BASH. Parse JSON and assign result to the value2019 Community Moderator ElectionGet the source directory of a Bash script from within the script itselfHow do I parse command line arguments in Bash?Can comments be used in JSON?What is the correct JSON content type?How to check if a program exists from a Bash script?How do I tell if a regular file does not exist in Bash?Why does Google prepend while(1); to their JSON responses?Parsing values from a JSON file?How to concatenate string variables in BashParse JSON in JavaScript?

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BASH. Parse JSON and assign result to the value



2019 Community Moderator ElectionGet the source directory of a Bash script from within the script itselfHow do I parse command line arguments in Bash?Can comments be used in JSON?What is the correct JSON content type?How to check if a program exists from a Bash script?How do I tell if a regular file does not exist in Bash?Why does Google prepend while(1); to their JSON responses?Parsing values from a JSON file?How to concatenate string variables in BashParse JSON in JavaScript?










0
















Hello everyone.



Please help me figure out how to implement the following: I am
interacting with AWS cli api. After making a request I'm assigning the
result into a variable.ASG_JSON.



If I do $ASG_JSON then getting json content. Did it In order not to
do a lot of requests to AWS.



Now I need to extract some values from that json variable. If I
perform echo $ASG_JSON | jq '."MinSize"'



I get in console result, but I ca not assign this value to new
variable, in result I got nothing: BUILD_MIN= $ASG_JSON | jq '."MinSize"'
Please give me some advice.
Thanks beforehand.










share


























    0
















    Hello everyone.



    Please help me figure out how to implement the following: I am
    interacting with AWS cli api. After making a request I'm assigning the
    result into a variable.ASG_JSON.



    If I do $ASG_JSON then getting json content. Did it In order not to
    do a lot of requests to AWS.



    Now I need to extract some values from that json variable. If I
    perform echo $ASG_JSON | jq '."MinSize"'



    I get in console result, but I ca not assign this value to new
    variable, in result I got nothing: BUILD_MIN= $ASG_JSON | jq '."MinSize"'
    Please give me some advice.
    Thanks beforehand.










    share
























      0












      0








      0









      Hello everyone.



      Please help me figure out how to implement the following: I am
      interacting with AWS cli api. After making a request I'm assigning the
      result into a variable.ASG_JSON.



      If I do $ASG_JSON then getting json content. Did it In order not to
      do a lot of requests to AWS.



      Now I need to extract some values from that json variable. If I
      perform echo $ASG_JSON | jq '."MinSize"'



      I get in console result, but I ca not assign this value to new
      variable, in result I got nothing: BUILD_MIN= $ASG_JSON | jq '."MinSize"'
      Please give me some advice.
      Thanks beforehand.










      share















      Hello everyone.



      Please help me figure out how to implement the following: I am
      interacting with AWS cli api. After making a request I'm assigning the
      result into a variable.ASG_JSON.



      If I do $ASG_JSON then getting json content. Did it In order not to
      do a lot of requests to AWS.



      Now I need to extract some values from that json variable. If I
      perform echo $ASG_JSON | jq '."MinSize"'



      I get in console result, but I ca not assign this value to new
      variable, in result I got nothing: BUILD_MIN= $ASG_JSON | jq '."MinSize"'
      Please give me some advice.
      Thanks beforehand.








      json bash





      share












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      share










      asked 5 mins ago









      VadymVadym

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