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Jupyter Notebook Add directory/file path to Windows Environment Variable
2019 Community Moderator ElectionHow to set env variable in Jupyter notebookHow do I list all files of a directory?Find all files in a directory with extension .txt in PythonHow to access environment variable values?fatal error: Python.h: No such file or directoryUnable to set up Jupyter NotebookEnvironment Munging in Anaconda, PyCharm, and Jupyter Notebooks? No such file or directory: 'conda'Jupyter notebook wrong pathGraphviz not running in jupyter notebook python = 3.6?No module named 'graphviz' in Jupyter NotebookWindows “jupyter notebook” command failing
I need some help with appending a file path to "PATH" variable in Windows 10 from Jupyter Notebook (Python 3.6). I need to do it at run time from notebook because my user account is doesn't have admin rights.
Background:
I want to use GrphViz 2.8 library. For this library to work from Jupyter notebook, the location of dot.exe file i.e. C:Program Files (x86)Graphviz2.38bindot.exe
needs to be added to PATH environment variable.
I have seen that os.getenv('Path')
command will get me the value of this Path variable but I couldn't find the equivalent set method to append my entry to this Path variable.
I have also seen this post which suggests using kernal.json
But I didn't understand how to update the PATH variable.
Any example how to achieve this will be very much appreciated.
If it is not possible, then can you please suggest an alternative way of using GrpahViz without updating "Path" variable.
PS I can't use Online dot-file to SVG/PNG converters because I am using a package which requires GrpahViz to be available locally.
python jupyter-notebook graphviz pygraphviz
add a comment |
I need some help with appending a file path to "PATH" variable in Windows 10 from Jupyter Notebook (Python 3.6). I need to do it at run time from notebook because my user account is doesn't have admin rights.
Background:
I want to use GrphViz 2.8 library. For this library to work from Jupyter notebook, the location of dot.exe file i.e. C:Program Files (x86)Graphviz2.38bindot.exe
needs to be added to PATH environment variable.
I have seen that os.getenv('Path')
command will get me the value of this Path variable but I couldn't find the equivalent set method to append my entry to this Path variable.
I have also seen this post which suggests using kernal.json
But I didn't understand how to update the PATH variable.
Any example how to achieve this will be very much appreciated.
If it is not possible, then can you please suggest an alternative way of using GrpahViz without updating "Path" variable.
PS I can't use Online dot-file to SVG/PNG converters because I am using a package which requires GrpahViz to be available locally.
python jupyter-notebook graphviz pygraphviz
1
Best would be to add te mentioned path to the PATH variable of your system. Alternatively you could, probably, useos.putenv
oros.environ
(see e.g. docs.python.org/3/library/os.html)
– albert
2 days ago
add a comment |
I need some help with appending a file path to "PATH" variable in Windows 10 from Jupyter Notebook (Python 3.6). I need to do it at run time from notebook because my user account is doesn't have admin rights.
Background:
I want to use GrphViz 2.8 library. For this library to work from Jupyter notebook, the location of dot.exe file i.e. C:Program Files (x86)Graphviz2.38bindot.exe
needs to be added to PATH environment variable.
I have seen that os.getenv('Path')
command will get me the value of this Path variable but I couldn't find the equivalent set method to append my entry to this Path variable.
I have also seen this post which suggests using kernal.json
But I didn't understand how to update the PATH variable.
Any example how to achieve this will be very much appreciated.
If it is not possible, then can you please suggest an alternative way of using GrpahViz without updating "Path" variable.
PS I can't use Online dot-file to SVG/PNG converters because I am using a package which requires GrpahViz to be available locally.
python jupyter-notebook graphviz pygraphviz
I need some help with appending a file path to "PATH" variable in Windows 10 from Jupyter Notebook (Python 3.6). I need to do it at run time from notebook because my user account is doesn't have admin rights.
Background:
I want to use GrphViz 2.8 library. For this library to work from Jupyter notebook, the location of dot.exe file i.e. C:Program Files (x86)Graphviz2.38bindot.exe
needs to be added to PATH environment variable.
I have seen that os.getenv('Path')
command will get me the value of this Path variable but I couldn't find the equivalent set method to append my entry to this Path variable.
I have also seen this post which suggests using kernal.json
But I didn't understand how to update the PATH variable.
Any example how to achieve this will be very much appreciated.
If it is not possible, then can you please suggest an alternative way of using GrpahViz without updating "Path" variable.
PS I can't use Online dot-file to SVG/PNG converters because I am using a package which requires GrpahViz to be available locally.
python jupyter-notebook graphviz pygraphviz
python jupyter-notebook graphviz pygraphviz
edited yesterday
Khurram Majeed
asked 2 days ago
Khurram MajeedKhurram Majeed
1,12062648
1,12062648
1
Best would be to add te mentioned path to the PATH variable of your system. Alternatively you could, probably, useos.putenv
oros.environ
(see e.g. docs.python.org/3/library/os.html)
– albert
2 days ago
add a comment |
1
Best would be to add te mentioned path to the PATH variable of your system. Alternatively you could, probably, useos.putenv
oros.environ
(see e.g. docs.python.org/3/library/os.html)
– albert
2 days ago
1
1
Best would be to add te mentioned path to the PATH variable of your system. Alternatively you could, probably, use
os.putenv
or os.environ
(see e.g. docs.python.org/3/library/os.html)– albert
2 days ago
Best would be to add te mentioned path to the PATH variable of your system. Alternatively you could, probably, use
os.putenv
or os.environ
(see e.g. docs.python.org/3/library/os.html)– albert
2 days ago
add a comment |
1 Answer
1
active
oldest
votes
Try this:
import os
os.environ['PATH'] += os.pathsep + r'C:Program Files (x86)Graphviz2.38bindot.exe'
path with the name of the executable?
– albert
2 days ago
Yes @albert, path to the executable file.
– Hiadore
2 days ago
You write "path to the executable file" but this would, as far as I know, be "C:Program Files (x86)Graphviz2.38bin"
– albert
2 days ago
I think path to executable mean the full path of the file, include filename. Your case is likely more precisely called path to directory of the executable. See itgeared.com/articles/1059-how-to-change-services-path-to
– Hiadore
2 days ago
add a comment |
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1 Answer
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oldest
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oldest
votes
Try this:
import os
os.environ['PATH'] += os.pathsep + r'C:Program Files (x86)Graphviz2.38bindot.exe'
path with the name of the executable?
– albert
2 days ago
Yes @albert, path to the executable file.
– Hiadore
2 days ago
You write "path to the executable file" but this would, as far as I know, be "C:Program Files (x86)Graphviz2.38bin"
– albert
2 days ago
I think path to executable mean the full path of the file, include filename. Your case is likely more precisely called path to directory of the executable. See itgeared.com/articles/1059-how-to-change-services-path-to
– Hiadore
2 days ago
add a comment |
Try this:
import os
os.environ['PATH'] += os.pathsep + r'C:Program Files (x86)Graphviz2.38bindot.exe'
path with the name of the executable?
– albert
2 days ago
Yes @albert, path to the executable file.
– Hiadore
2 days ago
You write "path to the executable file" but this would, as far as I know, be "C:Program Files (x86)Graphviz2.38bin"
– albert
2 days ago
I think path to executable mean the full path of the file, include filename. Your case is likely more precisely called path to directory of the executable. See itgeared.com/articles/1059-how-to-change-services-path-to
– Hiadore
2 days ago
add a comment |
Try this:
import os
os.environ['PATH'] += os.pathsep + r'C:Program Files (x86)Graphviz2.38bindot.exe'
Try this:
import os
os.environ['PATH'] += os.pathsep + r'C:Program Files (x86)Graphviz2.38bindot.exe'
answered 2 days ago
HiadoreHiadore
20317
20317
path with the name of the executable?
– albert
2 days ago
Yes @albert, path to the executable file.
– Hiadore
2 days ago
You write "path to the executable file" but this would, as far as I know, be "C:Program Files (x86)Graphviz2.38bin"
– albert
2 days ago
I think path to executable mean the full path of the file, include filename. Your case is likely more precisely called path to directory of the executable. See itgeared.com/articles/1059-how-to-change-services-path-to
– Hiadore
2 days ago
add a comment |
path with the name of the executable?
– albert
2 days ago
Yes @albert, path to the executable file.
– Hiadore
2 days ago
You write "path to the executable file" but this would, as far as I know, be "C:Program Files (x86)Graphviz2.38bin"
– albert
2 days ago
I think path to executable mean the full path of the file, include filename. Your case is likely more precisely called path to directory of the executable. See itgeared.com/articles/1059-how-to-change-services-path-to
– Hiadore
2 days ago
path with the name of the executable?
– albert
2 days ago
path with the name of the executable?
– albert
2 days ago
Yes @albert, path to the executable file.
– Hiadore
2 days ago
Yes @albert, path to the executable file.
– Hiadore
2 days ago
You write "path to the executable file" but this would, as far as I know, be "C:Program Files (x86)Graphviz2.38bin"
– albert
2 days ago
You write "path to the executable file" but this would, as far as I know, be "C:Program Files (x86)Graphviz2.38bin"
– albert
2 days ago
I think path to executable mean the full path of the file, include filename. Your case is likely more precisely called path to directory of the executable. See itgeared.com/articles/1059-how-to-change-services-path-to
– Hiadore
2 days ago
I think path to executable mean the full path of the file, include filename. Your case is likely more precisely called path to directory of the executable. See itgeared.com/articles/1059-how-to-change-services-path-to
– Hiadore
2 days ago
add a comment |
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1
Best would be to add te mentioned path to the PATH variable of your system. Alternatively you could, probably, use
os.putenv
oros.environ
(see e.g. docs.python.org/3/library/os.html)– albert
2 days ago