How to properly do an asynchronous call in a for loop?Using async/await with a forEach loopHow do I debug Node.js applications?How do I get started with Node.jsHow do I pass command line arguments to a Node.js program?How to decide when to use Node.js?How to exit in Node.jsWhat is the purpose of Node.js module.exports and how do you use it?How to call asynchronous method from synchronous method in C#?How do I update each dependency in package.json to the latest version?What is the difference between asynchronous programming and multithreading?Using async/await with a forEach loop
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How to properly do an asynchronous call in a for loop?
Using async/await with a forEach loopHow do I debug Node.js applications?How do I get started with Node.jsHow do I pass command line arguments to a Node.js program?How to decide when to use Node.js?How to exit in Node.jsWhat is the purpose of Node.js module.exports and how do you use it?How to call asynchronous method from synchronous method in C#?How do I update each dependency in package.json to the latest version?What is the difference between asynchronous programming and multithreading?Using async/await with a forEach loop
can someone please suggest a proper way on how I can do asynchronous call simultaneously with the values I extracted from an array?
Currently, I have the below implementation but it looks like a blocking code because of the await which basically waits for the result of the API call before it proceeds with the next iteration.
Your suggestions would be much appreciated. Thanks in advance! :)
async function getDetailsById()
let idArr = ['1000', '1001', '1002', '1003'];
let detailsArray = [];
for(let i = 0; i < idArr.length; i++)
let id = idArr[i];
let details = await callSomeApi(id);
detailsArray.push(details);
return detailsArray;
node.js async-await
asked Mar 7 at 8:59
jrmtmysjrmtmys
112
add a comment |
can someone please suggest a proper way on how I can do asynchronous call simultaneously with the values I extracted from an array?
Currently, I have the below implementation but it looks like a blocking code because of the await which basically waits for the result of the API call before it proceeds with the next iteration.
Your suggestions would be much appreciated. Thanks in advance! :)
async function getDetailsById()
let idArr = ['1000', '1001', '1002', '1003'];
let detailsArray = [];
for(let i = 0; i < idArr.length; i++)
let id = idArr[i];
let details = await callSomeApi(id);
detailsArray.push(details);
return detailsArray;
node.js async-await
asked Mar 7 at 8:59
jrmtmysjrmtmys
112
4
Possible duplicate of Using async/await with a forEach loop
– Liam
Mar 7 at 9:04
I'd agree with Liam. This is a duplicate and the link he's provided is a good one around using promises. It might be worth stepping away from your actual problem and look at async, promises and promise.all before returning to your problem.
– Chris Adams
Mar 7 at 9:10
1
Basically, if you just want to run all the async requests in parallel and then await them all, you could do something like this:return await Promise.all(idArr.map(id => callSomeApi(id)))
– noseratio
Mar 7 at 9:16
1
@noseratio, your simple solution worked for me! Thank you very much! :)
– jrmtmys
Mar 15 at 6:16
add a comment |
can someone please suggest a proper way on how I can do asynchronous call simultaneously with the values I extracted from an array?
Currently, I have the below implementation but it looks like a blocking code because of the await which basically waits for the result of the API call before it proceeds with the next iteration.
Your suggestions would be much appreciated. Thanks in advance! :)
async function getDetailsById()
let idArr = ['1000', '1001', '1002', '1003'];
let detailsArray = [];
for(let i = 0; i < idArr.length; i++)
let id = idArr[i];
let details = await callSomeApi(id);
detailsArray.push(details);
return detailsArray;
node.js async-await
asked Mar 7 at 8:59
jrmtmysjrmtmys
112
can someone please suggest a proper way on how I can do asynchronous call simultaneously with the values I extracted from an array?
Currently, I have the below implementation but it looks like a blocking code because of the await which basically waits for the result of the API call before it proceeds with the next iteration.
Your suggestions would be much appreciated. Thanks in advance! :)
async function getDetailsById()
let idArr = ['1000', '1001', '1002', '1003'];
let detailsArray = [];
for(let i = 0; i < idArr.length; i++)
let id = idArr[i];
let details = await callSomeApi(id);
detailsArray.push(details);
return detailsArray;
node.js async-await
node.js async-await
asked Mar 7 at 8:59
jrmtmysjrmtmys
112
asked Mar 7 at 8:59
jrmtmysjrmtmys
112
asked Mar 7 at 8:59
jrmtmysjrmtmys
112
asked Mar 7 at 8:59
jrmtmysjrmtmys
112
asked Mar 7 at 8:59
jrmtmysjrmtmys
112
112
4
Possible duplicate of Using async/await with a forEach loop
– Liam
Mar 7 at 9:04
I'd agree with Liam. This is a duplicate and the link he's provided is a good one around using promises. It might be worth stepping away from your actual problem and look at async, promises and promise.all before returning to your problem.
– Chris Adams
Mar 7 at 9:10
1
Basically, if you just want to run all the async requests in parallel and then await them all, you could do something like this:return await Promise.all(idArr.map(id => callSomeApi(id)))
– noseratio
Mar 7 at 9:16
1
@noseratio, your simple solution worked for me! Thank you very much! :)
– jrmtmys
Mar 15 at 6:16
add a comment |
4
Possible duplicate of Using async/await with a forEach loop
– Liam
Mar 7 at 9:04
I'd agree with Liam. This is a duplicate and the link he's provided is a good one around using promises. It might be worth stepping away from your actual problem and look at async, promises and promise.all before returning to your problem.
– Chris Adams
Mar 7 at 9:10
1
Basically, if you just want to run all the async requests in parallel and then await them all, you could do something like this:return await Promise.all(idArr.map(id => callSomeApi(id)))
– noseratio
Mar 7 at 9:16
1
@noseratio, your simple solution worked for me! Thank you very much! :)
– jrmtmys
Mar 15 at 6:16
4
4
Possible duplicate of Using async/await with a forEach loop
– Liam
Mar 7 at 9:04
Possible duplicate of Using async/await with a forEach loop
– Liam
Mar 7 at 9:04
I'd agree with Liam. This is a duplicate and the link he's provided is a good one around using promises. It might be worth stepping away from your actual problem and look at async, promises and promise.all before returning to your problem.
– Chris Adams
Mar 7 at 9:10
I'd agree with Liam. This is a duplicate and the link he's provided is a good one around using promises. It might be worth stepping away from your actual problem and look at async, promises and promise.all before returning to your problem.
– Chris Adams
Mar 7 at 9:10
1
1
Basically, if you just want to run all the async requests in parallel and then await them all, you could do something like this:
return await Promise.all(idArr.map(id => callSomeApi(id)))– noseratio
Mar 7 at 9:16
Basically, if you just want to run all the async requests in parallel and then await them all, you could do something like this:
return await Promise.all(idArr.map(id => callSomeApi(id)))– noseratio
Mar 7 at 9:16
1
1
@noseratio, your simple solution worked for me! Thank you very much! :)
– jrmtmys
Mar 15 at 6:16
@noseratio, your simple solution worked for me! Thank you very much! :)
– jrmtmys
Mar 15 at 6:16
add a comment |
1 Answer
1
active
oldest
votes
You could start all the Tasks and then await Task.WhenAll(...);
I don't know how to do it in your language, but you'll get the gist:
List<Task<returnType>> tasks = new List<Task<returnType>>();
// start all tasks, don't await for the result yet
for (int i=0; i<idArr.Length; ++i)
Task task = callSomeApi(idArr[i]);
tasks.Add(task);
// wait until all tasks finished:
await Task.Wait(tasks);
// if desired use Task.Result to use the return value:
foreach(Task<returnType> task in tasks)
var result = task.Result;
ProcessResult(result);
If you don't want to wait for all tasks to finish, but want to process the result as soon as one of the tasks is finished, use Task.WhenAny, and remove the finished task from the collection of awaited tasks. Use a HashSet for fast removal
HashSet<Task<returnType>> tasks = new HashSet<Task<returnType>>();
// start all tasks, don't await for the result:
for (int i=0; i<idArr.Length; ++i)
Task<returnType> task = callSomeApi(idArr[i]);
tasks.Add(task);
// as long as there are tasks in the HashSet,
// await until any of the tasks in the HashSet is finished:
while(tasks.Any())
Task finishedTask = await Task.WhenAny(tasks);
tasks.Remove(finishedTask);
ProcessResult(finishedTask.Result); // only if there is a result
answered Mar 12 at 13:03
Harald CoppoolseHarald Coppoolse
13.2k13064
Apparently someone doesn't like this answer and downvoted me. Couldn't he just write as a comment what is wrong? If it is because it is not in VB: in future someone might have the same problem in C#. Shall I just delete this answer?
– Harald Coppoolse
Mar 12 at 15:09
add a comment |
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1 Answer
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active
oldest
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oldest
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active
oldest
votes
You could start all the Tasks and then await Task.WhenAll(...);
I don't know how to do it in your language, but you'll get the gist:
List<Task<returnType>> tasks = new List<Task<returnType>>();
// start all tasks, don't await for the result yet
for (int i=0; i<idArr.Length; ++i)
Task task = callSomeApi(idArr[i]);
tasks.Add(task);
// wait until all tasks finished:
await Task.Wait(tasks);
// if desired use Task.Result to use the return value:
foreach(Task<returnType> task in tasks)
var result = task.Result;
ProcessResult(result);
If you don't want to wait for all tasks to finish, but want to process the result as soon as one of the tasks is finished, use Task.WhenAny, and remove the finished task from the collection of awaited tasks. Use a HashSet for fast removal
HashSet<Task<returnType>> tasks = new HashSet<Task<returnType>>();
// start all tasks, don't await for the result:
for (int i=0; i<idArr.Length; ++i)
Task<returnType> task = callSomeApi(idArr[i]);
tasks.Add(task);
// as long as there are tasks in the HashSet,
// await until any of the tasks in the HashSet is finished:
while(tasks.Any())
Task finishedTask = await Task.WhenAny(tasks);
tasks.Remove(finishedTask);
ProcessResult(finishedTask.Result); // only if there is a result
answered Mar 12 at 13:03
Harald CoppoolseHarald Coppoolse
13.2k13064
Apparently someone doesn't like this answer and downvoted me. Couldn't he just write as a comment what is wrong? If it is because it is not in VB: in future someone might have the same problem in C#. Shall I just delete this answer?
– Harald Coppoolse
Mar 12 at 15:09
add a comment |
You could start all the Tasks and then await Task.WhenAll(...);
I don't know how to do it in your language, but you'll get the gist:
List<Task<returnType>> tasks = new List<Task<returnType>>();
// start all tasks, don't await for the result yet
for (int i=0; i<idArr.Length; ++i)
Task task = callSomeApi(idArr[i]);
tasks.Add(task);
// wait until all tasks finished:
await Task.Wait(tasks);
// if desired use Task.Result to use the return value:
foreach(Task<returnType> task in tasks)
var result = task.Result;
ProcessResult(result);
If you don't want to wait for all tasks to finish, but want to process the result as soon as one of the tasks is finished, use Task.WhenAny, and remove the finished task from the collection of awaited tasks. Use a HashSet for fast removal
HashSet<Task<returnType>> tasks = new HashSet<Task<returnType>>();
// start all tasks, don't await for the result:
for (int i=0; i<idArr.Length; ++i)
Task<returnType> task = callSomeApi(idArr[i]);
tasks.Add(task);
// as long as there are tasks in the HashSet,
// await until any of the tasks in the HashSet is finished:
while(tasks.Any())
Task finishedTask = await Task.WhenAny(tasks);
tasks.Remove(finishedTask);
ProcessResult(finishedTask.Result); // only if there is a result
answered Mar 12 at 13:03
Harald CoppoolseHarald Coppoolse
13.2k13064
Apparently someone doesn't like this answer and downvoted me. Couldn't he just write as a comment what is wrong? If it is because it is not in VB: in future someone might have the same problem in C#. Shall I just delete this answer?
– Harald Coppoolse
Mar 12 at 15:09
add a comment |
You could start all the Tasks and then await Task.WhenAll(...);
I don't know how to do it in your language, but you'll get the gist:
List<Task<returnType>> tasks = new List<Task<returnType>>();
// start all tasks, don't await for the result yet
for (int i=0; i<idArr.Length; ++i)
Task task = callSomeApi(idArr[i]);
tasks.Add(task);
// wait until all tasks finished:
await Task.Wait(tasks);
// if desired use Task.Result to use the return value:
foreach(Task<returnType> task in tasks)
var result = task.Result;
ProcessResult(result);
If you don't want to wait for all tasks to finish, but want to process the result as soon as one of the tasks is finished, use Task.WhenAny, and remove the finished task from the collection of awaited tasks. Use a HashSet for fast removal
HashSet<Task<returnType>> tasks = new HashSet<Task<returnType>>();
// start all tasks, don't await for the result:
for (int i=0; i<idArr.Length; ++i)
Task<returnType> task = callSomeApi(idArr[i]);
tasks.Add(task);
// as long as there are tasks in the HashSet,
// await until any of the tasks in the HashSet is finished:
while(tasks.Any())
Task finishedTask = await Task.WhenAny(tasks);
tasks.Remove(finishedTask);
ProcessResult(finishedTask.Result); // only if there is a result
answered Mar 12 at 13:03
Harald CoppoolseHarald Coppoolse
13.2k13064
You could start all the Tasks and then await Task.WhenAll(...);
I don't know how to do it in your language, but you'll get the gist:
List<Task<returnType>> tasks = new List<Task<returnType>>();
// start all tasks, don't await for the result yet
for (int i=0; i<idArr.Length; ++i)
Task task = callSomeApi(idArr[i]);
tasks.Add(task);
// wait until all tasks finished:
await Task.Wait(tasks);
// if desired use Task.Result to use the return value:
foreach(Task<returnType> task in tasks)
var result = task.Result;
ProcessResult(result);
If you don't want to wait for all tasks to finish, but want to process the result as soon as one of the tasks is finished, use Task.WhenAny, and remove the finished task from the collection of awaited tasks. Use a HashSet for fast removal
HashSet<Task<returnType>> tasks = new HashSet<Task<returnType>>();
// start all tasks, don't await for the result:
for (int i=0; i<idArr.Length; ++i)
Task<returnType> task = callSomeApi(idArr[i]);
tasks.Add(task);
// as long as there are tasks in the HashSet,
// await until any of the tasks in the HashSet is finished:
while(tasks.Any())
Task finishedTask = await Task.WhenAny(tasks);
tasks.Remove(finishedTask);
ProcessResult(finishedTask.Result); // only if there is a result
answered Mar 12 at 13:03
Harald CoppoolseHarald Coppoolse
13.2k13064
answered Mar 12 at 13:03
Harald CoppoolseHarald Coppoolse
13.2k13064
answered Mar 12 at 13:03
Harald CoppoolseHarald Coppoolse
13.2k13064
answered Mar 12 at 13:03
Harald CoppoolseHarald Coppoolse
13.2k13064
13.2k13064
Apparently someone doesn't like this answer and downvoted me. Couldn't he just write as a comment what is wrong? If it is because it is not in VB: in future someone might have the same problem in C#. Shall I just delete this answer?
– Harald Coppoolse
Mar 12 at 15:09
add a comment |
Apparently someone doesn't like this answer and downvoted me. Couldn't he just write as a comment what is wrong? If it is because it is not in VB: in future someone might have the same problem in C#. Shall I just delete this answer?
– Harald Coppoolse
Mar 12 at 15:09
Apparently someone doesn't like this answer and downvoted me. Couldn't he just write as a comment what is wrong? If it is because it is not in VB: in future someone might have the same problem in C#. Shall I just delete this answer?
– Harald Coppoolse
Mar 12 at 15:09
Apparently someone doesn't like this answer and downvoted me. Couldn't he just write as a comment what is wrong? If it is because it is not in VB: in future someone might have the same problem in C#. Shall I just delete this answer?
– Harald Coppoolse
Mar 12 at 15:09
add a comment |
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4
Possible duplicate of Using async/await with a forEach loop
– Liam
Mar 7 at 9:04
I'd agree with Liam. This is a duplicate and the link he's provided is a good one around using promises. It might be worth stepping away from your actual problem and look at async, promises and promise.all before returning to your problem.
– Chris Adams
Mar 7 at 9:10
1
Basically, if you just want to run all the async requests in parallel and then await them all, you could do something like this:
return await Promise.all(idArr.map(id => callSomeApi(id)))– noseratio
Mar 7 at 9:16
1
@noseratio, your simple solution worked for me! Thank you very much! :)
– jrmtmys
Mar 15 at 6:16