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Jupyter Notebook Add directory/file path to Windows Environment Variable



2019 Community Moderator ElectionHow to set env variable in Jupyter notebookHow do I list all files of a directory?Find all files in a directory with extension .txt in PythonHow to access environment variable values?fatal error: Python.h: No such file or directoryUnable to set up Jupyter NotebookEnvironment Munging in Anaconda, PyCharm, and Jupyter Notebooks? No such file or directory: 'conda'Jupyter notebook wrong pathGraphviz not running in jupyter notebook python = 3.6?No module named 'graphviz' in Jupyter NotebookWindows “jupyter notebook” command failing










0















I need some help with appending a file path to "PATH" variable in Windows 10 from Jupyter Notebook (Python 3.6). I need to do it at run time from notebook because my user account is doesn't have admin rights.



Background:



I want to use GrphViz 2.8 library. For this library to work from Jupyter notebook, the location of dot.exe file i.e. C:Program Files (x86)Graphviz2.38bindot.exe needs to be added to PATH environment variable.



I have seen that os.getenv('Path') command will get me the value of this Path variable but I couldn't find the equivalent set method to append my entry to this Path variable.



I have also seen this post which suggests using kernal.json But I didn't understand how to update the PATH variable.



Any example how to achieve this will be very much appreciated.



If it is not possible, then can you please suggest an alternative way of using GrpahViz without updating "Path" variable.



PS I can't use Online dot-file to SVG/PNG converters because I am using a package which requires GrpahViz to be available locally.






python jupyter-notebook graphviz pygraphviz







share|improve this question



















  • 1





    Best would be to add te mentioned path to the PATH variable of your system. Alternatively you could, probably, use os.putenv or os.environ (see e.g. docs.python.org/3/library/os.html)

    – albert
    2 days ago
















0















I need some help with appending a file path to "PATH" variable in Windows 10 from Jupyter Notebook (Python 3.6). I need to do it at run time from notebook because my user account is doesn't have admin rights.



Background:



I want to use GrphViz 2.8 library. For this library to work from Jupyter notebook, the location of dot.exe file i.e. C:Program Files (x86)Graphviz2.38bindot.exe needs to be added to PATH environment variable.



I have seen that os.getenv('Path') command will get me the value of this Path variable but I couldn't find the equivalent set method to append my entry to this Path variable.



I have also seen this post which suggests using kernal.json But I didn't understand how to update the PATH variable.



Any example how to achieve this will be very much appreciated.



If it is not possible, then can you please suggest an alternative way of using GrpahViz without updating "Path" variable.



PS I can't use Online dot-file to SVG/PNG converters because I am using a package which requires GrpahViz to be available locally.






python jupyter-notebook graphviz pygraphviz







share|improve this question



















  • 1





    Best would be to add te mentioned path to the PATH variable of your system. Alternatively you could, probably, use os.putenv or os.environ (see e.g. docs.python.org/3/library/os.html)

    – albert
    2 days ago














0












0








0








I need some help with appending a file path to "PATH" variable in Windows 10 from Jupyter Notebook (Python 3.6). I need to do it at run time from notebook because my user account is doesn't have admin rights.



Background:



I want to use GrphViz 2.8 library. For this library to work from Jupyter notebook, the location of dot.exe file i.e. C:Program Files (x86)Graphviz2.38bindot.exe needs to be added to PATH environment variable.



I have seen that os.getenv('Path') command will get me the value of this Path variable but I couldn't find the equivalent set method to append my entry to this Path variable.



I have also seen this post which suggests using kernal.json But I didn't understand how to update the PATH variable.



Any example how to achieve this will be very much appreciated.



If it is not possible, then can you please suggest an alternative way of using GrpahViz without updating "Path" variable.



PS I can't use Online dot-file to SVG/PNG converters because I am using a package which requires GrpahViz to be available locally.






python jupyter-notebook graphviz pygraphviz







share|improve this question
















I need some help with appending a file path to "PATH" variable in Windows 10 from Jupyter Notebook (Python 3.6). I need to do it at run time from notebook because my user account is doesn't have admin rights.



Background:



I want to use GrphViz 2.8 library. For this library to work from Jupyter notebook, the location of dot.exe file i.e. C:Program Files (x86)Graphviz2.38bindot.exe needs to be added to PATH environment variable.



I have seen that os.getenv('Path') command will get me the value of this Path variable but I couldn't find the equivalent set method to append my entry to this Path variable.



I have also seen this post which suggests using kernal.json But I didn't understand how to update the PATH variable.



Any example how to achieve this will be very much appreciated.



If it is not possible, then can you please suggest an alternative way of using GrpahViz without updating "Path" variable.



PS I can't use Online dot-file to SVG/PNG converters because I am using a package which requires GrpahViz to be available locally.






python jupyter-notebook graphviz pygraphviz




python jupyter-notebook graphviz pygraphviz






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited yesterday







Khurram Majeed

















asked 2 days ago









Khurram MajeedKhurram Majeed

1,12062648




1,12062648







  • 1





    Best would be to add te mentioned path to the PATH variable of your system. Alternatively you could, probably, use os.putenv or os.environ (see e.g. docs.python.org/3/library/os.html)

    – albert
    2 days ago













  • 1





    Best would be to add te mentioned path to the PATH variable of your system. Alternatively you could, probably, use os.putenv or os.environ (see e.g. docs.python.org/3/library/os.html)

    – albert
    2 days ago








1




1





Best would be to add te mentioned path to the PATH variable of your system. Alternatively you could, probably, use os.putenv or os.environ (see e.g. docs.python.org/3/library/os.html)

– albert
2 days ago






Best would be to add te mentioned path to the PATH variable of your system. Alternatively you could, probably, use os.putenv or os.environ (see e.g. docs.python.org/3/library/os.html)

– albert
2 days ago













1 Answer
1






active

oldest

votes


















1














Try this:



import os
os.environ['PATH'] += os.pathsep + r'C:Program Files (x86)Graphviz2.38bindot.exe'





share|improve this answer























  • path with the name of the executable?

    – albert
    2 days ago











  • Yes @albert, path to the executable file.

    – Hiadore
    2 days ago











  • You write "path to the executable file" but this would, as far as I know, be "C:Program Files (x86)Graphviz2.38bin"

    – albert
    2 days ago











  • I think path to executable mean the full path of the file, include filename. Your case is likely more precisely called path to directory of the executable. See itgeared.com/articles/1059-how-to-change-services-path-to

    – Hiadore
    2 days ago










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1 Answer
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1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes









1














Try this:



import os
os.environ['PATH'] += os.pathsep + r'C:Program Files (x86)Graphviz2.38bindot.exe'





share|improve this answer























  • path with the name of the executable?

    – albert
    2 days ago











  • Yes @albert, path to the executable file.

    – Hiadore
    2 days ago











  • You write "path to the executable file" but this would, as far as I know, be "C:Program Files (x86)Graphviz2.38bin"

    – albert
    2 days ago











  • I think path to executable mean the full path of the file, include filename. Your case is likely more precisely called path to directory of the executable. See itgeared.com/articles/1059-how-to-change-services-path-to

    – Hiadore
    2 days ago















1














Try this:



import os
os.environ['PATH'] += os.pathsep + r'C:Program Files (x86)Graphviz2.38bindot.exe'





share|improve this answer























  • path with the name of the executable?

    – albert
    2 days ago











  • Yes @albert, path to the executable file.

    – Hiadore
    2 days ago











  • You write "path to the executable file" but this would, as far as I know, be "C:Program Files (x86)Graphviz2.38bin"

    – albert
    2 days ago











  • I think path to executable mean the full path of the file, include filename. Your case is likely more precisely called path to directory of the executable. See itgeared.com/articles/1059-how-to-change-services-path-to

    – Hiadore
    2 days ago













1












1








1







Try this:



import os
os.environ['PATH'] += os.pathsep + r'C:Program Files (x86)Graphviz2.38bindot.exe'





share|improve this answer













Try this:



import os
os.environ['PATH'] += os.pathsep + r'C:Program Files (x86)Graphviz2.38bindot.exe'






share|improve this answer












share|improve this answer



share|improve this answer










answered 2 days ago









HiadoreHiadore

20317




20317












  • path with the name of the executable?

    – albert
    2 days ago











  • Yes @albert, path to the executable file.

    – Hiadore
    2 days ago











  • You write "path to the executable file" but this would, as far as I know, be "C:Program Files (x86)Graphviz2.38bin"

    – albert
    2 days ago











  • I think path to executable mean the full path of the file, include filename. Your case is likely more precisely called path to directory of the executable. See itgeared.com/articles/1059-how-to-change-services-path-to

    – Hiadore
    2 days ago

















  • path with the name of the executable?

    – albert
    2 days ago











  • Yes @albert, path to the executable file.

    – Hiadore
    2 days ago











  • You write "path to the executable file" but this would, as far as I know, be "C:Program Files (x86)Graphviz2.38bin"

    – albert
    2 days ago











  • I think path to executable mean the full path of the file, include filename. Your case is likely more precisely called path to directory of the executable. See itgeared.com/articles/1059-how-to-change-services-path-to

    – Hiadore
    2 days ago
















path with the name of the executable?

– albert
2 days ago





path with the name of the executable?

– albert
2 days ago













Yes @albert, path to the executable file.

– Hiadore
2 days ago





Yes @albert, path to the executable file.

– Hiadore
2 days ago













You write "path to the executable file" but this would, as far as I know, be "C:Program Files (x86)Graphviz2.38bin"

– albert
2 days ago





You write "path to the executable file" but this would, as far as I know, be "C:Program Files (x86)Graphviz2.38bin"

– albert
2 days ago













I think path to executable mean the full path of the file, include filename. Your case is likely more precisely called path to directory of the executable. See itgeared.com/articles/1059-how-to-change-services-path-to

– Hiadore
2 days ago





I think path to executable mean the full path of the file, include filename. Your case is likely more precisely called path to directory of the executable. See itgeared.com/articles/1059-how-to-change-services-path-to

– Hiadore
2 days ago



















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