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regex: replace dynamically a searched word
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Data science time! April 2019 and salary with experience
The Ask Question Wizard is Live!A comprehensive regex for phone number validationHow can I merge properties of two JavaScript objects dynamically?Event binding on dynamically created elements?Regular expression to match a line that doesn't contain a wordInteractive search/replace regex in Vim?Converting user input string to regular expressionHow to replace all occurrences of a string in JavaScriptHow to negate specific word in regex?RegEx match open tags except XHTML self-contained tagsPython string.replace regular expression
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I want to replace file:///Downloads/project
by a another word like a github link :
const string = 'file:///Downloads/project/users/controllers/users/controller.js';
I tried working with .replace a world by a world but i got in the problem that file:///Downloads/project
is a dynamic value that may change from time to time.
string.replace(/file://Downloads/project/users/controller.js/gi, 'https://gitlab.com')
So i want to search for the word project
and replace from it backward by another path or word
javascript regex
add a comment |
I want to replace file:///Downloads/project
by a another word like a github link :
const string = 'file:///Downloads/project/users/controllers/users/controller.js';
I tried working with .replace a world by a world but i got in the problem that file:///Downloads/project
is a dynamic value that may change from time to time.
string.replace(/file://Downloads/project/users/controller.js/gi, 'https://gitlab.com')
So i want to search for the word project
and replace from it backward by another path or word
javascript regex
1
why do you need regex?
– alfasin
Mar 8 at 21:49
i'm reading about some way of replacing a substring by regex so i think that's the only ways instead of writing a whole function
– brxnzaz
Mar 8 at 21:51
string.replace('file:///Downloads/project', 'mynewvalue')
– Isaac Vidrine
Mar 8 at 21:51
add a comment |
I want to replace file:///Downloads/project
by a another word like a github link :
const string = 'file:///Downloads/project/users/controllers/users/controller.js';
I tried working with .replace a world by a world but i got in the problem that file:///Downloads/project
is a dynamic value that may change from time to time.
string.replace(/file://Downloads/project/users/controller.js/gi, 'https://gitlab.com')
So i want to search for the word project
and replace from it backward by another path or word
javascript regex
I want to replace file:///Downloads/project
by a another word like a github link :
const string = 'file:///Downloads/project/users/controllers/users/controller.js';
I tried working with .replace a world by a world but i got in the problem that file:///Downloads/project
is a dynamic value that may change from time to time.
string.replace(/file://Downloads/project/users/controller.js/gi, 'https://gitlab.com')
So i want to search for the word project
and replace from it backward by another path or word
javascript regex
javascript regex
asked Mar 8 at 21:47
brxnzazbrxnzaz
1248
1248
1
why do you need regex?
– alfasin
Mar 8 at 21:49
i'm reading about some way of replacing a substring by regex so i think that's the only ways instead of writing a whole function
– brxnzaz
Mar 8 at 21:51
string.replace('file:///Downloads/project', 'mynewvalue')
– Isaac Vidrine
Mar 8 at 21:51
add a comment |
1
why do you need regex?
– alfasin
Mar 8 at 21:49
i'm reading about some way of replacing a substring by regex so i think that's the only ways instead of writing a whole function
– brxnzaz
Mar 8 at 21:51
string.replace('file:///Downloads/project', 'mynewvalue')
– Isaac Vidrine
Mar 8 at 21:51
1
1
why do you need regex?
– alfasin
Mar 8 at 21:49
why do you need regex?
– alfasin
Mar 8 at 21:49
i'm reading about some way of replacing a substring by regex so i think that's the only ways instead of writing a whole function
– brxnzaz
Mar 8 at 21:51
i'm reading about some way of replacing a substring by regex so i think that's the only ways instead of writing a whole function
– brxnzaz
Mar 8 at 21:51
string.replace('file:///Downloads/project', 'mynewvalue')
– Isaac Vidrine
Mar 8 at 21:51
string.replace('file:///Downloads/project', 'mynewvalue')
– Isaac Vidrine
Mar 8 at 21:51
add a comment |
4 Answers
4
active
oldest
votes
To achieve expected result, use below option of using indexOf and substr and finally replacing with gitlab url
- Get index of project
- Get string from 0 to index of project
- Replace string from step 2 with gitlab using replace option
const string = 'file:///Downloads/project/users/controllers/users/controller.js';
const index = string.indexOf('project')
console.log(string.replace(string.substr(0, index), 'https://gitlab.com/'))
codepen - https://codepen.io/nagasai/pen/qvjdEa?editors=1010
add a comment |
Using regex you can match the first group which includes /project
and replace the first parenthesized capture group with your https://gitlab.com
. Here p1
denotes first parenthesized capture group and p2
denotes second parenthesized capture group.
const str = 'file:///Downloads/project/users/controllers/users/controller.js';
const res = str.replace(/^(.|/)+w*project(.+)*/gi, function(match, p1, p2)
return 'https://gitlab.com' + p2;
);
console.log(res);
add a comment |
you don't need a regex for that
const string = 'file:///Downloads/project/users/controllers/users/controller.js',
yourValue = "file:///Downloads/project/",
res = string.replace(yourValue, "https://gitlab.com/")
console.log(res)
i retreive string dynamically so the value file:///Downloads/project changes
– brxnzaz
Mar 8 at 21:52
same thing i updated my answer
– G.aziz
Mar 8 at 21:53
add a comment |
'https://gitlab.com/' + string.substr(string.indexOf('project'))
First find the position of 'project' in your string
string.indexOf('project')
then get a substring from that position to the end of the string (substr goes till the end when no second arg is provided)
string.substring(indexOfProject)
then concat it with '+'. Note that the url ends with '/' because your string will begin with 'p'.
'https://gitlab.com/' + extractedString
1
Please explain your answer.
– Wai Ha Lee
Mar 9 at 1:05
add a comment |
Your Answer
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
To achieve expected result, use below option of using indexOf and substr and finally replacing with gitlab url
- Get index of project
- Get string from 0 to index of project
- Replace string from step 2 with gitlab using replace option
const string = 'file:///Downloads/project/users/controllers/users/controller.js';
const index = string.indexOf('project')
console.log(string.replace(string.substr(0, index), 'https://gitlab.com/'))
codepen - https://codepen.io/nagasai/pen/qvjdEa?editors=1010
add a comment |
To achieve expected result, use below option of using indexOf and substr and finally replacing with gitlab url
- Get index of project
- Get string from 0 to index of project
- Replace string from step 2 with gitlab using replace option
const string = 'file:///Downloads/project/users/controllers/users/controller.js';
const index = string.indexOf('project')
console.log(string.replace(string.substr(0, index), 'https://gitlab.com/'))
codepen - https://codepen.io/nagasai/pen/qvjdEa?editors=1010
add a comment |
To achieve expected result, use below option of using indexOf and substr and finally replacing with gitlab url
- Get index of project
- Get string from 0 to index of project
- Replace string from step 2 with gitlab using replace option
const string = 'file:///Downloads/project/users/controllers/users/controller.js';
const index = string.indexOf('project')
console.log(string.replace(string.substr(0, index), 'https://gitlab.com/'))
codepen - https://codepen.io/nagasai/pen/qvjdEa?editors=1010
To achieve expected result, use below option of using indexOf and substr and finally replacing with gitlab url
- Get index of project
- Get string from 0 to index of project
- Replace string from step 2 with gitlab using replace option
const string = 'file:///Downloads/project/users/controllers/users/controller.js';
const index = string.indexOf('project')
console.log(string.replace(string.substr(0, index), 'https://gitlab.com/'))
codepen - https://codepen.io/nagasai/pen/qvjdEa?editors=1010
const string = 'file:///Downloads/project/users/controllers/users/controller.js';
const index = string.indexOf('project')
console.log(string.replace(string.substr(0, index), 'https://gitlab.com/'))
const string = 'file:///Downloads/project/users/controllers/users/controller.js';
const index = string.indexOf('project')
console.log(string.replace(string.substr(0, index), 'https://gitlab.com/'))
edited Mar 8 at 22:01
answered Mar 8 at 21:53
Naga Sai ANaga Sai A
6,4111927
6,4111927
add a comment |
add a comment |
Using regex you can match the first group which includes /project
and replace the first parenthesized capture group with your https://gitlab.com
. Here p1
denotes first parenthesized capture group and p2
denotes second parenthesized capture group.
const str = 'file:///Downloads/project/users/controllers/users/controller.js';
const res = str.replace(/^(.|/)+w*project(.+)*/gi, function(match, p1, p2)
return 'https://gitlab.com' + p2;
);
console.log(res);
add a comment |
Using regex you can match the first group which includes /project
and replace the first parenthesized capture group with your https://gitlab.com
. Here p1
denotes first parenthesized capture group and p2
denotes second parenthesized capture group.
const str = 'file:///Downloads/project/users/controllers/users/controller.js';
const res = str.replace(/^(.|/)+w*project(.+)*/gi, function(match, p1, p2)
return 'https://gitlab.com' + p2;
);
console.log(res);
add a comment |
Using regex you can match the first group which includes /project
and replace the first parenthesized capture group with your https://gitlab.com
. Here p1
denotes first parenthesized capture group and p2
denotes second parenthesized capture group.
const str = 'file:///Downloads/project/users/controllers/users/controller.js';
const res = str.replace(/^(.|/)+w*project(.+)*/gi, function(match, p1, p2)
return 'https://gitlab.com' + p2;
);
console.log(res);
Using regex you can match the first group which includes /project
and replace the first parenthesized capture group with your https://gitlab.com
. Here p1
denotes first parenthesized capture group and p2
denotes second parenthesized capture group.
const str = 'file:///Downloads/project/users/controllers/users/controller.js';
const res = str.replace(/^(.|/)+w*project(.+)*/gi, function(match, p1, p2)
return 'https://gitlab.com' + p2;
);
console.log(res);
const str = 'file:///Downloads/project/users/controllers/users/controller.js';
const res = str.replace(/^(.|/)+w*project(.+)*/gi, function(match, p1, p2)
return 'https://gitlab.com' + p2;
);
console.log(res);
const str = 'file:///Downloads/project/users/controllers/users/controller.js';
const res = str.replace(/^(.|/)+w*project(.+)*/gi, function(match, p1, p2)
return 'https://gitlab.com' + p2;
);
console.log(res);
answered Mar 8 at 22:22
Farhad YasirFarhad Yasir
1,52921430
1,52921430
add a comment |
add a comment |
you don't need a regex for that
const string = 'file:///Downloads/project/users/controllers/users/controller.js',
yourValue = "file:///Downloads/project/",
res = string.replace(yourValue, "https://gitlab.com/")
console.log(res)
i retreive string dynamically so the value file:///Downloads/project changes
– brxnzaz
Mar 8 at 21:52
same thing i updated my answer
– G.aziz
Mar 8 at 21:53
add a comment |
you don't need a regex for that
const string = 'file:///Downloads/project/users/controllers/users/controller.js',
yourValue = "file:///Downloads/project/",
res = string.replace(yourValue, "https://gitlab.com/")
console.log(res)
i retreive string dynamically so the value file:///Downloads/project changes
– brxnzaz
Mar 8 at 21:52
same thing i updated my answer
– G.aziz
Mar 8 at 21:53
add a comment |
you don't need a regex for that
const string = 'file:///Downloads/project/users/controllers/users/controller.js',
yourValue = "file:///Downloads/project/",
res = string.replace(yourValue, "https://gitlab.com/")
console.log(res)
you don't need a regex for that
const string = 'file:///Downloads/project/users/controllers/users/controller.js',
yourValue = "file:///Downloads/project/",
res = string.replace(yourValue, "https://gitlab.com/")
console.log(res)
const string = 'file:///Downloads/project/users/controllers/users/controller.js',
yourValue = "file:///Downloads/project/",
res = string.replace(yourValue, "https://gitlab.com/")
console.log(res)
const string = 'file:///Downloads/project/users/controllers/users/controller.js',
yourValue = "file:///Downloads/project/",
res = string.replace(yourValue, "https://gitlab.com/")
console.log(res)
edited Mar 8 at 21:53
answered Mar 8 at 21:51
G.azizG.aziz
1,138518
1,138518
i retreive string dynamically so the value file:///Downloads/project changes
– brxnzaz
Mar 8 at 21:52
same thing i updated my answer
– G.aziz
Mar 8 at 21:53
add a comment |
i retreive string dynamically so the value file:///Downloads/project changes
– brxnzaz
Mar 8 at 21:52
same thing i updated my answer
– G.aziz
Mar 8 at 21:53
i retreive string dynamically so the value file:///Downloads/project changes
– brxnzaz
Mar 8 at 21:52
i retreive string dynamically so the value file:///Downloads/project changes
– brxnzaz
Mar 8 at 21:52
same thing i updated my answer
– G.aziz
Mar 8 at 21:53
same thing i updated my answer
– G.aziz
Mar 8 at 21:53
add a comment |
'https://gitlab.com/' + string.substr(string.indexOf('project'))
First find the position of 'project' in your string
string.indexOf('project')
then get a substring from that position to the end of the string (substr goes till the end when no second arg is provided)
string.substring(indexOfProject)
then concat it with '+'. Note that the url ends with '/' because your string will begin with 'p'.
'https://gitlab.com/' + extractedString
1
Please explain your answer.
– Wai Ha Lee
Mar 9 at 1:05
add a comment |
'https://gitlab.com/' + string.substr(string.indexOf('project'))
First find the position of 'project' in your string
string.indexOf('project')
then get a substring from that position to the end of the string (substr goes till the end when no second arg is provided)
string.substring(indexOfProject)
then concat it with '+'. Note that the url ends with '/' because your string will begin with 'p'.
'https://gitlab.com/' + extractedString
1
Please explain your answer.
– Wai Ha Lee
Mar 9 at 1:05
add a comment |
'https://gitlab.com/' + string.substr(string.indexOf('project'))
First find the position of 'project' in your string
string.indexOf('project')
then get a substring from that position to the end of the string (substr goes till the end when no second arg is provided)
string.substring(indexOfProject)
then concat it with '+'. Note that the url ends with '/' because your string will begin with 'p'.
'https://gitlab.com/' + extractedString
'https://gitlab.com/' + string.substr(string.indexOf('project'))
First find the position of 'project' in your string
string.indexOf('project')
then get a substring from that position to the end of the string (substr goes till the end when no second arg is provided)
string.substring(indexOfProject)
then concat it with '+'. Note that the url ends with '/' because your string will begin with 'p'.
'https://gitlab.com/' + extractedString
edited Mar 11 at 16:01
answered Mar 8 at 22:10
Jeyko CaicedoJeyko Caicedo
313
313
1
Please explain your answer.
– Wai Ha Lee
Mar 9 at 1:05
add a comment |
1
Please explain your answer.
– Wai Ha Lee
Mar 9 at 1:05
1
1
Please explain your answer.
– Wai Ha Lee
Mar 9 at 1:05
Please explain your answer.
– Wai Ha Lee
Mar 9 at 1:05
add a comment |
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1
why do you need regex?
– alfasin
Mar 8 at 21:49
i'm reading about some way of replacing a substring by regex so i think that's the only ways instead of writing a whole function
– brxnzaz
Mar 8 at 21:51
string.replace('file:///Downloads/project', 'mynewvalue')
– Isaac Vidrine
Mar 8 at 21:51