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0

How do I trim leading zeroes in an ipv6 address string in python?

For eg: I need 1:1:1:1:1:1:0:1 to be trimmed to 1:1:1:1:1:1::1

I have tried using socket.inet_ntop and socket.inet_pton but they do not help in my case

#!/usr/bin/env python
import socket
import struct
address = '1:1:1:1:1:1:0:1'
addr = socket.inet_ntop(socket.AF_INET6,socket.inet_pton(socket.AF_INET6, address))
print (addr)

This prints the same string as the output 1:1:1:1:1:1:0:1

I have also tried the ipaddress lib which produces the same output as above.

#!/usr/bin/env python
import ipaddress
ip = '1:1:1:1:1:1:0:1'
print(str(ipaddress.ip_address(ip)))

I tried using the netaddr lib by referring to the top voted answer on this question but get an import error. I'm using Python 3.0.

I have also tried using this library but get an ImportError: No module named 'IPy' error

#!/usr/bin/env python
from IPy import IP
print(IP('1080:0:0:0:8:800:200C:417A'))

I'm surprised to find that no one has had a real clear cut solution in a built in library to solve this problem. Can someone help?

python-3.x ipv6 inet leading-zero

share|improve this question

asked Mar 8 at 12:25

Badri NarayananBadri Narayanan

63

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  You are not supposed to compress a single 0. RFC 5952, Section 4, explains the proper IPv6 address formatting, including: "The symbol "::" MUST NOT be used to shorten just one 16-bit 0 field. For example, the representation 2001:db8:0:1:1:1:1:1 is correct, but 2001:db8::1:1:1:1:1 is not correct."
  
  – Ron Maupin
  Mar 8 at 12:38
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @RonMaupin Thanks for your clarification. socket.inet_ntop(socket.AF_INET6,socket.inet_pton(socket.AF_INET6, "1:1:1:1:1:1::1") returns 1:1:1:1:1:1:0:1. This very much solves my use case.
  
  – Badri Narayanan
  Mar 8 at 16:37
  
  

  
  
  
  

add a comment | 

0

How do I trim leading zeroes in an ipv6 address string in python?

For eg: I need 1:1:1:1:1:1:0:1 to be trimmed to 1:1:1:1:1:1::1

I have tried using socket.inet_ntop and socket.inet_pton but they do not help in my case

#!/usr/bin/env python
import socket
import struct
address = '1:1:1:1:1:1:0:1'
addr = socket.inet_ntop(socket.AF_INET6,socket.inet_pton(socket.AF_INET6, address))
print (addr)

This prints the same string as the output 1:1:1:1:1:1:0:1

I have also tried the ipaddress lib which produces the same output as above.

#!/usr/bin/env python
import ipaddress
ip = '1:1:1:1:1:1:0:1'
print(str(ipaddress.ip_address(ip)))

I tried using the netaddr lib by referring to the top voted answer on this question but get an import error. I'm using Python 3.0.

I have also tried using this library but get an ImportError: No module named 'IPy' error

#!/usr/bin/env python
from IPy import IP
print(IP('1080:0:0:0:8:800:200C:417A'))

I'm surprised to find that no one has had a real clear cut solution in a built in library to solve this problem. Can someone help?

python-3.x ipv6 inet leading-zero

share|improve this question

asked Mar 8 at 12:25

Badri NarayananBadri Narayanan

63

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  You are not supposed to compress a single 0. RFC 5952, Section 4, explains the proper IPv6 address formatting, including: "The symbol "::" MUST NOT be used to shorten just one 16-bit 0 field. For example, the representation 2001:db8:0:1:1:1:1:1 is correct, but 2001:db8::1:1:1:1:1 is not correct."
  
  – Ron Maupin
  Mar 8 at 12:38
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @RonMaupin Thanks for your clarification. socket.inet_ntop(socket.AF_INET6,socket.inet_pton(socket.AF_INET6, "1:1:1:1:1:1::1") returns 1:1:1:1:1:1:0:1. This very much solves my use case.
  
  – Badri Narayanan
  Mar 8 at 16:37
  
  

  
  
  
  

add a comment | 

How do I trim leading zeroes in an ipv6 address string in python?

For eg: I need 1:1:1:1:1:1:0:1 to be trimmed to 1:1:1:1:1:1::1

I have tried using socket.inet_ntop and socket.inet_pton but they do not help in my case

#!/usr/bin/env python
import socket
import struct
address = '1:1:1:1:1:1:0:1'
addr = socket.inet_ntop(socket.AF_INET6,socket.inet_pton(socket.AF_INET6, address))
print (addr)

This prints the same string as the output 1:1:1:1:1:1:0:1

I have also tried the ipaddress lib which produces the same output as above.

#!/usr/bin/env python
import ipaddress
ip = '1:1:1:1:1:1:0:1'
print(str(ipaddress.ip_address(ip)))

I tried using the netaddr lib by referring to the top voted answer on this question but get an import error. I'm using Python 3.0.

I have also tried using this library but get an ImportError: No module named 'IPy' error

#!/usr/bin/env python
from IPy import IP
print(IP('1080:0:0:0:8:800:200C:417A'))

I'm surprised to find that no one has had a real clear cut solution in a built in library to solve this problem. Can someone help?

python-3.x ipv6 inet leading-zero

share|improve this question

asked Mar 8 at 12:25

Badri NarayananBadri Narayanan

63

#!/usr/bin/env python
import socket
import struct
address = '1:1:1:1:1:1:0:1'
addr = socket.inet_ntop(socket.AF_INET6,socket.inet_pton(socket.AF_INET6, address))
print (addr)

#!/usr/bin/env python
import ipaddress
ip = '1:1:1:1:1:1:0:1'
print(str(ipaddress.ip_address(ip)))

#!/usr/bin/env python
from IPy import IP
print(IP('1080:0:0:0:8:800:200C:417A'))

share|improve this question

asked Mar 8 at 12:25

Badri NarayananBadri Narayanan

63

share|improve this question

asked Mar 8 at 12:25

Badri NarayananBadri Narayanan

63

asked Mar 8 at 12:25

Badri NarayananBadri Narayanan

63

asked Mar 8 at 12:25

Badri NarayananBadri Narayanan

63