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Scala function that accepts array argument and returns a mutated array
2019 Community Moderator ElectionIs there a NumPy function to return the first index of something in an array?Converting an array to a function arguments listDifference between Array and List in scalaWhat is the apply function in Scala?Covariance of a passed function argumentHow to get distinct values from an array of objects in JavaScript?Why not inherit from List<T>?How do you return an array in a method?Scala ambiguity with paren-less function callsScala: type arguments do not conform to trait Subtractable's type parameter bounds
I would like to figure out the most pragmatic way to accept an array (or list) and append to the data structure. Then finally return the new data structure.
Something like this:
def template(array: Array[String]): Array[Nothing] =
val staging_path = "s3//clone-staging/"
var path_list = Array()
//iterate through each of the items in the array and append to the new string.
for(outputString <- array)
var new_path = staging_path.toString + outputString
println(new_path)
//path_list I thought would add these new staging_path to the array
path_list +: new_path
path_list(4)
However, calling a single index of the data structure as a shanty way of checking existence, path_list(4) returns an Out of Bounds.
Thanks.
arrays scala list string-interpolation
asked Mar 6 at 17:34
tjmorri7tjmorri7
34
add a comment |
I would like to figure out the most pragmatic way to accept an array (or list) and append to the data structure. Then finally return the new data structure.
Something like this:
def template(array: Array[String]): Array[Nothing] =
val staging_path = "s3//clone-staging/"
var path_list = Array()
//iterate through each of the items in the array and append to the new string.
for(outputString <- array)
var new_path = staging_path.toString + outputString
println(new_path)
//path_list I thought would add these new staging_path to the array
path_list +: new_path
path_list(4)
However, calling a single index of the data structure as a shanty way of checking existence, path_list(4) returns an Out of Bounds.
Thanks.
arrays scala list string-interpolation
asked Mar 6 at 17:34
tjmorri7tjmorri7
34
2
I'm not sure what thepath_list(4)is doing there, but a much more idiomatic solution would be something likedef template(values: List[String]) = values.map("s3//clone-staging" + _).
– Travis Brown
Mar 6 at 17:46
Just trying to return a single index from the new data structure as a way to check if it exists or not.
– tjmorri7
Mar 6 at 17:49
add a comment |
I would like to figure out the most pragmatic way to accept an array (or list) and append to the data structure. Then finally return the new data structure.
Something like this:
def template(array: Array[String]): Array[Nothing] =
val staging_path = "s3//clone-staging/"
var path_list = Array()
//iterate through each of the items in the array and append to the new string.
for(outputString <- array)
var new_path = staging_path.toString + outputString
println(new_path)
//path_list I thought would add these new staging_path to the array
path_list +: new_path
path_list(4)
However, calling a single index of the data structure as a shanty way of checking existence, path_list(4) returns an Out of Bounds.
Thanks.
arrays scala list string-interpolation
asked Mar 6 at 17:34
tjmorri7tjmorri7
34
I would like to figure out the most pragmatic way to accept an array (or list) and append to the data structure. Then finally return the new data structure.
Something like this:
def template(array: Array[String]): Array[Nothing] =
val staging_path = "s3//clone-staging/"
var path_list = Array()
//iterate through each of the items in the array and append to the new string.
for(outputString <- array)
var new_path = staging_path.toString + outputString
println(new_path)
//path_list I thought would add these new staging_path to the array
path_list +: new_path
path_list(4)
However, calling a single index of the data structure as a shanty way of checking existence, path_list(4) returns an Out of Bounds.
Thanks.
arrays scala list string-interpolation
arrays scala list string-interpolation
asked Mar 6 at 17:34
tjmorri7tjmorri7
34
asked Mar 6 at 17:34
tjmorri7tjmorri7
34
edited Mar 6 at 20:23
tjmorri7
asked Mar 6 at 17:34
tjmorri7tjmorri7
34
asked Mar 6 at 17:34
tjmorri7tjmorri7
34
asked Mar 6 at 17:34
tjmorri7tjmorri7
34
34
2
I'm not sure what thepath_list(4)is doing there, but a much more idiomatic solution would be something likedef template(values: List[String]) = values.map("s3//clone-staging" + _).
– Travis Brown
Mar 6 at 17:46
Just trying to return a single index from the new data structure as a way to check if it exists or not.
– tjmorri7
Mar 6 at 17:49
add a comment |
2
I'm not sure what thepath_list(4)is doing there, but a much more idiomatic solution would be something likedef template(values: List[String]) = values.map("s3//clone-staging" + _).
– Travis Brown
Mar 6 at 17:46
Just trying to return a single index from the new data structure as a way to check if it exists or not.
– tjmorri7
Mar 6 at 17:49
2
2
I'm not sure what the
path_list(4) is doing there, but a much more idiomatic solution would be something like def template(values: List[String]) = values.map("s3//clone-staging" + _).– Travis Brown
Mar 6 at 17:46
I'm not sure what the
path_list(4) is doing there, but a much more idiomatic solution would be something like def template(values: List[String]) = values.map("s3//clone-staging" + _).– Travis Brown
Mar 6 at 17:46
Just trying to return a single index from the new data structure as a way to check if it exists or not.
– tjmorri7
Mar 6 at 17:49
Just trying to return a single index from the new data structure as a way to check if it exists or not.
– tjmorri7
Mar 6 at 17:49
add a comment |
1 Answer
1
active
oldest
votes
I think you just want to use map here:
val staging_path = "s3//clone-staging/"
val dirs = Array("one", "two", "three", "four", "five")
val paths = dirs.map(dir => staging_path + dir)
println(paths)
// result: paths: Array[String] = Array(s3//clone-staging/one, s3//clone-staging/two, s3//clone-staging/three, s3//clone-staging/four, s3//clone-staging/five)
println(paths.length)
// result: 5
In functional programming land you are generally trying to avoid mutations. Instead, think of it as transforming your input array into a new array.
answered Mar 6 at 18:14
Kit MenkeKit Menke
6,56112752
Avoiding the original mutation of the data structure is what I was attempting by creating the local var path_list = Array()
– tjmorri7
Mar 6 at 18:24
@tjmorri7 if this solved your problem, please consider accepting this answer. If it does not, for whatever reason, please leave a comment explaining why it does not, so the answer could be improved. - Take a look to What should I do when someone answers my question?.
– Luis Miguel Mejía Suárez
Mar 6 at 18:43
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
I think you just want to use map here:
val staging_path = "s3//clone-staging/"
val dirs = Array("one", "two", "three", "four", "five")
val paths = dirs.map(dir => staging_path + dir)
println(paths)
// result: paths: Array[String] = Array(s3//clone-staging/one, s3//clone-staging/two, s3//clone-staging/three, s3//clone-staging/four, s3//clone-staging/five)
println(paths.length)
// result: 5
In functional programming land you are generally trying to avoid mutations. Instead, think of it as transforming your input array into a new array.
answered Mar 6 at 18:14
Kit MenkeKit Menke
6,56112752
Avoiding the original mutation of the data structure is what I was attempting by creating the local var path_list = Array()
– tjmorri7
Mar 6 at 18:24
@tjmorri7 if this solved your problem, please consider accepting this answer. If it does not, for whatever reason, please leave a comment explaining why it does not, so the answer could be improved. - Take a look to What should I do when someone answers my question?.
– Luis Miguel Mejía Suárez
Mar 6 at 18:43
add a comment |
I think you just want to use map here:
val staging_path = "s3//clone-staging/"
val dirs = Array("one", "two", "three", "four", "five")
val paths = dirs.map(dir => staging_path + dir)
println(paths)
// result: paths: Array[String] = Array(s3//clone-staging/one, s3//clone-staging/two, s3//clone-staging/three, s3//clone-staging/four, s3//clone-staging/five)
println(paths.length)
// result: 5
In functional programming land you are generally trying to avoid mutations. Instead, think of it as transforming your input array into a new array.
answered Mar 6 at 18:14
Kit MenkeKit Menke
6,56112752
Avoiding the original mutation of the data structure is what I was attempting by creating the local var path_list = Array()
– tjmorri7
Mar 6 at 18:24
@tjmorri7 if this solved your problem, please consider accepting this answer. If it does not, for whatever reason, please leave a comment explaining why it does not, so the answer could be improved. - Take a look to What should I do when someone answers my question?.
– Luis Miguel Mejía Suárez
Mar 6 at 18:43
add a comment |
I think you just want to use map here:
val staging_path = "s3//clone-staging/"
val dirs = Array("one", "two", "three", "four", "five")
val paths = dirs.map(dir => staging_path + dir)
println(paths)
// result: paths: Array[String] = Array(s3//clone-staging/one, s3//clone-staging/two, s3//clone-staging/three, s3//clone-staging/four, s3//clone-staging/five)
println(paths.length)
// result: 5
In functional programming land you are generally trying to avoid mutations. Instead, think of it as transforming your input array into a new array.
answered Mar 6 at 18:14
Kit MenkeKit Menke
6,56112752
I think you just want to use map here:
val staging_path = "s3//clone-staging/"
val dirs = Array("one", "two", "three", "four", "five")
val paths = dirs.map(dir => staging_path + dir)
println(paths)
// result: paths: Array[String] = Array(s3//clone-staging/one, s3//clone-staging/two, s3//clone-staging/three, s3//clone-staging/four, s3//clone-staging/five)
println(paths.length)
// result: 5
In functional programming land you are generally trying to avoid mutations. Instead, think of it as transforming your input array into a new array.
answered Mar 6 at 18:14
Kit MenkeKit Menke
6,56112752
answered Mar 6 at 18:14
Kit MenkeKit Menke
6,56112752
answered Mar 6 at 18:14
Kit MenkeKit Menke
6,56112752
answered Mar 6 at 18:14
Kit MenkeKit Menke
6,56112752
6,56112752
Avoiding the original mutation of the data structure is what I was attempting by creating the local var path_list = Array()
– tjmorri7
Mar 6 at 18:24
@tjmorri7 if this solved your problem, please consider accepting this answer. If it does not, for whatever reason, please leave a comment explaining why it does not, so the answer could be improved. - Take a look to What should I do when someone answers my question?.
– Luis Miguel Mejía Suárez
Mar 6 at 18:43
add a comment |
Avoiding the original mutation of the data structure is what I was attempting by creating the local var path_list = Array()
– tjmorri7
Mar 6 at 18:24
@tjmorri7 if this solved your problem, please consider accepting this answer. If it does not, for whatever reason, please leave a comment explaining why it does not, so the answer could be improved. - Take a look to What should I do when someone answers my question?.
– Luis Miguel Mejía Suárez
Mar 6 at 18:43
Avoiding the original mutation of the data structure is what I was attempting by creating the local var path_list = Array()
– tjmorri7
Mar 6 at 18:24
Avoiding the original mutation of the data structure is what I was attempting by creating the local var path_list = Array()
– tjmorri7
Mar 6 at 18:24
@tjmorri7 if this solved your problem, please consider accepting this answer. If it does not, for whatever reason, please leave a comment explaining why it does not, so the answer could be improved. - Take a look to What should I do when someone answers my question?.
– Luis Miguel Mejía Suárez
Mar 6 at 18:43
@tjmorri7 if this solved your problem, please consider accepting this answer. If it does not, for whatever reason, please leave a comment explaining why it does not, so the answer could be improved. - Take a look to What should I do when someone answers my question?.
– Luis Miguel Mejía Suárez
Mar 6 at 18:43
add a comment |
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2
I'm not sure what the
path_list(4)is doing there, but a much more idiomatic solution would be something likedef template(values: List[String]) = values.map("s3//clone-staging" + _).– Travis Brown
Mar 6 at 17:46
Just trying to return a single index from the new data structure as a way to check if it exists or not.
– tjmorri7
Mar 6 at 17:49