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Compute the ratio of the sum of cube of the first 'n' natural numbers to the sum of square of first 'n' natural numbers

Why are Python lambdas useful?Convert a number range to another range, maintaining ratioPython progression path - From apprentice to guruTaking square of summed numbersFunction to calculate the difference between sum of squares and square of sumsWhy is “1000000000000000 in range(1000000000000001)” so fast in Python 3?Sum of squares using lambda functionssum of squares of the first n odd numbersalgorithm to get power sum of natural numbersCompute cube root of extremely big number in Python3

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-4

Compute the ratio of the sum of cube of the first 'n' natural numbers to the sum of square of first 'n' natural numbers.

Code:

input_int=[x for x in range (1,input_int+1)]
python=reduce(lambda x,y:x+y **3/sum(input_int) % x +y**2/sum(input_int),input_int)
x=10

Solution output:

62.96363636363636

Expected output:

7.857142857142857

python python-3.x

share|improve this question

edited Mar 9 at 9:30

Patrick Artner

27.2k62544

asked Mar 9 at 8:16

Pradeep vPradeep v

1

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please add some context to your question as well as formatting your code.
  
  – Tobias Wilfert
  Mar 9 at 8:18
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You are only squaring and cubing the y .. for starters. Dividing through sum(input_int) makes no sense at all for your taks.
  
  – Patrick Artner
  Mar 9 at 9:41
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Reads like a university/college/interview programming assignment...
  
  – dijksterhuis
  Mar 9 at 12:43
  

  
  
  
  

add a comment | 

-4

Compute the ratio of the sum of cube of the first 'n' natural numbers to the sum of square of first 'n' natural numbers.

Code:

input_int=[x for x in range (1,input_int+1)]
python=reduce(lambda x,y:x+y **3/sum(input_int) % x +y**2/sum(input_int),input_int)
x=10

Solution output:

62.96363636363636

Expected output:

7.857142857142857

python python-3.x

share|improve this question

edited Mar 9 at 9:30

Patrick Artner

27.2k62544

asked Mar 9 at 8:16

Pradeep vPradeep v

1

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please add some context to your question as well as formatting your code.
  
  – Tobias Wilfert
  Mar 9 at 8:18
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You are only squaring and cubing the y .. for starters. Dividing through sum(input_int) makes no sense at all for your taks.
  
  – Patrick Artner
  Mar 9 at 9:41
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Reads like a university/college/interview programming assignment...
  
  – dijksterhuis
  Mar 9 at 12:43
  

  
  
  
  

add a comment | 

Compute the ratio of the sum of cube of the first 'n' natural numbers to the sum of square of first 'n' natural numbers.

Code:

input_int=[x for x in range (1,input_int+1)]
python=reduce(lambda x,y:x+y **3/sum(input_int) % x +y**2/sum(input_int),input_int)
x=10

Solution output:

62.96363636363636

Expected output:

7.857142857142857

python python-3.x

share|improve this question

edited Mar 9 at 9:30

Patrick Artner

27.2k62544

asked Mar 9 at 8:16

Pradeep vPradeep v

1

input_int=[x for x in range (1,input_int+1)]
python=reduce(lambda x,y:x+y **3/sum(input_int) % x +y**2/sum(input_int),input_int)
x=10

62.96363636363636

7.857142857142857

share|improve this question

edited Mar 9 at 9:30

Patrick Artner

27.2k62544

asked Mar 9 at 8:16

Pradeep vPradeep v

1

share|improve this question

edited Mar 9 at 9:30

Patrick Artner

27.2k62544

asked Mar 9 at 8:16

Pradeep vPradeep v

1

edited Mar 9 at 9:30

Patrick Artner

27.2k62544

edited Mar 9 at 9:30

Patrick Artner

27.2k62544

asked Mar 9 at 8:16

Pradeep vPradeep v

1

asked Mar 9 at 8:16

Pradeep vPradeep v

1

2 Answers
2

active

oldest

votes

0

Your code is very hard to understand and does not even run.

Based on your description of the goal, I can suggest a simpler code to achieve it:

def calc_ratio(n):
 sum_3 = sum(x**3 for x in range(1, n+1))
 sum_2 = sum(x**2 for x in range(1, n+1))
 return sum_3 / sum_2

This would give these results:

>>> calc_ratio(10)
7.857142857142857
>>> calc_ratio(100)
75.3731343283582
>>> calc_ratio(1000)
750.3748125937032
>>> calc_ratio(10000)
7500.374981250938
>>> calc_ratio(100000)
75000.37499812501

share|improve this answer

answered Mar 9 at 11:23

RalfRalf

7,55341438

add a comment | 

0

from functools import reduce
import ast,sys
input_int = int(sys.stdin.read())

num_list = [x for x in range(1, input_int+1)]
print(reduce(lambda x, y : x + y ** 3, num_list) / reduce(lambda x, y : x + y ** ,num_list))

share|improve this answer

edited Mar 9 at 19:20

Justice_Lords

732211

answered Mar 9 at 12:33

Pradeep vPradeep v

1

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Please consider adding a description of your code so we know what it does and why.
  
  – Pikachu the Purple Wizard
  Mar 9 at 19:33
  

  
  
  
  

add a comment | 

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0

Your code is very hard to understand and does not even run.

Based on your description of the goal, I can suggest a simpler code to achieve it:

def calc_ratio(n):
 sum_3 = sum(x**3 for x in range(1, n+1))
 sum_2 = sum(x**2 for x in range(1, n+1))
 return sum_3 / sum_2

This would give these results:

>>> calc_ratio(10)
7.857142857142857
>>> calc_ratio(100)
75.3731343283582
>>> calc_ratio(1000)
750.3748125937032
>>> calc_ratio(10000)
7500.374981250938
>>> calc_ratio(100000)
75000.37499812501

share|improve this answer

answered Mar 9 at 11:23

RalfRalf

7,55341438

add a comment | 

0

Your code is very hard to understand and does not even run.

Based on your description of the goal, I can suggest a simpler code to achieve it:

def calc_ratio(n):
 sum_3 = sum(x**3 for x in range(1, n+1))
 sum_2 = sum(x**2 for x in range(1, n+1))
 return sum_3 / sum_2

This would give these results:

>>> calc_ratio(10)
7.857142857142857
>>> calc_ratio(100)
75.3731343283582
>>> calc_ratio(1000)
750.3748125937032
>>> calc_ratio(10000)
7500.374981250938
>>> calc_ratio(100000)
75000.37499812501

share|improve this answer

answered Mar 9 at 11:23

RalfRalf

7,55341438

add a comment | 

Your code is very hard to understand and does not even run.

Based on your description of the goal, I can suggest a simpler code to achieve it:

def calc_ratio(n):
 sum_3 = sum(x**3 for x in range(1, n+1))
 sum_2 = sum(x**2 for x in range(1, n+1))
 return sum_3 / sum_2

This would give these results:

>>> calc_ratio(10)
7.857142857142857
>>> calc_ratio(100)
75.3731343283582
>>> calc_ratio(1000)
750.3748125937032
>>> calc_ratio(10000)
7500.374981250938
>>> calc_ratio(100000)
75000.37499812501

share|improve this answer

answered Mar 9 at 11:23

RalfRalf

7,55341438

def calc_ratio(n):
 sum_3 = sum(x**3 for x in range(1, n+1))
 sum_2 = sum(x**2 for x in range(1, n+1))
 return sum_3 / sum_2

>>> calc_ratio(10)
7.857142857142857
>>> calc_ratio(100)
75.3731343283582
>>> calc_ratio(1000)
750.3748125937032
>>> calc_ratio(10000)
7500.374981250938
>>> calc_ratio(100000)
75000.37499812501

share|improve this answer

answered Mar 9 at 11:23

RalfRalf

7,55341438

answered Mar 9 at 11:23

RalfRalf

7,55341438

answered Mar 9 at 11:23

RalfRalf

7,55341438

0

from functools import reduce
import ast,sys
input_int = int(sys.stdin.read())

num_list = [x for x in range(1, input_int+1)]
print(reduce(lambda x, y : x + y ** 3, num_list) / reduce(lambda x, y : x + y ** ,num_list))

share|improve this answer

edited Mar 9 at 19:20

Justice_Lords

732211

answered Mar 9 at 12:33

Pradeep vPradeep v

1

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Please consider adding a description of your code so we know what it does and why.
  
  – Pikachu the Purple Wizard
  Mar 9 at 19:33
  

  
  
  
  

add a comment | 

0

from functools import reduce
import ast,sys
input_int = int(sys.stdin.read())

num_list = [x for x in range(1, input_int+1)]
print(reduce(lambda x, y : x + y ** 3, num_list) / reduce(lambda x, y : x + y ** ,num_list))

share|improve this answer

edited Mar 9 at 19:20

Justice_Lords

732211

answered Mar 9 at 12:33

Pradeep vPradeep v

1

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Please consider adding a description of your code so we know what it does and why.
  
  – Pikachu the Purple Wizard
  Mar 9 at 19:33
  

  
  
  
  

add a comment | 

from functools import reduce
import ast,sys
input_int = int(sys.stdin.read())

num_list = [x for x in range(1, input_int+1)]
print(reduce(lambda x, y : x + y ** 3, num_list) / reduce(lambda x, y : x + y ** ,num_list))

share|improve this answer

edited Mar 9 at 19:20

Justice_Lords

732211

answered Mar 9 at 12:33

Pradeep vPradeep v

1

from functools import reduce
import ast,sys
input_int = int(sys.stdin.read())

num_list = [x for x in range(1, input_int+1)]
print(reduce(lambda x, y : x + y ** 3, num_list) / reduce(lambda x, y : x + y ** ,num_list))

share|improve this answer

edited Mar 9 at 19:20

Justice_Lords

732211

answered Mar 9 at 12:33

Pradeep vPradeep v

1

edited Mar 9 at 19:20

Justice_Lords

732211

edited Mar 9 at 19:20

Justice_Lords

732211

answered Mar 9 at 12:33

Pradeep vPradeep v

1

answered Mar 9 at 12:33

Pradeep vPradeep v

1