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How to parse xml using scrapy
The Next CEO of Stack OverflowHow to merge two dictionaries in a single expression?How do I check if a list is empty?How do I check whether a file exists without exceptions?How can I safely create a nested directory in Python?How do I parse a string to a float or int in Python?How do I sort a dictionary by value?How to make a chain of function decorators?How do I parse XML in Python?How do I list all files of a directory?How Do You Parse and Process HTML/XML in PHP?
How to scrape the XML using scrapy.
My XML looks something like this:
<rss xmlns:media="http://search.yahoo.com/mrss/" version="2.0">
<channel>
<generator>NFE/5.0</generator>
<title>"python" - Google News</title>
<link>
https://news.google.com/search?q=python&hl=en-IN&gl=IN&ceid=IN:en
</link>
<language>en-IN</language>
<webMaster>news-webmaster@google.com</webMaster>
<copyright>2019 Google Inc.</copyright>
<lastBuildDate>Thu, 07 Mar 2019 16:48:55 GMT</lastBuildDate>
<description>Google News</description>
<item>
<title>
Brown snake attacks python eating a rat - NEWS.com.au
</title>
</channel>
</rss>
My code looks like this:
from scrapy.spiders import XMLFeedSpider
from scrapy.http import HtmlResponse
from scrapy.selector import Selector
response = HtmlResponse(url='https://news.google.com/rss/search?q=python&hl=en-IN&gl=IN&ceid=IN:en')
xxs = Selector(response)
obj = xxs.xpath('//title/text()').extract()
I want to get the text in the title tag. But here I'm getting an empty list. Please help me out. It's important.
Thanks a lot
python xml web-scraping scrapy
asked Mar 7 at 16:58
A. AnandA. Anand
61
add a comment |
How to scrape the XML using scrapy.
My XML looks something like this:
<rss xmlns:media="http://search.yahoo.com/mrss/" version="2.0">
<channel>
<generator>NFE/5.0</generator>
<title>"python" - Google News</title>
<link>
https://news.google.com/search?q=python&hl=en-IN&gl=IN&ceid=IN:en
</link>
<language>en-IN</language>
<webMaster>news-webmaster@google.com</webMaster>
<copyright>2019 Google Inc.</copyright>
<lastBuildDate>Thu, 07 Mar 2019 16:48:55 GMT</lastBuildDate>
<description>Google News</description>
<item>
<title>
Brown snake attacks python eating a rat - NEWS.com.au
</title>
</channel>
</rss>
My code looks like this:
from scrapy.spiders import XMLFeedSpider
from scrapy.http import HtmlResponse
from scrapy.selector import Selector
response = HtmlResponse(url='https://news.google.com/rss/search?q=python&hl=en-IN&gl=IN&ceid=IN:en')
xxs = Selector(response)
obj = xxs.xpath('//title/text()').extract()
I want to get the text in the title tag. But here I'm getting an empty list. Please help me out. It's important.
Thanks a lot
python xml web-scraping scrapy
asked Mar 7 at 16:58
A. AnandA. Anand
61
add a comment |
How to scrape the XML using scrapy.
My XML looks something like this:
<rss xmlns:media="http://search.yahoo.com/mrss/" version="2.0">
<channel>
<generator>NFE/5.0</generator>
<title>"python" - Google News</title>
<link>
https://news.google.com/search?q=python&hl=en-IN&gl=IN&ceid=IN:en
</link>
<language>en-IN</language>
<webMaster>news-webmaster@google.com</webMaster>
<copyright>2019 Google Inc.</copyright>
<lastBuildDate>Thu, 07 Mar 2019 16:48:55 GMT</lastBuildDate>
<description>Google News</description>
<item>
<title>
Brown snake attacks python eating a rat - NEWS.com.au
</title>
</channel>
</rss>
My code looks like this:
from scrapy.spiders import XMLFeedSpider
from scrapy.http import HtmlResponse
from scrapy.selector import Selector
response = HtmlResponse(url='https://news.google.com/rss/search?q=python&hl=en-IN&gl=IN&ceid=IN:en')
xxs = Selector(response)
obj = xxs.xpath('//title/text()').extract()
I want to get the text in the title tag. But here I'm getting an empty list. Please help me out. It's important.
Thanks a lot
python xml web-scraping scrapy
asked Mar 7 at 16:58
A. AnandA. Anand
61
How to scrape the XML using scrapy.
My XML looks something like this:
<rss xmlns:media="http://search.yahoo.com/mrss/" version="2.0">
<channel>
<generator>NFE/5.0</generator>
<title>"python" - Google News</title>
<link>
https://news.google.com/search?q=python&hl=en-IN&gl=IN&ceid=IN:en
</link>
<language>en-IN</language>
<webMaster>news-webmaster@google.com</webMaster>
<copyright>2019 Google Inc.</copyright>
<lastBuildDate>Thu, 07 Mar 2019 16:48:55 GMT</lastBuildDate>
<description>Google News</description>
<item>
<title>
Brown snake attacks python eating a rat - NEWS.com.au
</title>
</channel>
</rss>
My code looks like this:
from scrapy.spiders import XMLFeedSpider
from scrapy.http import HtmlResponse
from scrapy.selector import Selector
response = HtmlResponse(url='https://news.google.com/rss/search?q=python&hl=en-IN&gl=IN&ceid=IN:en')
xxs = Selector(response)
obj = xxs.xpath('//title/text()').extract()
I want to get the text in the title tag. But here I'm getting an empty list. Please help me out. It's important.
Thanks a lot
python xml web-scraping scrapy
python xml web-scraping scrapy
asked Mar 7 at 16:58
A. AnandA. Anand
61
asked Mar 7 at 16:58
A. AnandA. Anand
61
asked Mar 7 at 16:58
A. AnandA. Anand
61
asked Mar 7 at 16:58
A. AnandA. Anand
61
asked Mar 7 at 16:58
A. AnandA. Anand
61
61
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You are getting forbidden by robots.txt.
You need to change this behavior in the settings.py and change ROBOTSTXT_OBEY=Trueto ROBOTSTXT_OBEY=False.
answered Mar 7 at 17:35
H. DucatiH. Ducati
31
It's still not working
– A. Anand
Mar 8 at 4:23
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You are getting forbidden by robots.txt.
You need to change this behavior in the settings.py and change ROBOTSTXT_OBEY=Trueto ROBOTSTXT_OBEY=False.
answered Mar 7 at 17:35
H. DucatiH. Ducati
31
It's still not working
– A. Anand
Mar 8 at 4:23
add a comment |
You are getting forbidden by robots.txt.
You need to change this behavior in the settings.py and change ROBOTSTXT_OBEY=Trueto ROBOTSTXT_OBEY=False.
answered Mar 7 at 17:35
H. DucatiH. Ducati
31
It's still not working
– A. Anand
Mar 8 at 4:23
add a comment |
You are getting forbidden by robots.txt.
You need to change this behavior in the settings.py and change ROBOTSTXT_OBEY=Trueto ROBOTSTXT_OBEY=False.
answered Mar 7 at 17:35
H. DucatiH. Ducati
31
You are getting forbidden by robots.txt.
You need to change this behavior in the settings.py and change ROBOTSTXT_OBEY=Trueto ROBOTSTXT_OBEY=False.
answered Mar 7 at 17:35
H. DucatiH. Ducati
31
answered Mar 7 at 17:35
H. DucatiH. Ducati
31
answered Mar 7 at 17:35
H. DucatiH. Ducati
31
answered Mar 7 at 17:35
H. DucatiH. Ducati
31
31
It's still not working
– A. Anand
Mar 8 at 4:23
add a comment |
It's still not working
– A. Anand
Mar 8 at 4:23
It's still not working
– A. Anand
Mar 8 at 4:23
It's still not working
– A. Anand
Mar 8 at 4:23
add a comment |
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