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How to access all elements of a list (composed of dictionaries)? [closed]

0

I have two variables that are lists composed of dictionaries; a and b which will always have same number of elements.

For 3d graphing I create another dictionary from them. When I know the amount of elements this code words fine; say example I know there are 3.

fig = dict( data=[a[0],a[1],a[2],b[0],b[1],b[2]], layout=layout )

The problem is I in general will not know how many elements are in a and b. I cannot seem to figure out how to correctly iterate or loop through to replicate the code above in the general case.

The goal is to replicate the code above for the general case where I do not know the number of elements in a and b.

Any help is appreciated.

python python-2.7 jupyter-notebook plotly

share|improve this question

edited Mar 7 at 19:57

glibdud

5,69921731

asked Mar 7 at 19:53

JB5JB5

155

closed as off-topic by roganjosh, js1568, Deadpool, Garrett Hyde, Al Foиce ѫ Mar 7 at 21:43

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – roganjosh, js1568, Deadpool, Garrett Hyde, Al Foиce ѫ

If this question can be reworded to fit the rules in the help center, please edit the question.

add a comment | 

0

I have two variables that are lists composed of dictionaries; a and b which will always have same number of elements.

For 3d graphing I create another dictionary from them. When I know the amount of elements this code words fine; say example I know there are 3.

fig = dict( data=[a[0],a[1],a[2],b[0],b[1],b[2]], layout=layout )

The problem is I in general will not know how many elements are in a and b. I cannot seem to figure out how to correctly iterate or loop through to replicate the code above in the general case.

The goal is to replicate the code above for the general case where I do not know the number of elements in a and b.

Any help is appreciated.

python python-2.7 jupyter-notebook plotly

share|improve this question

edited Mar 7 at 19:57

glibdud

5,69921731

asked Mar 7 at 19:53

JB5JB5

155

closed as off-topic by roganjosh, js1568, Deadpool, Garrett Hyde, Al Foиce ѫ Mar 7 at 21:43

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – roganjosh, js1568, Deadpool, Garrett Hyde, Al Foиce ѫ

If this question can be reworded to fit the rules in the help center, please edit the question.

add a comment | 

I have two variables that are lists composed of dictionaries; a and b which will always have same number of elements.

For 3d graphing I create another dictionary from them. When I know the amount of elements this code words fine; say example I know there are 3.

fig = dict( data=[a[0],a[1],a[2],b[0],b[1],b[2]], layout=layout )

The problem is I in general will not know how many elements are in a and b. I cannot seem to figure out how to correctly iterate or loop through to replicate the code above in the general case.

The goal is to replicate the code above for the general case where I do not know the number of elements in a and b.

Any help is appreciated.

python python-2.7 jupyter-notebook plotly

share|improve this question

edited Mar 7 at 19:57

glibdud

5,69921731

asked Mar 7 at 19:53

JB5JB5

155

fig = dict( data=[a[0],a[1],a[2],b[0],b[1],b[2]], layout=layout )

share|improve this question

edited Mar 7 at 19:57

glibdud

5,69921731

asked Mar 7 at 19:53

JB5JB5

155

share|improve this question

edited Mar 7 at 19:57

glibdud

5,69921731

asked Mar 7 at 19:53

JB5JB5

155

edited Mar 7 at 19:57

glibdud

5,69921731

edited Mar 7 at 19:57

glibdud

5,69921731

asked Mar 7 at 19:53

JB5JB5

155

asked Mar 7 at 19:53

JB5JB5

155

3 Answers
3

active

oldest

votes

0

This should do the job:

fig = dict(data=a + b, layout=layout)

The + operator will concatenate the operands when used between two lists.

For example:

>>> a = [1, 2, 3]
>>> b = [4, 5, 6]
>>> a + b 
[1, 2, 3, 4, 5, 6]

share|improve this answer

edited Mar 7 at 20:03

answered Mar 7 at 19:59

ruoholaruohola

1,447319

add a comment | 

0

this should work:

fig = dict( data=a + b, layout=layout )

share|improve this answer

edited Mar 7 at 20:04

answered Mar 7 at 19:58

MuditsMudits

70611028

add a comment | 

0

You can chain both lists. It is more time efficient than creating of a new list by concatenating:

from itertools import chain

a = [1, 2, 3]
b = [4, 5, 6]

for i in chain(a, b):
 print(i)

Output:

1
2
3
4
5
6

share|improve this answer

answered Mar 7 at 21:24

Mykola ZotkoMykola Zotko

1,895518

add a comment | 

0

This should do the job:

fig = dict(data=a + b, layout=layout)

The + operator will concatenate the operands when used between two lists.

For example:

>>> a = [1, 2, 3]
>>> b = [4, 5, 6]
>>> a + b 
[1, 2, 3, 4, 5, 6]

share|improve this answer

edited Mar 7 at 20:03

answered Mar 7 at 19:59

ruoholaruohola

1,447319

add a comment | 

0

This should do the job:

fig = dict(data=a + b, layout=layout)

The + operator will concatenate the operands when used between two lists.

For example:

>>> a = [1, 2, 3]
>>> b = [4, 5, 6]
>>> a + b 
[1, 2, 3, 4, 5, 6]

share|improve this answer

edited Mar 7 at 20:03

answered Mar 7 at 19:59

ruoholaruohola

1,447319

add a comment | 

This should do the job:

fig = dict(data=a + b, layout=layout)

The + operator will concatenate the operands when used between two lists.

For example:

>>> a = [1, 2, 3]
>>> b = [4, 5, 6]
>>> a + b 
[1, 2, 3, 4, 5, 6]

share|improve this answer

edited Mar 7 at 20:03

answered Mar 7 at 19:59

ruoholaruohola

1,447319

fig = dict(data=a + b, layout=layout)

>>> a = [1, 2, 3]
>>> b = [4, 5, 6]
>>> a + b 
[1, 2, 3, 4, 5, 6]

share|improve this answer

edited Mar 7 at 20:03

answered Mar 7 at 19:59

ruoholaruohola

1,447319

answered Mar 7 at 19:59

ruoholaruohola

1,447319

answered Mar 7 at 19:59

ruoholaruohola

1,447319

0

this should work:

fig = dict( data=a + b, layout=layout )

share|improve this answer

edited Mar 7 at 20:04

answered Mar 7 at 19:58

MuditsMudits

70611028

add a comment | 

0

this should work:

fig = dict( data=a + b, layout=layout )

share|improve this answer

edited Mar 7 at 20:04

answered Mar 7 at 19:58

MuditsMudits

70611028

add a comment | 

this should work:

fig = dict( data=a + b, layout=layout )

share|improve this answer

edited Mar 7 at 20:04

answered Mar 7 at 19:58

MuditsMudits

70611028

fig = dict( data=a + b, layout=layout )

share|improve this answer

edited Mar 7 at 20:04

answered Mar 7 at 19:58

MuditsMudits

70611028

answered Mar 7 at 19:58

MuditsMudits

70611028

answered Mar 7 at 19:58

MuditsMudits

70611028

0

You can chain both lists. It is more time efficient than creating of a new list by concatenating:

from itertools import chain

a = [1, 2, 3]
b = [4, 5, 6]

for i in chain(a, b):
 print(i)

Output:

1
2
3
4
5
6

share|improve this answer

answered Mar 7 at 21:24

Mykola ZotkoMykola Zotko

1,895518

add a comment | 

0

You can chain both lists. It is more time efficient than creating of a new list by concatenating:

from itertools import chain

a = [1, 2, 3]
b = [4, 5, 6]

for i in chain(a, b):
 print(i)

Output:

1
2
3
4
5
6

share|improve this answer

answered Mar 7 at 21:24

Mykola ZotkoMykola Zotko

1,895518

add a comment | 

You can chain both lists. It is more time efficient than creating of a new list by concatenating:

from itertools import chain

a = [1, 2, 3]
b = [4, 5, 6]

for i in chain(a, b):
 print(i)

Output:

1
2
3
4
5
6

share|improve this answer

answered Mar 7 at 21:24

Mykola ZotkoMykola Zotko

1,895518

from itertools import chain

a = [1, 2, 3]
b = [4, 5, 6]

for i in chain(a, b):
 print(i)

1
2
3
4
5
6

share|improve this answer

answered Mar 7 at 21:24

Mykola ZotkoMykola Zotko

1,895518

answered Mar 7 at 21:24

Mykola ZotkoMykola Zotko

1,895518

answered Mar 7 at 21:24

Mykola ZotkoMykola Zotko

1,895518