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Get TreeView nodes in sorted order
How can I cancel a user's WPF TreeView click?WPF: TreeView inside a ComboBoxDeferred loading of TreeView in .NETSetting treeview background color in VB6 has a flaw - help?TreeView vertical scrollbar does not expand to the last node, last node is hidden?WPF TreeView with databinding hierarchical dataC# Intricate Treeview DesignOptimize search-as-you-type performance on a ExtJS treeviewhow to find node in WPF treeview?Assign custom properties to a node in TreeView windows forms?
We have a legacy application written in VB6 using the default Microsoft TreeView control to display hierarchical data. Since there's a lot of information in this TreeView we thought about implementing a small filter/search possibility for the users.
The first attempt was to toggle the visibility and only make nodes (and their parents) visible, that match the defined search. But that was impossible, since the default Microsoft TreeView control doesn't allow their nodes to be visible or invisible.
So the second attempt is to traverse all the nodes in the tree and ensure a node's visibility when it matches the defined search (and stop traversing). When the found node isn't the one the user is looking for he can "continue" the search and look for the next node that matches his criteria.
This works quite good so far, except for one little problem. The search doesn't work from top to bottom, since the tree is filled with data in random sort order and then sorted by setting the Sorted property of each node (legacy code). So the search is going through the randomly added nodes and the found nodes "jump" between the top level nodes (the Nodes collection of the TreeView contains all the nodes in the order they were added, not just the top level nodes and not in the order they are presented to the user).
Is there any way to get all the nodes of the tree in the order they are shown to the user? I don't like to change the legacy code that is filling the tree with data, and sorting the data before it is added to the TreeView might affect performance.
Please be aware that I'm talking about an application written in VB6, so there's no such thing as LINQ to traverse the nodes in the desired order.
Here's my searching code so far:
Private Sub cmdSearch_Click()
Dim oMatch As Node
Set oMatch = GetNextMatch
If Not (oMatch Is Nothing) Then
oMatch.EnsureVisible
oMatch.Selected = True
Me.TreeView1.SelectedItem = oMatch
Me.TreeView1.SetFocus
End If
End Sub
Private Function GetNextMatch() As Node
Dim lIndex As Long
Dim oResult As Node
For lIndex = mlLastFoundIndex + 1 To Me.TreeView1.Nodes.Count
If IsMatch(Me.TreeView1.Nodes(lIndex).Text) Then
Set oResult = Me.TreeView1.Nodes(lIndex)
mlLastFoundIndex = lIndex
Exit For
End If
Next lIndex
Set GetNextMatch = oResult
End Function
Private Sub txtSearch_Change()
mlLastFoundIndex = 0
End Sub
vb6 treeview
asked Mar 7 at 11:42
NostromoNostromo
477214
add a comment |
We have a legacy application written in VB6 using the default Microsoft TreeView control to display hierarchical data. Since there's a lot of information in this TreeView we thought about implementing a small filter/search possibility for the users.
The first attempt was to toggle the visibility and only make nodes (and their parents) visible, that match the defined search. But that was impossible, since the default Microsoft TreeView control doesn't allow their nodes to be visible or invisible.
So the second attempt is to traverse all the nodes in the tree and ensure a node's visibility when it matches the defined search (and stop traversing). When the found node isn't the one the user is looking for he can "continue" the search and look for the next node that matches his criteria.
This works quite good so far, except for one little problem. The search doesn't work from top to bottom, since the tree is filled with data in random sort order and then sorted by setting the Sorted property of each node (legacy code). So the search is going through the randomly added nodes and the found nodes "jump" between the top level nodes (the Nodes collection of the TreeView contains all the nodes in the order they were added, not just the top level nodes and not in the order they are presented to the user).
Is there any way to get all the nodes of the tree in the order they are shown to the user? I don't like to change the legacy code that is filling the tree with data, and sorting the data before it is added to the TreeView might affect performance.
Please be aware that I'm talking about an application written in VB6, so there's no such thing as LINQ to traverse the nodes in the desired order.
Here's my searching code so far:
Private Sub cmdSearch_Click()
Dim oMatch As Node
Set oMatch = GetNextMatch
If Not (oMatch Is Nothing) Then
oMatch.EnsureVisible
oMatch.Selected = True
Me.TreeView1.SelectedItem = oMatch
Me.TreeView1.SetFocus
End If
End Sub
Private Function GetNextMatch() As Node
Dim lIndex As Long
Dim oResult As Node
For lIndex = mlLastFoundIndex + 1 To Me.TreeView1.Nodes.Count
If IsMatch(Me.TreeView1.Nodes(lIndex).Text) Then
Set oResult = Me.TreeView1.Nodes(lIndex)
mlLastFoundIndex = lIndex
Exit For
End If
Next lIndex
Set GetNextMatch = oResult
End Function
Private Sub txtSearch_Change()
mlLastFoundIndex = 0
End Sub
vb6 treeview
asked Mar 7 at 11:42
NostromoNostromo
477214
3
It sounds like you've already figured out a root cause of why this is hard - that the treeview itself is being used as the 'master' data structure for these operations. If instead you had a separate data structure you could implement anything you wanted and then just copy the results into the treeview. I can see where that might be a lot of work to an existing app, but sometimes that sort of refactoring turns out to be easier in the long run... less lurching from special case to special case (all of which are hard to anticipate)
– DaveInCaz
Mar 7 at 12:23
I agree with DaveInCaz but could you post the "search" code you're working with? I've worked with the control before and it can be quirky. The nodes I believe are indexed starting with 0.
– Jimmy Smith
Mar 7 at 16:13
No, the indexing with theNodesstarts with 1. I put the search code in the question. I'm looking for something that delivers theMe.TreeView1.Nodesin the order the nodes are presented to the user.
– Nostromo
Mar 8 at 5:58
add a comment |
We have a legacy application written in VB6 using the default Microsoft TreeView control to display hierarchical data. Since there's a lot of information in this TreeView we thought about implementing a small filter/search possibility for the users.
The first attempt was to toggle the visibility and only make nodes (and their parents) visible, that match the defined search. But that was impossible, since the default Microsoft TreeView control doesn't allow their nodes to be visible or invisible.
So the second attempt is to traverse all the nodes in the tree and ensure a node's visibility when it matches the defined search (and stop traversing). When the found node isn't the one the user is looking for he can "continue" the search and look for the next node that matches his criteria.
This works quite good so far, except for one little problem. The search doesn't work from top to bottom, since the tree is filled with data in random sort order and then sorted by setting the Sorted property of each node (legacy code). So the search is going through the randomly added nodes and the found nodes "jump" between the top level nodes (the Nodes collection of the TreeView contains all the nodes in the order they were added, not just the top level nodes and not in the order they are presented to the user).
Is there any way to get all the nodes of the tree in the order they are shown to the user? I don't like to change the legacy code that is filling the tree with data, and sorting the data before it is added to the TreeView might affect performance.
Please be aware that I'm talking about an application written in VB6, so there's no such thing as LINQ to traverse the nodes in the desired order.
Here's my searching code so far:
Private Sub cmdSearch_Click()
Dim oMatch As Node
Set oMatch = GetNextMatch
If Not (oMatch Is Nothing) Then
oMatch.EnsureVisible
oMatch.Selected = True
Me.TreeView1.SelectedItem = oMatch
Me.TreeView1.SetFocus
End If
End Sub
Private Function GetNextMatch() As Node
Dim lIndex As Long
Dim oResult As Node
For lIndex = mlLastFoundIndex + 1 To Me.TreeView1.Nodes.Count
If IsMatch(Me.TreeView1.Nodes(lIndex).Text) Then
Set oResult = Me.TreeView1.Nodes(lIndex)
mlLastFoundIndex = lIndex
Exit For
End If
Next lIndex
Set GetNextMatch = oResult
End Function
Private Sub txtSearch_Change()
mlLastFoundIndex = 0
End Sub
vb6 treeview
asked Mar 7 at 11:42
NostromoNostromo
477214
We have a legacy application written in VB6 using the default Microsoft TreeView control to display hierarchical data. Since there's a lot of information in this TreeView we thought about implementing a small filter/search possibility for the users.
The first attempt was to toggle the visibility and only make nodes (and their parents) visible, that match the defined search. But that was impossible, since the default Microsoft TreeView control doesn't allow their nodes to be visible or invisible.
So the second attempt is to traverse all the nodes in the tree and ensure a node's visibility when it matches the defined search (and stop traversing). When the found node isn't the one the user is looking for he can "continue" the search and look for the next node that matches his criteria.
This works quite good so far, except for one little problem. The search doesn't work from top to bottom, since the tree is filled with data in random sort order and then sorted by setting the Sorted property of each node (legacy code). So the search is going through the randomly added nodes and the found nodes "jump" between the top level nodes (the Nodes collection of the TreeView contains all the nodes in the order they were added, not just the top level nodes and not in the order they are presented to the user).
Is there any way to get all the nodes of the tree in the order they are shown to the user? I don't like to change the legacy code that is filling the tree with data, and sorting the data before it is added to the TreeView might affect performance.
Please be aware that I'm talking about an application written in VB6, so there's no such thing as LINQ to traverse the nodes in the desired order.
Here's my searching code so far:
Private Sub cmdSearch_Click()
Dim oMatch As Node
Set oMatch = GetNextMatch
If Not (oMatch Is Nothing) Then
oMatch.EnsureVisible
oMatch.Selected = True
Me.TreeView1.SelectedItem = oMatch
Me.TreeView1.SetFocus
End If
End Sub
Private Function GetNextMatch() As Node
Dim lIndex As Long
Dim oResult As Node
For lIndex = mlLastFoundIndex + 1 To Me.TreeView1.Nodes.Count
If IsMatch(Me.TreeView1.Nodes(lIndex).Text) Then
Set oResult = Me.TreeView1.Nodes(lIndex)
mlLastFoundIndex = lIndex
Exit For
End If
Next lIndex
Set GetNextMatch = oResult
End Function
Private Sub txtSearch_Change()
mlLastFoundIndex = 0
End Sub
vb6 treeview
vb6 treeview
asked Mar 7 at 11:42
NostromoNostromo
477214
asked Mar 7 at 11:42
NostromoNostromo
477214
edited Mar 8 at 5:56
Nostromo
asked Mar 7 at 11:42
NostromoNostromo
477214
asked Mar 7 at 11:42
NostromoNostromo
477214
asked Mar 7 at 11:42
NostromoNostromo
477214
477214
3
It sounds like you've already figured out a root cause of why this is hard - that the treeview itself is being used as the 'master' data structure for these operations. If instead you had a separate data structure you could implement anything you wanted and then just copy the results into the treeview. I can see where that might be a lot of work to an existing app, but sometimes that sort of refactoring turns out to be easier in the long run... less lurching from special case to special case (all of which are hard to anticipate)
– DaveInCaz
Mar 7 at 12:23
I agree with DaveInCaz but could you post the "search" code you're working with? I've worked with the control before and it can be quirky. The nodes I believe are indexed starting with 0.
– Jimmy Smith
Mar 7 at 16:13
No, the indexing with theNodesstarts with 1. I put the search code in the question. I'm looking for something that delivers theMe.TreeView1.Nodesin the order the nodes are presented to the user.
– Nostromo
Mar 8 at 5:58
add a comment |
3
It sounds like you've already figured out a root cause of why this is hard - that the treeview itself is being used as the 'master' data structure for these operations. If instead you had a separate data structure you could implement anything you wanted and then just copy the results into the treeview. I can see where that might be a lot of work to an existing app, but sometimes that sort of refactoring turns out to be easier in the long run... less lurching from special case to special case (all of which are hard to anticipate)
– DaveInCaz
Mar 7 at 12:23
I agree with DaveInCaz but could you post the "search" code you're working with? I've worked with the control before and it can be quirky. The nodes I believe are indexed starting with 0.
– Jimmy Smith
Mar 7 at 16:13
No, the indexing with theNodesstarts with 1. I put the search code in the question. I'm looking for something that delivers theMe.TreeView1.Nodesin the order the nodes are presented to the user.
– Nostromo
Mar 8 at 5:58
3
3
It sounds like you've already figured out a root cause of why this is hard - that the treeview itself is being used as the 'master' data structure for these operations. If instead you had a separate data structure you could implement anything you wanted and then just copy the results into the treeview. I can see where that might be a lot of work to an existing app, but sometimes that sort of refactoring turns out to be easier in the long run... less lurching from special case to special case (all of which are hard to anticipate)
– DaveInCaz
Mar 7 at 12:23
It sounds like you've already figured out a root cause of why this is hard - that the treeview itself is being used as the 'master' data structure for these operations. If instead you had a separate data structure you could implement anything you wanted and then just copy the results into the treeview. I can see where that might be a lot of work to an existing app, but sometimes that sort of refactoring turns out to be easier in the long run... less lurching from special case to special case (all of which are hard to anticipate)
– DaveInCaz
Mar 7 at 12:23
I agree with DaveInCaz but could you post the "search" code you're working with? I've worked with the control before and it can be quirky. The nodes I believe are indexed starting with 0.
– Jimmy Smith
Mar 7 at 16:13
I agree with DaveInCaz but could you post the "search" code you're working with? I've worked with the control before and it can be quirky. The nodes I believe are indexed starting with 0.
– Jimmy Smith
Mar 7 at 16:13
No, the indexing with the
Nodes starts with 1. I put the search code in the question. I'm looking for something that delivers the Me.TreeView1.Nodes in the order the nodes are presented to the user.– Nostromo
Mar 8 at 5:58
No, the indexing with the
Nodes starts with 1. I put the search code in the question. I'm looking for something that delivers the Me.TreeView1.Nodes in the order the nodes are presented to the user.– Nostromo
Mar 8 at 5:58
add a comment |
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3
It sounds like you've already figured out a root cause of why this is hard - that the treeview itself is being used as the 'master' data structure for these operations. If instead you had a separate data structure you could implement anything you wanted and then just copy the results into the treeview. I can see where that might be a lot of work to an existing app, but sometimes that sort of refactoring turns out to be easier in the long run... less lurching from special case to special case (all of which are hard to anticipate)
– DaveInCaz
Mar 7 at 12:23
I agree with DaveInCaz but could you post the "search" code you're working with? I've worked with the control before and it can be quirky. The nodes I believe are indexed starting with 0.
– Jimmy Smith
Mar 7 at 16:13
No, the indexing with the
Nodesstarts with 1. I put the search code in the question. I'm looking for something that delivers theMe.TreeView1.Nodesin the order the nodes are presented to the user.– Nostromo
Mar 8 at 5:58