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How to get Python Compound Interest Calculator to give the correct answer
final = P * (((1 + (r/n)) ** (n*t))) TypeError: unsupported operand type(s) for /: 'str' and 'int'How do I copy a file in Python?How can I safely create a nested directory in Python?How do I parse a string to a float or int in Python?How to get the current time in PythonHow can I make a time delay in Python?Getting the last element of a list in PythonHow do I get the number of elements in a list in Python?How do I concatenate two lists in Python?How do I lowercase a string in Python?Interest Calculator In Python
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Had posted a question earlier about errors. Thanks to a few people here I was able to fix that issue. Now I've run into the issues of my Compound Interest Calculator giving the wrong calculation when you input the principal, compounded interest (yearly, monthly, etc..), interest rate (0.03, etc...), and the amount of years.
Other Q link: final = P * (((1 + (r/n)) ** (n*t))) TypeError: unsupported operand type(s) for /: 'str' and 'int'
So from the previous code I removed p = 10000, n = 12, r = 0.08 because it would give a large number when you input different numbers. My hope was it would calculate it with the numbers inputted, but it doesn't.
# User must input principal, Compound rate, annual rate, and years.
P = int(input("Enter starting principle please. "))
n = int(input("Enter Compound intrest rate.(daily, monthly, quarterly, half-year, yearly) "))
r = float(input("Enter annual interest amount. (decimal) "))
t = int(input("Enter the amount of years. "))
final = P * (((1 + (r/n)) ** (n*t)))
#displays the final amount after number of years.
print ("The final amount after", t, "years is", final)
# At the moment it is displaying a very random number.
Enter starting principle please. 1000
Enter Compound intrest rate.(daily, monthly, quarterly, half-year, yearly) 1
Enter annual interest amount. (decimal) 0.01
Enter the amount of years. 1
The final amount after 1 years is 1010.0
The final amount should be 1000.10. Not sure what is going on. Trying to see if there is a way to make P, n, r equal the number a user inputs that will result in the correct final answer.
Thanks in advance.
python calculator
add a comment |
Had posted a question earlier about errors. Thanks to a few people here I was able to fix that issue. Now I've run into the issues of my Compound Interest Calculator giving the wrong calculation when you input the principal, compounded interest (yearly, monthly, etc..), interest rate (0.03, etc...), and the amount of years.
Other Q link: final = P * (((1 + (r/n)) ** (n*t))) TypeError: unsupported operand type(s) for /: 'str' and 'int'
So from the previous code I removed p = 10000, n = 12, r = 0.08 because it would give a large number when you input different numbers. My hope was it would calculate it with the numbers inputted, but it doesn't.
# User must input principal, Compound rate, annual rate, and years.
P = int(input("Enter starting principle please. "))
n = int(input("Enter Compound intrest rate.(daily, monthly, quarterly, half-year, yearly) "))
r = float(input("Enter annual interest amount. (decimal) "))
t = int(input("Enter the amount of years. "))
final = P * (((1 + (r/n)) ** (n*t)))
#displays the final amount after number of years.
print ("The final amount after", t, "years is", final)
# At the moment it is displaying a very random number.
Enter starting principle please. 1000
Enter Compound intrest rate.(daily, monthly, quarterly, half-year, yearly) 1
Enter annual interest amount. (decimal) 0.01
Enter the amount of years. 1
The final amount after 1 years is 1010.0
The final amount should be 1000.10. Not sure what is going on. Trying to see if there is a way to make P, n, r equal the number a user inputs that will result in the correct final answer.
Thanks in advance.
python calculator
Why should it be 1000.10? If I understand correctly, yearly compound interest rate 0.01, so 1000*(1.01)^1=1010.0. Am I missing something here?
– Sagar Waghmode
Jan 22 '16 at 17:33
When I run the number through a compound interest calculator to triple check the answer it gives me 1000.10.
– Joshua Gremo
Jan 22 '16 at 17:40
Added an answer. Please check if this is what you want.
– Sagar Waghmode
Jan 22 '16 at 17:42
add a comment |
Had posted a question earlier about errors. Thanks to a few people here I was able to fix that issue. Now I've run into the issues of my Compound Interest Calculator giving the wrong calculation when you input the principal, compounded interest (yearly, monthly, etc..), interest rate (0.03, etc...), and the amount of years.
Other Q link: final = P * (((1 + (r/n)) ** (n*t))) TypeError: unsupported operand type(s) for /: 'str' and 'int'
So from the previous code I removed p = 10000, n = 12, r = 0.08 because it would give a large number when you input different numbers. My hope was it would calculate it with the numbers inputted, but it doesn't.
# User must input principal, Compound rate, annual rate, and years.
P = int(input("Enter starting principle please. "))
n = int(input("Enter Compound intrest rate.(daily, monthly, quarterly, half-year, yearly) "))
r = float(input("Enter annual interest amount. (decimal) "))
t = int(input("Enter the amount of years. "))
final = P * (((1 + (r/n)) ** (n*t)))
#displays the final amount after number of years.
print ("The final amount after", t, "years is", final)
# At the moment it is displaying a very random number.
Enter starting principle please. 1000
Enter Compound intrest rate.(daily, monthly, quarterly, half-year, yearly) 1
Enter annual interest amount. (decimal) 0.01
Enter the amount of years. 1
The final amount after 1 years is 1010.0
The final amount should be 1000.10. Not sure what is going on. Trying to see if there is a way to make P, n, r equal the number a user inputs that will result in the correct final answer.
Thanks in advance.
python calculator
Had posted a question earlier about errors. Thanks to a few people here I was able to fix that issue. Now I've run into the issues of my Compound Interest Calculator giving the wrong calculation when you input the principal, compounded interest (yearly, monthly, etc..), interest rate (0.03, etc...), and the amount of years.
Other Q link: final = P * (((1 + (r/n)) ** (n*t))) TypeError: unsupported operand type(s) for /: 'str' and 'int'
So from the previous code I removed p = 10000, n = 12, r = 0.08 because it would give a large number when you input different numbers. My hope was it would calculate it with the numbers inputted, but it doesn't.
# User must input principal, Compound rate, annual rate, and years.
P = int(input("Enter starting principle please. "))
n = int(input("Enter Compound intrest rate.(daily, monthly, quarterly, half-year, yearly) "))
r = float(input("Enter annual interest amount. (decimal) "))
t = int(input("Enter the amount of years. "))
final = P * (((1 + (r/n)) ** (n*t)))
#displays the final amount after number of years.
print ("The final amount after", t, "years is", final)
# At the moment it is displaying a very random number.
Enter starting principle please. 1000
Enter Compound intrest rate.(daily, monthly, quarterly, half-year, yearly) 1
Enter annual interest amount. (decimal) 0.01
Enter the amount of years. 1
The final amount after 1 years is 1010.0
The final amount should be 1000.10. Not sure what is going on. Trying to see if there is a way to make P, n, r equal the number a user inputs that will result in the correct final answer.
Thanks in advance.
python calculator
python calculator
edited May 23 '17 at 12:31
Community♦
11
11
asked Jan 22 '16 at 17:30
Joshua GremoJoshua Gremo
6115
6115
Why should it be 1000.10? If I understand correctly, yearly compound interest rate 0.01, so 1000*(1.01)^1=1010.0. Am I missing something here?
– Sagar Waghmode
Jan 22 '16 at 17:33
When I run the number through a compound interest calculator to triple check the answer it gives me 1000.10.
– Joshua Gremo
Jan 22 '16 at 17:40
Added an answer. Please check if this is what you want.
– Sagar Waghmode
Jan 22 '16 at 17:42
add a comment |
Why should it be 1000.10? If I understand correctly, yearly compound interest rate 0.01, so 1000*(1.01)^1=1010.0. Am I missing something here?
– Sagar Waghmode
Jan 22 '16 at 17:33
When I run the number through a compound interest calculator to triple check the answer it gives me 1000.10.
– Joshua Gremo
Jan 22 '16 at 17:40
Added an answer. Please check if this is what you want.
– Sagar Waghmode
Jan 22 '16 at 17:42
Why should it be 1000.10? If I understand correctly, yearly compound interest rate 0.01, so 1000*(1.01)^1=1010.0. Am I missing something here?
– Sagar Waghmode
Jan 22 '16 at 17:33
Why should it be 1000.10? If I understand correctly, yearly compound interest rate 0.01, so 1000*(1.01)^1=1010.0. Am I missing something here?
– Sagar Waghmode
Jan 22 '16 at 17:33
When I run the number through a compound interest calculator to triple check the answer it gives me 1000.10.
– Joshua Gremo
Jan 22 '16 at 17:40
When I run the number through a compound interest calculator to triple check the answer it gives me 1000.10.
– Joshua Gremo
Jan 22 '16 at 17:40
Added an answer. Please check if this is what you want.
– Sagar Waghmode
Jan 22 '16 at 17:42
Added an answer. Please check if this is what you want.
– Sagar Waghmode
Jan 22 '16 at 17:42
add a comment |
4 Answers
4
active
oldest
votes
If you are entering interest in percentages, you should take care of that in your code.
final = P * (((1 + (r/(100.0 * n))) ** (n*t)))
Ahhh. didn't even think about that. Thanks, I will run it now and let you know.
– Joshua Gremo
Jan 22 '16 at 17:42
It works! Thank you, been doing these projects since 6am, can't believe I missed that. Appreciate the help @ Sagar
– Joshua Gremo
Jan 22 '16 at 17:44
Welcome. Please accept the answer if it solved your problem. :P
– Sagar Waghmode
Jan 22 '16 at 17:45
add a comment |
Please try the below Python code for Compound Interest:
p = float(input('Please enter principal amount:'))
t = float(input('Please enter number of years:'))
r = float(input('Please enter rate of interest:'))
n = float(input('Please enter number of times the interest is compounded in a year:'))
a = p*(1+(r/(100*n))**(n*t))
print('Amount compounded to: ', a)
add a comment |
Based on this:
Compound Interest Formula
FV = P (1 + r / n)^Yn,
where P is the starting principal, r is the annual interest rate, Y is the number of years invested, and n is the number of compounding periods per year. FV is the future value, meaning the amount the principal grows to after Y years.
P = int(input("Enter starting principle please. "))
n = int(input("Enter number of compounding periods per year. "))
r = float(input("Enter annual interest rate. e.g. 15 for 15% "))
y = int(input("Enter the amount of years. "))
FV = P * (((1 + ((r/100.0)/n)) ** (n*y)))
print ("The final amount after", y, "years is", FV)
add a comment |
P = int(input("Enter starting principle please: "))
n = int(input("Enter number of compounding periods per year: "))
r = float(input("Enter annual interest rate: "))
y = int(input("Enter the amount of years: "))
FV = P * (((1 + ((r/100.0)/n)) ** (n*y)))
print ("The final amount after", y, "years is", FV)
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you are entering interest in percentages, you should take care of that in your code.
final = P * (((1 + (r/(100.0 * n))) ** (n*t)))
Ahhh. didn't even think about that. Thanks, I will run it now and let you know.
– Joshua Gremo
Jan 22 '16 at 17:42
It works! Thank you, been doing these projects since 6am, can't believe I missed that. Appreciate the help @ Sagar
– Joshua Gremo
Jan 22 '16 at 17:44
Welcome. Please accept the answer if it solved your problem. :P
– Sagar Waghmode
Jan 22 '16 at 17:45
add a comment |
If you are entering interest in percentages, you should take care of that in your code.
final = P * (((1 + (r/(100.0 * n))) ** (n*t)))
Ahhh. didn't even think about that. Thanks, I will run it now and let you know.
– Joshua Gremo
Jan 22 '16 at 17:42
It works! Thank you, been doing these projects since 6am, can't believe I missed that. Appreciate the help @ Sagar
– Joshua Gremo
Jan 22 '16 at 17:44
Welcome. Please accept the answer if it solved your problem. :P
– Sagar Waghmode
Jan 22 '16 at 17:45
add a comment |
If you are entering interest in percentages, you should take care of that in your code.
final = P * (((1 + (r/(100.0 * n))) ** (n*t)))
If you are entering interest in percentages, you should take care of that in your code.
final = P * (((1 + (r/(100.0 * n))) ** (n*t)))
answered Jan 22 '16 at 17:39
Sagar WaghmodeSagar Waghmode
637414
637414
Ahhh. didn't even think about that. Thanks, I will run it now and let you know.
– Joshua Gremo
Jan 22 '16 at 17:42
It works! Thank you, been doing these projects since 6am, can't believe I missed that. Appreciate the help @ Sagar
– Joshua Gremo
Jan 22 '16 at 17:44
Welcome. Please accept the answer if it solved your problem. :P
– Sagar Waghmode
Jan 22 '16 at 17:45
add a comment |
Ahhh. didn't even think about that. Thanks, I will run it now and let you know.
– Joshua Gremo
Jan 22 '16 at 17:42
It works! Thank you, been doing these projects since 6am, can't believe I missed that. Appreciate the help @ Sagar
– Joshua Gremo
Jan 22 '16 at 17:44
Welcome. Please accept the answer if it solved your problem. :P
– Sagar Waghmode
Jan 22 '16 at 17:45
Ahhh. didn't even think about that. Thanks, I will run it now and let you know.
– Joshua Gremo
Jan 22 '16 at 17:42
Ahhh. didn't even think about that. Thanks, I will run it now and let you know.
– Joshua Gremo
Jan 22 '16 at 17:42
It works! Thank you, been doing these projects since 6am, can't believe I missed that. Appreciate the help @ Sagar
– Joshua Gremo
Jan 22 '16 at 17:44
It works! Thank you, been doing these projects since 6am, can't believe I missed that. Appreciate the help @ Sagar
– Joshua Gremo
Jan 22 '16 at 17:44
Welcome. Please accept the answer if it solved your problem. :P
– Sagar Waghmode
Jan 22 '16 at 17:45
Welcome. Please accept the answer if it solved your problem. :P
– Sagar Waghmode
Jan 22 '16 at 17:45
add a comment |
Please try the below Python code for Compound Interest:
p = float(input('Please enter principal amount:'))
t = float(input('Please enter number of years:'))
r = float(input('Please enter rate of interest:'))
n = float(input('Please enter number of times the interest is compounded in a year:'))
a = p*(1+(r/(100*n))**(n*t))
print('Amount compounded to: ', a)
add a comment |
Please try the below Python code for Compound Interest:
p = float(input('Please enter principal amount:'))
t = float(input('Please enter number of years:'))
r = float(input('Please enter rate of interest:'))
n = float(input('Please enter number of times the interest is compounded in a year:'))
a = p*(1+(r/(100*n))**(n*t))
print('Amount compounded to: ', a)
add a comment |
Please try the below Python code for Compound Interest:
p = float(input('Please enter principal amount:'))
t = float(input('Please enter number of years:'))
r = float(input('Please enter rate of interest:'))
n = float(input('Please enter number of times the interest is compounded in a year:'))
a = p*(1+(r/(100*n))**(n*t))
print('Amount compounded to: ', a)
Please try the below Python code for Compound Interest:
p = float(input('Please enter principal amount:'))
t = float(input('Please enter number of years:'))
r = float(input('Please enter rate of interest:'))
n = float(input('Please enter number of times the interest is compounded in a year:'))
a = p*(1+(r/(100*n))**(n*t))
print('Amount compounded to: ', a)
edited Mar 8 at 4:30
Pikachu the Purple Wizard
2,06561529
2,06561529
answered Mar 8 at 4:07
Srihari RaoSrihari Rao
112
112
add a comment |
add a comment |
Based on this:
Compound Interest Formula
FV = P (1 + r / n)^Yn,
where P is the starting principal, r is the annual interest rate, Y is the number of years invested, and n is the number of compounding periods per year. FV is the future value, meaning the amount the principal grows to after Y years.
P = int(input("Enter starting principle please. "))
n = int(input("Enter number of compounding periods per year. "))
r = float(input("Enter annual interest rate. e.g. 15 for 15% "))
y = int(input("Enter the amount of years. "))
FV = P * (((1 + ((r/100.0)/n)) ** (n*y)))
print ("The final amount after", y, "years is", FV)
add a comment |
Based on this:
Compound Interest Formula
FV = P (1 + r / n)^Yn,
where P is the starting principal, r is the annual interest rate, Y is the number of years invested, and n is the number of compounding periods per year. FV is the future value, meaning the amount the principal grows to after Y years.
P = int(input("Enter starting principle please. "))
n = int(input("Enter number of compounding periods per year. "))
r = float(input("Enter annual interest rate. e.g. 15 for 15% "))
y = int(input("Enter the amount of years. "))
FV = P * (((1 + ((r/100.0)/n)) ** (n*y)))
print ("The final amount after", y, "years is", FV)
add a comment |
Based on this:
Compound Interest Formula
FV = P (1 + r / n)^Yn,
where P is the starting principal, r is the annual interest rate, Y is the number of years invested, and n is the number of compounding periods per year. FV is the future value, meaning the amount the principal grows to after Y years.
P = int(input("Enter starting principle please. "))
n = int(input("Enter number of compounding periods per year. "))
r = float(input("Enter annual interest rate. e.g. 15 for 15% "))
y = int(input("Enter the amount of years. "))
FV = P * (((1 + ((r/100.0)/n)) ** (n*y)))
print ("The final amount after", y, "years is", FV)
Based on this:
Compound Interest Formula
FV = P (1 + r / n)^Yn,
where P is the starting principal, r is the annual interest rate, Y is the number of years invested, and n is the number of compounding periods per year. FV is the future value, meaning the amount the principal grows to after Y years.
P = int(input("Enter starting principle please. "))
n = int(input("Enter number of compounding periods per year. "))
r = float(input("Enter annual interest rate. e.g. 15 for 15% "))
y = int(input("Enter the amount of years. "))
FV = P * (((1 + ((r/100.0)/n)) ** (n*y)))
print ("The final amount after", y, "years is", FV)
answered Aug 4 '18 at 16:39
Tom KliseTom Klise
1
1
add a comment |
add a comment |
P = int(input("Enter starting principle please: "))
n = int(input("Enter number of compounding periods per year: "))
r = float(input("Enter annual interest rate: "))
y = int(input("Enter the amount of years: "))
FV = P * (((1 + ((r/100.0)/n)) ** (n*y)))
print ("The final amount after", y, "years is", FV)
add a comment |
P = int(input("Enter starting principle please: "))
n = int(input("Enter number of compounding periods per year: "))
r = float(input("Enter annual interest rate: "))
y = int(input("Enter the amount of years: "))
FV = P * (((1 + ((r/100.0)/n)) ** (n*y)))
print ("The final amount after", y, "years is", FV)
add a comment |
P = int(input("Enter starting principle please: "))
n = int(input("Enter number of compounding periods per year: "))
r = float(input("Enter annual interest rate: "))
y = int(input("Enter the amount of years: "))
FV = P * (((1 + ((r/100.0)/n)) ** (n*y)))
print ("The final amount after", y, "years is", FV)
P = int(input("Enter starting principle please: "))
n = int(input("Enter number of compounding periods per year: "))
r = float(input("Enter annual interest rate: "))
y = int(input("Enter the amount of years: "))
FV = P * (((1 + ((r/100.0)/n)) ** (n*y)))
print ("The final amount after", y, "years is", FV)
answered Mar 8 at 22:46
LeqitShxdowLeqitShxdow
31
31
add a comment |
add a comment |
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Why should it be 1000.10? If I understand correctly, yearly compound interest rate 0.01, so 1000*(1.01)^1=1010.0. Am I missing something here?
– Sagar Waghmode
Jan 22 '16 at 17:33
When I run the number through a compound interest calculator to triple check the answer it gives me 1000.10.
– Joshua Gremo
Jan 22 '16 at 17:40
Added an answer. Please check if this is what you want.
– Sagar Waghmode
Jan 22 '16 at 17:42