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Split multiple values in a cell to multiple rows - Oracle SQL
The 2019 Stack Overflow Developer Survey Results Are InSplit function in oracle to comma separated values with automatic sequenceAdd a column with a default value to an existing table in SQL ServerHow to concatenate text from multiple rows into a single text string in SQL server?Inserting multiple rows in a single SQL query?How do I limit the number of rows returned by an Oracle query after ordering?Finding duplicate values in a SQL tableWhat are the options for storing hierarchical data in a relational database?SQL Query to concatenate column values from multiple rows in OracleGet top 1 row of each groupSQL select only rows with max value on a columnSQL query return data from multiple tables
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I have a table:
table1
values
------------
x=new letter
------------
a=old letter
ba=older letter
xq=newer letter
------------
xf=new apple
xt=new orange
x3=new fruit
xtt=new seed
I have to separate the values in each cell to multiple rows.
The following is the output:
table2
code description
x new letter
a old letter
ba older letter
xq newer letter
xf new apple
xt new orange
x3 new fruit
xtt new seed
How can this be achieved?
sql oracle split
add a comment |
I have a table:
table1
values
------------
x=new letter
------------
a=old letter
ba=older letter
xq=newer letter
------------
xf=new apple
xt=new orange
x3=new fruit
xtt=new seed
I have to separate the values in each cell to multiple rows.
The following is the output:
table2
code description
x new letter
a old letter
ba older letter
xq newer letter
xf new apple
xt new orange
x3 new fruit
xtt new seed
How can this be achieved?
sql oracle split
look at this link : stackoverflow.com/questions/28677070/…
– saravanatn
Mar 8 at 9:56
Hint: useregexp_substr
– JohnHC
Mar 8 at 9:59
add a comment |
I have a table:
table1
values
------------
x=new letter
------------
a=old letter
ba=older letter
xq=newer letter
------------
xf=new apple
xt=new orange
x3=new fruit
xtt=new seed
I have to separate the values in each cell to multiple rows.
The following is the output:
table2
code description
x new letter
a old letter
ba older letter
xq newer letter
xf new apple
xt new orange
x3 new fruit
xtt new seed
How can this be achieved?
sql oracle split
I have a table:
table1
values
------------
x=new letter
------------
a=old letter
ba=older letter
xq=newer letter
------------
xf=new apple
xt=new orange
x3=new fruit
xtt=new seed
I have to separate the values in each cell to multiple rows.
The following is the output:
table2
code description
x new letter
a old letter
ba older letter
xq newer letter
xf new apple
xt new orange
x3 new fruit
xtt new seed
How can this be achieved?
sql oracle split
sql oracle split
edited Mar 8 at 10:21
a_horse_with_no_name
308k46470571
308k46470571
asked Mar 8 at 9:53
dangdang
59812044
59812044
look at this link : stackoverflow.com/questions/28677070/…
– saravanatn
Mar 8 at 9:56
Hint: useregexp_substr
– JohnHC
Mar 8 at 9:59
add a comment |
look at this link : stackoverflow.com/questions/28677070/…
– saravanatn
Mar 8 at 9:56
Hint: useregexp_substr
– JohnHC
Mar 8 at 9:59
look at this link : stackoverflow.com/questions/28677070/…
– saravanatn
Mar 8 at 9:56
look at this link : stackoverflow.com/questions/28677070/…
– saravanatn
Mar 8 at 9:56
Hint: use
regexp_substr
– JohnHC
Mar 8 at 9:59
Hint: use
regexp_substr
– JohnHC
Mar 8 at 9:59
add a comment |
2 Answers
2
active
oldest
votes
I would use regexp_replace()
or regexp_substr()
:
select regexp_substr(str, '^[^=]+') as code,
regexp_substr(str, '[^=]+$') as value
Here is a db<>fiddle.
Note that this does not use values
for the column name. That is a very bad choice for a column name because it is a SQL keyword.
Would it also separate multiple values in a single cell to multiple rows?
– dang
Mar 9 at 14:15
The second row has multi line value present. a=old letter ba=older letter xq=newer letter are in 1 cell with new line
– dang
Mar 9 at 14:16
add a comment |
try like below
SELECT NVL(SUBSTR('a=old letter', 0, INSTR('a=old letter', '=')-1), 'a=old letter')
AS col1, NVL(SUBSTR('a=old letter', INSTR('a=old letter', '=')+1), 'a=old letter')
FROM DUAL
so in you case
SELECT NVL(SUBSTR(values, 0, INSTR(values, '=')-1), values)
AS col1, NVL(SUBSTR(values, INSTR(values, '=')+1), values)
FROM table1
the second cell contains multi line values - a=old letter ba=older letter xq=newer letter, the sql above does not break multi line value to separate rows.
– dang
Mar 9 at 14:27
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
I would use regexp_replace()
or regexp_substr()
:
select regexp_substr(str, '^[^=]+') as code,
regexp_substr(str, '[^=]+$') as value
Here is a db<>fiddle.
Note that this does not use values
for the column name. That is a very bad choice for a column name because it is a SQL keyword.
Would it also separate multiple values in a single cell to multiple rows?
– dang
Mar 9 at 14:15
The second row has multi line value present. a=old letter ba=older letter xq=newer letter are in 1 cell with new line
– dang
Mar 9 at 14:16
add a comment |
I would use regexp_replace()
or regexp_substr()
:
select regexp_substr(str, '^[^=]+') as code,
regexp_substr(str, '[^=]+$') as value
Here is a db<>fiddle.
Note that this does not use values
for the column name. That is a very bad choice for a column name because it is a SQL keyword.
Would it also separate multiple values in a single cell to multiple rows?
– dang
Mar 9 at 14:15
The second row has multi line value present. a=old letter ba=older letter xq=newer letter are in 1 cell with new line
– dang
Mar 9 at 14:16
add a comment |
I would use regexp_replace()
or regexp_substr()
:
select regexp_substr(str, '^[^=]+') as code,
regexp_substr(str, '[^=]+$') as value
Here is a db<>fiddle.
Note that this does not use values
for the column name. That is a very bad choice for a column name because it is a SQL keyword.
I would use regexp_replace()
or regexp_substr()
:
select regexp_substr(str, '^[^=]+') as code,
regexp_substr(str, '[^=]+$') as value
Here is a db<>fiddle.
Note that this does not use values
for the column name. That is a very bad choice for a column name because it is a SQL keyword.
answered Mar 8 at 12:22
Gordon LinoffGordon Linoff
796k37318423
796k37318423
Would it also separate multiple values in a single cell to multiple rows?
– dang
Mar 9 at 14:15
The second row has multi line value present. a=old letter ba=older letter xq=newer letter are in 1 cell with new line
– dang
Mar 9 at 14:16
add a comment |
Would it also separate multiple values in a single cell to multiple rows?
– dang
Mar 9 at 14:15
The second row has multi line value present. a=old letter ba=older letter xq=newer letter are in 1 cell with new line
– dang
Mar 9 at 14:16
Would it also separate multiple values in a single cell to multiple rows?
– dang
Mar 9 at 14:15
Would it also separate multiple values in a single cell to multiple rows?
– dang
Mar 9 at 14:15
The second row has multi line value present. a=old letter ba=older letter xq=newer letter are in 1 cell with new line
– dang
Mar 9 at 14:16
The second row has multi line value present. a=old letter ba=older letter xq=newer letter are in 1 cell with new line
– dang
Mar 9 at 14:16
add a comment |
try like below
SELECT NVL(SUBSTR('a=old letter', 0, INSTR('a=old letter', '=')-1), 'a=old letter')
AS col1, NVL(SUBSTR('a=old letter', INSTR('a=old letter', '=')+1), 'a=old letter')
FROM DUAL
so in you case
SELECT NVL(SUBSTR(values, 0, INSTR(values, '=')-1), values)
AS col1, NVL(SUBSTR(values, INSTR(values, '=')+1), values)
FROM table1
the second cell contains multi line values - a=old letter ba=older letter xq=newer letter, the sql above does not break multi line value to separate rows.
– dang
Mar 9 at 14:27
add a comment |
try like below
SELECT NVL(SUBSTR('a=old letter', 0, INSTR('a=old letter', '=')-1), 'a=old letter')
AS col1, NVL(SUBSTR('a=old letter', INSTR('a=old letter', '=')+1), 'a=old letter')
FROM DUAL
so in you case
SELECT NVL(SUBSTR(values, 0, INSTR(values, '=')-1), values)
AS col1, NVL(SUBSTR(values, INSTR(values, '=')+1), values)
FROM table1
the second cell contains multi line values - a=old letter ba=older letter xq=newer letter, the sql above does not break multi line value to separate rows.
– dang
Mar 9 at 14:27
add a comment |
try like below
SELECT NVL(SUBSTR('a=old letter', 0, INSTR('a=old letter', '=')-1), 'a=old letter')
AS col1, NVL(SUBSTR('a=old letter', INSTR('a=old letter', '=')+1), 'a=old letter')
FROM DUAL
so in you case
SELECT NVL(SUBSTR(values, 0, INSTR(values, '=')-1), values)
AS col1, NVL(SUBSTR(values, INSTR(values, '=')+1), values)
FROM table1
try like below
SELECT NVL(SUBSTR('a=old letter', 0, INSTR('a=old letter', '=')-1), 'a=old letter')
AS col1, NVL(SUBSTR('a=old letter', INSTR('a=old letter', '=')+1), 'a=old letter')
FROM DUAL
so in you case
SELECT NVL(SUBSTR(values, 0, INSTR(values, '=')-1), values)
AS col1, NVL(SUBSTR(values, INSTR(values, '=')+1), values)
FROM table1
answered Mar 8 at 10:01
Zaynul Abadin TuhinZaynul Abadin Tuhin
19k31135
19k31135
the second cell contains multi line values - a=old letter ba=older letter xq=newer letter, the sql above does not break multi line value to separate rows.
– dang
Mar 9 at 14:27
add a comment |
the second cell contains multi line values - a=old letter ba=older letter xq=newer letter, the sql above does not break multi line value to separate rows.
– dang
Mar 9 at 14:27
the second cell contains multi line values - a=old letter ba=older letter xq=newer letter, the sql above does not break multi line value to separate rows.
– dang
Mar 9 at 14:27
the second cell contains multi line values - a=old letter ba=older letter xq=newer letter, the sql above does not break multi line value to separate rows.
– dang
Mar 9 at 14:27
add a comment |
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look at this link : stackoverflow.com/questions/28677070/…
– saravanatn
Mar 8 at 9:56
Hint: use
regexp_substr
– JohnHC
Mar 8 at 9:59