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Add elements to an array from specified position in typescript
The 2019 Stack Overflow Developer Survey Results Are InHow do I remove an array item in TypeScript?Extending Array in Typescript breaks constructorAdd element to Observable array typescriptGetting started - How to use Google maps api with angular-cliJavascript Array elements disappearingAngular 2 - ngFor while index < xrxjs: Index and condition inside a map functionTypescript recursively mapping object property types: object and array element typesUse findIndex, but start looking in a specific positionMove an item in array to first position from last position in typescript
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I am adding elements to array arr1
using map function. Is there any way to specify the index of starting position in typescript
e.g If I want to add elements from 3rd index position of the array. first two index should hold 0. how can I do that?
let years = [0,1,2,3,4];
data =
var1: 100000,
arr2: years.map(_ => 1000)
;
console.log(data.arr2);
I want to add 0 from starting of the array. If I specify position as 3 then first 2 element should be zero
angular typescript
add a comment |
I am adding elements to array arr1
using map function. Is there any way to specify the index of starting position in typescript
e.g If I want to add elements from 3rd index position of the array. first two index should hold 0. how can I do that?
let years = [0,1,2,3,4];
data =
var1: 100000,
arr2: years.map(_ => 1000)
;
console.log(data.arr2);
I want to add 0 from starting of the array. If I specify position as 3 then first 2 element should be zero
angular typescript
Are you aware your code snippet doesn't work ? I don' understand what you want to do.
– Florian
Mar 8 at 9:39
@Florian Sorry. Updated
– Naresh Shetty
Mar 8 at 9:48
add a comment |
I am adding elements to array arr1
using map function. Is there any way to specify the index of starting position in typescript
e.g If I want to add elements from 3rd index position of the array. first two index should hold 0. how can I do that?
let years = [0,1,2,3,4];
data =
var1: 100000,
arr2: years.map(_ => 1000)
;
console.log(data.arr2);
I want to add 0 from starting of the array. If I specify position as 3 then first 2 element should be zero
angular typescript
I am adding elements to array arr1
using map function. Is there any way to specify the index of starting position in typescript
e.g If I want to add elements from 3rd index position of the array. first two index should hold 0. how can I do that?
let years = [0,1,2,3,4];
data =
var1: 100000,
arr2: years.map(_ => 1000)
;
console.log(data.arr2);
I want to add 0 from starting of the array. If I specify position as 3 then first 2 element should be zero
let years = [0,1,2,3,4];
data =
var1: 100000,
arr2: years.map(_ => 1000)
;
console.log(data.arr2);
let years = [0,1,2,3,4];
data =
var1: 100000,
arr2: years.map(_ => 1000)
;
console.log(data.arr2);
angular typescript
angular typescript
edited Mar 8 at 9:44
Naresh Shetty
asked Mar 8 at 9:34
Naresh ShettyNaresh Shetty
6311
6311
Are you aware your code snippet doesn't work ? I don' understand what you want to do.
– Florian
Mar 8 at 9:39
@Florian Sorry. Updated
– Naresh Shetty
Mar 8 at 9:48
add a comment |
Are you aware your code snippet doesn't work ? I don' understand what you want to do.
– Florian
Mar 8 at 9:39
@Florian Sorry. Updated
– Naresh Shetty
Mar 8 at 9:48
Are you aware your code snippet doesn't work ? I don' understand what you want to do.
– Florian
Mar 8 at 9:39
Are you aware your code snippet doesn't work ? I don' understand what you want to do.
– Florian
Mar 8 at 9:39
@Florian Sorry. Updated
– Naresh Shetty
Mar 8 at 9:48
@Florian Sorry. Updated
– Naresh Shetty
Mar 8 at 9:48
add a comment |
2 Answers
2
active
oldest
votes
You can use array#map
and for all index value lower than your desired index place 0 other get the value from your array.
let years = [0,1,2,3,4],
index = 2,
result = years.map((v,i) => i < index ? 0 : v);
console.log(result);
add a comment |
I'm not sure if I understood what you want :
let years = [0,1,2,3,4];
data =
var1: 100000,
arr2: modifyArray(3, 100000)
;
console.log(data.arr2);
function modifyArray(position = 0, value)
const newArray = [];
for (let i = 0; i < position - 1; i++)
newArray.push(0);
return [...newArray, ...years.slice(0, position ), value, ...years.slice(position)];
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use array#map
and for all index value lower than your desired index place 0 other get the value from your array.
let years = [0,1,2,3,4],
index = 2,
result = years.map((v,i) => i < index ? 0 : v);
console.log(result);
add a comment |
You can use array#map
and for all index value lower than your desired index place 0 other get the value from your array.
let years = [0,1,2,3,4],
index = 2,
result = years.map((v,i) => i < index ? 0 : v);
console.log(result);
add a comment |
You can use array#map
and for all index value lower than your desired index place 0 other get the value from your array.
let years = [0,1,2,3,4],
index = 2,
result = years.map((v,i) => i < index ? 0 : v);
console.log(result);
You can use array#map
and for all index value lower than your desired index place 0 other get the value from your array.
let years = [0,1,2,3,4],
index = 2,
result = years.map((v,i) => i < index ? 0 : v);
console.log(result);
let years = [0,1,2,3,4],
index = 2,
result = years.map((v,i) => i < index ? 0 : v);
console.log(result);
let years = [0,1,2,3,4],
index = 2,
result = years.map((v,i) => i < index ? 0 : v);
console.log(result);
answered Mar 8 at 9:39
Hassan ImamHassan Imam
12k31632
12k31632
add a comment |
add a comment |
I'm not sure if I understood what you want :
let years = [0,1,2,3,4];
data =
var1: 100000,
arr2: modifyArray(3, 100000)
;
console.log(data.arr2);
function modifyArray(position = 0, value)
const newArray = [];
for (let i = 0; i < position - 1; i++)
newArray.push(0);
return [...newArray, ...years.slice(0, position ), value, ...years.slice(position)];
add a comment |
I'm not sure if I understood what you want :
let years = [0,1,2,3,4];
data =
var1: 100000,
arr2: modifyArray(3, 100000)
;
console.log(data.arr2);
function modifyArray(position = 0, value)
const newArray = [];
for (let i = 0; i < position - 1; i++)
newArray.push(0);
return [...newArray, ...years.slice(0, position ), value, ...years.slice(position)];
add a comment |
I'm not sure if I understood what you want :
let years = [0,1,2,3,4];
data =
var1: 100000,
arr2: modifyArray(3, 100000)
;
console.log(data.arr2);
function modifyArray(position = 0, value)
const newArray = [];
for (let i = 0; i < position - 1; i++)
newArray.push(0);
return [...newArray, ...years.slice(0, position ), value, ...years.slice(position)];
I'm not sure if I understood what you want :
let years = [0,1,2,3,4];
data =
var1: 100000,
arr2: modifyArray(3, 100000)
;
console.log(data.arr2);
function modifyArray(position = 0, value)
const newArray = [];
for (let i = 0; i < position - 1; i++)
newArray.push(0);
return [...newArray, ...years.slice(0, position ), value, ...years.slice(position)];
let years = [0,1,2,3,4];
data =
var1: 100000,
arr2: modifyArray(3, 100000)
;
console.log(data.arr2);
function modifyArray(position = 0, value)
const newArray = [];
for (let i = 0; i < position - 1; i++)
newArray.push(0);
return [...newArray, ...years.slice(0, position ), value, ...years.slice(position)];
let years = [0,1,2,3,4];
data =
var1: 100000,
arr2: modifyArray(3, 100000)
;
console.log(data.arr2);
function modifyArray(position = 0, value)
const newArray = [];
for (let i = 0; i < position - 1; i++)
newArray.push(0);
return [...newArray, ...years.slice(0, position ), value, ...years.slice(position)];
answered Mar 8 at 10:19
FlorianFlorian
720412
720412
add a comment |
add a comment |
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Are you aware your code snippet doesn't work ? I don' understand what you want to do.
– Florian
Mar 8 at 9:39
@Florian Sorry. Updated
– Naresh Shetty
Mar 8 at 9:48