over it?



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0















I am learning MVC and for do this I am developing a "smart forum".
How can I get value from Model directly , without foreach iteration when data is "a single row"?



@model IEnumerable<WebApplication28.ModelsFromDb.ArgomentiViewModel>
@foreach (var item in Model)


<dl class="dl-horizontal">
<dt>
@Html.DisplayNameFor(model => model.NomeArea)
</dt>

<dd>
@Html.DisplayFor(modelItem => item.NomeArea)
</dd>










share|improve this question

















  • 1





    If your data is a single row, then you shouldn't pass in an IEnumerable into the view.

    – DavidG
    Mar 8 at 16:25

















0















I am learning MVC and for do this I am developing a "smart forum".
How can I get value from Model directly , without foreach iteration when data is "a single row"?



@model IEnumerable<WebApplication28.ModelsFromDb.ArgomentiViewModel>
@foreach (var item in Model)


<dl class="dl-horizontal">
<dt>
@Html.DisplayNameFor(model => model.NomeArea)
</dt>

<dd>
@Html.DisplayFor(modelItem => item.NomeArea)
</dd>










share|improve this question

















  • 1





    If your data is a single row, then you shouldn't pass in an IEnumerable into the view.

    – DavidG
    Mar 8 at 16:25













0












0








0








I am learning MVC and for do this I am developing a "smart forum".
How can I get value from Model directly , without foreach iteration when data is "a single row"?



@model IEnumerable<WebApplication28.ModelsFromDb.ArgomentiViewModel>
@foreach (var item in Model)


<dl class="dl-horizontal">
<dt>
@Html.DisplayNameFor(model => model.NomeArea)
</dt>

<dd>
@Html.DisplayFor(modelItem => item.NomeArea)
</dd>










share|improve this question














I am learning MVC and for do this I am developing a "smart forum".
How can I get value from Model directly , without foreach iteration when data is "a single row"?



@model IEnumerable<WebApplication28.ModelsFromDb.ArgomentiViewModel>
@foreach (var item in Model)


<dl class="dl-horizontal">
<dt>
@Html.DisplayNameFor(model => model.NomeArea)
</dt>

<dd>
@Html.DisplayFor(modelItem => item.NomeArea)
</dd>







c# asp.net-mvc model






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 8 at 16:17









surferNetsurferNet

141




141







  • 1





    If your data is a single row, then you shouldn't pass in an IEnumerable into the view.

    – DavidG
    Mar 8 at 16:25












  • 1





    If your data is a single row, then you shouldn't pass in an IEnumerable into the view.

    – DavidG
    Mar 8 at 16:25







1




1





If your data is a single row, then you shouldn't pass in an IEnumerable into the view.

– DavidG
Mar 8 at 16:25





If your data is a single row, then you shouldn't pass in an IEnumerable into the view.

– DavidG
Mar 8 at 16:25












2 Answers
2






active

oldest

votes


















0














That would be messy code if you keep your model type as IEnumerable<>. So I suggest you change that, in one of two ways.



If you know there will always be a single item, why do you need to have a enumerable at all? Just remove it and make sure to return the underlying object from the controller:



@model WebApplication28.ModelsFromDb.ArgomentiViewModel


If you have to deal with collections, I bet it is a more specific type you are returning from the controller. If it is a list, you could use IList<>, which has many more operations, and which you could index:



@model IList<WebApplication28.ModelsFromDb.ArgomentiViewModel>
...
@Html.DisplayNameFor(model => model[0].NomeArea)





share|improve this answer






























    0














    Your ActionMethod is going to have to only return a single row, not an IEnumerable. Use the SingleOrDefault() method on your entity. Return that in your view to ensure that you're only going to at most, return one row.



    @model WebApplication28.ModelsFromDb.ArgomentiViewModel
    <dl class="dl-horizontal">
    <dt>
    @Html.DisplayNameFor(model => model.NomeArea)
    </dt>
    <dd>
    @Html.DisplayFor(modelItem => item.NomeArea)
    </dd>
    </dl>





    share|improve this answer























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0














      That would be messy code if you keep your model type as IEnumerable<>. So I suggest you change that, in one of two ways.



      If you know there will always be a single item, why do you need to have a enumerable at all? Just remove it and make sure to return the underlying object from the controller:



      @model WebApplication28.ModelsFromDb.ArgomentiViewModel


      If you have to deal with collections, I bet it is a more specific type you are returning from the controller. If it is a list, you could use IList<>, which has many more operations, and which you could index:



      @model IList<WebApplication28.ModelsFromDb.ArgomentiViewModel>
      ...
      @Html.DisplayNameFor(model => model[0].NomeArea)





      share|improve this answer



























        0














        That would be messy code if you keep your model type as IEnumerable<>. So I suggest you change that, in one of two ways.



        If you know there will always be a single item, why do you need to have a enumerable at all? Just remove it and make sure to return the underlying object from the controller:



        @model WebApplication28.ModelsFromDb.ArgomentiViewModel


        If you have to deal with collections, I bet it is a more specific type you are returning from the controller. If it is a list, you could use IList<>, which has many more operations, and which you could index:



        @model IList<WebApplication28.ModelsFromDb.ArgomentiViewModel>
        ...
        @Html.DisplayNameFor(model => model[0].NomeArea)





        share|improve this answer

























          0












          0








          0







          That would be messy code if you keep your model type as IEnumerable<>. So I suggest you change that, in one of two ways.



          If you know there will always be a single item, why do you need to have a enumerable at all? Just remove it and make sure to return the underlying object from the controller:



          @model WebApplication28.ModelsFromDb.ArgomentiViewModel


          If you have to deal with collections, I bet it is a more specific type you are returning from the controller. If it is a list, you could use IList<>, which has many more operations, and which you could index:



          @model IList<WebApplication28.ModelsFromDb.ArgomentiViewModel>
          ...
          @Html.DisplayNameFor(model => model[0].NomeArea)





          share|improve this answer













          That would be messy code if you keep your model type as IEnumerable<>. So I suggest you change that, in one of two ways.



          If you know there will always be a single item, why do you need to have a enumerable at all? Just remove it and make sure to return the underlying object from the controller:



          @model WebApplication28.ModelsFromDb.ArgomentiViewModel


          If you have to deal with collections, I bet it is a more specific type you are returning from the controller. If it is a list, you could use IList<>, which has many more operations, and which you could index:



          @model IList<WebApplication28.ModelsFromDb.ArgomentiViewModel>
          ...
          @Html.DisplayNameFor(model => model[0].NomeArea)






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Mar 8 at 16:24









          AndreiAndrei

          48.3k77093




          48.3k77093























              0














              Your ActionMethod is going to have to only return a single row, not an IEnumerable. Use the SingleOrDefault() method on your entity. Return that in your view to ensure that you're only going to at most, return one row.



              @model WebApplication28.ModelsFromDb.ArgomentiViewModel
              <dl class="dl-horizontal">
              <dt>
              @Html.DisplayNameFor(model => model.NomeArea)
              </dt>
              <dd>
              @Html.DisplayFor(modelItem => item.NomeArea)
              </dd>
              </dl>





              share|improve this answer



























                0














                Your ActionMethod is going to have to only return a single row, not an IEnumerable. Use the SingleOrDefault() method on your entity. Return that in your view to ensure that you're only going to at most, return one row.



                @model WebApplication28.ModelsFromDb.ArgomentiViewModel
                <dl class="dl-horizontal">
                <dt>
                @Html.DisplayNameFor(model => model.NomeArea)
                </dt>
                <dd>
                @Html.DisplayFor(modelItem => item.NomeArea)
                </dd>
                </dl>





                share|improve this answer

























                  0












                  0








                  0







                  Your ActionMethod is going to have to only return a single row, not an IEnumerable. Use the SingleOrDefault() method on your entity. Return that in your view to ensure that you're only going to at most, return one row.



                  @model WebApplication28.ModelsFromDb.ArgomentiViewModel
                  <dl class="dl-horizontal">
                  <dt>
                  @Html.DisplayNameFor(model => model.NomeArea)
                  </dt>
                  <dd>
                  @Html.DisplayFor(modelItem => item.NomeArea)
                  </dd>
                  </dl>





                  share|improve this answer













                  Your ActionMethod is going to have to only return a single row, not an IEnumerable. Use the SingleOrDefault() method on your entity. Return that in your view to ensure that you're only going to at most, return one row.



                  @model WebApplication28.ModelsFromDb.ArgomentiViewModel
                  <dl class="dl-horizontal">
                  <dt>
                  @Html.DisplayNameFor(model => model.NomeArea)
                  </dt>
                  <dd>
                  @Html.DisplayFor(modelItem => item.NomeArea)
                  </dd>
                  </dl>






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Mar 9 at 2:46









                  Charles OwenCharles Owen

                  70367




                  70367



























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