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Creating a list of widgets from map with keys and values

How to specify the output directory for Dart's “pub deploy”?how to define a variable of type “function”? (using optional typing)Switching on class type in DartFlutter - Create a countdown widgettype 'List<dynamic>' is not a subtype of type 'List<Widget>'What are Keys in the Stateless widgets class?Creating widgets based on a listHow to create flutter list linear gradien widget?Flutter: Question about async function to retrieve Firebase user IDWhat is the difference between functions and classes to create widgets?

3

If I have say a SimpleDialog() and it accepts children[] and I want to populate it from a Map<int, String>, how would I do that? I need both the key and value to create the child widget.

const optionsMap = 
 111:"First option",
 222:"Second option",

return SimpleDialog(
 title: Text('Choose one'),
 children: // I don't know what to put here
 // I want to have widgets based on optionsMap keys and values
)

I solved it by creating a List<Widget> beforehand above the return statement, but just for convenience (and becoming better in Dart) I'd like to know if there's a way to do it inline.

dart flutter

share|improve this question

edited Mar 7 at 9:18

TimSim

asked Mar 7 at 9:06

TimSimTimSim

1,20732860

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You could use the Map.map() function to obtain a new Map<int, Widget> and then use this new map's values: children : options.map((entry) return MapEntry<int, Widget>(entry.key, /*here create the widget from entry.key and entry.value*/);).values.toList().
  
  – Luksprog
  Mar 7 at 9:40
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Using a ListView and converting your map into a list should work
  
  – Willy
  Mar 7 at 9:44
  

  
  
  
  

add a comment | 

3

If I have say a SimpleDialog() and it accepts children[] and I want to populate it from a Map<int, String>, how would I do that? I need both the key and value to create the child widget.

const optionsMap = 
 111:"First option",
 222:"Second option",

return SimpleDialog(
 title: Text('Choose one'),
 children: // I don't know what to put here
 // I want to have widgets based on optionsMap keys and values
)

I solved it by creating a List<Widget> beforehand above the return statement, but just for convenience (and becoming better in Dart) I'd like to know if there's a way to do it inline.

dart flutter

share|improve this question

edited Mar 7 at 9:18

TimSim

asked Mar 7 at 9:06

TimSimTimSim

1,20732860

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You could use the Map.map() function to obtain a new Map<int, Widget> and then use this new map's values: children : options.map((entry) return MapEntry<int, Widget>(entry.key, /*here create the widget from entry.key and entry.value*/);).values.toList().
  
  – Luksprog
  Mar 7 at 9:40
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Using a ListView and converting your map into a list should work
  
  – Willy
  Mar 7 at 9:44
  

  
  
  
  

add a comment | 

If I have say a SimpleDialog() and it accepts children[] and I want to populate it from a Map<int, String>, how would I do that? I need both the key and value to create the child widget.

const optionsMap = 
 111:"First option",
 222:"Second option",

return SimpleDialog(
 title: Text('Choose one'),
 children: // I don't know what to put here
 // I want to have widgets based on optionsMap keys and values
)

I solved it by creating a List<Widget> beforehand above the return statement, but just for convenience (and becoming better in Dart) I'd like to know if there's a way to do it inline.

dart flutter

share|improve this question

edited Mar 7 at 9:18

TimSim

asked Mar 7 at 9:06

TimSimTimSim

1,20732860

const optionsMap = 
 111:"First option",
 222:"Second option",

return SimpleDialog(
 title: Text('Choose one'),
 children: // I don't know what to put here
 // I want to have widgets based on optionsMap keys and values
)

dart flutter

dart flutter

share|improve this question

edited Mar 7 at 9:18

TimSim

asked Mar 7 at 9:06

TimSimTimSim

1,20732860

share|improve this question

edited Mar 7 at 9:18

TimSim

asked Mar 7 at 9:06

TimSimTimSim

1,20732860

asked Mar 7 at 9:06

TimSimTimSim

1,20732860

asked Mar 7 at 9:06

TimSimTimSim

1,20732860

1 Answer
1

active

oldest

votes

1

Update answer to incorporate @lrn 's comment

You can use map

const optionsMap = 
 111:"First option",
 222:"Second option",
 
 return SimpleDialog(
 title: Text('Choose one'),
 children: optionsMap.entries.map((entry) 
 var w = Text(entry.value);
 doSomething(entry.key);
 return w;
 ).toList());
;

share|improve this answer

edited Mar 8 at 1:22

answered Mar 7 at 10:50

TruongSinhTruongSinh

1,518822

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I want to be able to access both keys and values.
  
  – TimSim
  Mar 7 at 10:53
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  update my answer to have both keys and values
  
  – TruongSinh
  Mar 7 at 11:01
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Slightly simpler: optionsMap.entries.map((entry) var w = Text(entry.value); doSomething(key); return w; ). So, instead of creating a map and using only the values, just create the values as an iterable.
  
  – lrn
  Mar 7 at 15:09
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @irn thanks, but did you try you code? I think you will still ned to to have toList()
  
  – TruongSinh
  Mar 8 at 1:17
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I didn't know about entries property, that makes dealing with maps so much easier.
  
  – TimSim
  Mar 9 at 10:25
  

  
  
  
  

add a comment | 

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1

Update answer to incorporate @lrn 's comment

You can use map

const optionsMap = 
 111:"First option",
 222:"Second option",
 
 return SimpleDialog(
 title: Text('Choose one'),
 children: optionsMap.entries.map((entry) 
 var w = Text(entry.value);
 doSomething(entry.key);
 return w;
 ).toList());
;

share|improve this answer

edited Mar 8 at 1:22

answered Mar 7 at 10:50

TruongSinhTruongSinh

1,518822

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I want to be able to access both keys and values.
  
  – TimSim
  Mar 7 at 10:53
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  update my answer to have both keys and values
  
  – TruongSinh
  Mar 7 at 11:01
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Slightly simpler: optionsMap.entries.map((entry) var w = Text(entry.value); doSomething(key); return w; ). So, instead of creating a map and using only the values, just create the values as an iterable.
  
  – lrn
  Mar 7 at 15:09
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @irn thanks, but did you try you code? I think you will still ned to to have toList()
  
  – TruongSinh
  Mar 8 at 1:17
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I didn't know about entries property, that makes dealing with maps so much easier.
  
  – TimSim
  Mar 9 at 10:25
  

  
  
  
  

add a comment | 

1

Update answer to incorporate @lrn 's comment

You can use map

const optionsMap = 
 111:"First option",
 222:"Second option",
 
 return SimpleDialog(
 title: Text('Choose one'),
 children: optionsMap.entries.map((entry) 
 var w = Text(entry.value);
 doSomething(entry.key);
 return w;
 ).toList());
;

share|improve this answer

edited Mar 8 at 1:22

answered Mar 7 at 10:50

TruongSinhTruongSinh

1,518822

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I want to be able to access both keys and values.
  
  – TimSim
  Mar 7 at 10:53
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  update my answer to have both keys and values
  
  – TruongSinh
  Mar 7 at 11:01
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Slightly simpler: optionsMap.entries.map((entry) var w = Text(entry.value); doSomething(key); return w; ). So, instead of creating a map and using only the values, just create the values as an iterable.
  
  – lrn
  Mar 7 at 15:09
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @irn thanks, but did you try you code? I think you will still ned to to have toList()
  
  – TruongSinh
  Mar 8 at 1:17
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I didn't know about entries property, that makes dealing with maps so much easier.
  
  – TimSim
  Mar 9 at 10:25
  

  
  
  
  

add a comment | 

Update answer to incorporate @lrn 's comment

You can use map

const optionsMap = 
 111:"First option",
 222:"Second option",
 
 return SimpleDialog(
 title: Text('Choose one'),
 children: optionsMap.entries.map((entry) 
 var w = Text(entry.value);
 doSomething(entry.key);
 return w;
 ).toList());
;

share|improve this answer

edited Mar 8 at 1:22

answered Mar 7 at 10:50

TruongSinhTruongSinh

1,518822

const optionsMap = 
 111:"First option",
 222:"Second option",
 
 return SimpleDialog(
 title: Text('Choose one'),
 children: optionsMap.entries.map((entry) 
 var w = Text(entry.value);
 doSomething(entry.key);
 return w;
 ).toList());
;

share|improve this answer

edited Mar 8 at 1:22

answered Mar 7 at 10:50

TruongSinhTruongSinh

1,518822

answered Mar 7 at 10:50

TruongSinhTruongSinh

1,518822

answered Mar 7 at 10:50

TruongSinhTruongSinh

1,518822