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match each occurrence of a dot until a single colon
Match all occurrences of a regexWhat regex will match every character except comma ',' or semi-colon ';'?Regex: matching up to the first occurrence of a characterHow to match “anything up until this sequence of characters” in a regular expression?Finding @mentions in stringPHP - preg_replace not matching multiple occurrencesJavascript: Some kind of preg_match with a callback on each match?regular expression replace all except captured expressionHow to match until first occurrence of a pattern?Match between two single quotes and continue matching if two single quotes appear in a row or if '.' appears in the middle?
Take this string
bob.ted.dave.allan::james.fred: hello.dave
I need to replace each occurrence of . with # until I hit a singular ":" not stopping at the namespace '::' but just the ":"
So in the above string, the end result will be
bob#ted#dave#allan::james#fred: hello.dave
currently I have [.] which matches all dots in the string but cant get it to anchor on the single ":"
regex
add a comment |
Take this string
bob.ted.dave.allan::james.fred: hello.dave
I need to replace each occurrence of . with # until I hit a singular ":" not stopping at the namespace '::' but just the ":"
So in the above string, the end result will be
bob#ted#dave#allan::james#fred: hello.dave
currently I have [.] which matches all dots in the string but cant get it to anchor on the single ":"
regex
add a comment |
Take this string
bob.ted.dave.allan::james.fred: hello.dave
I need to replace each occurrence of . with # until I hit a singular ":" not stopping at the namespace '::' but just the ":"
So in the above string, the end result will be
bob#ted#dave#allan::james#fred: hello.dave
currently I have [.] which matches all dots in the string but cant get it to anchor on the single ":"
regex
Take this string
bob.ted.dave.allan::james.fred: hello.dave
I need to replace each occurrence of . with # until I hit a singular ":" not stopping at the namespace '::' but just the ":"
So in the above string, the end result will be
bob#ted#dave#allan::james#fred: hello.dave
currently I have [.] which matches all dots in the string but cant get it to anchor on the single ":"
regex
regex
asked Mar 7 at 21:19
fmanfman
41
41
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
If you want a pure regex solution this can only be done with a variable-width lookbehind pattern, which is supported by only a few regex engines:
(?<!(?<!:):(?!:).*).
Demo: https://regex101.com/r/Crq49C/2
Or if there is always going to be a colon, you can use a positive lookahead pattern instead:
.(?=.*(?<!:):(?!:))
Demo: https://regex101.com/r/Crq49C/3
add a comment |
To just anchor on a single .
and not stop until seeing exactly one :
I think[.](?=.*:1)
will work.
This does not work if there is more than one :
on a line.
add a comment |
You can capture the entire string up until the single :
with a simple character set match:
[w. :]+(?::1)
Then do a replace on all of the .
's in the captured string.
Demo: https://regex101.com/r/xDfstu/1
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you want a pure regex solution this can only be done with a variable-width lookbehind pattern, which is supported by only a few regex engines:
(?<!(?<!:):(?!:).*).
Demo: https://regex101.com/r/Crq49C/2
Or if there is always going to be a colon, you can use a positive lookahead pattern instead:
.(?=.*(?<!:):(?!:))
Demo: https://regex101.com/r/Crq49C/3
add a comment |
If you want a pure regex solution this can only be done with a variable-width lookbehind pattern, which is supported by only a few regex engines:
(?<!(?<!:):(?!:).*).
Demo: https://regex101.com/r/Crq49C/2
Or if there is always going to be a colon, you can use a positive lookahead pattern instead:
.(?=.*(?<!:):(?!:))
Demo: https://regex101.com/r/Crq49C/3
add a comment |
If you want a pure regex solution this can only be done with a variable-width lookbehind pattern, which is supported by only a few regex engines:
(?<!(?<!:):(?!:).*).
Demo: https://regex101.com/r/Crq49C/2
Or if there is always going to be a colon, you can use a positive lookahead pattern instead:
.(?=.*(?<!:):(?!:))
Demo: https://regex101.com/r/Crq49C/3
If you want a pure regex solution this can only be done with a variable-width lookbehind pattern, which is supported by only a few regex engines:
(?<!(?<!:):(?!:).*).
Demo: https://regex101.com/r/Crq49C/2
Or if there is always going to be a colon, you can use a positive lookahead pattern instead:
.(?=.*(?<!:):(?!:))
Demo: https://regex101.com/r/Crq49C/3
edited Mar 7 at 21:34
answered Mar 7 at 21:29
blhsingblhsing
41.6k41743
41.6k41743
add a comment |
add a comment |
To just anchor on a single .
and not stop until seeing exactly one :
I think[.](?=.*:1)
will work.
This does not work if there is more than one :
on a line.
add a comment |
To just anchor on a single .
and not stop until seeing exactly one :
I think[.](?=.*:1)
will work.
This does not work if there is more than one :
on a line.
add a comment |
To just anchor on a single .
and not stop until seeing exactly one :
I think[.](?=.*:1)
will work.
This does not work if there is more than one :
on a line.
To just anchor on a single .
and not stop until seeing exactly one :
I think[.](?=.*:1)
will work.
This does not work if there is more than one :
on a line.
answered Mar 7 at 21:33
Mischa MichaelMischa Michael
263
263
add a comment |
add a comment |
You can capture the entire string up until the single :
with a simple character set match:
[w. :]+(?::1)
Then do a replace on all of the .
's in the captured string.
Demo: https://regex101.com/r/xDfstu/1
add a comment |
You can capture the entire string up until the single :
with a simple character set match:
[w. :]+(?::1)
Then do a replace on all of the .
's in the captured string.
Demo: https://regex101.com/r/xDfstu/1
add a comment |
You can capture the entire string up until the single :
with a simple character set match:
[w. :]+(?::1)
Then do a replace on all of the .
's in the captured string.
Demo: https://regex101.com/r/xDfstu/1
You can capture the entire string up until the single :
with a simple character set match:
[w. :]+(?::1)
Then do a replace on all of the .
's in the captured string.
Demo: https://regex101.com/r/xDfstu/1
edited Mar 7 at 21:36
answered Mar 7 at 21:26
ChrisChris
1,794419
1,794419
add a comment |
add a comment |
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