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In Python 3.x, raw_input was renamed to input and the Python 2.x input was removed.

This means that, just like raw_input, input in Python 3.x always returns a string object.

To fix the problem, you need to explicitly make those inputs into integers by putting them in int:

x = int(input("Enter a number: "))
y = int(input("Enter a number: "))

Also, Python does not need/use semicolons to end lines. So, having them doesn't do anything positive.

For multiple integer in a single line, map might be better.

arr = map(int, raw_input().split())

If the number is already known, (like 2 integers), you can use

num1, num2 = map(int, raw_input().split())

input() (Python 3) and raw_input() (Python 2) always return strings. Convert the result to integer explicitly with int().

x = int(input("Enter a number: "))
y = int(input("Enter a number: "))

Pro tip: semi-colons are not needed in Python.

Multiple questions require input for several integers on single line. The best way is to input the whole string of numbers one one line and then split them to integers.

 p=raw_input()
 p=p.split() 
 for i in p:
 a.append(int(i))

Convert to integers:

my_number = int(input("enter the number"))

Similarly for floating point numbers:

my_decimalnumber = float(input("enter the number"))

Python 3.x

Taking int as input in python:
we take a simple string input using:

input()

Now we want int as input. So we typecast this string to int simply using:

int(input())

Python 3.x has input() function which returns always string.So you must convert to int

python 3.x

x = int(input("Enter a number: "))
y = int(input("Enter a number: "))

python 2.x

In python 2.x raw_input() and input() functions always return string so you must convert them to int too.

x = int(raw_input("Enter a number: "))
y = int(input("Enter a number: "))

In Python 3.x by default the input function takes input in string format. To convert it into integer you need to include int(input()):

x=int(input("Enter the number"))

I encountered a problem of taking integer input while solving a problem on CodeChef, where two integers - separated by space - should be read from one line.

While int(input()) is sufficient for a single integer, I did not find a direct way to input two integers. I tried this:

num = input()
num1 = 0
num2 = 0

for i in range(len(num)):
 if num[i] == ' ':
 break

num1 = int(num[:i])
num2 = int(num[i+1:])

Now I use num1 and num2 as integers. Hope this helps.

def dbz():
 try:
 r = raw_input("Enter number:")
 if r.isdigit():
 i = int(raw_input("Enter divident:"))
 d = int(r)/i
 print "O/p is -:",d
 else:
 print "Not a number"
 except Exception ,e:
 print "Program halted incorrect data entered",type(e)
dbz()

Or 

num = input("Enter Number:")#"input" will accept only numbers

While in your example, int(input(...)) does the trick in any case, python-future's builtins.input is worth consideration since that makes sure your code works for both Python 2 and 3 and disables Python2's default behaviour of input trying to be "clever" about the input data type (builtins.input basically just behaves like raw_input).

n=int(input())
for i in range(n):
 n=input()
 n=int(n)
 arr1=list(map(int,input().split()))

the for loop shall run 'n' number of times . the second 'n' is the length of the array.
the last statement maps the integers to a list and takes input in space separated form .
you can also return the array at the end of for loop.

play = True

while play:

 #you can simply contain the input function inside an int function i.e int(input(""))
 #This will only accept int inputs
 # and can also convert any variable to 'int' form

 x = int(input("Enter a number: ")) 
 y = int(input("Enter a number: "))

 print(x + y)
 print(x - y)
 print(x * y)
 print(x / y)
 print(x % y)

 if input("Play again? ") == "no":
 play = False

Yes, in python 3.x, raw_input is replaced with input. In order to revert to old behavior of input use:

eval(input("Enter a number: "))

This will let python know that entered input is integer

Lots of people like to do int(input("etc")), but if you put in a string, it will raise an error.

What I like to do is this:

s = input("integer: ")
integer = int(s)

Now use integer for whatever purpose!!

Plus, if s is an string, this doesn't raise an error!!!

At least, not immediately.

parse the input into an integer with int

x = int(input("What is x?"))

play = True

while play:
 x = input("Enter a number: ")
 y = input("Enter a number: ")

 print(int(x) + int(y))
 print(int(x) - int(y))
 print(int(x) * int(y))
 print(int(x) / int(y))
 print(int(x) % int(y))

 if input("Play again? ") == "no":
 play = False

This makes it know that the variable x and y are integers and therefore uses them like integers.

If you want it to be able to use decimals change int to float.

The output for the first function:

print(int(x) + int(y))

x = 3 and y = 7 returned 10.

Try this,

x = int(input("Enter a number: "))
y = int(input("Enter a number: ")

int() is a built-in python function that converts any datatype to a integer.