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How do I replace [number] to number - 1 using Regex in C#?

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1

1

I have string values like A, something happened [1], something else [2], whatever [3] and want to replace it to A, something happened 0, something else 1, whatever 2.

So, basically replace [ with and ] with if there is a number between and then decrement the number between by one. Is this possible with Regex somehow?

So far I got this:

var text = "A, something happened [1], something else [2], whatever [3]";
var result = Regex.Replace(text, @"[(d+)]", @"$1");
Console.Write(result);

However, this gives me A, something happened 1, something else 2, whatever 3.

Is there an option to decrement the numbers by one?

c# regex replace

share|improve this question

edited Mar 7 at 13:10

Peter B

13.6k52046

asked Mar 7 at 13:06

FranzHuber23FranzHuber23

198318

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Peter B: Thanks for the edit, I did some wrong typing there...
  
  – FranzHuber23
  Mar 7 at 13:13
  
  

  
  
  
  

add a comment | 

1

1

I have string values like A, something happened [1], something else [2], whatever [3] and want to replace it to A, something happened 0, something else 1, whatever 2.

So, basically replace [ with and ] with if there is a number between and then decrement the number between by one. Is this possible with Regex somehow?

So far I got this:

var text = "A, something happened [1], something else [2], whatever [3]";
var result = Regex.Replace(text, @"[(d+)]", @"$1");
Console.Write(result);

However, this gives me A, something happened 1, something else 2, whatever 3.

Is there an option to decrement the numbers by one?

c# regex replace

share|improve this question

edited Mar 7 at 13:10

Peter B

13.6k52046

asked Mar 7 at 13:06

FranzHuber23FranzHuber23

198318

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Peter B: Thanks for the edit, I did some wrong typing there...
  
  – FranzHuber23
  Mar 7 at 13:13
  
  

  
  
  
  

add a comment | 

I have string values like A, something happened [1], something else [2], whatever [3] and want to replace it to A, something happened 0, something else 1, whatever 2.

So, basically replace [ with and ] with if there is a number between and then decrement the number between by one. Is this possible with Regex somehow?

So far I got this:

var text = "A, something happened [1], something else [2], whatever [3]";
var result = Regex.Replace(text, @"[(d+)]", @"$1");
Console.Write(result);

However, this gives me A, something happened 1, something else 2, whatever 3.

Is there an option to decrement the numbers by one?

c# regex replace

share|improve this question

edited Mar 7 at 13:10

Peter B

13.6k52046

asked Mar 7 at 13:06

FranzHuber23FranzHuber23

198318

var text = "A, something happened [1], something else [2], whatever [3]";
var result = Regex.Replace(text, @"[(d+)]", @"$1");
Console.Write(result);

share|improve this question

edited Mar 7 at 13:10

Peter B

13.6k52046

asked Mar 7 at 13:06

FranzHuber23FranzHuber23

198318

share|improve this question

edited Mar 7 at 13:10

Peter B

13.6k52046

asked Mar 7 at 13:06

FranzHuber23FranzHuber23

198318

edited Mar 7 at 13:10

Peter B

13.6k52046

edited Mar 7 at 13:10

Peter B

13.6k52046

asked Mar 7 at 13:06

FranzHuber23FranzHuber23

198318

asked Mar 7 at 13:06

FranzHuber23FranzHuber23

198318

1 Answer
1

active

oldest

votes

2

You may decrement the number in a match evaluator:

var text = "A, something happened [1], something else [2], whatever [3]";
var result = Regex.Replace(text, @"[(d+)]", m => $"int.Parse(m.Groups[1].Value)-1");
Console.Write(result); // => A, something happened 0, something else 1, whatever 2

See the C# demo

In case the number cannot be cast to int use int.TryParse:

var result = Regex.Replace(text, @"[(d+)]", m => 
 int.TryParse(m.Groups[1].Value, out var number) ? $"number - 1" : m.Value);

For C# prior to C#7:

var result = Regex.Replace(text, @"[(d+)]", m => 
 int number;
 if (int.TryParse(m.Groups[1].Value, out number))
 
 return $"number-1";
 
 else
 
 return m.Value;
 
 );

share|improve this answer

edited Mar 7 at 13:30

answered Mar 7 at 13:09

Wiktor StribiżewWiktor Stribiżew

326k16147226

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I will try this. I guess, that's what I was looking for :)
  
  – FranzHuber23
  Mar 7 at 13:12
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @FranzHuber23 If you want you may replace int with long, just make sure you use what works for your scenario best.
  
  – Wiktor Stribiżew
  Mar 7 at 13:18
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Wiktor Stribiżew I put your code into one line like that: var result = Regex.Replace(text, @"[(d+)]", m => int.TryParse(m.Groups[1].Value, out var number) ? $"number - 1" : m.Value);. Of course, if the value is a long, I can simply use the same with long.TryParse. Thank you for the fast reply.
  
  – FranzHuber23
  Mar 7 at 13:21
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @FranzHuber23 Yeah, it will work starting with C#7, since the out argument "can pass without its declaration and initialization".
  
  – Wiktor Stribiżew
  Mar 7 at 13:29
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Wiktor Stribiżew Thank you for the additional information, I did not really look for the C# version as I'm always using the latest features but it's good to notice this to others.
  
  – FranzHuber23
  Mar 7 at 13:51
  

  
  
  
  

add a comment | 

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2

You may decrement the number in a match evaluator:

var text = "A, something happened [1], something else [2], whatever [3]";
var result = Regex.Replace(text, @"[(d+)]", m => $"int.Parse(m.Groups[1].Value)-1");
Console.Write(result); // => A, something happened 0, something else 1, whatever 2

See the C# demo

In case the number cannot be cast to int use int.TryParse:

var result = Regex.Replace(text, @"[(d+)]", m => 
 int.TryParse(m.Groups[1].Value, out var number) ? $"number - 1" : m.Value);

For C# prior to C#7:

var result = Regex.Replace(text, @"[(d+)]", m => 
 int number;
 if (int.TryParse(m.Groups[1].Value, out number))
 
 return $"number-1";
 
 else
 
 return m.Value;
 
 );

share|improve this answer

edited Mar 7 at 13:30

answered Mar 7 at 13:09

Wiktor StribiżewWiktor Stribiżew

326k16147226

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I will try this. I guess, that's what I was looking for :)
  
  – FranzHuber23
  Mar 7 at 13:12
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @FranzHuber23 If you want you may replace int with long, just make sure you use what works for your scenario best.
  
  – Wiktor Stribiżew
  Mar 7 at 13:18
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Wiktor Stribiżew I put your code into one line like that: var result = Regex.Replace(text, @"[(d+)]", m => int.TryParse(m.Groups[1].Value, out var number) ? $"number - 1" : m.Value);. Of course, if the value is a long, I can simply use the same with long.TryParse. Thank you for the fast reply.
  
  – FranzHuber23
  Mar 7 at 13:21
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @FranzHuber23 Yeah, it will work starting with C#7, since the out argument "can pass without its declaration and initialization".
  
  – Wiktor Stribiżew
  Mar 7 at 13:29
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Wiktor Stribiżew Thank you for the additional information, I did not really look for the C# version as I'm always using the latest features but it's good to notice this to others.
  
  – FranzHuber23
  Mar 7 at 13:51
  

  
  
  
  

add a comment | 

2

You may decrement the number in a match evaluator:

var text = "A, something happened [1], something else [2], whatever [3]";
var result = Regex.Replace(text, @"[(d+)]", m => $"int.Parse(m.Groups[1].Value)-1");
Console.Write(result); // => A, something happened 0, something else 1, whatever 2

See the C# demo

In case the number cannot be cast to int use int.TryParse:

var result = Regex.Replace(text, @"[(d+)]", m => 
 int.TryParse(m.Groups[1].Value, out var number) ? $"number - 1" : m.Value);

For C# prior to C#7:

var result = Regex.Replace(text, @"[(d+)]", m => 
 int number;
 if (int.TryParse(m.Groups[1].Value, out number))
 
 return $"number-1";
 
 else
 
 return m.Value;
 
 );

share|improve this answer

edited Mar 7 at 13:30

answered Mar 7 at 13:09

Wiktor StribiżewWiktor Stribiżew

326k16147226

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I will try this. I guess, that's what I was looking for :)
  
  – FranzHuber23
  Mar 7 at 13:12
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @FranzHuber23 If you want you may replace int with long, just make sure you use what works for your scenario best.
  
  – Wiktor Stribiżew
  Mar 7 at 13:18
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Wiktor Stribiżew I put your code into one line like that: var result = Regex.Replace(text, @"[(d+)]", m => int.TryParse(m.Groups[1].Value, out var number) ? $"number - 1" : m.Value);. Of course, if the value is a long, I can simply use the same with long.TryParse. Thank you for the fast reply.
  
  – FranzHuber23
  Mar 7 at 13:21
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @FranzHuber23 Yeah, it will work starting with C#7, since the out argument "can pass without its declaration and initialization".
  
  – Wiktor Stribiżew
  Mar 7 at 13:29
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Wiktor Stribiżew Thank you for the additional information, I did not really look for the C# version as I'm always using the latest features but it's good to notice this to others.
  
  – FranzHuber23
  Mar 7 at 13:51
  

  
  
  
  

add a comment | 

You may decrement the number in a match evaluator:

var text = "A, something happened [1], something else [2], whatever [3]";
var result = Regex.Replace(text, @"[(d+)]", m => $"int.Parse(m.Groups[1].Value)-1");
Console.Write(result); // => A, something happened 0, something else 1, whatever 2

See the C# demo

In case the number cannot be cast to int use int.TryParse:

var result = Regex.Replace(text, @"[(d+)]", m => 
 int.TryParse(m.Groups[1].Value, out var number) ? $"number - 1" : m.Value);

For C# prior to C#7:

var result = Regex.Replace(text, @"[(d+)]", m => 
 int number;
 if (int.TryParse(m.Groups[1].Value, out number))
 
 return $"number-1";
 
 else
 
 return m.Value;
 
 );

share|improve this answer

edited Mar 7 at 13:30

answered Mar 7 at 13:09

Wiktor StribiżewWiktor Stribiżew

326k16147226

var text = "A, something happened [1], something else [2], whatever [3]";
var result = Regex.Replace(text, @"[(d+)]", m => $"int.Parse(m.Groups[1].Value)-1");
Console.Write(result); // => A, something happened 0, something else 1, whatever 2

var result = Regex.Replace(text, @"[(d+)]", m => 
 int.TryParse(m.Groups[1].Value, out var number) ? $"number - 1" : m.Value);

var result = Regex.Replace(text, @"[(d+)]", m => 
 int number;
 if (int.TryParse(m.Groups[1].Value, out number))
 
 return $"number-1";
 
 else
 
 return m.Value;
 
 );

share|improve this answer

edited Mar 7 at 13:30

answered Mar 7 at 13:09

Wiktor StribiżewWiktor Stribiżew

326k16147226

answered Mar 7 at 13:09

Wiktor StribiżewWiktor Stribiżew

326k16147226

answered Mar 7 at 13:09

Wiktor StribiżewWiktor Stribiżew

326k16147226