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How do i connect between user input(Scanner) and if condition in Java
2019 Community Moderator ElectionHow do I efficiently iterate over each entry in a Java Map?What is the difference between public, protected, package-private and private in Java?How do I call one constructor from another in Java?How do I read / convert an InputStream into a String in Java?How do I generate random integers within a specific range in Java?How to get an enum value from a string value in Java?How do I determine whether an array contains a particular value in Java?How do I declare and initialize an array in Java?How to split a string in JavaHow do I convert a String to an int in Java?
I know i have to use scanner and if condition but i don't know how to connect them
Example:
Are you willing to convert weight or height?
(user input= weight)
Will it be for imperial unit or metric unit?
(user input=metric)
Please provide the weight information in kg
(user input=75)
Your weight in kgs 75.00 is equal to 165.38 in pounds
java conditional java.util.scanner
asked Mar 5 at 19:40
Selim SariSelim Sari
1
add a comment |
I know i have to use scanner and if condition but i don't know how to connect them
Example:
Are you willing to convert weight or height?
(user input= weight)
Will it be for imperial unit or metric unit?
(user input=metric)
Please provide the weight information in kg
(user input=75)
Your weight in kgs 75.00 is equal to 165.38 in pounds
java conditional java.util.scanner
asked Mar 5 at 19:40
Selim SariSelim Sari
1
1
Use local variables.
– Dawood ibn Kareem
Mar 5 at 19:42
add a comment |
I know i have to use scanner and if condition but i don't know how to connect them
Example:
Are you willing to convert weight or height?
(user input= weight)
Will it be for imperial unit or metric unit?
(user input=metric)
Please provide the weight information in kg
(user input=75)
Your weight in kgs 75.00 is equal to 165.38 in pounds
java conditional java.util.scanner
asked Mar 5 at 19:40
Selim SariSelim Sari
1
I know i have to use scanner and if condition but i don't know how to connect them
Example:
Are you willing to convert weight or height?
(user input= weight)
Will it be for imperial unit or metric unit?
(user input=metric)
Please provide the weight information in kg
(user input=75)
Your weight in kgs 75.00 is equal to 165.38 in pounds
java conditional java.util.scanner
java conditional java.util.scanner
asked Mar 5 at 19:40
Selim SariSelim Sari
1
asked Mar 5 at 19:40
Selim SariSelim Sari
1
asked Mar 5 at 19:40
Selim SariSelim Sari
1
asked Mar 5 at 19:40
Selim SariSelim Sari
1
asked Mar 5 at 19:40
Selim SariSelim Sari
1
1
1
Use local variables.
– Dawood ibn Kareem
Mar 5 at 19:42
add a comment |
1
Use local variables.
– Dawood ibn Kareem
Mar 5 at 19:42
1
1
Use local variables.
– Dawood ibn Kareem
Mar 5 at 19:42
Use local variables.
– Dawood ibn Kareem
Mar 5 at 19:42
add a comment |
2 Answers
2
active
oldest
votes
Scanner scanner = new Scanner(System.in);
System.out.println("Enter an input");
String input= scanner.next();
You can start by putting the user input into a variable. Depending on the flow of your program, you might need to parse the input into either integer or float.
int integerinput = Integer.parseInt(input);
float floatInput = Float.parseFloat(input);
From there, you can start doing the comparison. You have to be careful when parsing information, if the user entered a word and you try to convert that into either integer or float, you will get an exception.
answered Mar 5 at 19:57
SemjeromeSemjerome
386
add a comment |
You should get user’s input just once:String answer = ask.nextLine();
And then inspect the input with if():if (answer.equals("heght"))
// heght conversion goes here
else
// weght conversion goes here
answered Mar 5 at 21:05
user11156080user11156080
1
i used this and it gives me an error called cannot find symbol
– Selim Sari
Mar 5 at 23:36
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Scanner scanner = new Scanner(System.in);
System.out.println("Enter an input");
String input= scanner.next();
You can start by putting the user input into a variable. Depending on the flow of your program, you might need to parse the input into either integer or float.
int integerinput = Integer.parseInt(input);
float floatInput = Float.parseFloat(input);
From there, you can start doing the comparison. You have to be careful when parsing information, if the user entered a word and you try to convert that into either integer or float, you will get an exception.
answered Mar 5 at 19:57
SemjeromeSemjerome
386
add a comment |
Scanner scanner = new Scanner(System.in);
System.out.println("Enter an input");
String input= scanner.next();
You can start by putting the user input into a variable. Depending on the flow of your program, you might need to parse the input into either integer or float.
int integerinput = Integer.parseInt(input);
float floatInput = Float.parseFloat(input);
From there, you can start doing the comparison. You have to be careful when parsing information, if the user entered a word and you try to convert that into either integer or float, you will get an exception.
answered Mar 5 at 19:57
SemjeromeSemjerome
386
add a comment |
Scanner scanner = new Scanner(System.in);
System.out.println("Enter an input");
String input= scanner.next();
You can start by putting the user input into a variable. Depending on the flow of your program, you might need to parse the input into either integer or float.
int integerinput = Integer.parseInt(input);
float floatInput = Float.parseFloat(input);
From there, you can start doing the comparison. You have to be careful when parsing information, if the user entered a word and you try to convert that into either integer or float, you will get an exception.
answered Mar 5 at 19:57
SemjeromeSemjerome
386
Scanner scanner = new Scanner(System.in);
System.out.println("Enter an input");
String input= scanner.next();
You can start by putting the user input into a variable. Depending on the flow of your program, you might need to parse the input into either integer or float.
int integerinput = Integer.parseInt(input);
float floatInput = Float.parseFloat(input);
From there, you can start doing the comparison. You have to be careful when parsing information, if the user entered a word and you try to convert that into either integer or float, you will get an exception.
answered Mar 5 at 19:57
SemjeromeSemjerome
386
answered Mar 5 at 19:57
SemjeromeSemjerome
386
answered Mar 5 at 19:57
SemjeromeSemjerome
386
answered Mar 5 at 19:57
SemjeromeSemjerome
386
386
add a comment |
add a comment |
You should get user’s input just once:String answer = ask.nextLine();
And then inspect the input with if():if (answer.equals("heght"))
// heght conversion goes here
else
// weght conversion goes here
answered Mar 5 at 21:05
user11156080user11156080
1
i used this and it gives me an error called cannot find symbol
– Selim Sari
Mar 5 at 23:36
add a comment |
You should get user’s input just once:String answer = ask.nextLine();
And then inspect the input with if():if (answer.equals("heght"))
// heght conversion goes here
else
// weght conversion goes here
answered Mar 5 at 21:05
user11156080user11156080
1
i used this and it gives me an error called cannot find symbol
– Selim Sari
Mar 5 at 23:36
add a comment |
You should get user’s input just once:String answer = ask.nextLine();
And then inspect the input with if():if (answer.equals("heght"))
// heght conversion goes here
else
// weght conversion goes here
answered Mar 5 at 21:05
user11156080user11156080
1
You should get user’s input just once:String answer = ask.nextLine();
And then inspect the input with if():if (answer.equals("heght"))
// heght conversion goes here
else
// weght conversion goes here
answered Mar 5 at 21:05
user11156080user11156080
1
answered Mar 5 at 21:05
user11156080user11156080
1
answered Mar 5 at 21:05
user11156080user11156080
1
answered Mar 5 at 21:05
user11156080user11156080
1
1
i used this and it gives me an error called cannot find symbol
– Selim Sari
Mar 5 at 23:36
add a comment |
i used this and it gives me an error called cannot find symbol
– Selim Sari
Mar 5 at 23:36
i used this and it gives me an error called cannot find symbol
– Selim Sari
Mar 5 at 23:36
i used this and it gives me an error called cannot find symbol
– Selim Sari
Mar 5 at 23:36
add a comment |
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1
Use local variables.
– Dawood ibn Kareem
Mar 5 at 19:42