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python numpy std vs scala breeze stddev

2019 Community Moderator ElectionScala: What is the generic way to calculate standard deviationCalling an external command in PythonWhat are metaclasses in Python?Finding the index of an item given a list containing it in PythonDifference between append vs. extend list methods in PythonHow can I safely create a nested directory in Python?Does Python have a ternary conditional operator?How to get the current time in PythonHow can I make a time delay in Python?How to make a flat list out of list of lists?Does Python have a string 'contains' substring method?

I'm currently working on migrating some python code to scala. I'm using breeze lib as a substitution for numpy.

Everything looks fine, but I faced different behaviour in output of standard deviation implementations:

Python:

series = np.array([1,4,5])
np.mean(series) // 3.3333333333333335
np.std(series) // 1.699673171197595

Scala:

val vector = breeze.linalg.Vector[Double](Array(1.0, 4.0, 5.0))
val mean = breeze.stats.mean(vector) // 3.3333333333333335
val std = breeze.stats.stddev(vector) // 2.081665999466133

I know how to reproduce python's behaviour in plain scala. Sample code is presented here: Scala: What is the generic way to calculate standard deviation

But I'm looking for a way to get it with breeze. Any ideas?

edited Oct 17 '18 at 13:46

martineau

68.8k1091185

asked Oct 17 '18 at 13:24

Normal

5461423

add a comment |

I'm currently working on migrating some python code to scala. I'm using breeze lib as a substitution for numpy.

Everything looks fine, but I faced different behaviour in output of standard deviation implementations:

Python:

series = np.array([1,4,5])
np.mean(series) // 3.3333333333333335
np.std(series) // 1.699673171197595

Scala:

val vector = breeze.linalg.Vector[Double](Array(1.0, 4.0, 5.0))
val mean = breeze.stats.mean(vector) // 3.3333333333333335
val std = breeze.stats.stddev(vector) // 2.081665999466133

I know how to reproduce python's behaviour in plain scala. Sample code is presented here: Scala: What is the generic way to calculate standard deviation

But I'm looking for a way to get it with breeze. Any ideas?

edited Oct 17 '18 at 13:46

martineau

68.8k1091185

asked Oct 17 '18 at 13:24

Normal

5461423

add a comment |

I'm currently working on migrating some python code to scala. I'm using breeze lib as a substitution for numpy.

Everything looks fine, but I faced different behaviour in output of standard deviation implementations:

Python:

series = np.array([1,4,5])
np.mean(series) // 3.3333333333333335
np.std(series) // 1.699673171197595

Scala:

val vector = breeze.linalg.Vector[Double](Array(1.0, 4.0, 5.0))
val mean = breeze.stats.mean(vector) // 3.3333333333333335
val std = breeze.stats.stddev(vector) // 2.081665999466133

I know how to reproduce python's behaviour in plain scala. Sample code is presented here: Scala: What is the generic way to calculate standard deviation

But I'm looking for a way to get it with breeze. Any ideas?

edited Oct 17 '18 at 13:46

martineau

68.8k1091185

asked Oct 17 '18 at 13:24

Normal

5461423

I'm currently working on migrating some python code to scala. I'm using breeze lib as a substitution for numpy.

Everything looks fine, but I faced different behaviour in output of standard deviation implementations:

Python:

series = np.array([1,4,5])
np.mean(series) // 3.3333333333333335
np.std(series) // 1.699673171197595

Scala:

val vector = breeze.linalg.Vector[Double](Array(1.0, 4.0, 5.0))
val mean = breeze.stats.mean(vector) // 3.3333333333333335
val std = breeze.stats.stddev(vector) // 2.081665999466133

I know how to reproduce python's behaviour in plain scala. Sample code is presented here: Scala: What is the generic way to calculate standard deviation

But I'm looking for a way to get it with breeze. Any ideas?

python scala scala-breeze

edited Oct 17 '18 at 13:46

martineau

68.8k1091185

asked Oct 17 '18 at 13:24

Normal

5461423

edited Oct 17 '18 at 13:46

martineau

68.8k1091185

asked Oct 17 '18 at 13:24

Normal

5461423

edited Oct 17 '18 at 13:46

martineau

68.8k1091185

edited Oct 17 '18 at 13:46

martineau

68.8k1091185

edited Oct 17 '18 at 13:46

martineau

68.8k1091185

asked Oct 17 '18 at 13:24

Normal

5461423

asked Oct 17 '18 at 13:24

Normal

5461423

asked Oct 17 '18 at 13:24

Normal

5461423

add a comment |

2 Answers
2

active

oldest

votes

This is related to the number of degrees of freedom. Indeed,

>>> np.std(series, ddof=1)
2.081665999466133

Which is the sample std. With breeze, something you can do to get the population std is

var n = 3
val std = breeze.stats.stddev(vector)*Math.pow((n-1)/n, .5)
# 1.6996731711975948

edited Oct 17 '18 at 13:45

answered Oct 17 '18 at 13:30

keepAlive

3,18541224

Thanks for explanation. I've found related issue in breeze GitHub page: github.com/scalanlp/breeze/issues/507

– Normal
Oct 17 '18 at 13:40

@Normal This may be something you know but see my update regarding how to deal with this issue.

– keepAlive
Oct 17 '18 at 14:01

1

works for me, thanks!

– Normal
Oct 17 '18 at 14:26

add a comment |

If keepAlive's solution don't work, you should change "n" to Double

var n : Double = 3
val std = breeze.stats.stddev(vector)*Math.pow((n-1)/n, .5)
# 1.6996731711975948

answered 2 days ago

Pablo López Gallego

add a comment |

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2 Answers
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2 Answers
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active

oldest

votes

This is related to the number of degrees of freedom. Indeed,

>>> np.std(series, ddof=1)
2.081665999466133

Which is the sample std. With breeze, something you can do to get the population std is

var n = 3
val std = breeze.stats.stddev(vector)*Math.pow((n-1)/n, .5)
# 1.6996731711975948

edited Oct 17 '18 at 13:45

answered Oct 17 '18 at 13:30

keepAlive

3,18541224

Thanks for explanation. I've found related issue in breeze GitHub page: github.com/scalanlp/breeze/issues/507

– Normal
Oct 17 '18 at 13:40

@Normal This may be something you know but see my update regarding how to deal with this issue.

– keepAlive
Oct 17 '18 at 14:01

1

works for me, thanks!

– Normal
Oct 17 '18 at 14:26

add a comment |

This is related to the number of degrees of freedom. Indeed,

>>> np.std(series, ddof=1)
2.081665999466133

Which is the sample std. With breeze, something you can do to get the population std is

var n = 3
val std = breeze.stats.stddev(vector)*Math.pow((n-1)/n, .5)
# 1.6996731711975948

edited Oct 17 '18 at 13:45

answered Oct 17 '18 at 13:30

keepAlive

3,18541224

Thanks for explanation. I've found related issue in breeze GitHub page: github.com/scalanlp/breeze/issues/507

– Normal
Oct 17 '18 at 13:40

@Normal This may be something you know but see my update regarding how to deal with this issue.

– keepAlive
Oct 17 '18 at 14:01

1

works for me, thanks!

– Normal
Oct 17 '18 at 14:26

add a comment |

This is related to the number of degrees of freedom. Indeed,

>>> np.std(series, ddof=1)
2.081665999466133

Which is the sample std. With breeze, something you can do to get the population std is

var n = 3
val std = breeze.stats.stddev(vector)*Math.pow((n-1)/n, .5)
# 1.6996731711975948

edited Oct 17 '18 at 13:45

answered Oct 17 '18 at 13:30

keepAlive

3,18541224

This is related to the number of degrees of freedom. Indeed,

>>> np.std(series, ddof=1)
2.081665999466133

Which is the sample std. With breeze, something you can do to get the population std is

var n = 3
val std = breeze.stats.stddev(vector)*Math.pow((n-1)/n, .5)
# 1.6996731711975948

edited Oct 17 '18 at 13:45

answered Oct 17 '18 at 13:30

keepAlive

3,18541224

edited Oct 17 '18 at 13:45

answered Oct 17 '18 at 13:30

keepAlive

3,18541224

answered Oct 17 '18 at 13:30

keepAlive

3,18541224

answered Oct 17 '18 at 13:30

keepAlive

3,18541224

Thanks for explanation. I've found related issue in breeze GitHub page: github.com/scalanlp/breeze/issues/507

– Normal
Oct 17 '18 at 13:40

@Normal This may be something you know but see my update regarding how to deal with this issue.

– keepAlive
Oct 17 '18 at 14:01

1

works for me, thanks!

– Normal
Oct 17 '18 at 14:26

add a comment |

Thanks for explanation. I've found related issue in breeze GitHub page: github.com/scalanlp/breeze/issues/507

– Normal
Oct 17 '18 at 13:40

@Normal This may be something you know but see my update regarding how to deal with this issue.

– keepAlive
Oct 17 '18 at 14:01

1

works for me, thanks!

– Normal
Oct 17 '18 at 14:26

Thanks for explanation. I've found related issue in breeze GitHub page: github.com/scalanlp/breeze/issues/507

– Normal
Oct 17 '18 at 13:40

@Normal This may be something you know but see my update regarding how to deal with this issue.

– keepAlive
Oct 17 '18 at 14:01

works for me, thanks!

– Normal
Oct 17 '18 at 14:26

add a comment |

If keepAlive's solution don't work, you should change "n" to Double

var n : Double = 3
val std = breeze.stats.stddev(vector)*Math.pow((n-1)/n, .5)
# 1.6996731711975948

answered 2 days ago

Pablo López Gallego

add a comment |

If keepAlive's solution don't work, you should change "n" to Double

var n : Double = 3
val std = breeze.stats.stddev(vector)*Math.pow((n-1)/n, .5)
# 1.6996731711975948

answered 2 days ago

Pablo López Gallego

add a comment |

If keepAlive's solution don't work, you should change "n" to Double

var n : Double = 3
val std = breeze.stats.stddev(vector)*Math.pow((n-1)/n, .5)
# 1.6996731711975948

answered 2 days ago

Pablo López Gallego

If keepAlive's solution don't work, you should change "n" to Double

var n : Double = 3
val std = breeze.stats.stddev(vector)*Math.pow((n-1)/n, .5)
# 1.6996731711975948

answered 2 days ago

Pablo López Gallego

answered 2 days ago

Pablo López Gallego

answered 2 days ago

Pablo López Gallego

answered 2 days ago

Pablo López Gallego

add a comment |

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