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assigning to an array in google script


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0















This is probably an ignorant mistake on my part, but I am trying to assign different values from different column to an array to put in a master sheet. I would like the last column to be equal the the sheet name where the data came from to track it back.



I feel I am close, but when I get to the last column which I want to be the sheet name I get the following error: Cannot convert Array to Object[][]. (line 19, file "combineTOmaster")



This is my code so far. I know the issue is the other column are array[[][]] and the last one is array [][] but I don't know how to fix it. Any ideas?



function getColValues(label,sheetName) 

var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheetName);
var colIndex = getColumnIndex(label, sheetName);
var numRows = ss.getLastRow() -1;
if (colIndex > 0 )
var colValues = ss.getRange(2, colIndex, numRows, 1).getValues();

else if (colIndex = "orginalsheet")
var colValues = [];
var array = [];
for (var i = 0; i < numRows-1;i++)
array[i] = sheetName;

colValues = array;

else
var colValues = [];

Logger.log(colValues);
return colValues;



Thank you










share|improve this question






















  • Should it really be orgin? Probably you meant origin, i.e. "originalsheet". Then there's the issue that you use = as the operator in a conditional check. You must review language fundamentals: developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/…

    – tehhowch
    Mar 9 at 14:38











  • @tehhoch Yes rookie mistake with the = versus ==. That page is a great resource.

    – Jerome Learman
    Mar 10 at 11:51

















0















This is probably an ignorant mistake on my part, but I am trying to assign different values from different column to an array to put in a master sheet. I would like the last column to be equal the the sheet name where the data came from to track it back.



I feel I am close, but when I get to the last column which I want to be the sheet name I get the following error: Cannot convert Array to Object[][]. (line 19, file "combineTOmaster")



This is my code so far. I know the issue is the other column are array[[][]] and the last one is array [][] but I don't know how to fix it. Any ideas?



function getColValues(label,sheetName) 

var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheetName);
var colIndex = getColumnIndex(label, sheetName);
var numRows = ss.getLastRow() -1;
if (colIndex > 0 )
var colValues = ss.getRange(2, colIndex, numRows, 1).getValues();

else if (colIndex = "orginalsheet")
var colValues = [];
var array = [];
for (var i = 0; i < numRows-1;i++)
array[i] = sheetName;

colValues = array;

else
var colValues = [];

Logger.log(colValues);
return colValues;



Thank you










share|improve this question






















  • Should it really be orgin? Probably you meant origin, i.e. "originalsheet". Then there's the issue that you use = as the operator in a conditional check. You must review language fundamentals: developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/…

    – tehhowch
    Mar 9 at 14:38











  • @tehhoch Yes rookie mistake with the = versus ==. That page is a great resource.

    – Jerome Learman
    Mar 10 at 11:51













0












0








0








This is probably an ignorant mistake on my part, but I am trying to assign different values from different column to an array to put in a master sheet. I would like the last column to be equal the the sheet name where the data came from to track it back.



I feel I am close, but when I get to the last column which I want to be the sheet name I get the following error: Cannot convert Array to Object[][]. (line 19, file "combineTOmaster")



This is my code so far. I know the issue is the other column are array[[][]] and the last one is array [][] but I don't know how to fix it. Any ideas?



function getColValues(label,sheetName) 

var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheetName);
var colIndex = getColumnIndex(label, sheetName);
var numRows = ss.getLastRow() -1;
if (colIndex > 0 )
var colValues = ss.getRange(2, colIndex, numRows, 1).getValues();

else if (colIndex = "orginalsheet")
var colValues = [];
var array = [];
for (var i = 0; i < numRows-1;i++)
array[i] = sheetName;

colValues = array;

else
var colValues = [];

Logger.log(colValues);
return colValues;



Thank you










share|improve this question














This is probably an ignorant mistake on my part, but I am trying to assign different values from different column to an array to put in a master sheet. I would like the last column to be equal the the sheet name where the data came from to track it back.



I feel I am close, but when I get to the last column which I want to be the sheet name I get the following error: Cannot convert Array to Object[][]. (line 19, file "combineTOmaster")



This is my code so far. I know the issue is the other column are array[[][]] and the last one is array [][] but I don't know how to fix it. Any ideas?



function getColValues(label,sheetName) 

var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheetName);
var colIndex = getColumnIndex(label, sheetName);
var numRows = ss.getLastRow() -1;
if (colIndex > 0 )
var colValues = ss.getRange(2, colIndex, numRows, 1).getValues();

else if (colIndex = "orginalsheet")
var colValues = [];
var array = [];
for (var i = 0; i < numRows-1;i++)
array[i] = sheetName;

colValues = array;

else
var colValues = [];

Logger.log(colValues);
return colValues;



Thank you







arrays google-apps-script






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 9 at 7:31









Jerome LearmanJerome Learman

115




115












  • Should it really be orgin? Probably you meant origin, i.e. "originalsheet". Then there's the issue that you use = as the operator in a conditional check. You must review language fundamentals: developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/…

    – tehhowch
    Mar 9 at 14:38











  • @tehhoch Yes rookie mistake with the = versus ==. That page is a great resource.

    – Jerome Learman
    Mar 10 at 11:51

















  • Should it really be orgin? Probably you meant origin, i.e. "originalsheet". Then there's the issue that you use = as the operator in a conditional check. You must review language fundamentals: developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/…

    – tehhowch
    Mar 9 at 14:38











  • @tehhoch Yes rookie mistake with the = versus ==. That page is a great resource.

    – Jerome Learman
    Mar 10 at 11:51
















Should it really be orgin? Probably you meant origin, i.e. "originalsheet". Then there's the issue that you use = as the operator in a conditional check. You must review language fundamentals: developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/…

– tehhowch
Mar 9 at 14:38





Should it really be orgin? Probably you meant origin, i.e. "originalsheet". Then there's the issue that you use = as the operator in a conditional check. You must review language fundamentals: developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/…

– tehhowch
Mar 9 at 14:38













@tehhoch Yes rookie mistake with the = versus ==. That page is a great resource.

– Jerome Learman
Mar 10 at 11:51





@tehhoch Yes rookie mistake with the = versus ==. That page is a great resource.

– Jerome Learman
Mar 10 at 11:51












2 Answers
2






active

oldest

votes


















0














Lets break your function down -



// you're passing column header and sheet name, OK
function getColValues(label, sheetName)
// getting sheet, OK
var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheetName);

// getting column index, OK
var colIndex = getColumnIndex(label, sheetName);

// getting number of rows to collect, OK
var numRows = ss.getLastRow() - 1;

// at this point, i assume, variable colIndex is a number, because it should be
// if label column exists, colIndex will be greater than 0, OK
if (colIndex > 0)
// get values of that column, OK
var colValues = ss.getRange(2, colIndex, numRows, 1).getValues();
// colValues will be like this, at this point-
// [ [value], [value], [value] ... ]

else if ((colIndex = 'orginalsheet'))
// NOT OK, = sign assigns 'orginalsheet' to colIndex
// do you wanna assign or compare?
// to compare, use == sign
// besides why are you assigning a string value to colIndex ?
// colIndex should be a number, in my understanding

// now, what do you wanna do here ?
var colValues = [];
var array = [];
for (var i = 0; i < numRows - 1; i++)
array[i] = sheetName;

colValues = array;
// at his point, colValues is -
// [sheetName, sheetName, sheetName...]

// is this correct colValues ?
// i guess not
// i think you're trying to use sheetName as a column value for every row
// if that is the case, do this
var colValues = [];
for (var i = 0; i < numRows; i++) colValues.push([sheetName]);
// now colValues is -
// [ [sheetName], [sheetName], [sheetName].... ]
// which you can insert in a sheet as values of a column
else
var colValues = [];

Logger.log(colValues);
return colValues;






share|improve this answer






























    0














    @ra89fi Thank you so much. You lead me to the answer. So mess up 1 was using = and not ==. Mess up two was using colIndex instead of label. Mess up three was not using push. Is there a good resource on push? Thank you again!!



    Below is the final code that worked for me.



    function getColValues(label,sheetName) 

    var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheetName);
    var colIndex = getColumnIndex(label, sheetName);
    var numRows = ss.getLastRow() -1;
    if (colIndex > 0 )
    var colValues = ss.getRange(2, colIndex, numRows, 1).getValues();

    else if (label == "orginalsheet")
    var colValues = [];
    for (var i = 0; i < numRows;i++)
    colValues.push([sheetName]);


    else
    var colValues = [];

    return colValues;






    share|improve this answer























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0














      Lets break your function down -



      // you're passing column header and sheet name, OK
      function getColValues(label, sheetName)
      // getting sheet, OK
      var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheetName);

      // getting column index, OK
      var colIndex = getColumnIndex(label, sheetName);

      // getting number of rows to collect, OK
      var numRows = ss.getLastRow() - 1;

      // at this point, i assume, variable colIndex is a number, because it should be
      // if label column exists, colIndex will be greater than 0, OK
      if (colIndex > 0)
      // get values of that column, OK
      var colValues = ss.getRange(2, colIndex, numRows, 1).getValues();
      // colValues will be like this, at this point-
      // [ [value], [value], [value] ... ]

      else if ((colIndex = 'orginalsheet'))
      // NOT OK, = sign assigns 'orginalsheet' to colIndex
      // do you wanna assign or compare?
      // to compare, use == sign
      // besides why are you assigning a string value to colIndex ?
      // colIndex should be a number, in my understanding

      // now, what do you wanna do here ?
      var colValues = [];
      var array = [];
      for (var i = 0; i < numRows - 1; i++)
      array[i] = sheetName;

      colValues = array;
      // at his point, colValues is -
      // [sheetName, sheetName, sheetName...]

      // is this correct colValues ?
      // i guess not
      // i think you're trying to use sheetName as a column value for every row
      // if that is the case, do this
      var colValues = [];
      for (var i = 0; i < numRows; i++) colValues.push([sheetName]);
      // now colValues is -
      // [ [sheetName], [sheetName], [sheetName].... ]
      // which you can insert in a sheet as values of a column
      else
      var colValues = [];

      Logger.log(colValues);
      return colValues;






      share|improve this answer



























        0














        Lets break your function down -



        // you're passing column header and sheet name, OK
        function getColValues(label, sheetName)
        // getting sheet, OK
        var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheetName);

        // getting column index, OK
        var colIndex = getColumnIndex(label, sheetName);

        // getting number of rows to collect, OK
        var numRows = ss.getLastRow() - 1;

        // at this point, i assume, variable colIndex is a number, because it should be
        // if label column exists, colIndex will be greater than 0, OK
        if (colIndex > 0)
        // get values of that column, OK
        var colValues = ss.getRange(2, colIndex, numRows, 1).getValues();
        // colValues will be like this, at this point-
        // [ [value], [value], [value] ... ]

        else if ((colIndex = 'orginalsheet'))
        // NOT OK, = sign assigns 'orginalsheet' to colIndex
        // do you wanna assign or compare?
        // to compare, use == sign
        // besides why are you assigning a string value to colIndex ?
        // colIndex should be a number, in my understanding

        // now, what do you wanna do here ?
        var colValues = [];
        var array = [];
        for (var i = 0; i < numRows - 1; i++)
        array[i] = sheetName;

        colValues = array;
        // at his point, colValues is -
        // [sheetName, sheetName, sheetName...]

        // is this correct colValues ?
        // i guess not
        // i think you're trying to use sheetName as a column value for every row
        // if that is the case, do this
        var colValues = [];
        for (var i = 0; i < numRows; i++) colValues.push([sheetName]);
        // now colValues is -
        // [ [sheetName], [sheetName], [sheetName].... ]
        // which you can insert in a sheet as values of a column
        else
        var colValues = [];

        Logger.log(colValues);
        return colValues;






        share|improve this answer

























          0












          0








          0







          Lets break your function down -



          // you're passing column header and sheet name, OK
          function getColValues(label, sheetName)
          // getting sheet, OK
          var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheetName);

          // getting column index, OK
          var colIndex = getColumnIndex(label, sheetName);

          // getting number of rows to collect, OK
          var numRows = ss.getLastRow() - 1;

          // at this point, i assume, variable colIndex is a number, because it should be
          // if label column exists, colIndex will be greater than 0, OK
          if (colIndex > 0)
          // get values of that column, OK
          var colValues = ss.getRange(2, colIndex, numRows, 1).getValues();
          // colValues will be like this, at this point-
          // [ [value], [value], [value] ... ]

          else if ((colIndex = 'orginalsheet'))
          // NOT OK, = sign assigns 'orginalsheet' to colIndex
          // do you wanna assign or compare?
          // to compare, use == sign
          // besides why are you assigning a string value to colIndex ?
          // colIndex should be a number, in my understanding

          // now, what do you wanna do here ?
          var colValues = [];
          var array = [];
          for (var i = 0; i < numRows - 1; i++)
          array[i] = sheetName;

          colValues = array;
          // at his point, colValues is -
          // [sheetName, sheetName, sheetName...]

          // is this correct colValues ?
          // i guess not
          // i think you're trying to use sheetName as a column value for every row
          // if that is the case, do this
          var colValues = [];
          for (var i = 0; i < numRows; i++) colValues.push([sheetName]);
          // now colValues is -
          // [ [sheetName], [sheetName], [sheetName].... ]
          // which you can insert in a sheet as values of a column
          else
          var colValues = [];

          Logger.log(colValues);
          return colValues;






          share|improve this answer













          Lets break your function down -



          // you're passing column header and sheet name, OK
          function getColValues(label, sheetName)
          // getting sheet, OK
          var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheetName);

          // getting column index, OK
          var colIndex = getColumnIndex(label, sheetName);

          // getting number of rows to collect, OK
          var numRows = ss.getLastRow() - 1;

          // at this point, i assume, variable colIndex is a number, because it should be
          // if label column exists, colIndex will be greater than 0, OK
          if (colIndex > 0)
          // get values of that column, OK
          var colValues = ss.getRange(2, colIndex, numRows, 1).getValues();
          // colValues will be like this, at this point-
          // [ [value], [value], [value] ... ]

          else if ((colIndex = 'orginalsheet'))
          // NOT OK, = sign assigns 'orginalsheet' to colIndex
          // do you wanna assign or compare?
          // to compare, use == sign
          // besides why are you assigning a string value to colIndex ?
          // colIndex should be a number, in my understanding

          // now, what do you wanna do here ?
          var colValues = [];
          var array = [];
          for (var i = 0; i < numRows - 1; i++)
          array[i] = sheetName;

          colValues = array;
          // at his point, colValues is -
          // [sheetName, sheetName, sheetName...]

          // is this correct colValues ?
          // i guess not
          // i think you're trying to use sheetName as a column value for every row
          // if that is the case, do this
          var colValues = [];
          for (var i = 0; i < numRows; i++) colValues.push([sheetName]);
          // now colValues is -
          // [ [sheetName], [sheetName], [sheetName].... ]
          // which you can insert in a sheet as values of a column
          else
          var colValues = [];

          Logger.log(colValues);
          return colValues;







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Mar 9 at 9:15









          ra89fira89fi

          969168




          969168























              0














              @ra89fi Thank you so much. You lead me to the answer. So mess up 1 was using = and not ==. Mess up two was using colIndex instead of label. Mess up three was not using push. Is there a good resource on push? Thank you again!!



              Below is the final code that worked for me.



              function getColValues(label,sheetName) 

              var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheetName);
              var colIndex = getColumnIndex(label, sheetName);
              var numRows = ss.getLastRow() -1;
              if (colIndex > 0 )
              var colValues = ss.getRange(2, colIndex, numRows, 1).getValues();

              else if (label == "orginalsheet")
              var colValues = [];
              for (var i = 0; i < numRows;i++)
              colValues.push([sheetName]);


              else
              var colValues = [];

              return colValues;






              share|improve this answer



























                0














                @ra89fi Thank you so much. You lead me to the answer. So mess up 1 was using = and not ==. Mess up two was using colIndex instead of label. Mess up three was not using push. Is there a good resource on push? Thank you again!!



                Below is the final code that worked for me.



                function getColValues(label,sheetName) 

                var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheetName);
                var colIndex = getColumnIndex(label, sheetName);
                var numRows = ss.getLastRow() -1;
                if (colIndex > 0 )
                var colValues = ss.getRange(2, colIndex, numRows, 1).getValues();

                else if (label == "orginalsheet")
                var colValues = [];
                for (var i = 0; i < numRows;i++)
                colValues.push([sheetName]);


                else
                var colValues = [];

                return colValues;






                share|improve this answer

























                  0












                  0








                  0







                  @ra89fi Thank you so much. You lead me to the answer. So mess up 1 was using = and not ==. Mess up two was using colIndex instead of label. Mess up three was not using push. Is there a good resource on push? Thank you again!!



                  Below is the final code that worked for me.



                  function getColValues(label,sheetName) 

                  var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheetName);
                  var colIndex = getColumnIndex(label, sheetName);
                  var numRows = ss.getLastRow() -1;
                  if (colIndex > 0 )
                  var colValues = ss.getRange(2, colIndex, numRows, 1).getValues();

                  else if (label == "orginalsheet")
                  var colValues = [];
                  for (var i = 0; i < numRows;i++)
                  colValues.push([sheetName]);


                  else
                  var colValues = [];

                  return colValues;






                  share|improve this answer













                  @ra89fi Thank you so much. You lead me to the answer. So mess up 1 was using = and not ==. Mess up two was using colIndex instead of label. Mess up three was not using push. Is there a good resource on push? Thank you again!!



                  Below is the final code that worked for me.



                  function getColValues(label,sheetName) 

                  var ss = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheetName);
                  var colIndex = getColumnIndex(label, sheetName);
                  var numRows = ss.getLastRow() -1;
                  if (colIndex > 0 )
                  var colValues = ss.getRange(2, colIndex, numRows, 1).getValues();

                  else if (label == "orginalsheet")
                  var colValues = [];
                  for (var i = 0; i < numRows;i++)
                  colValues.push([sheetName]);


                  else
                  var colValues = [];

                  return colValues;







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Mar 10 at 12:02









                  Jerome LearmanJerome Learman

                  115




                  115



























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