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Unmarshal a string to a map struct using a base template (reverse process of template parse)
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30UTC (7:30pm US/Eastern)
Data science time! April 2019 and salary with experience
The Ask Question Wizard is Live!Map of structs vs array of structs in GoCalling a template with several pipeline parametersIterating through map in templateUnmarshalling JSON to interface variable while matching the underlying type in GoGo template to structis there a way to list used variables?Golang - map data from one complex struct to anotherReflection: Struct by stringUnmarshal map[string]DynamoDBAttributeValue into a structParse and validate “key1:value1; key2:value2” string to Go struct efficiently?
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I'm curious to see if there is a way to marshal a map or struct from a string and a Go Template (the reverse of template.Execute)
For example, let's say we have the following template for a filename pattern
const NameTemplate = ` .Os.Type / .Os.Variant ! .Os.Version ! .Name ! .Version `
And let's say we have the following map (using a structure in my solution, but I'll use a map here for simplicity)
data := map[string]interface
"Name": "some-name",
"Version": "1.0",
"Os": map[string]interface
"Type": "linux",
"Variant": "debian",
"Version": "9.0",
,
Doing a tmpl.Execute(NameTemplate, data) will result in linux/debian!9.0!some-name!1.0
Now what if we had that string linux/debian!9.0!some-name!1.0 and the template defined above NameTemplate. Is there a simple way to do obtain a map (or struct) like the one defined in data?
go go-templates
add a comment |
I'm curious to see if there is a way to marshal a map or struct from a string and a Go Template (the reverse of template.Execute)
For example, let's say we have the following template for a filename pattern
const NameTemplate = ` .Os.Type / .Os.Variant ! .Os.Version ! .Name ! .Version `
And let's say we have the following map (using a structure in my solution, but I'll use a map here for simplicity)
data := map[string]interface
"Name": "some-name",
"Version": "1.0",
"Os": map[string]interface
"Type": "linux",
"Variant": "debian",
"Version": "9.0",
,
Doing a tmpl.Execute(NameTemplate, data) will result in linux/debian!9.0!some-name!1.0
Now what if we had that string linux/debian!9.0!some-name!1.0 and the template defined above NameTemplate. Is there a simple way to do obtain a map (or struct) like the one defined in data?
go go-templates
2
No, this is not possible. fmt.Scanf may do something similar for simple enough cases, though.
– Flimzy
Mar 8 at 22:40
add a comment |
I'm curious to see if there is a way to marshal a map or struct from a string and a Go Template (the reverse of template.Execute)
For example, let's say we have the following template for a filename pattern
const NameTemplate = ` .Os.Type / .Os.Variant ! .Os.Version ! .Name ! .Version `
And let's say we have the following map (using a structure in my solution, but I'll use a map here for simplicity)
data := map[string]interface
"Name": "some-name",
"Version": "1.0",
"Os": map[string]interface
"Type": "linux",
"Variant": "debian",
"Version": "9.0",
,
Doing a tmpl.Execute(NameTemplate, data) will result in linux/debian!9.0!some-name!1.0
Now what if we had that string linux/debian!9.0!some-name!1.0 and the template defined above NameTemplate. Is there a simple way to do obtain a map (or struct) like the one defined in data?
go go-templates
I'm curious to see if there is a way to marshal a map or struct from a string and a Go Template (the reverse of template.Execute)
For example, let's say we have the following template for a filename pattern
const NameTemplate = ` .Os.Type / .Os.Variant ! .Os.Version ! .Name ! .Version `
And let's say we have the following map (using a structure in my solution, but I'll use a map here for simplicity)
data := map[string]interface
"Name": "some-name",
"Version": "1.0",
"Os": map[string]interface
"Type": "linux",
"Variant": "debian",
"Version": "9.0",
,
Doing a tmpl.Execute(NameTemplate, data) will result in linux/debian!9.0!some-name!1.0
Now what if we had that string linux/debian!9.0!some-name!1.0 and the template defined above NameTemplate. Is there a simple way to do obtain a map (or struct) like the one defined in data?
go go-templates
go go-templates
edited Mar 9 at 23:09
jucardi
asked Mar 8 at 21:49
jucardijucardi
1,43511110
1,43511110
2
No, this is not possible. fmt.Scanf may do something similar for simple enough cases, though.
– Flimzy
Mar 8 at 22:40
add a comment |
2
No, this is not possible. fmt.Scanf may do something similar for simple enough cases, though.
– Flimzy
Mar 8 at 22:40
2
2
No, this is not possible. fmt.Scanf may do something similar for simple enough cases, though.
– Flimzy
Mar 8 at 22:40
No, this is not possible. fmt.Scanf may do something similar for simple enough cases, though.
– Flimzy
Mar 8 at 22:40
add a comment |
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No, this is not possible. fmt.Scanf may do something similar for simple enough cases, though.
– Flimzy
Mar 8 at 22:40