How to Ignore Certain terms in search using Fusejs? The 2019 Stack Overflow Developer Survey Results Are InHow do JavaScript closures work?How do I check if an element is hidden in jQuery?How do I remove a property from a JavaScript object?How do I redirect to another webpage?How do I include a JavaScript file in another JavaScript file?How to replace all occurrences of a string in JavaScriptWhy is the Android emulator so slow? How can we speed up the Android emulator?How to check whether a string contains a substring in JavaScript?How do I remove a particular element from an array in JavaScript?How do I return the response from an asynchronous call?
What is this sharp, curved notch on my knife for?
How do I free up internal storage if I don't have any apps downloaded?
Will it cause any balance problems to have PCs level up and gain the benefits of a long rest mid-fight?
What could be the right powersource for 15 seconds lifespan disposable giant chainsaw?
Why not take a picture of a closer black hole?
Short story: child made less intelligent and less attractive
Why doesn't UInt have a toDouble()?
What can I do if neighbor is blocking my solar panels intentionally
Ubuntu Server install with full GUI
Why can't devices on different VLANs, but on the same subnet, communicate?
How can I define good in a religion that claims no moral authority?
How do PCB vias affect signal quality?
What to do when moving next to a bird sanctuary with a loosely-domesticated cat?
How did passengers keep warm on sail ships?
Is it ok to offer lower paid work as a trial period before negotiating for a full-time job?
A word that means fill it to the required quantity
Why does the nucleus not repel itself?
Can withdrawing asylum be illegal?
Falsification in Math vs Science
What is the meaning of Triage in Cybersec world?
Are there any other methods to apply to solving simultaneous equations?
A female thief is not sold to make restitution -- so what happens instead?
Can there be female White Walkers?
Why can I use a list index as an indexing variable in a for loop?
How to Ignore Certain terms in search using Fusejs?
The 2019 Stack Overflow Developer Survey Results Are InHow do JavaScript closures work?How do I check if an element is hidden in jQuery?How do I remove a property from a JavaScript object?How do I redirect to another webpage?How do I include a JavaScript file in another JavaScript file?How to replace all occurrences of a string in JavaScriptWhy is the Android emulator so slow? How can we speed up the Android emulator?How to check whether a string contains a substring in JavaScript?How do I remove a particular element from an array in JavaScript?How do I return the response from an asynchronous call?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I want to create a search using fusejs, in which an entity or keyword can have multiple names, (alias). In fusejs the score is calculated based on the user input, he/she can enter any of the names.
In my data i can have only 1 name.
For Example: "House"
[
"label": "House No. 436, Street 12, Phase 3"
]
If a user enter "house" it works perfectly, but what if user enter Plot no, or home no, apartment no , flat no or any such word. In that case the score calculated will effect the search results.
Please let me know if there is any way out for this.
javascript performance fuse.js
asked Mar 8 at 11:11
saadat alisaadat ali
239
add a comment |
I want to create a search using fusejs, in which an entity or keyword can have multiple names, (alias). In fusejs the score is calculated based on the user input, he/she can enter any of the names.
In my data i can have only 1 name.
For Example: "House"
[
"label": "House No. 436, Street 12, Phase 3"
]
If a user enter "house" it works perfectly, but what if user enter Plot no, or home no, apartment no , flat no or any such word. In that case the score calculated will effect the search results.
Please let me know if there is any way out for this.
javascript performance fuse.js
asked Mar 8 at 11:11
saadat alisaadat ali
239
add a comment |
I want to create a search using fusejs, in which an entity or keyword can have multiple names, (alias). In fusejs the score is calculated based on the user input, he/she can enter any of the names.
In my data i can have only 1 name.
For Example: "House"
[
"label": "House No. 436, Street 12, Phase 3"
]
If a user enter "house" it works perfectly, but what if user enter Plot no, or home no, apartment no , flat no or any such word. In that case the score calculated will effect the search results.
Please let me know if there is any way out for this.
javascript performance fuse.js
asked Mar 8 at 11:11
saadat alisaadat ali
239
I want to create a search using fusejs, in which an entity or keyword can have multiple names, (alias). In fusejs the score is calculated based on the user input, he/she can enter any of the names.
In my data i can have only 1 name.
For Example: "House"
[
"label": "House No. 436, Street 12, Phase 3"
]
If a user enter "house" it works perfectly, but what if user enter Plot no, or home no, apartment no , flat no or any such word. In that case the score calculated will effect the search results.
Please let me know if there is any way out for this.
javascript performance fuse.js
javascript performance fuse.js
asked Mar 8 at 11:11
saadat alisaadat ali
239
asked Mar 8 at 11:11
saadat alisaadat ali
239
asked Mar 8 at 11:11
saadat alisaadat ali
239
asked Mar 8 at 11:11
saadat alisaadat ali
239
asked Mar 8 at 11:11
saadat alisaadat ali
239
239
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I solved this problem by adding a new array containing all the alias to each object.
["label": "House No. 436, Street 12, Phase 3", tags: ["Plot No", "Flat no", "Apartment no"]]
and so on. And then i applied the weighted search with 0.7 weight to the variable label and 0.3 to array of alias.
keys: [
name: 'tags',
weight: 0.3
,
name: 'label',
weight: 0.7
]
};
Now if user inputs any of the keyword, it will have same impact, Thus the actual search results are not effected.
answered Mar 11 at 5:13
saadat alisaadat ali
239
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55061997%2fhow-to-ignore-certain-terms-in-search-using-fusejs%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I solved this problem by adding a new array containing all the alias to each object.
["label": "House No. 436, Street 12, Phase 3", tags: ["Plot No", "Flat no", "Apartment no"]]
and so on. And then i applied the weighted search with 0.7 weight to the variable label and 0.3 to array of alias.
keys: [
name: 'tags',
weight: 0.3
,
name: 'label',
weight: 0.7
]
};
Now if user inputs any of the keyword, it will have same impact, Thus the actual search results are not effected.
answered Mar 11 at 5:13
saadat alisaadat ali
239
add a comment |
I solved this problem by adding a new array containing all the alias to each object.
["label": "House No. 436, Street 12, Phase 3", tags: ["Plot No", "Flat no", "Apartment no"]]
and so on. And then i applied the weighted search with 0.7 weight to the variable label and 0.3 to array of alias.
keys: [
name: 'tags',
weight: 0.3
,
name: 'label',
weight: 0.7
]
};
Now if user inputs any of the keyword, it will have same impact, Thus the actual search results are not effected.
answered Mar 11 at 5:13
saadat alisaadat ali
239
add a comment |
I solved this problem by adding a new array containing all the alias to each object.
["label": "House No. 436, Street 12, Phase 3", tags: ["Plot No", "Flat no", "Apartment no"]]
and so on. And then i applied the weighted search with 0.7 weight to the variable label and 0.3 to array of alias.
keys: [
name: 'tags',
weight: 0.3
,
name: 'label',
weight: 0.7
]
};
Now if user inputs any of the keyword, it will have same impact, Thus the actual search results are not effected.
answered Mar 11 at 5:13
saadat alisaadat ali
239
I solved this problem by adding a new array containing all the alias to each object.
["label": "House No. 436, Street 12, Phase 3", tags: ["Plot No", "Flat no", "Apartment no"]]
and so on. And then i applied the weighted search with 0.7 weight to the variable label and 0.3 to array of alias.
keys: [
name: 'tags',
weight: 0.3
,
name: 'label',
weight: 0.7
]
};
Now if user inputs any of the keyword, it will have same impact, Thus the actual search results are not effected.
answered Mar 11 at 5:13
saadat alisaadat ali
239
answered Mar 11 at 5:13
saadat alisaadat ali
239
answered Mar 11 at 5:13
saadat alisaadat ali
239
answered Mar 11 at 5:13
saadat alisaadat ali
239
239
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55061997%2fhow-to-ignore-certain-terms-in-search-using-fusejs%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
