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Listing word final consonants cluster in German
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)
Data science time! April 2019 and salary with experience
The Ask Question Wizard is Live!How do I check if a list is empty?Finding the index of an item given a list containing it in PythonDifference between append vs. extend list methods in PythonRegular expression to match a line that doesn't contain a wordHow to make a flat list out of list of listsHow do I get the number of elements in a list in Python?How do I concatenate two lists in Python?How to clone or copy a list?How do I list all files of a directory?How to read a file line-by-line into a list?
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I wrote a program that finds and counts initial consonant clusters in German and Spanish texts. I want a regex that will find clusters on final positions. Using b or $ does not work. Can someone help me determine how I should change my regex so that it will work for final consonants clusters?
I currently have sth like this for initial clusters:
for w in words:
initial = re.search('^([^aeiouy]*)[aeiouy]',w)
Or sth like this:
initial = re.search('^[^aeiouy]2,',w)
python regex cluster-computing final
edited Mar 8 at 20:44
marchoy
16918
asked Mar 8 at 20:28
WhiteWhite
83
add a comment |
I wrote a program that finds and counts initial consonant clusters in German and Spanish texts. I want a regex that will find clusters on final positions. Using b or $ does not work. Can someone help me determine how I should change my regex so that it will work for final consonants clusters?
I currently have sth like this for initial clusters:
for w in words:
initial = re.search('^([^aeiouy]*)[aeiouy]',w)
Or sth like this:
initial = re.search('^[^aeiouy]2,',w)
python regex cluster-computing final
edited Mar 8 at 20:44
marchoy
16918
asked Mar 8 at 20:28
WhiteWhite
83
1
Tryre.search(r'[^aeiouy]2,b', w)orre.search(r'[^aeiouy]+$', w)
– Wiktor Stribiżew
Mar 8 at 20:29
Actually, already tried that and the outcome of using it is just a list of words with frequency. I am looking for sth like in English 'singing' - the outcome should be: 'ng' cluster. So now that I am thinking maybe it should be a code more like this:(?:(?![aeiou])[a-z])2,but with modification to final cluster, still doesn't work
– White
Mar 8 at 20:43
Try(?:(?![aeiou])[a-z])2,$, see demo.
– Wiktor Stribiżew
Mar 8 at 20:44
Thank you very much for your help!
– White
Mar 8 at 20:47
add a comment |
I wrote a program that finds and counts initial consonant clusters in German and Spanish texts. I want a regex that will find clusters on final positions. Using b or $ does not work. Can someone help me determine how I should change my regex so that it will work for final consonants clusters?
I currently have sth like this for initial clusters:
for w in words:
initial = re.search('^([^aeiouy]*)[aeiouy]',w)
Or sth like this:
initial = re.search('^[^aeiouy]2,',w)
python regex cluster-computing final
edited Mar 8 at 20:44
marchoy
16918
asked Mar 8 at 20:28
WhiteWhite
83
I wrote a program that finds and counts initial consonant clusters in German and Spanish texts. I want a regex that will find clusters on final positions. Using b or $ does not work. Can someone help me determine how I should change my regex so that it will work for final consonants clusters?
I currently have sth like this for initial clusters:
for w in words:
initial = re.search('^([^aeiouy]*)[aeiouy]',w)
Or sth like this:
initial = re.search('^[^aeiouy]2,',w)
python regex cluster-computing final
python regex cluster-computing final
edited Mar 8 at 20:44
marchoy
16918
asked Mar 8 at 20:28
WhiteWhite
83
edited Mar 8 at 20:44
marchoy
16918
asked Mar 8 at 20:28
WhiteWhite
83
edited Mar 8 at 20:44
marchoy
16918
edited Mar 8 at 20:44
marchoy
16918
edited Mar 8 at 20:44
marchoy
16918
16918
asked Mar 8 at 20:28
WhiteWhite
83
asked Mar 8 at 20:28
WhiteWhite
83
asked Mar 8 at 20:28
WhiteWhite
83
83
1
Tryre.search(r'[^aeiouy]2,b', w)orre.search(r'[^aeiouy]+$', w)
– Wiktor Stribiżew
Mar 8 at 20:29
Actually, already tried that and the outcome of using it is just a list of words with frequency. I am looking for sth like in English 'singing' - the outcome should be: 'ng' cluster. So now that I am thinking maybe it should be a code more like this:(?:(?![aeiou])[a-z])2,but with modification to final cluster, still doesn't work
– White
Mar 8 at 20:43
Try(?:(?![aeiou])[a-z])2,$, see demo.
– Wiktor Stribiżew
Mar 8 at 20:44
Thank you very much for your help!
– White
Mar 8 at 20:47
add a comment |
1
Tryre.search(r'[^aeiouy]2,b', w)orre.search(r'[^aeiouy]+$', w)
– Wiktor Stribiżew
Mar 8 at 20:29
Actually, already tried that and the outcome of using it is just a list of words with frequency. I am looking for sth like in English 'singing' - the outcome should be: 'ng' cluster. So now that I am thinking maybe it should be a code more like this:(?:(?![aeiou])[a-z])2,but with modification to final cluster, still doesn't work
– White
Mar 8 at 20:43
Try(?:(?![aeiou])[a-z])2,$, see demo.
– Wiktor Stribiżew
Mar 8 at 20:44
Thank you very much for your help!
– White
Mar 8 at 20:47
1
1
Try
re.search(r'[^aeiouy]2,b', w) or re.search(r'[^aeiouy]+$', w)– Wiktor Stribiżew
Mar 8 at 20:29
Try
re.search(r'[^aeiouy]2,b', w) or re.search(r'[^aeiouy]+$', w)– Wiktor Stribiżew
Mar 8 at 20:29
Actually, already tried that and the outcome of using it is just a list of words with frequency. I am looking for sth like in English 'singing' - the outcome should be: 'ng' cluster. So now that I am thinking maybe it should be a code more like this:
(?:(?![aeiou])[a-z])2, but with modification to final cluster, still doesn't work– White
Mar 8 at 20:43
Actually, already tried that and the outcome of using it is just a list of words with frequency. I am looking for sth like in English 'singing' - the outcome should be: 'ng' cluster. So now that I am thinking maybe it should be a code more like this:
(?:(?![aeiou])[a-z])2, but with modification to final cluster, still doesn't work– White
Mar 8 at 20:43
Try
(?:(?![aeiou])[a-z])2,$, see demo.– Wiktor Stribiżew
Mar 8 at 20:44
Try
(?:(?![aeiou])[a-z])2,$, see demo.– Wiktor Stribiżew
Mar 8 at 20:44
Thank you very much for your help!
– White
Mar 8 at 20:47
Thank you very much for your help!
– White
Mar 8 at 20:47
add a comment |
1 Answer
1
active
oldest
votes
You seem to want to extract chunks of 2 or more consonant letters at the end of the string.
You may use
(?:(?![aeiou])[a-z])2,$
See the regex demo.
Details
(?:- start of a non-capturing group:(?![aeiou])- a negative lookahead that fails the match if the next char is a vowel[a-z]- an ASCII letter (case insensitive mode can be set withre.Iflag)
)2,- end of the group, 2 or more occurrences$- end of string.
answered Mar 8 at 20:56
Wiktor StribiżewWiktor Stribiżew
331k16149232
add a comment |
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1 Answer
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active
oldest
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oldest
votes
active
oldest
votes
You seem to want to extract chunks of 2 or more consonant letters at the end of the string.
You may use
(?:(?![aeiou])[a-z])2,$
See the regex demo.
Details
(?:- start of a non-capturing group:(?![aeiou])- a negative lookahead that fails the match if the next char is a vowel[a-z]- an ASCII letter (case insensitive mode can be set withre.Iflag)
)2,- end of the group, 2 or more occurrences$- end of string.
answered Mar 8 at 20:56
Wiktor StribiżewWiktor Stribiżew
331k16149232
add a comment |
You seem to want to extract chunks of 2 or more consonant letters at the end of the string.
You may use
(?:(?![aeiou])[a-z])2,$
See the regex demo.
Details
(?:- start of a non-capturing group:(?![aeiou])- a negative lookahead that fails the match if the next char is a vowel[a-z]- an ASCII letter (case insensitive mode can be set withre.Iflag)
)2,- end of the group, 2 or more occurrences$- end of string.
answered Mar 8 at 20:56
Wiktor StribiżewWiktor Stribiżew
331k16149232
add a comment |
You seem to want to extract chunks of 2 or more consonant letters at the end of the string.
You may use
(?:(?![aeiou])[a-z])2,$
See the regex demo.
Details
(?:- start of a non-capturing group:(?![aeiou])- a negative lookahead that fails the match if the next char is a vowel[a-z]- an ASCII letter (case insensitive mode can be set withre.Iflag)
)2,- end of the group, 2 or more occurrences$- end of string.
answered Mar 8 at 20:56
Wiktor StribiżewWiktor Stribiżew
331k16149232
You seem to want to extract chunks of 2 or more consonant letters at the end of the string.
You may use
(?:(?![aeiou])[a-z])2,$
See the regex demo.
Details
(?:- start of a non-capturing group:(?![aeiou])- a negative lookahead that fails the match if the next char is a vowel[a-z]- an ASCII letter (case insensitive mode can be set withre.Iflag)
)2,- end of the group, 2 or more occurrences$- end of string.
answered Mar 8 at 20:56
Wiktor StribiżewWiktor Stribiżew
331k16149232
answered Mar 8 at 20:56
Wiktor StribiżewWiktor Stribiżew
331k16149232
answered Mar 8 at 20:56
Wiktor StribiżewWiktor Stribiżew
331k16149232
answered Mar 8 at 20:56
Wiktor StribiżewWiktor Stribiżew
331k16149232
331k16149232
add a comment |
add a comment |
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re.search(r'[^aeiouy]2,b', w)orre.search(r'[^aeiouy]+$', w)– Wiktor Stribiżew
Mar 8 at 20:29
Actually, already tried that and the outcome of using it is just a list of words with frequency. I am looking for sth like in English 'singing' - the outcome should be: 'ng' cluster. So now that I am thinking maybe it should be a code more like this:
(?:(?![aeiou])[a-z])2,but with modification to final cluster, still doesn't work– White
Mar 8 at 20:43
Try
(?:(?![aeiou])[a-z])2,$, see demo.– Wiktor Stribiżew
Mar 8 at 20:44
Thank you very much for your help!
– White
Mar 8 at 20:47