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Openlayers: feature.get returns the attributes path



2019 Community Moderator ElectionOpenLayers vs Google Maps?event.preventDefault() vs. return falseReturn multiple values in JavaScript?Javascript: Close Popup, Open New Window & RedirectHow to get the data-id attribute?Why does ++[[]][+[]]+[+[]] return the string “10”?How do I return the response from an asynchronous call?Android WebView: Determine <a> target= “_ blank”Href vs select boxThe relative path in Vue single file components does not work properly










0















I have an openlayers map with a point layer that on click on a feature opens a popup. Inside the popup I show a clickable link that is supposed to lead to a url that is stored inside the attribute table of the layer.



But if I click the layer a link opens to a path like "C:/Users/user/.../URL". The URL is all I want to have, but the browser also opens the path to where the project is saved.



My code:



map.on('click', function(event) 
var feature = map.forEachFeatureAtPixel(event.pixel, function(feature, layer)
if (layer === knoten)
return feature;

);
if (feature != null)
var pixel = event.pixel;
var coord = map.getCoordinateFromPixel(pixel);
popup.setPosition(coord);
$(elementPopup).attr('data-content', '<b>1: </b>' + '&ensp;' + feature.get('ERHEB_NR') +
'</br><b>2: </b>' + '&emsp;&emsp;&nbsp;&nbsp;' + '<a id="link" target="_blank" rel="noopener noreferrer">Link</a>');
$(elementPopup).popover('placement': 'top', 'html': true);
$(elementPopup).popover('show');

document.getElementById('link').href = feature.get('KATASTER')

else
$(elementPopup).popover('html': true);
$(elementPopup).popover('hide');

);


If I substitute '<a id="link" target="_blank" rel="noopener noreferrer">Link</a>' for feature.get('KATASTER') the correct link appears (but since since it is not inside the statement it is not clickable).










share|improve this question


























    0















    I have an openlayers map with a point layer that on click on a feature opens a popup. Inside the popup I show a clickable link that is supposed to lead to a url that is stored inside the attribute table of the layer.



    But if I click the layer a link opens to a path like "C:/Users/user/.../URL". The URL is all I want to have, but the browser also opens the path to where the project is saved.



    My code:



    map.on('click', function(event) 
    var feature = map.forEachFeatureAtPixel(event.pixel, function(feature, layer)
    if (layer === knoten)
    return feature;

    );
    if (feature != null)
    var pixel = event.pixel;
    var coord = map.getCoordinateFromPixel(pixel);
    popup.setPosition(coord);
    $(elementPopup).attr('data-content', '<b>1: </b>' + '&ensp;' + feature.get('ERHEB_NR') +
    '</br><b>2: </b>' + '&emsp;&emsp;&nbsp;&nbsp;' + '<a id="link" target="_blank" rel="noopener noreferrer">Link</a>');
    $(elementPopup).popover('placement': 'top', 'html': true);
    $(elementPopup).popover('show');

    document.getElementById('link').href = feature.get('KATASTER')

    else
    $(elementPopup).popover('html': true);
    $(elementPopup).popover('hide');

    );


    If I substitute '<a id="link" target="_blank" rel="noopener noreferrer">Link</a>' for feature.get('KATASTER') the correct link appears (but since since it is not inside the statement it is not clickable).










    share|improve this question
























      0












      0








      0








      I have an openlayers map with a point layer that on click on a feature opens a popup. Inside the popup I show a clickable link that is supposed to lead to a url that is stored inside the attribute table of the layer.



      But if I click the layer a link opens to a path like "C:/Users/user/.../URL". The URL is all I want to have, but the browser also opens the path to where the project is saved.



      My code:



      map.on('click', function(event) 
      var feature = map.forEachFeatureAtPixel(event.pixel, function(feature, layer)
      if (layer === knoten)
      return feature;

      );
      if (feature != null)
      var pixel = event.pixel;
      var coord = map.getCoordinateFromPixel(pixel);
      popup.setPosition(coord);
      $(elementPopup).attr('data-content', '<b>1: </b>' + '&ensp;' + feature.get('ERHEB_NR') +
      '</br><b>2: </b>' + '&emsp;&emsp;&nbsp;&nbsp;' + '<a id="link" target="_blank" rel="noopener noreferrer">Link</a>');
      $(elementPopup).popover('placement': 'top', 'html': true);
      $(elementPopup).popover('show');

      document.getElementById('link').href = feature.get('KATASTER')

      else
      $(elementPopup).popover('html': true);
      $(elementPopup).popover('hide');

      );


      If I substitute '<a id="link" target="_blank" rel="noopener noreferrer">Link</a>' for feature.get('KATASTER') the correct link appears (but since since it is not inside the statement it is not clickable).










      share|improve this question














      I have an openlayers map with a point layer that on click on a feature opens a popup. Inside the popup I show a clickable link that is supposed to lead to a url that is stored inside the attribute table of the layer.



      But if I click the layer a link opens to a path like "C:/Users/user/.../URL". The URL is all I want to have, but the browser also opens the path to where the project is saved.



      My code:



      map.on('click', function(event) 
      var feature = map.forEachFeatureAtPixel(event.pixel, function(feature, layer)
      if (layer === knoten)
      return feature;

      );
      if (feature != null)
      var pixel = event.pixel;
      var coord = map.getCoordinateFromPixel(pixel);
      popup.setPosition(coord);
      $(elementPopup).attr('data-content', '<b>1: </b>' + '&ensp;' + feature.get('ERHEB_NR') +
      '</br><b>2: </b>' + '&emsp;&emsp;&nbsp;&nbsp;' + '<a id="link" target="_blank" rel="noopener noreferrer">Link</a>');
      $(elementPopup).popover('placement': 'top', 'html': true);
      $(elementPopup).popover('show');

      document.getElementById('link').href = feature.get('KATASTER')

      else
      $(elementPopup).popover('html': true);
      $(elementPopup).popover('hide');

      );


      If I substitute '<a id="link" target="_blank" rel="noopener noreferrer">Link</a>' for feature.get('KATASTER') the correct link appears (but since since it is not inside the statement it is not clickable).







      javascript openlayers






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 2 days ago









      gHupfgHupf

      1105




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          0














          What about intializing the popever with the content option, instead updating only the link?



          map.on('click', function(event) {
          var feature = map.forEachFeatureAtPixel(event.pixel, function(feature, layer)
          if (layer === knoten)
          return feature;

          );
          // Always hide the popover
          $(elementPopup).popover('hide');
          if (feature != null)
          var pixel = event.pixel;
          var coord = map.getCoordinateFromPixel(pixel);
          popup.setPosition(coord);

          $(elementPopup).popover(
          placement: 'top',
          animation: false,
          html: true,
          trigger: 'focus',
          title: "",
          content: '<b>1: </b>' + '&ensp;' + feature.get('ERHEB_NR') +
          '</br><b>2: </b>' + '&emsp;&emsp;&nbsp;&nbsp;' + '<a id="link" target="_blank" href="'+feature.get('KATASTER')+'" rel="noopener noreferrer">Link</a>'
          );
          );





          share|improve this answer























          • I didn't know about the content option yet, thats definetly a cleaner way to do it, thanks! But still, I get the same as before: Not the url appears in the new browser window, but the path to the project with the url appended shows up.

            – gHupf
            2 days ago






          • 1





            ups. i didn't get the question then. what's inside feature.get('KATASTER') then?

            – GiuServ
            2 days ago











          • I have a layer with an attribute called KATASTER and the KATASTER holds a link for each feature. So with the feature.get('KATASTER') request I am supposed to get back a link. But what I get is the path where the code is saved with the url appended like "C:/Users/user/.../URL", if the project is saved in "C:/Users/user/...". I don't have the problem if I just use feature.get('KATASTER') without the <a href ...>. I just get the unclickable url, but I need a clickable one. I was probably unclear in my question. Is it clear now?

            – gHupf
            2 days ago











          • so if you print out the first feature.get('KATASTER') what are you getting? if it's C:/Users/user/.../URL the problema is where you're assigning KATASTER, so that's why will be usefull to see your feature declaration to find out the problem.

            – GiuServ
            2 days ago






          • 1





            The url starts with ´www´ and that seems to be the problem. If I add ´http://´ everything works fine. I see that it is needed, so the browser recognizes the string as an url.

            – gHupf
            20 hours ago










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          0














          What about intializing the popever with the content option, instead updating only the link?



          map.on('click', function(event) {
          var feature = map.forEachFeatureAtPixel(event.pixel, function(feature, layer)
          if (layer === knoten)
          return feature;

          );
          // Always hide the popover
          $(elementPopup).popover('hide');
          if (feature != null)
          var pixel = event.pixel;
          var coord = map.getCoordinateFromPixel(pixel);
          popup.setPosition(coord);

          $(elementPopup).popover(
          placement: 'top',
          animation: false,
          html: true,
          trigger: 'focus',
          title: "",
          content: '<b>1: </b>' + '&ensp;' + feature.get('ERHEB_NR') +
          '</br><b>2: </b>' + '&emsp;&emsp;&nbsp;&nbsp;' + '<a id="link" target="_blank" href="'+feature.get('KATASTER')+'" rel="noopener noreferrer">Link</a>'
          );
          );





          share|improve this answer























          • I didn't know about the content option yet, thats definetly a cleaner way to do it, thanks! But still, I get the same as before: Not the url appears in the new browser window, but the path to the project with the url appended shows up.

            – gHupf
            2 days ago






          • 1





            ups. i didn't get the question then. what's inside feature.get('KATASTER') then?

            – GiuServ
            2 days ago











          • I have a layer with an attribute called KATASTER and the KATASTER holds a link for each feature. So with the feature.get('KATASTER') request I am supposed to get back a link. But what I get is the path where the code is saved with the url appended like "C:/Users/user/.../URL", if the project is saved in "C:/Users/user/...". I don't have the problem if I just use feature.get('KATASTER') without the <a href ...>. I just get the unclickable url, but I need a clickable one. I was probably unclear in my question. Is it clear now?

            – gHupf
            2 days ago











          • so if you print out the first feature.get('KATASTER') what are you getting? if it's C:/Users/user/.../URL the problema is where you're assigning KATASTER, so that's why will be usefull to see your feature declaration to find out the problem.

            – GiuServ
            2 days ago






          • 1





            The url starts with ´www´ and that seems to be the problem. If I add ´http://´ everything works fine. I see that it is needed, so the browser recognizes the string as an url.

            – gHupf
            20 hours ago















          0














          What about intializing the popever with the content option, instead updating only the link?



          map.on('click', function(event) {
          var feature = map.forEachFeatureAtPixel(event.pixel, function(feature, layer)
          if (layer === knoten)
          return feature;

          );
          // Always hide the popover
          $(elementPopup).popover('hide');
          if (feature != null)
          var pixel = event.pixel;
          var coord = map.getCoordinateFromPixel(pixel);
          popup.setPosition(coord);

          $(elementPopup).popover(
          placement: 'top',
          animation: false,
          html: true,
          trigger: 'focus',
          title: "",
          content: '<b>1: </b>' + '&ensp;' + feature.get('ERHEB_NR') +
          '</br><b>2: </b>' + '&emsp;&emsp;&nbsp;&nbsp;' + '<a id="link" target="_blank" href="'+feature.get('KATASTER')+'" rel="noopener noreferrer">Link</a>'
          );
          );





          share|improve this answer























          • I didn't know about the content option yet, thats definetly a cleaner way to do it, thanks! But still, I get the same as before: Not the url appears in the new browser window, but the path to the project with the url appended shows up.

            – gHupf
            2 days ago






          • 1





            ups. i didn't get the question then. what's inside feature.get('KATASTER') then?

            – GiuServ
            2 days ago











          • I have a layer with an attribute called KATASTER and the KATASTER holds a link for each feature. So with the feature.get('KATASTER') request I am supposed to get back a link. But what I get is the path where the code is saved with the url appended like "C:/Users/user/.../URL", if the project is saved in "C:/Users/user/...". I don't have the problem if I just use feature.get('KATASTER') without the <a href ...>. I just get the unclickable url, but I need a clickable one. I was probably unclear in my question. Is it clear now?

            – gHupf
            2 days ago











          • so if you print out the first feature.get('KATASTER') what are you getting? if it's C:/Users/user/.../URL the problema is where you're assigning KATASTER, so that's why will be usefull to see your feature declaration to find out the problem.

            – GiuServ
            2 days ago






          • 1





            The url starts with ´www´ and that seems to be the problem. If I add ´http://´ everything works fine. I see that it is needed, so the browser recognizes the string as an url.

            – gHupf
            20 hours ago













          0












          0








          0







          What about intializing the popever with the content option, instead updating only the link?



          map.on('click', function(event) {
          var feature = map.forEachFeatureAtPixel(event.pixel, function(feature, layer)
          if (layer === knoten)
          return feature;

          );
          // Always hide the popover
          $(elementPopup).popover('hide');
          if (feature != null)
          var pixel = event.pixel;
          var coord = map.getCoordinateFromPixel(pixel);
          popup.setPosition(coord);

          $(elementPopup).popover(
          placement: 'top',
          animation: false,
          html: true,
          trigger: 'focus',
          title: "",
          content: '<b>1: </b>' + '&ensp;' + feature.get('ERHEB_NR') +
          '</br><b>2: </b>' + '&emsp;&emsp;&nbsp;&nbsp;' + '<a id="link" target="_blank" href="'+feature.get('KATASTER')+'" rel="noopener noreferrer">Link</a>'
          );
          );





          share|improve this answer













          What about intializing the popever with the content option, instead updating only the link?



          map.on('click', function(event) {
          var feature = map.forEachFeatureAtPixel(event.pixel, function(feature, layer)
          if (layer === knoten)
          return feature;

          );
          // Always hide the popover
          $(elementPopup).popover('hide');
          if (feature != null)
          var pixel = event.pixel;
          var coord = map.getCoordinateFromPixel(pixel);
          popup.setPosition(coord);

          $(elementPopup).popover(
          placement: 'top',
          animation: false,
          html: true,
          trigger: 'focus',
          title: "",
          content: '<b>1: </b>' + '&ensp;' + feature.get('ERHEB_NR') +
          '</br><b>2: </b>' + '&emsp;&emsp;&nbsp;&nbsp;' + '<a id="link" target="_blank" href="'+feature.get('KATASTER')+'" rel="noopener noreferrer">Link</a>'
          );
          );






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 2 days ago









          GiuServGiuServ

          8381423




          8381423












          • I didn't know about the content option yet, thats definetly a cleaner way to do it, thanks! But still, I get the same as before: Not the url appears in the new browser window, but the path to the project with the url appended shows up.

            – gHupf
            2 days ago






          • 1





            ups. i didn't get the question then. what's inside feature.get('KATASTER') then?

            – GiuServ
            2 days ago











          • I have a layer with an attribute called KATASTER and the KATASTER holds a link for each feature. So with the feature.get('KATASTER') request I am supposed to get back a link. But what I get is the path where the code is saved with the url appended like "C:/Users/user/.../URL", if the project is saved in "C:/Users/user/...". I don't have the problem if I just use feature.get('KATASTER') without the <a href ...>. I just get the unclickable url, but I need a clickable one. I was probably unclear in my question. Is it clear now?

            – gHupf
            2 days ago











          • so if you print out the first feature.get('KATASTER') what are you getting? if it's C:/Users/user/.../URL the problema is where you're assigning KATASTER, so that's why will be usefull to see your feature declaration to find out the problem.

            – GiuServ
            2 days ago






          • 1





            The url starts with ´www´ and that seems to be the problem. If I add ´http://´ everything works fine. I see that it is needed, so the browser recognizes the string as an url.

            – gHupf
            20 hours ago

















          • I didn't know about the content option yet, thats definetly a cleaner way to do it, thanks! But still, I get the same as before: Not the url appears in the new browser window, but the path to the project with the url appended shows up.

            – gHupf
            2 days ago






          • 1





            ups. i didn't get the question then. what's inside feature.get('KATASTER') then?

            – GiuServ
            2 days ago











          • I have a layer with an attribute called KATASTER and the KATASTER holds a link for each feature. So with the feature.get('KATASTER') request I am supposed to get back a link. But what I get is the path where the code is saved with the url appended like "C:/Users/user/.../URL", if the project is saved in "C:/Users/user/...". I don't have the problem if I just use feature.get('KATASTER') without the <a href ...>. I just get the unclickable url, but I need a clickable one. I was probably unclear in my question. Is it clear now?

            – gHupf
            2 days ago











          • so if you print out the first feature.get('KATASTER') what are you getting? if it's C:/Users/user/.../URL the problema is where you're assigning KATASTER, so that's why will be usefull to see your feature declaration to find out the problem.

            – GiuServ
            2 days ago






          • 1





            The url starts with ´www´ and that seems to be the problem. If I add ´http://´ everything works fine. I see that it is needed, so the browser recognizes the string as an url.

            – gHupf
            20 hours ago
















          I didn't know about the content option yet, thats definetly a cleaner way to do it, thanks! But still, I get the same as before: Not the url appears in the new browser window, but the path to the project with the url appended shows up.

          – gHupf
          2 days ago





          I didn't know about the content option yet, thats definetly a cleaner way to do it, thanks! But still, I get the same as before: Not the url appears in the new browser window, but the path to the project with the url appended shows up.

          – gHupf
          2 days ago




          1




          1





          ups. i didn't get the question then. what's inside feature.get('KATASTER') then?

          – GiuServ
          2 days ago





          ups. i didn't get the question then. what's inside feature.get('KATASTER') then?

          – GiuServ
          2 days ago













          I have a layer with an attribute called KATASTER and the KATASTER holds a link for each feature. So with the feature.get('KATASTER') request I am supposed to get back a link. But what I get is the path where the code is saved with the url appended like "C:/Users/user/.../URL", if the project is saved in "C:/Users/user/...". I don't have the problem if I just use feature.get('KATASTER') without the <a href ...>. I just get the unclickable url, but I need a clickable one. I was probably unclear in my question. Is it clear now?

          – gHupf
          2 days ago





          I have a layer with an attribute called KATASTER and the KATASTER holds a link for each feature. So with the feature.get('KATASTER') request I am supposed to get back a link. But what I get is the path where the code is saved with the url appended like "C:/Users/user/.../URL", if the project is saved in "C:/Users/user/...". I don't have the problem if I just use feature.get('KATASTER') without the <a href ...>. I just get the unclickable url, but I need a clickable one. I was probably unclear in my question. Is it clear now?

          – gHupf
          2 days ago













          so if you print out the first feature.get('KATASTER') what are you getting? if it's C:/Users/user/.../URL the problema is where you're assigning KATASTER, so that's why will be usefull to see your feature declaration to find out the problem.

          – GiuServ
          2 days ago





          so if you print out the first feature.get('KATASTER') what are you getting? if it's C:/Users/user/.../URL the problema is where you're assigning KATASTER, so that's why will be usefull to see your feature declaration to find out the problem.

          – GiuServ
          2 days ago




          1




          1





          The url starts with ´www´ and that seems to be the problem. If I add ´http://´ everything works fine. I see that it is needed, so the browser recognizes the string as an url.

          – gHupf
          20 hours ago





          The url starts with ´www´ and that seems to be the problem. If I add ´http://´ everything works fine. I see that it is needed, so the browser recognizes the string as an url.

          – gHupf
          20 hours ago



















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