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FullCalendar: show reversed list views
2019 Community Moderator Electionfullcalendar - display half-day event in the month viewFullCalendar month view is only showing events for the current monthFullCalendar View More Button movingView specific event in FullCalendarfullcalendar: allDay events not listed in the agendaWeekFullcalendar shows wrong day in month viewFullcalendar eventDrop with Timeline ViewOnly show upcoming events in fullcalendar list viewFullCalendar Events show in month and list, but not week and dayIs there a way to have FullCalendar start at closest date in listYear view?
How can I reverse the events in the list views, so that the event with the most futuristic date appears at the beginning (top)?
fullcalendar
asked Sep 1 '17 at 20:12
Daniel FDaniel F
6,61345067
add a comment |
How can I reverse the events in the list views, so that the event with the most futuristic date appears at the beginning (top)?
fullcalendar
asked Sep 1 '17 at 20:12
Daniel FDaniel F
6,61345067
There's no built-in option for this, so you could either modify the fullCalendar source code to do what you want, or create your own custom view (fullcalendar.io/docs/views/Custom_Views, not a quick task). Failing that you could probably make it as a feature request to the maintainer, via GitHub.
– ADyson
Sep 3 '17 at 6:27
add a comment |
How can I reverse the events in the list views, so that the event with the most futuristic date appears at the beginning (top)?
fullcalendar
asked Sep 1 '17 at 20:12
Daniel FDaniel F
6,61345067
How can I reverse the events in the list views, so that the event with the most futuristic date appears at the beginning (top)?
fullcalendar
fullcalendar
asked Sep 1 '17 at 20:12
Daniel FDaniel F
6,61345067
asked Sep 1 '17 at 20:12
Daniel FDaniel F
6,61345067
asked Sep 1 '17 at 20:12
Daniel FDaniel F
6,61345067
asked Sep 1 '17 at 20:12
Daniel FDaniel F
6,61345067
asked Sep 1 '17 at 20:12
Daniel FDaniel F
6,61345067
6,61345067
There's no built-in option for this, so you could either modify the fullCalendar source code to do what you want, or create your own custom view (fullcalendar.io/docs/views/Custom_Views, not a quick task). Failing that you could probably make it as a feature request to the maintainer, via GitHub.
– ADyson
Sep 3 '17 at 6:27
add a comment |
There's no built-in option for this, so you could either modify the fullCalendar source code to do what you want, or create your own custom view (fullcalendar.io/docs/views/Custom_Views, not a quick task). Failing that you could probably make it as a feature request to the maintainer, via GitHub.
– ADyson
Sep 3 '17 at 6:27
There's no built-in option for this, so you could either modify the fullCalendar source code to do what you want, or create your own custom view (fullcalendar.io/docs/views/Custom_Views, not a quick task). Failing that you could probably make it as a feature request to the maintainer, via GitHub.
– ADyson
Sep 3 '17 at 6:27
There's no built-in option for this, so you could either modify the fullCalendar source code to do what you want, or create your own custom view (fullcalendar.io/docs/views/Custom_Views, not a quick task). Failing that you could probably make it as a feature request to the maintainer, via GitHub.
– ADyson
Sep 3 '17 at 6:27
add a comment |
2 Answers
2
active
oldest
votes
For anyone still looking for this, inverted event lists using jquery:
eventAfterAllRender: function(view)
var eventosRendered = $('#timeline tr');
var eventosInversa = [];
var headingPendiente = null;
eventosRendered.map(function(key, evento)
switch(evento.className)
case 'fc-list-heading':
if (headingPendiente)
eventosInversa.unshift(headingPendiente);
headingPendiente = evento;
break;
case 'fc-list-item':
eventosInversa.unshift(evento);
break;
);
eventosInversa.unshift(headingPendiente);
$('#timeline tbody').append(eventosInversa);
answered Jun 27 '18 at 15:30
F. MoraF. Mora
61
add a comment |
@F.Mora your solution is almost perfect but in our case we add some custom classNames and have multiple items under each headline.
Here is our enhanced version :
eventAfterAllRender: function(view)
var renderedEvents = $('.fc-list-table tr');
var reorderedEvents = [];
var blockEvents = null;
renderedEvents.map(function(key, event)
if ($(event).hasClass('fc-list-heading'))
if (blockEvents)
reorderedEvents.unshift(blockEvents.children());
blockEvents = $('<tbody></tbody>');
blockEvents.append(event);
);
reorderedEvents.unshift(blockEvents.children());
$('.fc-list-table tbody').html(reorderedEvents);
answered Mar 6 at 14:32
Yo1Yo1
11114
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
For anyone still looking for this, inverted event lists using jquery:
eventAfterAllRender: function(view)
var eventosRendered = $('#timeline tr');
var eventosInversa = [];
var headingPendiente = null;
eventosRendered.map(function(key, evento)
switch(evento.className)
case 'fc-list-heading':
if (headingPendiente)
eventosInversa.unshift(headingPendiente);
headingPendiente = evento;
break;
case 'fc-list-item':
eventosInversa.unshift(evento);
break;
);
eventosInversa.unshift(headingPendiente);
$('#timeline tbody').append(eventosInversa);
answered Jun 27 '18 at 15:30
F. MoraF. Mora
61
add a comment |
For anyone still looking for this, inverted event lists using jquery:
eventAfterAllRender: function(view)
var eventosRendered = $('#timeline tr');
var eventosInversa = [];
var headingPendiente = null;
eventosRendered.map(function(key, evento)
switch(evento.className)
case 'fc-list-heading':
if (headingPendiente)
eventosInversa.unshift(headingPendiente);
headingPendiente = evento;
break;
case 'fc-list-item':
eventosInversa.unshift(evento);
break;
);
eventosInversa.unshift(headingPendiente);
$('#timeline tbody').append(eventosInversa);
answered Jun 27 '18 at 15:30
F. MoraF. Mora
61
add a comment |
For anyone still looking for this, inverted event lists using jquery:
eventAfterAllRender: function(view)
var eventosRendered = $('#timeline tr');
var eventosInversa = [];
var headingPendiente = null;
eventosRendered.map(function(key, evento)
switch(evento.className)
case 'fc-list-heading':
if (headingPendiente)
eventosInversa.unshift(headingPendiente);
headingPendiente = evento;
break;
case 'fc-list-item':
eventosInversa.unshift(evento);
break;
);
eventosInversa.unshift(headingPendiente);
$('#timeline tbody').append(eventosInversa);
answered Jun 27 '18 at 15:30
F. MoraF. Mora
61
For anyone still looking for this, inverted event lists using jquery:
eventAfterAllRender: function(view)
var eventosRendered = $('#timeline tr');
var eventosInversa = [];
var headingPendiente = null;
eventosRendered.map(function(key, evento)
switch(evento.className)
case 'fc-list-heading':
if (headingPendiente)
eventosInversa.unshift(headingPendiente);
headingPendiente = evento;
break;
case 'fc-list-item':
eventosInversa.unshift(evento);
break;
);
eventosInversa.unshift(headingPendiente);
$('#timeline tbody').append(eventosInversa);
answered Jun 27 '18 at 15:30
F. MoraF. Mora
61
answered Jun 27 '18 at 15:30
F. MoraF. Mora
61
answered Jun 27 '18 at 15:30
F. MoraF. Mora
61
answered Jun 27 '18 at 15:30
F. MoraF. Mora
61
61
add a comment |
add a comment |
@F.Mora your solution is almost perfect but in our case we add some custom classNames and have multiple items under each headline.
Here is our enhanced version :
eventAfterAllRender: function(view)
var renderedEvents = $('.fc-list-table tr');
var reorderedEvents = [];
var blockEvents = null;
renderedEvents.map(function(key, event)
if ($(event).hasClass('fc-list-heading'))
if (blockEvents)
reorderedEvents.unshift(blockEvents.children());
blockEvents = $('<tbody></tbody>');
blockEvents.append(event);
);
reorderedEvents.unshift(blockEvents.children());
$('.fc-list-table tbody').html(reorderedEvents);
answered Mar 6 at 14:32
Yo1Yo1
11114
add a comment |
@F.Mora your solution is almost perfect but in our case we add some custom classNames and have multiple items under each headline.
Here is our enhanced version :
eventAfterAllRender: function(view)
var renderedEvents = $('.fc-list-table tr');
var reorderedEvents = [];
var blockEvents = null;
renderedEvents.map(function(key, event)
if ($(event).hasClass('fc-list-heading'))
if (blockEvents)
reorderedEvents.unshift(blockEvents.children());
blockEvents = $('<tbody></tbody>');
blockEvents.append(event);
);
reorderedEvents.unshift(blockEvents.children());
$('.fc-list-table tbody').html(reorderedEvents);
answered Mar 6 at 14:32
Yo1Yo1
11114
add a comment |
@F.Mora your solution is almost perfect but in our case we add some custom classNames and have multiple items under each headline.
Here is our enhanced version :
eventAfterAllRender: function(view)
var renderedEvents = $('.fc-list-table tr');
var reorderedEvents = [];
var blockEvents = null;
renderedEvents.map(function(key, event)
if ($(event).hasClass('fc-list-heading'))
if (blockEvents)
reorderedEvents.unshift(blockEvents.children());
blockEvents = $('<tbody></tbody>');
blockEvents.append(event);
);
reorderedEvents.unshift(blockEvents.children());
$('.fc-list-table tbody').html(reorderedEvents);
answered Mar 6 at 14:32
Yo1Yo1
11114
@F.Mora your solution is almost perfect but in our case we add some custom classNames and have multiple items under each headline.
Here is our enhanced version :
eventAfterAllRender: function(view)
var renderedEvents = $('.fc-list-table tr');
var reorderedEvents = [];
var blockEvents = null;
renderedEvents.map(function(key, event)
if ($(event).hasClass('fc-list-heading'))
if (blockEvents)
reorderedEvents.unshift(blockEvents.children());
blockEvents = $('<tbody></tbody>');
blockEvents.append(event);
);
reorderedEvents.unshift(blockEvents.children());
$('.fc-list-table tbody').html(reorderedEvents);
answered Mar 6 at 14:32
Yo1Yo1
11114
edited Mar 6 at 15:23
answered Mar 6 at 14:32
Yo1Yo1
11114
answered Mar 6 at 14:32
Yo1Yo1
11114
answered Mar 6 at 14:32
Yo1Yo1
11114
11114
add a comment |
add a comment |
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There's no built-in option for this, so you could either modify the fullCalendar source code to do what you want, or create your own custom view (fullcalendar.io/docs/views/Custom_Views, not a quick task). Failing that you could probably make it as a feature request to the maintainer, via GitHub.
– ADyson
Sep 3 '17 at 6:27