Ufdjrw

Should I tell management that I intend to leave due to bad software development practices?

Blender 2.8 I can't see vertices, edges or faces in edit mode

Why are electrically insulating heatsinks so rare? Is it just cost?

Is there a hemisphere-neutral way of specifying a season?

What killed these X2 caps?

Is the Joker left-handed?

How to say in German "enjoying home comforts"

Alternative to sending password over mail?

How to draw the figure with four pentagons?

What exploit are these user agents trying to use?

What does it mean to describe someone as a butt steak?

What is the intuition behind short exact sequences of groups; in particular, what is the intuition behind group extensions?

Intersection of two sorted vectors in C++

UK: Is there precedent for the governments e-petition site changing the direction of a government decision?

Do I have a twin with permutated remainders?

How can saying a song's name be a copyright violation?

Why is consensus so controversial in Britain?

Watching something be written to a file live with tail

Why does Kotter return in Welcome Back Kotter

Can I ask the recruiters in my resume to put the reason why I am rejected?

Why do I get two different answers for this counting problem?

How do conventional missiles fly?

What is the PIE reconstruction for word-initial alpha with rough breathing?

Has there ever been an airliner design involving reducing generator load by installing solar panels?

Send the file and the filename using Python

How do I check whether a file exists without exceptions?Calling an external command in PythonWhat are metaclasses in Python?How do I copy a file in Python?Finding the index of an item given a list containing it in PythonDifference between append vs. extend list methods in PythonHow can I safely create a nested directory in Python?Does Python have a ternary conditional operator?How do I list all files of a directory?Does Python have a string 'contains' substring method?

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;

3

1

I want to make a dead simple server that accepts different types of files from clients. The problem is, that I cannot get the filename sent over from the client, so all the files are saved as 1 filename, whatever the file is called.

This is my client.py:

import socket
with socket.socket() as s:
 s.connect(('192.168.1.2',10000))
 with open('Image.jpg','rb') as f:
 s.sendall(f.read())

And this is my server.py:

import socket
print("Server started")
while True:
 with socket.socket() as s:
 s.bind(('192.168.1.2',10000))
 s.listen(1)
 with s.accept()[0] as c:
 chunks = []
 while True:
 chunk = c.recv(4096)
 if not chunk: break
 chunks.append(chunk)
 print("Receiving file")
 with open('Image.jpg','wb') as f:
 f.write(b''.join(chunks))
 print("File Received")

Which works fine. The problem starts, that if I send another file, for example "data.csv" it will still be saved as "Image.jpg" on the server.

Is there any way to also save the filename along with the file?

python sockets

share|improve this question

edited Mar 8 at 0:07

orde

4,81762533

asked Mar 8 at 0:02

Ioannis Tzon TsolakidisIoannis Tzon Tsolakidis

161

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Maybe you could include it as a header, or as a message before the picture?
  
  – Reedinationer
  Mar 8 at 0:04
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Sending files in clear text isn't a great idea nowadays, have you considered using scp ?
  
  – Benoît Pilatte
  Mar 8 at 0:13
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You'll need to create a wire protocol that lets you include the file name (or use one that already can do so, like e.g. ftp...)
  
  – thebjorn
  Mar 8 at 0:22
  

  
  
  
  

add a comment | 

3

1

I want to make a dead simple server that accepts different types of files from clients. The problem is, that I cannot get the filename sent over from the client, so all the files are saved as 1 filename, whatever the file is called.

This is my client.py:

import socket
with socket.socket() as s:
 s.connect(('192.168.1.2',10000))
 with open('Image.jpg','rb') as f:
 s.sendall(f.read())

And this is my server.py:

import socket
print("Server started")
while True:
 with socket.socket() as s:
 s.bind(('192.168.1.2',10000))
 s.listen(1)
 with s.accept()[0] as c:
 chunks = []
 while True:
 chunk = c.recv(4096)
 if not chunk: break
 chunks.append(chunk)
 print("Receiving file")
 with open('Image.jpg','wb') as f:
 f.write(b''.join(chunks))
 print("File Received")

Which works fine. The problem starts, that if I send another file, for example "data.csv" it will still be saved as "Image.jpg" on the server.

Is there any way to also save the filename along with the file?

python sockets

share|improve this question

edited Mar 8 at 0:07

orde

4,81762533

asked Mar 8 at 0:02

Ioannis Tzon TsolakidisIoannis Tzon Tsolakidis

161

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Maybe you could include it as a header, or as a message before the picture?
  
  – Reedinationer
  Mar 8 at 0:04
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Sending files in clear text isn't a great idea nowadays, have you considered using scp ?
  
  – Benoît Pilatte
  Mar 8 at 0:13
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You'll need to create a wire protocol that lets you include the file name (or use one that already can do so, like e.g. ftp...)
  
  – thebjorn
  Mar 8 at 0:22
  

  
  
  
  

add a comment | 

I want to make a dead simple server that accepts different types of files from clients. The problem is, that I cannot get the filename sent over from the client, so all the files are saved as 1 filename, whatever the file is called.

This is my client.py:

import socket
with socket.socket() as s:
 s.connect(('192.168.1.2',10000))
 with open('Image.jpg','rb') as f:
 s.sendall(f.read())

And this is my server.py:

import socket
print("Server started")
while True:
 with socket.socket() as s:
 s.bind(('192.168.1.2',10000))
 s.listen(1)
 with s.accept()[0] as c:
 chunks = []
 while True:
 chunk = c.recv(4096)
 if not chunk: break
 chunks.append(chunk)
 print("Receiving file")
 with open('Image.jpg','wb') as f:
 f.write(b''.join(chunks))
 print("File Received")

Which works fine. The problem starts, that if I send another file, for example "data.csv" it will still be saved as "Image.jpg" on the server.

Is there any way to also save the filename along with the file?

python sockets

share|improve this question

edited Mar 8 at 0:07

orde

4,81762533

asked Mar 8 at 0:02

Ioannis Tzon TsolakidisIoannis Tzon Tsolakidis

161

import socket
with socket.socket() as s:
 s.connect(('192.168.1.2',10000))
 with open('Image.jpg','rb') as f:
 s.sendall(f.read())

import socket
print("Server started")
while True:
 with socket.socket() as s:
 s.bind(('192.168.1.2',10000))
 s.listen(1)
 with s.accept()[0] as c:
 chunks = []
 while True:
 chunk = c.recv(4096)
 if not chunk: break
 chunks.append(chunk)
 print("Receiving file")
 with open('Image.jpg','wb') as f:
 f.write(b''.join(chunks))
 print("File Received")

share|improve this question

edited Mar 8 at 0:07

orde

4,81762533

asked Mar 8 at 0:02

Ioannis Tzon TsolakidisIoannis Tzon Tsolakidis

161

share|improve this question

edited Mar 8 at 0:07

orde

4,81762533

asked Mar 8 at 0:02

Ioannis Tzon TsolakidisIoannis Tzon Tsolakidis

161

edited Mar 8 at 0:07

orde

4,81762533

edited Mar 8 at 0:07

orde

4,81762533

asked Mar 8 at 0:02

Ioannis Tzon TsolakidisIoannis Tzon Tsolakidis

161

asked Mar 8 at 0:02

Ioannis Tzon TsolakidisIoannis Tzon Tsolakidis

161