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How to force NumPy to always use a precision (float32, float64 …)?



2019 Community Moderator ElectionHow do I print a double value with full precision using cout?How can I force division to be floating point? Division keeps rounding down to 0?How can the Euclidean distance be calculated with NumPy?How to deal with floating point number precision in JavaScript?How to print the full NumPy array, without truncation?How to access the ith column of a NumPy multidimensional array?What should I worry about if I compress float64 array to float32 in numpy?Golang floating point precision float32 vs float64Python+numpy: a lucky floating point case?NumPy casts lower precision to higher precision in floating point arithmetic










0















I am trying to study a little FIR example written in Python. See https://scipy-cookbook.readthedocs.io/items/FIRFilter.html



My goal is to study how output precision varies for each float16, float32 and float64 (available in numpy). So for the first case I need to keep all my computations done in float16 only. The thing is i should each time cast the data to ensure that I'm using the right format. Is there a method to consistently use a unified context for the whole computations i.e. to perform all computations (additions, substractions, cos, sin ...etc) using float16 for example without re-writing code with casts?










share|improve this question

















  • 1





    one way to do it as a 1-time hassle, is to assign a dtype to all your operations using a variable, that you can then set and change at top of the file as needed.

    – Paritosh Singh
    Mar 6 at 14:33






  • 1





    See Issue #6860: How to set float32 as default.

    – jdehesa
    Mar 6 at 14:49















0















I am trying to study a little FIR example written in Python. See https://scipy-cookbook.readthedocs.io/items/FIRFilter.html



My goal is to study how output precision varies for each float16, float32 and float64 (available in numpy). So for the first case I need to keep all my computations done in float16 only. The thing is i should each time cast the data to ensure that I'm using the right format. Is there a method to consistently use a unified context for the whole computations i.e. to perform all computations (additions, substractions, cos, sin ...etc) using float16 for example without re-writing code with casts?










share|improve this question

















  • 1





    one way to do it as a 1-time hassle, is to assign a dtype to all your operations using a variable, that you can then set and change at top of the file as needed.

    – Paritosh Singh
    Mar 6 at 14:33






  • 1





    See Issue #6860: How to set float32 as default.

    – jdehesa
    Mar 6 at 14:49













0












0








0








I am trying to study a little FIR example written in Python. See https://scipy-cookbook.readthedocs.io/items/FIRFilter.html



My goal is to study how output precision varies for each float16, float32 and float64 (available in numpy). So for the first case I need to keep all my computations done in float16 only. The thing is i should each time cast the data to ensure that I'm using the right format. Is there a method to consistently use a unified context for the whole computations i.e. to perform all computations (additions, substractions, cos, sin ...etc) using float16 for example without re-writing code with casts?










share|improve this question














I am trying to study a little FIR example written in Python. See https://scipy-cookbook.readthedocs.io/items/FIRFilter.html



My goal is to study how output precision varies for each float16, float32 and float64 (available in numpy). So for the first case I need to keep all my computations done in float16 only. The thing is i should each time cast the data to ensure that I'm using the right format. Is there a method to consistently use a unified context for the whole computations i.e. to perform all computations (additions, substractions, cos, sin ...etc) using float16 for example without re-writing code with casts?







python numpy floating-point precision






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 6 at 14:31









noureddine-asnoureddine-as

236




236







  • 1





    one way to do it as a 1-time hassle, is to assign a dtype to all your operations using a variable, that you can then set and change at top of the file as needed.

    – Paritosh Singh
    Mar 6 at 14:33






  • 1





    See Issue #6860: How to set float32 as default.

    – jdehesa
    Mar 6 at 14:49












  • 1





    one way to do it as a 1-time hassle, is to assign a dtype to all your operations using a variable, that you can then set and change at top of the file as needed.

    – Paritosh Singh
    Mar 6 at 14:33






  • 1





    See Issue #6860: How to set float32 as default.

    – jdehesa
    Mar 6 at 14:49







1




1





one way to do it as a 1-time hassle, is to assign a dtype to all your operations using a variable, that you can then set and change at top of the file as needed.

– Paritosh Singh
Mar 6 at 14:33





one way to do it as a 1-time hassle, is to assign a dtype to all your operations using a variable, that you can then set and change at top of the file as needed.

– Paritosh Singh
Mar 6 at 14:33




1




1





See Issue #6860: How to set float32 as default.

– jdehesa
Mar 6 at 14:49





See Issue #6860: How to set float32 as default.

– jdehesa
Mar 6 at 14:49












1 Answer
1






active

oldest

votes


















1














From the numpy basics:




When operating with arrays of different types, the type of the
resulting array corresponds to the more general or precise one (a
behavior known as upcasting).




You can define the data type on the array creation. Applying a sum, multiplication or substraction, result will upcast to the "larger" type, it will also keep the dtype if you perform operations on the array, e.g.:



x = np.ones(10, dtype=np.float16)
y = np.ones(10, dtype=np.float32)
print((x + y).dtype, (x - y).dtype, (x * y).dtype)
print(np.sin(x).dtype, np.sin(y).dtype)
>> float32 float32 float32
float16 float32


An exception is when passing an integer, in which case, by default, numpy upcasts to float64



print(np.sin(np.ones(10, dtype=int)).dtype)
>> float64





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    1 Answer
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    active

    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    From the numpy basics:




    When operating with arrays of different types, the type of the
    resulting array corresponds to the more general or precise one (a
    behavior known as upcasting).




    You can define the data type on the array creation. Applying a sum, multiplication or substraction, result will upcast to the "larger" type, it will also keep the dtype if you perform operations on the array, e.g.:



    x = np.ones(10, dtype=np.float16)
    y = np.ones(10, dtype=np.float32)
    print((x + y).dtype, (x - y).dtype, (x * y).dtype)
    print(np.sin(x).dtype, np.sin(y).dtype)
    >> float32 float32 float32
    float16 float32


    An exception is when passing an integer, in which case, by default, numpy upcasts to float64



    print(np.sin(np.ones(10, dtype=int)).dtype)
    >> float64





    share|improve this answer



























      1














      From the numpy basics:




      When operating with arrays of different types, the type of the
      resulting array corresponds to the more general or precise one (a
      behavior known as upcasting).




      You can define the data type on the array creation. Applying a sum, multiplication or substraction, result will upcast to the "larger" type, it will also keep the dtype if you perform operations on the array, e.g.:



      x = np.ones(10, dtype=np.float16)
      y = np.ones(10, dtype=np.float32)
      print((x + y).dtype, (x - y).dtype, (x * y).dtype)
      print(np.sin(x).dtype, np.sin(y).dtype)
      >> float32 float32 float32
      float16 float32


      An exception is when passing an integer, in which case, by default, numpy upcasts to float64



      print(np.sin(np.ones(10, dtype=int)).dtype)
      >> float64





      share|improve this answer

























        1












        1








        1







        From the numpy basics:




        When operating with arrays of different types, the type of the
        resulting array corresponds to the more general or precise one (a
        behavior known as upcasting).




        You can define the data type on the array creation. Applying a sum, multiplication or substraction, result will upcast to the "larger" type, it will also keep the dtype if you perform operations on the array, e.g.:



        x = np.ones(10, dtype=np.float16)
        y = np.ones(10, dtype=np.float32)
        print((x + y).dtype, (x - y).dtype, (x * y).dtype)
        print(np.sin(x).dtype, np.sin(y).dtype)
        >> float32 float32 float32
        float16 float32


        An exception is when passing an integer, in which case, by default, numpy upcasts to float64



        print(np.sin(np.ones(10, dtype=int)).dtype)
        >> float64





        share|improve this answer













        From the numpy basics:




        When operating with arrays of different types, the type of the
        resulting array corresponds to the more general or precise one (a
        behavior known as upcasting).




        You can define the data type on the array creation. Applying a sum, multiplication or substraction, result will upcast to the "larger" type, it will also keep the dtype if you perform operations on the array, e.g.:



        x = np.ones(10, dtype=np.float16)
        y = np.ones(10, dtype=np.float32)
        print((x + y).dtype, (x - y).dtype, (x * y).dtype)
        print(np.sin(x).dtype, np.sin(y).dtype)
        >> float32 float32 float32
        float16 float32


        An exception is when passing an integer, in which case, by default, numpy upcasts to float64



        print(np.sin(np.ones(10, dtype=int)).dtype)
        >> float64






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Mar 6 at 14:57









        MstainoMstaino

        1,8451412




        1,8451412





























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