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how to use canvas.SetLeft on DateTime in wpf
What is the correct way to create a single-instance WPF application?How do I use WPF bindings with RelativeSource?In WPF, what are the differences between the x:Name and Name attributes?WPF - ScreenSaver graphics performance improvementsHow do I exit a WPF application programmatically?Drawing lines and ellipses using ObservableCollection and ItemsControlWhy does a databinding for a Path's fill work but any binding for any of its child elements don't?How to draw simple shapes onto a WPF xaml-defined canvas programaticallyNew row in Binded DataGrid shows DatePicker as 01/01/0001How to WPF draw rectangle on top of image view dragged onto canvas
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Sesaonallist is an ObservableCollection of type DataPoint.
I am trying to write each datapoint within the observable collection as an ellipse and draw it to a canvas. The problem is that X axis is of DateTime and I get the error
cannot convert DateTime to double
when I use Canvas.SetLeft(ellipse, Seasonallist[i].X);.
I don't want to use any third party libraries to do this, should i look into Converters?
Seasonallist = new ObservableCollection<DataPoint>();
if (Seasonallist != null)
for (int i = 0; i <= Seasonallist.Count - 1; i++)
Ellipse ellipse = new Ellipse();
ellipse.Width = 5;
ellipse.Height = 5;
ellipse.Fill = Brushes.Blue;
Canvas.SetLeft(ellipse, Seasonallist[i].X); <--error here
Canvas.SetTop(ellipse, Seasonallist.Y);
textCanvas.Children.Add(ellipse);
public class DataPoint
public DateTime X get; set;
public double Y get; set;
wpf
edited Mar 8 at 6:31
RN92
1,024725
asked Mar 8 at 4:34
masterinexmasterinex
1672411
add a comment |
Sesaonallist is an ObservableCollection of type DataPoint.
I am trying to write each datapoint within the observable collection as an ellipse and draw it to a canvas. The problem is that X axis is of DateTime and I get the error
cannot convert DateTime to double
when I use Canvas.SetLeft(ellipse, Seasonallist[i].X);.
I don't want to use any third party libraries to do this, should i look into Converters?
Seasonallist = new ObservableCollection<DataPoint>();
if (Seasonallist != null)
for (int i = 0; i <= Seasonallist.Count - 1; i++)
Ellipse ellipse = new Ellipse();
ellipse.Width = 5;
ellipse.Height = 5;
ellipse.Fill = Brushes.Blue;
Canvas.SetLeft(ellipse, Seasonallist[i].X); <--error here
Canvas.SetTop(ellipse, Seasonallist.Y);
textCanvas.Children.Add(ellipse);
public class DataPoint
public DateTime X get; set;
public double Y get; set;
wpf
edited Mar 8 at 6:31
RN92
1,024725
asked Mar 8 at 4:34
masterinexmasterinex
1672411
add a comment |
Sesaonallist is an ObservableCollection of type DataPoint.
I am trying to write each datapoint within the observable collection as an ellipse and draw it to a canvas. The problem is that X axis is of DateTime and I get the error
cannot convert DateTime to double
when I use Canvas.SetLeft(ellipse, Seasonallist[i].X);.
I don't want to use any third party libraries to do this, should i look into Converters?
Seasonallist = new ObservableCollection<DataPoint>();
if (Seasonallist != null)
for (int i = 0; i <= Seasonallist.Count - 1; i++)
Ellipse ellipse = new Ellipse();
ellipse.Width = 5;
ellipse.Height = 5;
ellipse.Fill = Brushes.Blue;
Canvas.SetLeft(ellipse, Seasonallist[i].X); <--error here
Canvas.SetTop(ellipse, Seasonallist.Y);
textCanvas.Children.Add(ellipse);
public class DataPoint
public DateTime X get; set;
public double Y get; set;
wpf
edited Mar 8 at 6:31
RN92
1,024725
asked Mar 8 at 4:34
masterinexmasterinex
1672411
Sesaonallist is an ObservableCollection of type DataPoint.
I am trying to write each datapoint within the observable collection as an ellipse and draw it to a canvas. The problem is that X axis is of DateTime and I get the error
cannot convert DateTime to double
when I use Canvas.SetLeft(ellipse, Seasonallist[i].X);.
I don't want to use any third party libraries to do this, should i look into Converters?
Seasonallist = new ObservableCollection<DataPoint>();
if (Seasonallist != null)
for (int i = 0; i <= Seasonallist.Count - 1; i++)
Ellipse ellipse = new Ellipse();
ellipse.Width = 5;
ellipse.Height = 5;
ellipse.Fill = Brushes.Blue;
Canvas.SetLeft(ellipse, Seasonallist[i].X); <--error here
Canvas.SetTop(ellipse, Seasonallist.Y);
textCanvas.Children.Add(ellipse);
public class DataPoint
public DateTime X get; set;
public double Y get; set;
wpf
wpf
edited Mar 8 at 6:31
RN92
1,024725
asked Mar 8 at 4:34
masterinexmasterinex
1672411
edited Mar 8 at 6:31
RN92
1,024725
asked Mar 8 at 4:34
masterinexmasterinex
1672411
edited Mar 8 at 6:31
RN92
1,024725
edited Mar 8 at 6:31
RN92
1,024725
edited Mar 8 at 6:31
RN92
1,024725
1,024725
asked Mar 8 at 4:34
masterinexmasterinex
1672411
asked Mar 8 at 4:34
masterinexmasterinex
1672411
asked Mar 8 at 4:34
masterinexmasterinex
1672411
1672411
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
you can try the Ticks Property of the DataTime.
Canvas.SetLeft(ellipse, Convert.ToDouble(Seasonallist[i].X.Ticks));
you have to find a good way to convert this big number into X Canvas coordination.
answered Mar 8 at 6:35
Hakam FostokHakam Fostok
5,74284470
okay, i have used the Ticks property, but it is giving a really huge number like Seasonallist[i].X.Ticks = 635241312000000000, can i just arbitrary divide that large number by some other number to reduce it to a smaller number ?
– masterinex
Mar 8 at 10:14
add a comment |
Yes, you will need to use a converter but first you must determine the width of a time interval. This is best done using the ticks values so:
TicksPerPixel is Display duration / Display Width
You can then store this value and use formula DateTime.Ticks / TicksPerPixel to calculate the left property needed to draw it in the correct location.
answered Mar 8 at 10:18
Matt NorrieMatt Norrie
43111
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
you can try the Ticks Property of the DataTime.
Canvas.SetLeft(ellipse, Convert.ToDouble(Seasonallist[i].X.Ticks));
you have to find a good way to convert this big number into X Canvas coordination.
answered Mar 8 at 6:35
Hakam FostokHakam Fostok
5,74284470
okay, i have used the Ticks property, but it is giving a really huge number like Seasonallist[i].X.Ticks = 635241312000000000, can i just arbitrary divide that large number by some other number to reduce it to a smaller number ?
– masterinex
Mar 8 at 10:14
add a comment |
you can try the Ticks Property of the DataTime.
Canvas.SetLeft(ellipse, Convert.ToDouble(Seasonallist[i].X.Ticks));
you have to find a good way to convert this big number into X Canvas coordination.
answered Mar 8 at 6:35
Hakam FostokHakam Fostok
5,74284470
okay, i have used the Ticks property, but it is giving a really huge number like Seasonallist[i].X.Ticks = 635241312000000000, can i just arbitrary divide that large number by some other number to reduce it to a smaller number ?
– masterinex
Mar 8 at 10:14
add a comment |
you can try the Ticks Property of the DataTime.
Canvas.SetLeft(ellipse, Convert.ToDouble(Seasonallist[i].X.Ticks));
you have to find a good way to convert this big number into X Canvas coordination.
answered Mar 8 at 6:35
Hakam FostokHakam Fostok
5,74284470
you can try the Ticks Property of the DataTime.
Canvas.SetLeft(ellipse, Convert.ToDouble(Seasonallist[i].X.Ticks));
you have to find a good way to convert this big number into X Canvas coordination.
answered Mar 8 at 6:35
Hakam FostokHakam Fostok
5,74284470
answered Mar 8 at 6:35
Hakam FostokHakam Fostok
5,74284470
answered Mar 8 at 6:35
Hakam FostokHakam Fostok
5,74284470
answered Mar 8 at 6:35
Hakam FostokHakam Fostok
5,74284470
5,74284470
okay, i have used the Ticks property, but it is giving a really huge number like Seasonallist[i].X.Ticks = 635241312000000000, can i just arbitrary divide that large number by some other number to reduce it to a smaller number ?
– masterinex
Mar 8 at 10:14
add a comment |
okay, i have used the Ticks property, but it is giving a really huge number like Seasonallist[i].X.Ticks = 635241312000000000, can i just arbitrary divide that large number by some other number to reduce it to a smaller number ?
– masterinex
Mar 8 at 10:14
okay, i have used the Ticks property, but it is giving a really huge number like Seasonallist[i].X.Ticks = 635241312000000000, can i just arbitrary divide that large number by some other number to reduce it to a smaller number ?
– masterinex
Mar 8 at 10:14
okay, i have used the Ticks property, but it is giving a really huge number like Seasonallist[i].X.Ticks = 635241312000000000, can i just arbitrary divide that large number by some other number to reduce it to a smaller number ?
– masterinex
Mar 8 at 10:14
add a comment |
Yes, you will need to use a converter but first you must determine the width of a time interval. This is best done using the ticks values so:
TicksPerPixel is Display duration / Display Width
You can then store this value and use formula DateTime.Ticks / TicksPerPixel to calculate the left property needed to draw it in the correct location.
answered Mar 8 at 10:18
Matt NorrieMatt Norrie
43111
add a comment |
Yes, you will need to use a converter but first you must determine the width of a time interval. This is best done using the ticks values so:
TicksPerPixel is Display duration / Display Width
You can then store this value and use formula DateTime.Ticks / TicksPerPixel to calculate the left property needed to draw it in the correct location.
answered Mar 8 at 10:18
Matt NorrieMatt Norrie
43111
add a comment |
Yes, you will need to use a converter but first you must determine the width of a time interval. This is best done using the ticks values so:
TicksPerPixel is Display duration / Display Width
You can then store this value and use formula DateTime.Ticks / TicksPerPixel to calculate the left property needed to draw it in the correct location.
answered Mar 8 at 10:18
Matt NorrieMatt Norrie
43111
Yes, you will need to use a converter but first you must determine the width of a time interval. This is best done using the ticks values so:
TicksPerPixel is Display duration / Display Width
You can then store this value and use formula DateTime.Ticks / TicksPerPixel to calculate the left property needed to draw it in the correct location.
answered Mar 8 at 10:18
Matt NorrieMatt Norrie
43111
edited Mar 8 at 10:24
answered Mar 8 at 10:18
Matt NorrieMatt Norrie
43111
answered Mar 8 at 10:18
Matt NorrieMatt Norrie
43111
answered Mar 8 at 10:18
Matt NorrieMatt Norrie
43111
43111
add a comment |
add a comment |
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