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Is it possible to have multiple tries, with only one catch



The 2019 Stack Overflow Developer Survey Results Are InMultiple or Single Try CatchCatch multiple exceptions at once?Exception thrown inside catch block - will it be caught again?Including all the jars in a directory within the Java classpathThe case against checked exceptionsWhy does Java have transient fields?How can I catch all the exceptions that will be thrown through reading and writing a file?Proper way to declare custom exceptions in modern Python?Can I catch multiple Java exceptions in the same catch clause?Catch multiple exceptions in one line (except block)Which part of throwing an Exception is expensive?



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-1















I'm adding multiple players to a team and each individual player needs a try catch, but the catch is always the same



try
team.addPlayer( new Player( 1, "PLYR1" ) );
catch ( Exception e )
System.out.println( e.toString() );


try
team.addPlayer( new Player( 2, "PLYR2" ) );
catch ( Exception e )
System.out.println( e.toString() );



Is there any way to simplify this?










share|improve this question



















  • 3





    You can add the players in the same try clause, and have only one catch.

    – Maroun
    Mar 8 at 11:08






  • 3





    The answer is yes, but the exact way you would do it depends on what behaviour you want. For example, if adding player 1 fails do you want to try adding player 2 or do you want to stop?

    – Steve Bosman
    Mar 8 at 11:12











  • Possible duplicate of Multiple or Single Try Catch

    – Googlian
    Mar 8 at 11:14

















-1















I'm adding multiple players to a team and each individual player needs a try catch, but the catch is always the same



try
team.addPlayer( new Player( 1, "PLYR1" ) );
catch ( Exception e )
System.out.println( e.toString() );


try
team.addPlayer( new Player( 2, "PLYR2" ) );
catch ( Exception e )
System.out.println( e.toString() );



Is there any way to simplify this?










share|improve this question



















  • 3





    You can add the players in the same try clause, and have only one catch.

    – Maroun
    Mar 8 at 11:08






  • 3





    The answer is yes, but the exact way you would do it depends on what behaviour you want. For example, if adding player 1 fails do you want to try adding player 2 or do you want to stop?

    – Steve Bosman
    Mar 8 at 11:12











  • Possible duplicate of Multiple or Single Try Catch

    – Googlian
    Mar 8 at 11:14













-1












-1








-1








I'm adding multiple players to a team and each individual player needs a try catch, but the catch is always the same



try
team.addPlayer( new Player( 1, "PLYR1" ) );
catch ( Exception e )
System.out.println( e.toString() );


try
team.addPlayer( new Player( 2, "PLYR2" ) );
catch ( Exception e )
System.out.println( e.toString() );



Is there any way to simplify this?










share|improve this question
















I'm adding multiple players to a team and each individual player needs a try catch, but the catch is always the same



try
team.addPlayer( new Player( 1, "PLYR1" ) );
catch ( Exception e )
System.out.println( e.toString() );


try
team.addPlayer( new Player( 2, "PLYR2" ) );
catch ( Exception e )
System.out.println( e.toString() );



Is there any way to simplify this?







java exception






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 8 at 11:08









Maroun

74.8k19146207




74.8k19146207










asked Mar 8 at 11:06









CrazineXCrazineX

1




1







  • 3





    You can add the players in the same try clause, and have only one catch.

    – Maroun
    Mar 8 at 11:08






  • 3





    The answer is yes, but the exact way you would do it depends on what behaviour you want. For example, if adding player 1 fails do you want to try adding player 2 or do you want to stop?

    – Steve Bosman
    Mar 8 at 11:12











  • Possible duplicate of Multiple or Single Try Catch

    – Googlian
    Mar 8 at 11:14












  • 3





    You can add the players in the same try clause, and have only one catch.

    – Maroun
    Mar 8 at 11:08






  • 3





    The answer is yes, but the exact way you would do it depends on what behaviour you want. For example, if adding player 1 fails do you want to try adding player 2 or do you want to stop?

    – Steve Bosman
    Mar 8 at 11:12











  • Possible duplicate of Multiple or Single Try Catch

    – Googlian
    Mar 8 at 11:14







3




3





You can add the players in the same try clause, and have only one catch.

– Maroun
Mar 8 at 11:08





You can add the players in the same try clause, and have only one catch.

– Maroun
Mar 8 at 11:08




3




3





The answer is yes, but the exact way you would do it depends on what behaviour you want. For example, if adding player 1 fails do you want to try adding player 2 or do you want to stop?

– Steve Bosman
Mar 8 at 11:12





The answer is yes, but the exact way you would do it depends on what behaviour you want. For example, if adding player 1 fails do you want to try adding player 2 or do you want to stop?

– Steve Bosman
Mar 8 at 11:12













Possible duplicate of Multiple or Single Try Catch

– Googlian
Mar 8 at 11:14





Possible duplicate of Multiple or Single Try Catch

– Googlian
Mar 8 at 11:14












3 Answers
3






active

oldest

votes


















1














as saying at your comments you can use this



try
team.addPlayer( new Player( 1, "PLYR1" ) );
team.addPlayer( new Player( 2, "PLYR2" ) );
catch ( Exception e )
System.out.println( e.toString() );



of if you care about if the first player is added, use this:



try
team.addPlayer( new Player( 1, "PLYR1" ) );
try
team.addPlayer( new Player( 2, "PLYR2" ) );
catch ( Exception e )
System.out.println( e.toString() );

catch ( Exception e )
System.out.println( e.toString() );






share|improve this answer






























    1














    you can try this code instead of using two try blocks.



    try
    team.addPlayer( new Player( 1, "PLYR1" ) );
    team.addPlayer( new Player( 2, "PLYR2" ) );

    catch ( Exception e )
    System.out.println( e.toString() );






    share|improve this answer






























      0














      If you want to iterate through all possible players using catch and throw the same error to stdout if an exception occurs you should use a basic for loop.



      Player class is assumed to be defined and team object created:



      String[] players = "PLYR1", "PLYR2", "PLYR3"

      for (String player: players)
      try
      team.addPlayer( new Player( 1, player ) );
      catch ( Exception e )
      System.out.println( e.toString() );







      share|improve this answer























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        3 Answers
        3






        active

        oldest

        votes








        3 Answers
        3






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        1














        as saying at your comments you can use this



        try
        team.addPlayer( new Player( 1, "PLYR1" ) );
        team.addPlayer( new Player( 2, "PLYR2" ) );
        catch ( Exception e )
        System.out.println( e.toString() );



        of if you care about if the first player is added, use this:



        try
        team.addPlayer( new Player( 1, "PLYR1" ) );
        try
        team.addPlayer( new Player( 2, "PLYR2" ) );
        catch ( Exception e )
        System.out.println( e.toString() );

        catch ( Exception e )
        System.out.println( e.toString() );






        share|improve this answer



























          1














          as saying at your comments you can use this



          try
          team.addPlayer( new Player( 1, "PLYR1" ) );
          team.addPlayer( new Player( 2, "PLYR2" ) );
          catch ( Exception e )
          System.out.println( e.toString() );



          of if you care about if the first player is added, use this:



          try
          team.addPlayer( new Player( 1, "PLYR1" ) );
          try
          team.addPlayer( new Player( 2, "PLYR2" ) );
          catch ( Exception e )
          System.out.println( e.toString() );

          catch ( Exception e )
          System.out.println( e.toString() );






          share|improve this answer

























            1












            1








            1







            as saying at your comments you can use this



            try
            team.addPlayer( new Player( 1, "PLYR1" ) );
            team.addPlayer( new Player( 2, "PLYR2" ) );
            catch ( Exception e )
            System.out.println( e.toString() );



            of if you care about if the first player is added, use this:



            try
            team.addPlayer( new Player( 1, "PLYR1" ) );
            try
            team.addPlayer( new Player( 2, "PLYR2" ) );
            catch ( Exception e )
            System.out.println( e.toString() );

            catch ( Exception e )
            System.out.println( e.toString() );






            share|improve this answer













            as saying at your comments you can use this



            try
            team.addPlayer( new Player( 1, "PLYR1" ) );
            team.addPlayer( new Player( 2, "PLYR2" ) );
            catch ( Exception e )
            System.out.println( e.toString() );



            of if you care about if the first player is added, use this:



            try
            team.addPlayer( new Player( 1, "PLYR1" ) );
            try
            team.addPlayer( new Player( 2, "PLYR2" ) );
            catch ( Exception e )
            System.out.println( e.toString() );

            catch ( Exception e )
            System.out.println( e.toString() );







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Mar 8 at 11:16









            Christos ThemelisChristos Themelis

            1044




            1044























                1














                you can try this code instead of using two try blocks.



                try
                team.addPlayer( new Player( 1, "PLYR1" ) );
                team.addPlayer( new Player( 2, "PLYR2" ) );

                catch ( Exception e )
                System.out.println( e.toString() );






                share|improve this answer



























                  1














                  you can try this code instead of using two try blocks.



                  try
                  team.addPlayer( new Player( 1, "PLYR1" ) );
                  team.addPlayer( new Player( 2, "PLYR2" ) );

                  catch ( Exception e )
                  System.out.println( e.toString() );






                  share|improve this answer

























                    1












                    1








                    1







                    you can try this code instead of using two try blocks.



                    try
                    team.addPlayer( new Player( 1, "PLYR1" ) );
                    team.addPlayer( new Player( 2, "PLYR2" ) );

                    catch ( Exception e )
                    System.out.println( e.toString() );






                    share|improve this answer













                    you can try this code instead of using two try blocks.



                    try
                    team.addPlayer( new Player( 1, "PLYR1" ) );
                    team.addPlayer( new Player( 2, "PLYR2" ) );

                    catch ( Exception e )
                    System.out.println( e.toString() );







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Mar 8 at 11:21









                    pavithrapavithra

                    111




                    111





















                        0














                        If you want to iterate through all possible players using catch and throw the same error to stdout if an exception occurs you should use a basic for loop.



                        Player class is assumed to be defined and team object created:



                        String[] players = "PLYR1", "PLYR2", "PLYR3"

                        for (String player: players)
                        try
                        team.addPlayer( new Player( 1, player ) );
                        catch ( Exception e )
                        System.out.println( e.toString() );







                        share|improve this answer



























                          0














                          If you want to iterate through all possible players using catch and throw the same error to stdout if an exception occurs you should use a basic for loop.



                          Player class is assumed to be defined and team object created:



                          String[] players = "PLYR1", "PLYR2", "PLYR3"

                          for (String player: players)
                          try
                          team.addPlayer( new Player( 1, player ) );
                          catch ( Exception e )
                          System.out.println( e.toString() );







                          share|improve this answer

























                            0












                            0








                            0







                            If you want to iterate through all possible players using catch and throw the same error to stdout if an exception occurs you should use a basic for loop.



                            Player class is assumed to be defined and team object created:



                            String[] players = "PLYR1", "PLYR2", "PLYR3"

                            for (String player: players)
                            try
                            team.addPlayer( new Player( 1, player ) );
                            catch ( Exception e )
                            System.out.println( e.toString() );







                            share|improve this answer













                            If you want to iterate through all possible players using catch and throw the same error to stdout if an exception occurs you should use a basic for loop.



                            Player class is assumed to be defined and team object created:



                            String[] players = "PLYR1", "PLYR2", "PLYR3"

                            for (String player: players)
                            try
                            team.addPlayer( new Player( 1, player ) );
                            catch ( Exception e )
                            System.out.println( e.toString() );








                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Mar 8 at 11:53









                            Szymon MaszkeSzymon Maszke

                            2,725724




                            2,725724



























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