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Add the value of next min(Date) in sequential order
Add a column with a default value to an existing table in SQL ServerSQL Server: Is it possible to insert into two tables at the same time?Select Distinct Records for min dateupdate data when a button pressedIn one to many relationship, return distinct rows based on MIN valueSQL Server 2014 - How to find the Min Date between 2 tablesHow can i select only id of min created date in each groupNeed to create a table with values filled in before datesAggregate error on join clause (selecting MIN date)Is there a way to group timestamp data by 30 day intervals starting from the min(date) and add them as columns
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I'm updating the table with first 3 visits height value of ID's like...
ID fvdate Visit Ht_date Ht_value
1 06jun2010 1 06jun2010 168
1 06jun2010 2 18Dec2010 168.2
1 06jun2010 3 ? ?
2 12dec2011 1 25dec2011 175
2 12dec2011 2 12feb2012 175.8
2 12dec2011 3 ? ?
For the first 2 visits, I update well.
but on updating the 3rd visit I face some trouble...
I used the below code to update the value with its date
update mytab
set ht_DT = b.Record_date,
ht = b.Height
FROM mytaba JOIN anthropometry b
ON a.mno = b.patient_id and Visit ='1' and
b.record_date = fvdate
update mytabset
ht_DT = b.Record_date,
ht = b.Height
FROM mytaba JOIN anthropometry b
ON a.mno = b.patient_id and Visit ='2' and
b.record_date = (select min(record_date) from anthropometry cc where
a.mno = cc.patient_id and cc.record_date > fvdate)
update mytabset ht_DT = b.Record_date, ht = b.Height FROM
mytaba JOIN anthropometry b ON a.mno =
b.patient_id and Visit ='3' and b.record_date =
(select min(record_date) from anthropometry cc where
a.mno = cc.patient_id and cc.record_date > a.ht_Dt and Visit ='2')
Please correct my mistake on the given code.
sql mysqli
add a comment |
I'm updating the table with first 3 visits height value of ID's like...
ID fvdate Visit Ht_date Ht_value
1 06jun2010 1 06jun2010 168
1 06jun2010 2 18Dec2010 168.2
1 06jun2010 3 ? ?
2 12dec2011 1 25dec2011 175
2 12dec2011 2 12feb2012 175.8
2 12dec2011 3 ? ?
For the first 2 visits, I update well.
but on updating the 3rd visit I face some trouble...
I used the below code to update the value with its date
update mytab
set ht_DT = b.Record_date,
ht = b.Height
FROM mytaba JOIN anthropometry b
ON a.mno = b.patient_id and Visit ='1' and
b.record_date = fvdate
update mytabset
ht_DT = b.Record_date,
ht = b.Height
FROM mytaba JOIN anthropometry b
ON a.mno = b.patient_id and Visit ='2' and
b.record_date = (select min(record_date) from anthropometry cc where
a.mno = cc.patient_id and cc.record_date > fvdate)
update mytabset ht_DT = b.Record_date, ht = b.Height FROM
mytaba JOIN anthropometry b ON a.mno =
b.patient_id and Visit ='3' and b.record_date =
(select min(record_date) from anthropometry cc where
a.mno = cc.patient_id and cc.record_date > a.ht_Dt and Visit ='2')
Please correct my mistake on the given code.
sql mysqli
add a comment |
I'm updating the table with first 3 visits height value of ID's like...
ID fvdate Visit Ht_date Ht_value
1 06jun2010 1 06jun2010 168
1 06jun2010 2 18Dec2010 168.2
1 06jun2010 3 ? ?
2 12dec2011 1 25dec2011 175
2 12dec2011 2 12feb2012 175.8
2 12dec2011 3 ? ?
For the first 2 visits, I update well.
but on updating the 3rd visit I face some trouble...
I used the below code to update the value with its date
update mytab
set ht_DT = b.Record_date,
ht = b.Height
FROM mytaba JOIN anthropometry b
ON a.mno = b.patient_id and Visit ='1' and
b.record_date = fvdate
update mytabset
ht_DT = b.Record_date,
ht = b.Height
FROM mytaba JOIN anthropometry b
ON a.mno = b.patient_id and Visit ='2' and
b.record_date = (select min(record_date) from anthropometry cc where
a.mno = cc.patient_id and cc.record_date > fvdate)
update mytabset ht_DT = b.Record_date, ht = b.Height FROM
mytaba JOIN anthropometry b ON a.mno =
b.patient_id and Visit ='3' and b.record_date =
(select min(record_date) from anthropometry cc where
a.mno = cc.patient_id and cc.record_date > a.ht_Dt and Visit ='2')
Please correct my mistake on the given code.
sql mysqli
I'm updating the table with first 3 visits height value of ID's like...
ID fvdate Visit Ht_date Ht_value
1 06jun2010 1 06jun2010 168
1 06jun2010 2 18Dec2010 168.2
1 06jun2010 3 ? ?
2 12dec2011 1 25dec2011 175
2 12dec2011 2 12feb2012 175.8
2 12dec2011 3 ? ?
For the first 2 visits, I update well.
but on updating the 3rd visit I face some trouble...
I used the below code to update the value with its date
update mytab
set ht_DT = b.Record_date,
ht = b.Height
FROM mytaba JOIN anthropometry b
ON a.mno = b.patient_id and Visit ='1' and
b.record_date = fvdate
update mytabset
ht_DT = b.Record_date,
ht = b.Height
FROM mytaba JOIN anthropometry b
ON a.mno = b.patient_id and Visit ='2' and
b.record_date = (select min(record_date) from anthropometry cc where
a.mno = cc.patient_id and cc.record_date > fvdate)
update mytabset ht_DT = b.Record_date, ht = b.Height FROM
mytaba JOIN anthropometry b ON a.mno =
b.patient_id and Visit ='3' and b.record_date =
(select min(record_date) from anthropometry cc where
a.mno = cc.patient_id and cc.record_date > a.ht_Dt and Visit ='2')
Please correct my mistake on the given code.
sql mysqli
sql mysqli
edited Mar 9 at 9:25
Arslanbekov
669419
669419
asked Mar 9 at 9:20
Sathish JaySathish Jay
36
36
add a comment |
add a comment |
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