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Difference in values with out-of-sample technique between forecast and predict in R



2019 Community Moderator ElectionWhat is the difference between a generative and a discriminative algorithm?What are the differences between “=” and “<-” in R?What's the difference between ViewData and ViewBag?What is the difference between require() and library()?What is the difference between JVM, JDK, JRE & OpenJDK?R, Times Series, Arima Model, Forecasting, Daily dataDifferences between Oracle JDK and OpenJDKR ARIMA model giving odd resultsOut of Sample forecast with auto.arima() and xregStatsmodels: Implementing a direct and recursive multi-step forecasting strategy with ARIMA










0















I am trying to figure out the difference between the forecastand predictmethod.



I have the following. The data can be found on the DataMarket website.



Both functions give the same value for a forecast with full data but not with an out-of-sample technique. Shouldn't it be the same since Arima is a wrapper around arima ?



> library(forecast)
> library(tidyverse)
>
> data = read.csv("Data/monthly-lake-erie-levels-1921-19.csv", sep = ",", header = TRUE)
> data = data[-dim(data)[1],]
>
> y = ts(data$Monthly.Lake.Erie.Levels.1921...1970.,
+ frequency = 12,
+ start = c(1921,1))
>
> model.arima = arima(y, order = c(0, 1, 1), seasonal = c(0, 1, 0))
> model.Arima = Arima(y, order = c(0, 1, 1), seasonal = c(0, 1, 0))
>
> preds.arima = predict(model.arima, n.ahead=1)$pred[1]
> preds.Arima = forecast(model.Arima, h=1)$mean[1]
>
> preds.Arima
[1] 15.51397
> preds.arima
[1] 15.51397
>
> S = round(0.75 * length(y))
> h = 1
> errors.a = c()
> errors.A = c()
> preds.a = c()
> preds.A = c()
>
> for (i in S:(length(y) - h))
+
+ model.sub.a = arima(y[1:i], order = c(0, 1, 1), seasonal = c(0, 1, 0))
+ pred.a = predict(model.sub.a, n.ahead = h)$pred[h]
+ preds.a = c(preds.a, pred.a)
+ errors.a = c(errors.a, y[i + h] - pred.a)
+
+ model.sub.A = Arima(y[1:i], order = c(0, 1, 1), seasonal = c(0, 1, 0))
+ pred.A = forecast(model.sub.A, h = h)$mean[h]
+ preds.A = c(preds.A, pred.A)
+ errors.A = c(errors.A, y[i + h] - pred.A)
+
>
> all = cbind(errors.A, errors.a, preds.A, preds.a)
>
> head(all)
errors.A errors.a preds.A preds.a
[1,] 0.4352598 0.27795891 14.53674 14.69404
[2,] -0.1875257 -0.42878261 15.15953 15.40078
[3,] -0.3183146 -0.49988640 14.89131 15.07289
[4,] -0.6598827 -0.51497911 14.43588 14.29098
[5,] -0.4743845 -0.08133969 13.49138 13.09834
[6,] -0.2121536 0.32318767 12.81215 12.27681









share|improve this question









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antoinetorrini is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
























    0















    I am trying to figure out the difference between the forecastand predictmethod.



    I have the following. The data can be found on the DataMarket website.



    Both functions give the same value for a forecast with full data but not with an out-of-sample technique. Shouldn't it be the same since Arima is a wrapper around arima ?



    > library(forecast)
    > library(tidyverse)
    >
    > data = read.csv("Data/monthly-lake-erie-levels-1921-19.csv", sep = ",", header = TRUE)
    > data = data[-dim(data)[1],]
    >
    > y = ts(data$Monthly.Lake.Erie.Levels.1921...1970.,
    + frequency = 12,
    + start = c(1921,1))
    >
    > model.arima = arima(y, order = c(0, 1, 1), seasonal = c(0, 1, 0))
    > model.Arima = Arima(y, order = c(0, 1, 1), seasonal = c(0, 1, 0))
    >
    > preds.arima = predict(model.arima, n.ahead=1)$pred[1]
    > preds.Arima = forecast(model.Arima, h=1)$mean[1]
    >
    > preds.Arima
    [1] 15.51397
    > preds.arima
    [1] 15.51397
    >
    > S = round(0.75 * length(y))
    > h = 1
    > errors.a = c()
    > errors.A = c()
    > preds.a = c()
    > preds.A = c()
    >
    > for (i in S:(length(y) - h))
    +
    + model.sub.a = arima(y[1:i], order = c(0, 1, 1), seasonal = c(0, 1, 0))
    + pred.a = predict(model.sub.a, n.ahead = h)$pred[h]
    + preds.a = c(preds.a, pred.a)
    + errors.a = c(errors.a, y[i + h] - pred.a)
    +
    + model.sub.A = Arima(y[1:i], order = c(0, 1, 1), seasonal = c(0, 1, 0))
    + pred.A = forecast(model.sub.A, h = h)$mean[h]
    + preds.A = c(preds.A, pred.A)
    + errors.A = c(errors.A, y[i + h] - pred.A)
    +
    >
    > all = cbind(errors.A, errors.a, preds.A, preds.a)
    >
    > head(all)
    errors.A errors.a preds.A preds.a
    [1,] 0.4352598 0.27795891 14.53674 14.69404
    [2,] -0.1875257 -0.42878261 15.15953 15.40078
    [3,] -0.3183146 -0.49988640 14.89131 15.07289
    [4,] -0.6598827 -0.51497911 14.43588 14.29098
    [5,] -0.4743845 -0.08133969 13.49138 13.09834
    [6,] -0.2121536 0.32318767 12.81215 12.27681









    share|improve this question









    New contributor




    antoinetorrini is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






















      0












      0








      0








      I am trying to figure out the difference between the forecastand predictmethod.



      I have the following. The data can be found on the DataMarket website.



      Both functions give the same value for a forecast with full data but not with an out-of-sample technique. Shouldn't it be the same since Arima is a wrapper around arima ?



      > library(forecast)
      > library(tidyverse)
      >
      > data = read.csv("Data/monthly-lake-erie-levels-1921-19.csv", sep = ",", header = TRUE)
      > data = data[-dim(data)[1],]
      >
      > y = ts(data$Monthly.Lake.Erie.Levels.1921...1970.,
      + frequency = 12,
      + start = c(1921,1))
      >
      > model.arima = arima(y, order = c(0, 1, 1), seasonal = c(0, 1, 0))
      > model.Arima = Arima(y, order = c(0, 1, 1), seasonal = c(0, 1, 0))
      >
      > preds.arima = predict(model.arima, n.ahead=1)$pred[1]
      > preds.Arima = forecast(model.Arima, h=1)$mean[1]
      >
      > preds.Arima
      [1] 15.51397
      > preds.arima
      [1] 15.51397
      >
      > S = round(0.75 * length(y))
      > h = 1
      > errors.a = c()
      > errors.A = c()
      > preds.a = c()
      > preds.A = c()
      >
      > for (i in S:(length(y) - h))
      +
      + model.sub.a = arima(y[1:i], order = c(0, 1, 1), seasonal = c(0, 1, 0))
      + pred.a = predict(model.sub.a, n.ahead = h)$pred[h]
      + preds.a = c(preds.a, pred.a)
      + errors.a = c(errors.a, y[i + h] - pred.a)
      +
      + model.sub.A = Arima(y[1:i], order = c(0, 1, 1), seasonal = c(0, 1, 0))
      + pred.A = forecast(model.sub.A, h = h)$mean[h]
      + preds.A = c(preds.A, pred.A)
      + errors.A = c(errors.A, y[i + h] - pred.A)
      +
      >
      > all = cbind(errors.A, errors.a, preds.A, preds.a)
      >
      > head(all)
      errors.A errors.a preds.A preds.a
      [1,] 0.4352598 0.27795891 14.53674 14.69404
      [2,] -0.1875257 -0.42878261 15.15953 15.40078
      [3,] -0.3183146 -0.49988640 14.89131 15.07289
      [4,] -0.6598827 -0.51497911 14.43588 14.29098
      [5,] -0.4743845 -0.08133969 13.49138 13.09834
      [6,] -0.2121536 0.32318767 12.81215 12.27681









      share|improve this question









      New contributor




      antoinetorrini is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      I am trying to figure out the difference between the forecastand predictmethod.



      I have the following. The data can be found on the DataMarket website.



      Both functions give the same value for a forecast with full data but not with an out-of-sample technique. Shouldn't it be the same since Arima is a wrapper around arima ?



      > library(forecast)
      > library(tidyverse)
      >
      > data = read.csv("Data/monthly-lake-erie-levels-1921-19.csv", sep = ",", header = TRUE)
      > data = data[-dim(data)[1],]
      >
      > y = ts(data$Monthly.Lake.Erie.Levels.1921...1970.,
      + frequency = 12,
      + start = c(1921,1))
      >
      > model.arima = arima(y, order = c(0, 1, 1), seasonal = c(0, 1, 0))
      > model.Arima = Arima(y, order = c(0, 1, 1), seasonal = c(0, 1, 0))
      >
      > preds.arima = predict(model.arima, n.ahead=1)$pred[1]
      > preds.Arima = forecast(model.Arima, h=1)$mean[1]
      >
      > preds.Arima
      [1] 15.51397
      > preds.arima
      [1] 15.51397
      >
      > S = round(0.75 * length(y))
      > h = 1
      > errors.a = c()
      > errors.A = c()
      > preds.a = c()
      > preds.A = c()
      >
      > for (i in S:(length(y) - h))
      +
      + model.sub.a = arima(y[1:i], order = c(0, 1, 1), seasonal = c(0, 1, 0))
      + pred.a = predict(model.sub.a, n.ahead = h)$pred[h]
      + preds.a = c(preds.a, pred.a)
      + errors.a = c(errors.a, y[i + h] - pred.a)
      +
      + model.sub.A = Arima(y[1:i], order = c(0, 1, 1), seasonal = c(0, 1, 0))
      + pred.A = forecast(model.sub.A, h = h)$mean[h]
      + preds.A = c(preds.A, pred.A)
      + errors.A = c(errors.A, y[i + h] - pred.A)
      +
      >
      > all = cbind(errors.A, errors.a, preds.A, preds.a)
      >
      > head(all)
      errors.A errors.a preds.A preds.a
      [1,] 0.4352598 0.27795891 14.53674 14.69404
      [2,] -0.1875257 -0.42878261 15.15953 15.40078
      [3,] -0.3183146 -0.49988640 14.89131 15.07289
      [4,] -0.6598827 -0.51497911 14.43588 14.29098
      [5,] -0.4743845 -0.08133969 13.49138 13.09834
      [6,] -0.2121536 0.32318767 12.81215 12.27681






      r difference predict forecast






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      share|improve this question








      edited 2 days ago









      Arun kumar mahesh

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      asked 2 days ago









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