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How to verify if audio magnitude is correct in Core Audio?
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I am using the following code to record audio and produce a magnitude float data. But I am not sure if the data is correct. Could someone please verify?
The main program used for recording audio is similar to the example AudioQueueRecorder.
In there once I create the queue, I add AudioQueueProcessingTapNew
with callback as:
guard let queue = queue else return
var maxFrames : UInt32 = 0;
var tapFormat = AudioStreamBasicDescription()
var tap : AudioQueueProcessingTapRef? = nil
var player = MyInfo()
utils.checkError(AudioQueueProcessingTapNew(queue, tapCallback, &player, AudioQueueProcessingTapFlags.preEffects, &maxFrames, &tapFormat, &tap),
"Failed to create audio queue tap")
In the tap callback (linked above), I use the code to get the magnitude:
let info = userData.assumingMemoryBound(to: MyInfo.self)
var sourceFlags: AudioQueueProcessingTapFlags = AudioQueueProcessingTapFlags(rawValue: 0)
var sourceNumFrames: UInt32 = 0
AudioQueueProcessingTapGetSourceAudio(tap, inNumFrames, ts, &sourceFlags, &sourceNumFrames, ioData)
print("ts:", ts.pointee)
print("num frames:", inNumFrames)
let numBuffers = ioData.pointee.mNumberBuffers
print("num buffers:", numBuffers)
if numBuffers > 0
let numChans = ioData.pointee.mBuffers.mNumberChannels
let size = ioData.pointee.mBuffers.mDataByteSize / 4 //Size of a float is 4
let data: [Float] = Array(UnsafeMutableBufferPointer(start: ioData.pointee.mBuffers.mData!.assumingMemoryBound(to: Float.self), count: Int(size)))
print("num chans:", numChans)
print("size:", size)
let fft = TempiFFT(withSize: Int(size), sampleRate: 44100.0)
fft.windowType = TempiFFTWindowType.hamming
fft.fftForward(data)
fft.calculateLinearBands(minFrequency: 0, maxFrequency: fft.nyquistFrequency, numberOfBands: 20)
var magnitudeArr = [Float](repeating: Float(0), count: 20)
var magnitudeDBArr = [Float](repeating: Float(0), count: 20)
for i in 0..<20
magnitudeArr[i] = fft.magnitudeAtBand(i)
//var magnitudeDB = TempiFFT.toDB(fft.magnitudeAtBand(i))
log.debug("fft.magnitudeAtBand((i)) = (fft.magnitudeAtBand(i))")
I am getting the following output. I want to draw a plot for the amplitude.
ts: AudioTimeStamp(mSampleTime: 359433.0, mHostTime: 7385045310414, mRateScalar: 0.9999903367259503, mWordClockTime: 4424786032, mSMPTETime: __C.SMPTETime(mSubframes: 0, mSubframeDivisor: 16384, mCounter: 0, mType: __C.SMPTETimeType, mFlags: __C.SMPTETimeFlags(rawValue: 1), mHours: 4800, mMinutes: 179, mSeconds: 1, mFrames: 0), mFlags: __C.AudioTimeStampFlags(rawValue: 7), mReserved: 28672)
num frames: 2048
num buffers: 2
num chans: 1
size: 2048
data: [-0.00013435386, 4.471163e-05, 2.5250512e-07, -0.00013112863, -4.2305917e-05, -6.0883203e-06, -6.9609705e-05, 1.3280656e-05, 2.6565194e-06, -7.048986e-05, -4.371278e-05, -0.00012498278, -0.00015581526, 2.6477476e-06, 0.00014767727, 0.00015129645, 0.0002481592, 0.00020998582, 7.0496775e-05, 0.00023169718, 0.00032023923, 9.4876516e-05, 3.0334933e-05, -0.00010365831, -0.00012052287, -3.4284778e-06, -8.221614e-05, -0.00013551829, -8.154745e-05, -8.845353e-06, -5.211319e-05, 6.356722e-05, 0.00014827582] ...
fft.magnitudeAtBand(0) = 0.0019885404
fft.magnitudeAtBand(1) = 0.0002433162
fft.magnitudeAtBand(2) = 0.00011211308
fft.magnitudeAtBand(3) = 0.00019586945
fft.magnitudeAtBand(4) = 0.00015595475
fft.magnitudeAtBand(5) = 1.6589744e-05
fft.magnitudeAtBand(6) = 0.0019934585
fft.magnitudeAtBand(7) = 0.00035403066
fft.magnitudeAtBand(8) = 0.0020195032
fft.magnitudeAtBand(9) = 0.0019526586
fft.magnitudeAtBand(10) = 0.0010482509
fft.magnitudeAtBand(11) = 0.0015899779
fft.magnitudeAtBand(12) = 0.00021513038
fft.magnitudeAtBand(13) = 8.8768e-05
fft.magnitudeAtBand(14) = 0.00088070636
fft.magnitudeAtBand(15) = 3.6925994e-05
fft.magnitudeAtBand(16) = 0.0013688633
fft.magnitudeAtBand(17) = 0.0020811968
fft.magnitudeAtBand(18) = 0.00039211413
fft.magnitudeAtBand(19) = 1.50605065e-05
stop record did tap
But the magnitudeAtBand
value seems to be very small value. Is this correct? How to draw a plot of amplitude?
In the data value, there are negatives. Why is it negative?
ios swift plot core-audio
add a comment |
I am using the following code to record audio and produce a magnitude float data. But I am not sure if the data is correct. Could someone please verify?
The main program used for recording audio is similar to the example AudioQueueRecorder.
In there once I create the queue, I add AudioQueueProcessingTapNew
with callback as:
guard let queue = queue else return
var maxFrames : UInt32 = 0;
var tapFormat = AudioStreamBasicDescription()
var tap : AudioQueueProcessingTapRef? = nil
var player = MyInfo()
utils.checkError(AudioQueueProcessingTapNew(queue, tapCallback, &player, AudioQueueProcessingTapFlags.preEffects, &maxFrames, &tapFormat, &tap),
"Failed to create audio queue tap")
In the tap callback (linked above), I use the code to get the magnitude:
let info = userData.assumingMemoryBound(to: MyInfo.self)
var sourceFlags: AudioQueueProcessingTapFlags = AudioQueueProcessingTapFlags(rawValue: 0)
var sourceNumFrames: UInt32 = 0
AudioQueueProcessingTapGetSourceAudio(tap, inNumFrames, ts, &sourceFlags, &sourceNumFrames, ioData)
print("ts:", ts.pointee)
print("num frames:", inNumFrames)
let numBuffers = ioData.pointee.mNumberBuffers
print("num buffers:", numBuffers)
if numBuffers > 0
let numChans = ioData.pointee.mBuffers.mNumberChannels
let size = ioData.pointee.mBuffers.mDataByteSize / 4 //Size of a float is 4
let data: [Float] = Array(UnsafeMutableBufferPointer(start: ioData.pointee.mBuffers.mData!.assumingMemoryBound(to: Float.self), count: Int(size)))
print("num chans:", numChans)
print("size:", size)
let fft = TempiFFT(withSize: Int(size), sampleRate: 44100.0)
fft.windowType = TempiFFTWindowType.hamming
fft.fftForward(data)
fft.calculateLinearBands(minFrequency: 0, maxFrequency: fft.nyquistFrequency, numberOfBands: 20)
var magnitudeArr = [Float](repeating: Float(0), count: 20)
var magnitudeDBArr = [Float](repeating: Float(0), count: 20)
for i in 0..<20
magnitudeArr[i] = fft.magnitudeAtBand(i)
//var magnitudeDB = TempiFFT.toDB(fft.magnitudeAtBand(i))
log.debug("fft.magnitudeAtBand((i)) = (fft.magnitudeAtBand(i))")
I am getting the following output. I want to draw a plot for the amplitude.
ts: AudioTimeStamp(mSampleTime: 359433.0, mHostTime: 7385045310414, mRateScalar: 0.9999903367259503, mWordClockTime: 4424786032, mSMPTETime: __C.SMPTETime(mSubframes: 0, mSubframeDivisor: 16384, mCounter: 0, mType: __C.SMPTETimeType, mFlags: __C.SMPTETimeFlags(rawValue: 1), mHours: 4800, mMinutes: 179, mSeconds: 1, mFrames: 0), mFlags: __C.AudioTimeStampFlags(rawValue: 7), mReserved: 28672)
num frames: 2048
num buffers: 2
num chans: 1
size: 2048
data: [-0.00013435386, 4.471163e-05, 2.5250512e-07, -0.00013112863, -4.2305917e-05, -6.0883203e-06, -6.9609705e-05, 1.3280656e-05, 2.6565194e-06, -7.048986e-05, -4.371278e-05, -0.00012498278, -0.00015581526, 2.6477476e-06, 0.00014767727, 0.00015129645, 0.0002481592, 0.00020998582, 7.0496775e-05, 0.00023169718, 0.00032023923, 9.4876516e-05, 3.0334933e-05, -0.00010365831, -0.00012052287, -3.4284778e-06, -8.221614e-05, -0.00013551829, -8.154745e-05, -8.845353e-06, -5.211319e-05, 6.356722e-05, 0.00014827582] ...
fft.magnitudeAtBand(0) = 0.0019885404
fft.magnitudeAtBand(1) = 0.0002433162
fft.magnitudeAtBand(2) = 0.00011211308
fft.magnitudeAtBand(3) = 0.00019586945
fft.magnitudeAtBand(4) = 0.00015595475
fft.magnitudeAtBand(5) = 1.6589744e-05
fft.magnitudeAtBand(6) = 0.0019934585
fft.magnitudeAtBand(7) = 0.00035403066
fft.magnitudeAtBand(8) = 0.0020195032
fft.magnitudeAtBand(9) = 0.0019526586
fft.magnitudeAtBand(10) = 0.0010482509
fft.magnitudeAtBand(11) = 0.0015899779
fft.magnitudeAtBand(12) = 0.00021513038
fft.magnitudeAtBand(13) = 8.8768e-05
fft.magnitudeAtBand(14) = 0.00088070636
fft.magnitudeAtBand(15) = 3.6925994e-05
fft.magnitudeAtBand(16) = 0.0013688633
fft.magnitudeAtBand(17) = 0.0020811968
fft.magnitudeAtBand(18) = 0.00039211413
fft.magnitudeAtBand(19) = 1.50605065e-05
stop record did tap
But the magnitudeAtBand
value seems to be very small value. Is this correct? How to draw a plot of amplitude?
In the data value, there are negatives. Why is it negative?
ios swift plot core-audio
add a comment |
I am using the following code to record audio and produce a magnitude float data. But I am not sure if the data is correct. Could someone please verify?
The main program used for recording audio is similar to the example AudioQueueRecorder.
In there once I create the queue, I add AudioQueueProcessingTapNew
with callback as:
guard let queue = queue else return
var maxFrames : UInt32 = 0;
var tapFormat = AudioStreamBasicDescription()
var tap : AudioQueueProcessingTapRef? = nil
var player = MyInfo()
utils.checkError(AudioQueueProcessingTapNew(queue, tapCallback, &player, AudioQueueProcessingTapFlags.preEffects, &maxFrames, &tapFormat, &tap),
"Failed to create audio queue tap")
In the tap callback (linked above), I use the code to get the magnitude:
let info = userData.assumingMemoryBound(to: MyInfo.self)
var sourceFlags: AudioQueueProcessingTapFlags = AudioQueueProcessingTapFlags(rawValue: 0)
var sourceNumFrames: UInt32 = 0
AudioQueueProcessingTapGetSourceAudio(tap, inNumFrames, ts, &sourceFlags, &sourceNumFrames, ioData)
print("ts:", ts.pointee)
print("num frames:", inNumFrames)
let numBuffers = ioData.pointee.mNumberBuffers
print("num buffers:", numBuffers)
if numBuffers > 0
let numChans = ioData.pointee.mBuffers.mNumberChannels
let size = ioData.pointee.mBuffers.mDataByteSize / 4 //Size of a float is 4
let data: [Float] = Array(UnsafeMutableBufferPointer(start: ioData.pointee.mBuffers.mData!.assumingMemoryBound(to: Float.self), count: Int(size)))
print("num chans:", numChans)
print("size:", size)
let fft = TempiFFT(withSize: Int(size), sampleRate: 44100.0)
fft.windowType = TempiFFTWindowType.hamming
fft.fftForward(data)
fft.calculateLinearBands(minFrequency: 0, maxFrequency: fft.nyquistFrequency, numberOfBands: 20)
var magnitudeArr = [Float](repeating: Float(0), count: 20)
var magnitudeDBArr = [Float](repeating: Float(0), count: 20)
for i in 0..<20
magnitudeArr[i] = fft.magnitudeAtBand(i)
//var magnitudeDB = TempiFFT.toDB(fft.magnitudeAtBand(i))
log.debug("fft.magnitudeAtBand((i)) = (fft.magnitudeAtBand(i))")
I am getting the following output. I want to draw a plot for the amplitude.
ts: AudioTimeStamp(mSampleTime: 359433.0, mHostTime: 7385045310414, mRateScalar: 0.9999903367259503, mWordClockTime: 4424786032, mSMPTETime: __C.SMPTETime(mSubframes: 0, mSubframeDivisor: 16384, mCounter: 0, mType: __C.SMPTETimeType, mFlags: __C.SMPTETimeFlags(rawValue: 1), mHours: 4800, mMinutes: 179, mSeconds: 1, mFrames: 0), mFlags: __C.AudioTimeStampFlags(rawValue: 7), mReserved: 28672)
num frames: 2048
num buffers: 2
num chans: 1
size: 2048
data: [-0.00013435386, 4.471163e-05, 2.5250512e-07, -0.00013112863, -4.2305917e-05, -6.0883203e-06, -6.9609705e-05, 1.3280656e-05, 2.6565194e-06, -7.048986e-05, -4.371278e-05, -0.00012498278, -0.00015581526, 2.6477476e-06, 0.00014767727, 0.00015129645, 0.0002481592, 0.00020998582, 7.0496775e-05, 0.00023169718, 0.00032023923, 9.4876516e-05, 3.0334933e-05, -0.00010365831, -0.00012052287, -3.4284778e-06, -8.221614e-05, -0.00013551829, -8.154745e-05, -8.845353e-06, -5.211319e-05, 6.356722e-05, 0.00014827582] ...
fft.magnitudeAtBand(0) = 0.0019885404
fft.magnitudeAtBand(1) = 0.0002433162
fft.magnitudeAtBand(2) = 0.00011211308
fft.magnitudeAtBand(3) = 0.00019586945
fft.magnitudeAtBand(4) = 0.00015595475
fft.magnitudeAtBand(5) = 1.6589744e-05
fft.magnitudeAtBand(6) = 0.0019934585
fft.magnitudeAtBand(7) = 0.00035403066
fft.magnitudeAtBand(8) = 0.0020195032
fft.magnitudeAtBand(9) = 0.0019526586
fft.magnitudeAtBand(10) = 0.0010482509
fft.magnitudeAtBand(11) = 0.0015899779
fft.magnitudeAtBand(12) = 0.00021513038
fft.magnitudeAtBand(13) = 8.8768e-05
fft.magnitudeAtBand(14) = 0.00088070636
fft.magnitudeAtBand(15) = 3.6925994e-05
fft.magnitudeAtBand(16) = 0.0013688633
fft.magnitudeAtBand(17) = 0.0020811968
fft.magnitudeAtBand(18) = 0.00039211413
fft.magnitudeAtBand(19) = 1.50605065e-05
stop record did tap
But the magnitudeAtBand
value seems to be very small value. Is this correct? How to draw a plot of amplitude?
In the data value, there are negatives. Why is it negative?
ios swift plot core-audio
I am using the following code to record audio and produce a magnitude float data. But I am not sure if the data is correct. Could someone please verify?
The main program used for recording audio is similar to the example AudioQueueRecorder.
In there once I create the queue, I add AudioQueueProcessingTapNew
with callback as:
guard let queue = queue else return
var maxFrames : UInt32 = 0;
var tapFormat = AudioStreamBasicDescription()
var tap : AudioQueueProcessingTapRef? = nil
var player = MyInfo()
utils.checkError(AudioQueueProcessingTapNew(queue, tapCallback, &player, AudioQueueProcessingTapFlags.preEffects, &maxFrames, &tapFormat, &tap),
"Failed to create audio queue tap")
In the tap callback (linked above), I use the code to get the magnitude:
let info = userData.assumingMemoryBound(to: MyInfo.self)
var sourceFlags: AudioQueueProcessingTapFlags = AudioQueueProcessingTapFlags(rawValue: 0)
var sourceNumFrames: UInt32 = 0
AudioQueueProcessingTapGetSourceAudio(tap, inNumFrames, ts, &sourceFlags, &sourceNumFrames, ioData)
print("ts:", ts.pointee)
print("num frames:", inNumFrames)
let numBuffers = ioData.pointee.mNumberBuffers
print("num buffers:", numBuffers)
if numBuffers > 0
let numChans = ioData.pointee.mBuffers.mNumberChannels
let size = ioData.pointee.mBuffers.mDataByteSize / 4 //Size of a float is 4
let data: [Float] = Array(UnsafeMutableBufferPointer(start: ioData.pointee.mBuffers.mData!.assumingMemoryBound(to: Float.self), count: Int(size)))
print("num chans:", numChans)
print("size:", size)
let fft = TempiFFT(withSize: Int(size), sampleRate: 44100.0)
fft.windowType = TempiFFTWindowType.hamming
fft.fftForward(data)
fft.calculateLinearBands(minFrequency: 0, maxFrequency: fft.nyquistFrequency, numberOfBands: 20)
var magnitudeArr = [Float](repeating: Float(0), count: 20)
var magnitudeDBArr = [Float](repeating: Float(0), count: 20)
for i in 0..<20
magnitudeArr[i] = fft.magnitudeAtBand(i)
//var magnitudeDB = TempiFFT.toDB(fft.magnitudeAtBand(i))
log.debug("fft.magnitudeAtBand((i)) = (fft.magnitudeAtBand(i))")
I am getting the following output. I want to draw a plot for the amplitude.
ts: AudioTimeStamp(mSampleTime: 359433.0, mHostTime: 7385045310414, mRateScalar: 0.9999903367259503, mWordClockTime: 4424786032, mSMPTETime: __C.SMPTETime(mSubframes: 0, mSubframeDivisor: 16384, mCounter: 0, mType: __C.SMPTETimeType, mFlags: __C.SMPTETimeFlags(rawValue: 1), mHours: 4800, mMinutes: 179, mSeconds: 1, mFrames: 0), mFlags: __C.AudioTimeStampFlags(rawValue: 7), mReserved: 28672)
num frames: 2048
num buffers: 2
num chans: 1
size: 2048
data: [-0.00013435386, 4.471163e-05, 2.5250512e-07, -0.00013112863, -4.2305917e-05, -6.0883203e-06, -6.9609705e-05, 1.3280656e-05, 2.6565194e-06, -7.048986e-05, -4.371278e-05, -0.00012498278, -0.00015581526, 2.6477476e-06, 0.00014767727, 0.00015129645, 0.0002481592, 0.00020998582, 7.0496775e-05, 0.00023169718, 0.00032023923, 9.4876516e-05, 3.0334933e-05, -0.00010365831, -0.00012052287, -3.4284778e-06, -8.221614e-05, -0.00013551829, -8.154745e-05, -8.845353e-06, -5.211319e-05, 6.356722e-05, 0.00014827582] ...
fft.magnitudeAtBand(0) = 0.0019885404
fft.magnitudeAtBand(1) = 0.0002433162
fft.magnitudeAtBand(2) = 0.00011211308
fft.magnitudeAtBand(3) = 0.00019586945
fft.magnitudeAtBand(4) = 0.00015595475
fft.magnitudeAtBand(5) = 1.6589744e-05
fft.magnitudeAtBand(6) = 0.0019934585
fft.magnitudeAtBand(7) = 0.00035403066
fft.magnitudeAtBand(8) = 0.0020195032
fft.magnitudeAtBand(9) = 0.0019526586
fft.magnitudeAtBand(10) = 0.0010482509
fft.magnitudeAtBand(11) = 0.0015899779
fft.magnitudeAtBand(12) = 0.00021513038
fft.magnitudeAtBand(13) = 8.8768e-05
fft.magnitudeAtBand(14) = 0.00088070636
fft.magnitudeAtBand(15) = 3.6925994e-05
fft.magnitudeAtBand(16) = 0.0013688633
fft.magnitudeAtBand(17) = 0.0020811968
fft.magnitudeAtBand(18) = 0.00039211413
fft.magnitudeAtBand(19) = 1.50605065e-05
stop record did tap
But the magnitudeAtBand
value seems to be very small value. Is this correct? How to draw a plot of amplitude?
In the data value, there are negatives. Why is it negative?
ios swift plot core-audio
ios swift plot core-audio
asked Mar 9 at 7:42
jsloopjsloop
332211
332211
add a comment |
add a comment |
1 Answer
1
active
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The range on OS X for 32 bit floating point samples is -1.0f to 1.0f. The negative numbers are there because the (row of) samples describe an analog waveform signal.
To verify the validity of the data I would suggest to play it back so you can hear if the data is correct.
More complex solutions to verify are to feed a testsignal and view it on an oscilloscope or spectrum analyser.
add a comment |
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The range on OS X for 32 bit floating point samples is -1.0f to 1.0f. The negative numbers are there because the (row of) samples describe an analog waveform signal.
To verify the validity of the data I would suggest to play it back so you can hear if the data is correct.
More complex solutions to verify are to feed a testsignal and view it on an oscilloscope or spectrum analyser.
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The range on OS X for 32 bit floating point samples is -1.0f to 1.0f. The negative numbers are there because the (row of) samples describe an analog waveform signal.
To verify the validity of the data I would suggest to play it back so you can hear if the data is correct.
More complex solutions to verify are to feed a testsignal and view it on an oscilloscope or spectrum analyser.
add a comment |
The range on OS X for 32 bit floating point samples is -1.0f to 1.0f. The negative numbers are there because the (row of) samples describe an analog waveform signal.
To verify the validity of the data I would suggest to play it back so you can hear if the data is correct.
More complex solutions to verify are to feed a testsignal and view it on an oscilloscope or spectrum analyser.
The range on OS X for 32 bit floating point samples is -1.0f to 1.0f. The negative numbers are there because the (row of) samples describe an analog waveform signal.
To verify the validity of the data I would suggest to play it back so you can hear if the data is correct.
More complex solutions to verify are to feed a testsignal and view it on an oscilloscope or spectrum analyser.
answered Mar 10 at 7:45
Ruurd AdemaRuurd Adema
1689
1689
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