Get RSA Public or Private Key from KeyPair Generation Flutter Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) The Ask Question Wizard is Live! Data science time! April 2019 and salary with experience Should we burninate the [wrap] tag?Public & Private Keys in .NET besides RSAUse RSA private key to generate public key?How can I get the private key from an RSA public key?Can we have multiple public keys with a single private key for RSA?RSA Public Key formatJava - Public-private key encryption - how to calculate private key in RSAprivate/public key ssh-keygen -t rsaComputing private key of a user from his RSA public keyGenerate RSA Public Key from Modulus and ExponentFlutter - How can I generate a private/public key pair to encrypt messages
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Get RSA Public or Private Key from KeyPair Generation Flutter
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
The Ask Question Wizard is Live!
Data science time! April 2019 and salary with experience
Should we burninate the [wrap] tag?Public & Private Keys in .NET besides RSAUse RSA private key to generate public key?How can I get the private key from an RSA public key?Can we have multiple public keys with a single private key for RSA?RSA Public Key formatJava - Public-private key encryption - how to calculate private key in RSAprivate/public key ssh-keygen -t rsaComputing private key of a user from his RSA public keyGenerate RSA Public Key from Modulus and ExponentFlutter - How can I generate a private/public key pair to encrypt messages
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I have added pointycastle and generated a keypair, encrypting the trial "Hello World" string. From this, I want to get the values of the Private and Public Key. Is there anywhere they are stored, because whenever I try to print the values of keyPair.privateKey, it returns Instance of 'RSAPrivateKey.
Here is the code I used
var keyParams = new RSAKeyGeneratorParameters(new BigInt.from(65537), 2048, 5);
var secureRandom = new FortunaRandom();
var random = new Random.secure();
List<int> seeds = [];
for (int i = 0; i < 32; i++)
seeds.add(random.nextInt(255));
secureRandom.seed(new KeyParameter(new Uint8List.fromList(seeds)));
var rngParams = new ParametersWithRandom(keyParams, secureRandom);
var k = new RSAKeyGenerator();
k.init(rngParams);
var keyPair = k.generateKeyPair();
var cipher = new RSAEngine()..init( true, new PublicKeyParameter<RSAPublicKey>(keyPair.publicKey));
print("pubkey: $keyPair.publicKey.toString()");
var cipherText = cipher.process(new Uint8List.fromList("Hello World".codeUnits));
print("Encrypted: $new String.fromCharCodes(cipherText)");
cipher.init( false, new PrivateKeyParameter<RSAPrivateKey>(keyPair.privateKey));
//cipher.init( false, new PrivateKeyParameter(keyPair.privateKey) )
var decrypted = cipher.process(cipherText);
print("Decrypted: $new String.fromCharCodes(decrypted)");
dart
add a comment |
I have added pointycastle and generated a keypair, encrypting the trial "Hello World" string. From this, I want to get the values of the Private and Public Key. Is there anywhere they are stored, because whenever I try to print the values of keyPair.privateKey, it returns Instance of 'RSAPrivateKey.
Here is the code I used
var keyParams = new RSAKeyGeneratorParameters(new BigInt.from(65537), 2048, 5);
var secureRandom = new FortunaRandom();
var random = new Random.secure();
List<int> seeds = [];
for (int i = 0; i < 32; i++)
seeds.add(random.nextInt(255));
secureRandom.seed(new KeyParameter(new Uint8List.fromList(seeds)));
var rngParams = new ParametersWithRandom(keyParams, secureRandom);
var k = new RSAKeyGenerator();
k.init(rngParams);
var keyPair = k.generateKeyPair();
var cipher = new RSAEngine()..init( true, new PublicKeyParameter<RSAPublicKey>(keyPair.publicKey));
print("pubkey: $keyPair.publicKey.toString()");
var cipherText = cipher.process(new Uint8List.fromList("Hello World".codeUnits));
print("Encrypted: $new String.fromCharCodes(cipherText)");
cipher.init( false, new PrivateKeyParameter<RSAPrivateKey>(keyPair.privateKey));
//cipher.init( false, new PrivateKeyParameter(keyPair.privateKey) )
var decrypted = cipher.process(cipherText);
print("Decrypted: $new String.fromCharCodes(decrypted)");
dart
Did you try keyPair.privateKey.toString() ?
– Mazin Ibrahim
Mar 8 at 16:17
@MazinIbrahim yes, that returns the sameInstance of RSAPrivateKey
– Epic Gamer_1
Mar 8 at 16:33
This package is poorly documented.I suggest you take a look inside their github code to figure out how to convertRSAPrivateKeyto a readable form.
– Mazin Ibrahim
Mar 8 at 16:41
@MazinIbrahim I have tried, but I can't see anything converting it into a readable form. I've tried looking in their Object, as well its generation function, but in there it still shows the same instance output
– Epic Gamer_1
Mar 8 at 16:55
add a comment |
I have added pointycastle and generated a keypair, encrypting the trial "Hello World" string. From this, I want to get the values of the Private and Public Key. Is there anywhere they are stored, because whenever I try to print the values of keyPair.privateKey, it returns Instance of 'RSAPrivateKey.
Here is the code I used
var keyParams = new RSAKeyGeneratorParameters(new BigInt.from(65537), 2048, 5);
var secureRandom = new FortunaRandom();
var random = new Random.secure();
List<int> seeds = [];
for (int i = 0; i < 32; i++)
seeds.add(random.nextInt(255));
secureRandom.seed(new KeyParameter(new Uint8List.fromList(seeds)));
var rngParams = new ParametersWithRandom(keyParams, secureRandom);
var k = new RSAKeyGenerator();
k.init(rngParams);
var keyPair = k.generateKeyPair();
var cipher = new RSAEngine()..init( true, new PublicKeyParameter<RSAPublicKey>(keyPair.publicKey));
print("pubkey: $keyPair.publicKey.toString()");
var cipherText = cipher.process(new Uint8List.fromList("Hello World".codeUnits));
print("Encrypted: $new String.fromCharCodes(cipherText)");
cipher.init( false, new PrivateKeyParameter<RSAPrivateKey>(keyPair.privateKey));
//cipher.init( false, new PrivateKeyParameter(keyPair.privateKey) )
var decrypted = cipher.process(cipherText);
print("Decrypted: $new String.fromCharCodes(decrypted)");
dart
I have added pointycastle and generated a keypair, encrypting the trial "Hello World" string. From this, I want to get the values of the Private and Public Key. Is there anywhere they are stored, because whenever I try to print the values of keyPair.privateKey, it returns Instance of 'RSAPrivateKey.
Here is the code I used
var keyParams = new RSAKeyGeneratorParameters(new BigInt.from(65537), 2048, 5);
var secureRandom = new FortunaRandom();
var random = new Random.secure();
List<int> seeds = [];
for (int i = 0; i < 32; i++)
seeds.add(random.nextInt(255));
secureRandom.seed(new KeyParameter(new Uint8List.fromList(seeds)));
var rngParams = new ParametersWithRandom(keyParams, secureRandom);
var k = new RSAKeyGenerator();
k.init(rngParams);
var keyPair = k.generateKeyPair();
var cipher = new RSAEngine()..init( true, new PublicKeyParameter<RSAPublicKey>(keyPair.publicKey));
print("pubkey: $keyPair.publicKey.toString()");
var cipherText = cipher.process(new Uint8List.fromList("Hello World".codeUnits));
print("Encrypted: $new String.fromCharCodes(cipherText)");
cipher.init( false, new PrivateKeyParameter<RSAPrivateKey>(keyPair.privateKey));
//cipher.init( false, new PrivateKeyParameter(keyPair.privateKey) )
var decrypted = cipher.process(cipherText);
print("Decrypted: $new String.fromCharCodes(decrypted)");
dart
dart
asked Mar 8 at 16:08
Epic Gamer_1Epic Gamer_1
3029
3029
Did you try keyPair.privateKey.toString() ?
– Mazin Ibrahim
Mar 8 at 16:17
@MazinIbrahim yes, that returns the sameInstance of RSAPrivateKey
– Epic Gamer_1
Mar 8 at 16:33
This package is poorly documented.I suggest you take a look inside their github code to figure out how to convertRSAPrivateKeyto a readable form.
– Mazin Ibrahim
Mar 8 at 16:41
@MazinIbrahim I have tried, but I can't see anything converting it into a readable form. I've tried looking in their Object, as well its generation function, but in there it still shows the same instance output
– Epic Gamer_1
Mar 8 at 16:55
add a comment |
Did you try keyPair.privateKey.toString() ?
– Mazin Ibrahim
Mar 8 at 16:17
@MazinIbrahim yes, that returns the sameInstance of RSAPrivateKey
– Epic Gamer_1
Mar 8 at 16:33
This package is poorly documented.I suggest you take a look inside their github code to figure out how to convertRSAPrivateKeyto a readable form.
– Mazin Ibrahim
Mar 8 at 16:41
@MazinIbrahim I have tried, but I can't see anything converting it into a readable form. I've tried looking in their Object, as well its generation function, but in there it still shows the same instance output
– Epic Gamer_1
Mar 8 at 16:55
Did you try keyPair.privateKey.toString() ?
– Mazin Ibrahim
Mar 8 at 16:17
Did you try keyPair.privateKey.toString() ?
– Mazin Ibrahim
Mar 8 at 16:17
@MazinIbrahim yes, that returns the same
Instance of RSAPrivateKey– Epic Gamer_1
Mar 8 at 16:33
@MazinIbrahim yes, that returns the same
Instance of RSAPrivateKey– Epic Gamer_1
Mar 8 at 16:33
This package is poorly documented.I suggest you take a look inside their github code to figure out how to convert
RSAPrivateKey to a readable form.– Mazin Ibrahim
Mar 8 at 16:41
This package is poorly documented.I suggest you take a look inside their github code to figure out how to convert
RSAPrivateKey to a readable form.– Mazin Ibrahim
Mar 8 at 16:41
@MazinIbrahim I have tried, but I can't see anything converting it into a readable form. I've tried looking in their Object, as well its generation function, but in there it still shows the same instance output
– Epic Gamer_1
Mar 8 at 16:55
@MazinIbrahim I have tried, but I can't see anything converting it into a readable form. I've tried looking in their Object, as well its generation function, but in there it still shows the same instance output
– Epic Gamer_1
Mar 8 at 16:55
add a comment |
1 Answer
1
active
oldest
votes
Make sure to import package:pointycastle/asymmetric/api.dart, then use:
var k = RSAKeyGenerator()..init(rngParams);
AsymmetricKeyPair<PublicKey, PrivateKey> keyPair = k.generateKeyPair();
RSAPrivateKey privateKey = keyPair.privateKey;
RSAPublicKey publicKey = keyPair.publicKey;
print(privateKey.d); // prints private exponent
print(publicKey.n); // prints modulus
Recreate from the individual parts:
RSAPrivateKey foo = RSAPrivateKey(
privateKey.n,
privateKey.d,
privateKey.p,
privateKey.q,
);
RSAPublicKey bar = RSAPublicKey(publicKey.n, publicKey.e);
From this, can i recreate a key from just the modulus of public key and exponent of private key?
– Epic Gamer_1
Mar 19 at 16:38
Both need the modulus and exponent. The private key also needspandq. Check the constructors ofRSAPrivateKeyandRSAPublicKey.
– Richard Heap
Mar 19 at 16:59
I know you can do that, but from the value of the key, can you make it? (From a single key value?)
– Epic Gamer_1
Mar 19 at 19:27
It doesn't look like it, but try it by supplying dummy values instead. (Incidentally, PKCS#1 format includespandqso if you're storing your key using that format you'll have those numbers available.)
– Richard Heap
Mar 19 at 21:31
also, can I generate a .pem file for this?
– Epic Gamer_1
Mar 20 at 11:12
|
show 2 more comments
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1 Answer
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votes
Make sure to import package:pointycastle/asymmetric/api.dart, then use:
var k = RSAKeyGenerator()..init(rngParams);
AsymmetricKeyPair<PublicKey, PrivateKey> keyPair = k.generateKeyPair();
RSAPrivateKey privateKey = keyPair.privateKey;
RSAPublicKey publicKey = keyPair.publicKey;
print(privateKey.d); // prints private exponent
print(publicKey.n); // prints modulus
Recreate from the individual parts:
RSAPrivateKey foo = RSAPrivateKey(
privateKey.n,
privateKey.d,
privateKey.p,
privateKey.q,
);
RSAPublicKey bar = RSAPublicKey(publicKey.n, publicKey.e);
From this, can i recreate a key from just the modulus of public key and exponent of private key?
– Epic Gamer_1
Mar 19 at 16:38
Both need the modulus and exponent. The private key also needspandq. Check the constructors ofRSAPrivateKeyandRSAPublicKey.
– Richard Heap
Mar 19 at 16:59
I know you can do that, but from the value of the key, can you make it? (From a single key value?)
– Epic Gamer_1
Mar 19 at 19:27
It doesn't look like it, but try it by supplying dummy values instead. (Incidentally, PKCS#1 format includespandqso if you're storing your key using that format you'll have those numbers available.)
– Richard Heap
Mar 19 at 21:31
also, can I generate a .pem file for this?
– Epic Gamer_1
Mar 20 at 11:12
|
show 2 more comments
Make sure to import package:pointycastle/asymmetric/api.dart, then use:
var k = RSAKeyGenerator()..init(rngParams);
AsymmetricKeyPair<PublicKey, PrivateKey> keyPair = k.generateKeyPair();
RSAPrivateKey privateKey = keyPair.privateKey;
RSAPublicKey publicKey = keyPair.publicKey;
print(privateKey.d); // prints private exponent
print(publicKey.n); // prints modulus
Recreate from the individual parts:
RSAPrivateKey foo = RSAPrivateKey(
privateKey.n,
privateKey.d,
privateKey.p,
privateKey.q,
);
RSAPublicKey bar = RSAPublicKey(publicKey.n, publicKey.e);
From this, can i recreate a key from just the modulus of public key and exponent of private key?
– Epic Gamer_1
Mar 19 at 16:38
Both need the modulus and exponent. The private key also needspandq. Check the constructors ofRSAPrivateKeyandRSAPublicKey.
– Richard Heap
Mar 19 at 16:59
I know you can do that, but from the value of the key, can you make it? (From a single key value?)
– Epic Gamer_1
Mar 19 at 19:27
It doesn't look like it, but try it by supplying dummy values instead. (Incidentally, PKCS#1 format includespandqso if you're storing your key using that format you'll have those numbers available.)
– Richard Heap
Mar 19 at 21:31
also, can I generate a .pem file for this?
– Epic Gamer_1
Mar 20 at 11:12
|
show 2 more comments
Make sure to import package:pointycastle/asymmetric/api.dart, then use:
var k = RSAKeyGenerator()..init(rngParams);
AsymmetricKeyPair<PublicKey, PrivateKey> keyPair = k.generateKeyPair();
RSAPrivateKey privateKey = keyPair.privateKey;
RSAPublicKey publicKey = keyPair.publicKey;
print(privateKey.d); // prints private exponent
print(publicKey.n); // prints modulus
Recreate from the individual parts:
RSAPrivateKey foo = RSAPrivateKey(
privateKey.n,
privateKey.d,
privateKey.p,
privateKey.q,
);
RSAPublicKey bar = RSAPublicKey(publicKey.n, publicKey.e);
Make sure to import package:pointycastle/asymmetric/api.dart, then use:
var k = RSAKeyGenerator()..init(rngParams);
AsymmetricKeyPair<PublicKey, PrivateKey> keyPair = k.generateKeyPair();
RSAPrivateKey privateKey = keyPair.privateKey;
RSAPublicKey publicKey = keyPair.publicKey;
print(privateKey.d); // prints private exponent
print(publicKey.n); // prints modulus
Recreate from the individual parts:
RSAPrivateKey foo = RSAPrivateKey(
privateKey.n,
privateKey.d,
privateKey.p,
privateKey.q,
);
RSAPublicKey bar = RSAPublicKey(publicKey.n, publicKey.e);
edited Mar 19 at 17:35
answered Mar 8 at 17:31
Richard HeapRichard Heap
8,13521120
8,13521120
From this, can i recreate a key from just the modulus of public key and exponent of private key?
– Epic Gamer_1
Mar 19 at 16:38
Both need the modulus and exponent. The private key also needspandq. Check the constructors ofRSAPrivateKeyandRSAPublicKey.
– Richard Heap
Mar 19 at 16:59
I know you can do that, but from the value of the key, can you make it? (From a single key value?)
– Epic Gamer_1
Mar 19 at 19:27
It doesn't look like it, but try it by supplying dummy values instead. (Incidentally, PKCS#1 format includespandqso if you're storing your key using that format you'll have those numbers available.)
– Richard Heap
Mar 19 at 21:31
also, can I generate a .pem file for this?
– Epic Gamer_1
Mar 20 at 11:12
|
show 2 more comments
From this, can i recreate a key from just the modulus of public key and exponent of private key?
– Epic Gamer_1
Mar 19 at 16:38
Both need the modulus and exponent. The private key also needspandq. Check the constructors ofRSAPrivateKeyandRSAPublicKey.
– Richard Heap
Mar 19 at 16:59
I know you can do that, but from the value of the key, can you make it? (From a single key value?)
– Epic Gamer_1
Mar 19 at 19:27
It doesn't look like it, but try it by supplying dummy values instead. (Incidentally, PKCS#1 format includespandqso if you're storing your key using that format you'll have those numbers available.)
– Richard Heap
Mar 19 at 21:31
also, can I generate a .pem file for this?
– Epic Gamer_1
Mar 20 at 11:12
From this, can i recreate a key from just the modulus of public key and exponent of private key?
– Epic Gamer_1
Mar 19 at 16:38
From this, can i recreate a key from just the modulus of public key and exponent of private key?
– Epic Gamer_1
Mar 19 at 16:38
Both need the modulus and exponent. The private key also needs
p and q. Check the constructors of RSAPrivateKey and RSAPublicKey.– Richard Heap
Mar 19 at 16:59
Both need the modulus and exponent. The private key also needs
p and q. Check the constructors of RSAPrivateKey and RSAPublicKey.– Richard Heap
Mar 19 at 16:59
I know you can do that, but from the value of the key, can you make it? (From a single key value?)
– Epic Gamer_1
Mar 19 at 19:27
I know you can do that, but from the value of the key, can you make it? (From a single key value?)
– Epic Gamer_1
Mar 19 at 19:27
It doesn't look like it, but try it by supplying dummy values instead. (Incidentally, PKCS#1 format includes
p and q so if you're storing your key using that format you'll have those numbers available.)– Richard Heap
Mar 19 at 21:31
It doesn't look like it, but try it by supplying dummy values instead. (Incidentally, PKCS#1 format includes
p and q so if you're storing your key using that format you'll have those numbers available.)– Richard Heap
Mar 19 at 21:31
also, can I generate a .pem file for this?
– Epic Gamer_1
Mar 20 at 11:12
also, can I generate a .pem file for this?
– Epic Gamer_1
Mar 20 at 11:12
|
show 2 more comments
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Did you try keyPair.privateKey.toString() ?
– Mazin Ibrahim
Mar 8 at 16:17
@MazinIbrahim yes, that returns the same
Instance of RSAPrivateKey– Epic Gamer_1
Mar 8 at 16:33
This package is poorly documented.I suggest you take a look inside their github code to figure out how to convert
RSAPrivateKeyto a readable form.– Mazin Ibrahim
Mar 8 at 16:41
@MazinIbrahim I have tried, but I can't see anything converting it into a readable form. I've tried looking in their Object, as well its generation function, but in there it still shows the same instance output
– Epic Gamer_1
Mar 8 at 16:55