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Assign values returning from Python to JQuery

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0

I am still new in python and I have a code that read the geometry of the shapefile, then do calculations from 4 functions then return these values to a table in JQuery. How do I assign values returned to a row of a table.

...
jQuery.ajax({
 type: "POST",
 url: "Results.php",
 data: 
 city: city
 ,
 dataType: 'json',

PHP code...

...Results.php
$command = shell_exec('python ../spatialCal.py ' . $geom);
if($command){
 $resp['success'] = true; 
 $resp['results'] = $command;
....
....
header('Content-type: application/json',true);
print json_encode($resp);

Python

....
def main(): 
 informalRead() 
 lowcostRead() 
 builtRead() 
 villageRead() 

if __name__ == '__main__':
 main()

I fairly new in python world

python

share|improve this question

asked Mar 7 at 7:36

Asanda LambaAsanda Lamba

176

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Your question title provides no attempt to do what you intent to with what you have in Python Code
  
  – DirtyBit
  Mar 7 at 7:47
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The title could have been long soI tried to put all that in description
  
  – Asanda Lamba
  Mar 7 at 7:50
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You will need to explain in more detail how the parts that you show in your question are interacting between them. After than could you clarify what exactly is the issue you are facing? What isn't working as expected?
  
  – Ralf
  Mar 7 at 9:59
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I am sending a data to php then from php retrieve additional data then pass that data to python, I want the results to be populated to the table
  
  – Asanda Lamba
  Mar 7 at 12:08
  

  
  
  
  

add a comment | 

0

I am still new in python and I have a code that read the geometry of the shapefile, then do calculations from 4 functions then return these values to a table in JQuery. How do I assign values returned to a row of a table.

...
jQuery.ajax({
 type: "POST",
 url: "Results.php",
 data: 
 city: city
 ,
 dataType: 'json',

PHP code...

...Results.php
$command = shell_exec('python ../spatialCal.py ' . $geom);
if($command){
 $resp['success'] = true; 
 $resp['results'] = $command;
....
....
header('Content-type: application/json',true);
print json_encode($resp);

Python

....
def main(): 
 informalRead() 
 lowcostRead() 
 builtRead() 
 villageRead() 

if __name__ == '__main__':
 main()

I fairly new in python world

python

share|improve this question

asked Mar 7 at 7:36

Asanda LambaAsanda Lamba

176

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Your question title provides no attempt to do what you intent to with what you have in Python Code
  
  – DirtyBit
  Mar 7 at 7:47
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The title could have been long soI tried to put all that in description
  
  – Asanda Lamba
  Mar 7 at 7:50
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You will need to explain in more detail how the parts that you show in your question are interacting between them. After than could you clarify what exactly is the issue you are facing? What isn't working as expected?
  
  – Ralf
  Mar 7 at 9:59
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I am sending a data to php then from php retrieve additional data then pass that data to python, I want the results to be populated to the table
  
  – Asanda Lamba
  Mar 7 at 12:08
  

  
  
  
  

add a comment | 

I am still new in python and I have a code that read the geometry of the shapefile, then do calculations from 4 functions then return these values to a table in JQuery. How do I assign values returned to a row of a table.

...
jQuery.ajax({
 type: "POST",
 url: "Results.php",
 data: 
 city: city
 ,
 dataType: 'json',

PHP code...

...Results.php
$command = shell_exec('python ../spatialCal.py ' . $geom);
if($command){
 $resp['success'] = true; 
 $resp['results'] = $command;
....
....
header('Content-type: application/json',true);
print json_encode($resp);

Python

....
def main(): 
 informalRead() 
 lowcostRead() 
 builtRead() 
 villageRead() 

if __name__ == '__main__':
 main()

I fairly new in python world

python

share|improve this question

asked Mar 7 at 7:36

Asanda LambaAsanda Lamba

176

...
jQuery.ajax({
 type: "POST",
 url: "Results.php",
 data: 
 city: city
 ,
 dataType: 'json',

...Results.php
$command = shell_exec('python ../spatialCal.py ' . $geom);
if($command){
 $resp['success'] = true; 
 $resp['results'] = $command;
....
....
header('Content-type: application/json',true);
print json_encode($resp);

....
def main(): 
 informalRead() 
 lowcostRead() 
 builtRead() 
 villageRead() 

if __name__ == '__main__':
 main()

share|improve this question

asked Mar 7 at 7:36

Asanda LambaAsanda Lamba

176

share|improve this question

asked Mar 7 at 7:36

Asanda LambaAsanda Lamba

176

asked Mar 7 at 7:36

Asanda LambaAsanda Lamba

176

asked Mar 7 at 7:36

Asanda LambaAsanda Lamba

176