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About Node JS Asynchronous [duplicate]
How do I return the response from an asynchronous call?Why is my variable unaltered after I modify it inside of a function? - Asynchronous code referenceHow can I get jQuery to perform a synchronous, rather than asynchronous, Ajax request?How can I upload files asynchronously?Asynchronous vs synchronous execution, what does it really mean?JavaScript, Node.js: is Array.forEach asynchronous?How to return value from an asynchronous callback function?How to uninstall npm modules in node js?How do I return the response from an asynchronous call?AngularJS : Initialize service with asynchronous dataWhy is my variable unaltered after I modify it inside of a function? - Asynchronous code reference“Cannot GET /db/read/getall” accessing node.js express API using reverse proxy nginx on digitalocean droplet
This question already has an answer here:
How do I return the response from an asynchronous call?
33 answers
Why is my variable unaltered after I modify it inside of a function? - Asynchronous code reference
6 answers
I don't why both updateOne and updateMany are executed, please explain :(
I thinks one of them should be finished first and call its callback, execute its db.close().
Please show me the order of the executions
Thanks a lot
var MongoClient = require('mongodb').MongoClient;
var url = 'mongodb://localhost:27017';
MongoClient.connect(url, useNewUrlParser: true , (err, db) =>
if (err) throw err;
var col = db.db('mydb').collection('user');
var query = address: "Thanh Xuan, Ha Noi" ;
var newVal = $set: user: 'thedblaster', address: 'Nguyen Xien' ;
//Update first occurence
col.updateOne(query, newVal, (err, res) =>
if (err) throw err;
console.log(`Modi $res.result.nModified file`);
db.close();
);
var aQuery = user: /a/ ;
var newUs = $set: user: 'K64-UET' ;
//Update all
col.updateMany(aQuery, newUs, (err, res) =>
if (err) throw err;
console.log(`Modified $res.result.nModified files`);
db.close();
);
);
javascript node.js asynchronous
marked as duplicate by Liam, Quentin
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Mar 7 at 13:15
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
This question already has an answer here:
How do I return the response from an asynchronous call?
33 answers
Why is my variable unaltered after I modify it inside of a function? - Asynchronous code reference
6 answers
I don't why both updateOne and updateMany are executed, please explain :(
I thinks one of them should be finished first and call its callback, execute its db.close().
Please show me the order of the executions
Thanks a lot
var MongoClient = require('mongodb').MongoClient;
var url = 'mongodb://localhost:27017';
MongoClient.connect(url, useNewUrlParser: true , (err, db) =>
if (err) throw err;
var col = db.db('mydb').collection('user');
var query = address: "Thanh Xuan, Ha Noi" ;
var newVal = $set: user: 'thedblaster', address: 'Nguyen Xien' ;
//Update first occurence
col.updateOne(query, newVal, (err, res) =>
if (err) throw err;
console.log(`Modi $res.result.nModified file`);
db.close();
);
var aQuery = user: /a/ ;
var newUs = $set: user: 'K64-UET' ;
//Update all
col.updateMany(aQuery, newUs, (err, res) =>
if (err) throw err;
console.log(`Modified $res.result.nModified files`);
db.close();
);
);
javascript node.js asynchronous
marked as duplicate by Liam, Quentin
StackExchange.ready(function()
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$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
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Mar 7 at 13:15
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
Please show me the order of the executions they are executed in order soupdateOne
thenupdateMany
, but they could return in any order
– Liam
Mar 7 at 13:14
add a comment |
This question already has an answer here:
How do I return the response from an asynchronous call?
33 answers
Why is my variable unaltered after I modify it inside of a function? - Asynchronous code reference
6 answers
I don't why both updateOne and updateMany are executed, please explain :(
I thinks one of them should be finished first and call its callback, execute its db.close().
Please show me the order of the executions
Thanks a lot
var MongoClient = require('mongodb').MongoClient;
var url = 'mongodb://localhost:27017';
MongoClient.connect(url, useNewUrlParser: true , (err, db) =>
if (err) throw err;
var col = db.db('mydb').collection('user');
var query = address: "Thanh Xuan, Ha Noi" ;
var newVal = $set: user: 'thedblaster', address: 'Nguyen Xien' ;
//Update first occurence
col.updateOne(query, newVal, (err, res) =>
if (err) throw err;
console.log(`Modi $res.result.nModified file`);
db.close();
);
var aQuery = user: /a/ ;
var newUs = $set: user: 'K64-UET' ;
//Update all
col.updateMany(aQuery, newUs, (err, res) =>
if (err) throw err;
console.log(`Modified $res.result.nModified files`);
db.close();
);
);
javascript node.js asynchronous
This question already has an answer here:
How do I return the response from an asynchronous call?
33 answers
Why is my variable unaltered after I modify it inside of a function? - Asynchronous code reference
6 answers
I don't why both updateOne and updateMany are executed, please explain :(
I thinks one of them should be finished first and call its callback, execute its db.close().
Please show me the order of the executions
Thanks a lot
var MongoClient = require('mongodb').MongoClient;
var url = 'mongodb://localhost:27017';
MongoClient.connect(url, useNewUrlParser: true , (err, db) =>
if (err) throw err;
var col = db.db('mydb').collection('user');
var query = address: "Thanh Xuan, Ha Noi" ;
var newVal = $set: user: 'thedblaster', address: 'Nguyen Xien' ;
//Update first occurence
col.updateOne(query, newVal, (err, res) =>
if (err) throw err;
console.log(`Modi $res.result.nModified file`);
db.close();
);
var aQuery = user: /a/ ;
var newUs = $set: user: 'K64-UET' ;
//Update all
col.updateMany(aQuery, newUs, (err, res) =>
if (err) throw err;
console.log(`Modified $res.result.nModified files`);
db.close();
);
);
This question already has an answer here:
How do I return the response from an asynchronous call?
33 answers
Why is my variable unaltered after I modify it inside of a function? - Asynchronous code reference
6 answers
javascript node.js asynchronous
javascript node.js asynchronous
edited Mar 7 at 13:13
Liam
16.4k1678130
16.4k1678130
asked Mar 7 at 13:08
le duyle duy
1
1
marked as duplicate by Liam, Quentin
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Mar 7 at 13:15
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Liam, Quentin
StackExchange.ready(function()
if (StackExchange.options.isMobile) return;
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var $hover = $(this).addClass('hover-bound'),
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messageElement: $msg.clone().show(),
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dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();
);
);
);
Mar 7 at 13:15
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
Please show me the order of the executions they are executed in order soupdateOne
thenupdateMany
, but they could return in any order
– Liam
Mar 7 at 13:14
add a comment |
Please show me the order of the executions they are executed in order soupdateOne
thenupdateMany
, but they could return in any order
– Liam
Mar 7 at 13:14
Please show me the order of the executions they are executed in order so
updateOne
then updateMany
, but they could return in any order– Liam
Mar 7 at 13:14
Please show me the order of the executions they are executed in order so
updateOne
then updateMany
, but they could return in any order– Liam
Mar 7 at 13:14
add a comment |
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Please show me the order of the executions they are executed in order so
updateOne
thenupdateMany
, but they could return in any order– Liam
Mar 7 at 13:14