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Include Jquery Parameter in Echo PHP with Row



The Next CEO of Stack OverflowIs there an “exists” function for jQuery?How can I prevent SQL injection in PHP?Add table row in jQueryHow do I check if an element is hidden in jQuery?Setting “checked” for a checkbox with jQuery?How can I know which radio button is selected via jQuery?How to check whether a checkbox is checked in jQuery?Reference — What does this symbol mean in PHP?jQuery scroll to element“Thinking in AngularJS” if I have a jQuery background?










0















hello ive been trying to figure this out for days now.



What i want to do is echo a test and then create a button that copies the echoed text to the clipboard.



So what i want is that i have an SQL list, in that List there is an ID row i can pass to my echo in the paragraph, but when i try to do the same with the parameter the # seems to an issue.



while($row = mysqli_fetch_array($result)) 
echo "<div>";
echo " <p id='" . $row['ID'] . "'>" . $row['Message'] . "</p>";
echo '<button onclick="copyToClipboard('. $row['Title'] . ')">Copy TEXT 2</button>';
echo " </div>";



Also it somehow generates the parameter but there is a blank space between
(" #om2")".



  • my SQL

  • ID = OM2

  • Title = "#OM2"

  • Message = some3ohruihrgfijbfgbrfghrgjikbnhjergbnergbg

any help is greatly appreciated



Edit.



Script



<script type="text/javascript">
function copyToClipboard(element)
var $temp = $("<textarea>");
$("body").append($temp);
var html = $(element).html();
html = html.replace(/<br>/g, "n"); // or rn
console.log(html);
$temp.val(html).select();
document.execCommand("copy");
$temp.remove();



</script>


with echo '<button onclick="copyToClipboard(' . $row['Title'] . ')>Copy TEXT 2</button>';



Image!!!










share|improve this question



















  • 1





    You can use trim() to eliminate whitespaces..

    – Vidal
    Mar 7 at 16:56











  • i tried in on after the echo and before the row started, tried on the row it self. Same issue

    – Carlos Reyes
    Mar 7 at 16:59











  • trim($row['Title']) ? can we see your copyToClipboard javascript function ?

    – Vidal
    Mar 7 at 16:59











  • added it on edit.

    – Carlos Reyes
    Mar 7 at 17:03






  • 1





    Maybe it's quote problem, I think you would like to have the param as a string?: echo '<button onclick="copyToClipboard("' . $row['Title'] . '")">Copy TEXT 2</button>';

    – arvie
    Mar 7 at 17:06
















0















hello ive been trying to figure this out for days now.



What i want to do is echo a test and then create a button that copies the echoed text to the clipboard.



So what i want is that i have an SQL list, in that List there is an ID row i can pass to my echo in the paragraph, but when i try to do the same with the parameter the # seems to an issue.



while($row = mysqli_fetch_array($result)) 
echo "<div>";
echo " <p id='" . $row['ID'] . "'>" . $row['Message'] . "</p>";
echo '<button onclick="copyToClipboard('. $row['Title'] . ')">Copy TEXT 2</button>';
echo " </div>";



Also it somehow generates the parameter but there is a blank space between
(" #om2")".



  • my SQL

  • ID = OM2

  • Title = "#OM2"

  • Message = some3ohruihrgfijbfgbrfghrgjikbnhjergbnergbg

any help is greatly appreciated



Edit.



Script



<script type="text/javascript">
function copyToClipboard(element)
var $temp = $("<textarea>");
$("body").append($temp);
var html = $(element).html();
html = html.replace(/<br>/g, "n"); // or rn
console.log(html);
$temp.val(html).select();
document.execCommand("copy");
$temp.remove();



</script>


with echo '<button onclick="copyToClipboard(' . $row['Title'] . ')>Copy TEXT 2</button>';



Image!!!










share|improve this question



















  • 1





    You can use trim() to eliminate whitespaces..

    – Vidal
    Mar 7 at 16:56











  • i tried in on after the echo and before the row started, tried on the row it self. Same issue

    – Carlos Reyes
    Mar 7 at 16:59











  • trim($row['Title']) ? can we see your copyToClipboard javascript function ?

    – Vidal
    Mar 7 at 16:59











  • added it on edit.

    – Carlos Reyes
    Mar 7 at 17:03






  • 1





    Maybe it's quote problem, I think you would like to have the param as a string?: echo '<button onclick="copyToClipboard("' . $row['Title'] . '")">Copy TEXT 2</button>';

    – arvie
    Mar 7 at 17:06














0












0








0








hello ive been trying to figure this out for days now.



What i want to do is echo a test and then create a button that copies the echoed text to the clipboard.



So what i want is that i have an SQL list, in that List there is an ID row i can pass to my echo in the paragraph, but when i try to do the same with the parameter the # seems to an issue.



while($row = mysqli_fetch_array($result)) 
echo "<div>";
echo " <p id='" . $row['ID'] . "'>" . $row['Message'] . "</p>";
echo '<button onclick="copyToClipboard('. $row['Title'] . ')">Copy TEXT 2</button>';
echo " </div>";



Also it somehow generates the parameter but there is a blank space between
(" #om2")".



  • my SQL

  • ID = OM2

  • Title = "#OM2"

  • Message = some3ohruihrgfijbfgbrfghrgjikbnhjergbnergbg

any help is greatly appreciated



Edit.



Script



<script type="text/javascript">
function copyToClipboard(element)
var $temp = $("<textarea>");
$("body").append($temp);
var html = $(element).html();
html = html.replace(/<br>/g, "n"); // or rn
console.log(html);
$temp.val(html).select();
document.execCommand("copy");
$temp.remove();



</script>


with echo '<button onclick="copyToClipboard(' . $row['Title'] . ')>Copy TEXT 2</button>';



Image!!!










share|improve this question
















hello ive been trying to figure this out for days now.



What i want to do is echo a test and then create a button that copies the echoed text to the clipboard.



So what i want is that i have an SQL list, in that List there is an ID row i can pass to my echo in the paragraph, but when i try to do the same with the parameter the # seems to an issue.



while($row = mysqli_fetch_array($result)) 
echo "<div>";
echo " <p id='" . $row['ID'] . "'>" . $row['Message'] . "</p>";
echo '<button onclick="copyToClipboard('. $row['Title'] . ')">Copy TEXT 2</button>';
echo " </div>";



Also it somehow generates the parameter but there is a blank space between
(" #om2")".



  • my SQL

  • ID = OM2

  • Title = "#OM2"

  • Message = some3ohruihrgfijbfgbrfghrgjikbnhjergbnergbg

any help is greatly appreciated



Edit.



Script



<script type="text/javascript">
function copyToClipboard(element)
var $temp = $("<textarea>");
$("body").append($temp);
var html = $(element).html();
html = html.replace(/<br>/g, "n"); // or rn
console.log(html);
$temp.val(html).select();
document.execCommand("copy");
$temp.remove();



</script>


with echo '<button onclick="copyToClipboard(' . $row['Title'] . ')>Copy TEXT 2</button>';



Image!!!







php jquery html sql






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 7 at 17:17







Carlos Reyes

















asked Mar 7 at 16:52









Carlos ReyesCarlos Reyes

32




32







  • 1





    You can use trim() to eliminate whitespaces..

    – Vidal
    Mar 7 at 16:56











  • i tried in on after the echo and before the row started, tried on the row it self. Same issue

    – Carlos Reyes
    Mar 7 at 16:59











  • trim($row['Title']) ? can we see your copyToClipboard javascript function ?

    – Vidal
    Mar 7 at 16:59











  • added it on edit.

    – Carlos Reyes
    Mar 7 at 17:03






  • 1





    Maybe it's quote problem, I think you would like to have the param as a string?: echo '<button onclick="copyToClipboard("' . $row['Title'] . '")">Copy TEXT 2</button>';

    – arvie
    Mar 7 at 17:06













  • 1





    You can use trim() to eliminate whitespaces..

    – Vidal
    Mar 7 at 16:56











  • i tried in on after the echo and before the row started, tried on the row it self. Same issue

    – Carlos Reyes
    Mar 7 at 16:59











  • trim($row['Title']) ? can we see your copyToClipboard javascript function ?

    – Vidal
    Mar 7 at 16:59











  • added it on edit.

    – Carlos Reyes
    Mar 7 at 17:03






  • 1





    Maybe it's quote problem, I think you would like to have the param as a string?: echo '<button onclick="copyToClipboard("' . $row['Title'] . '")">Copy TEXT 2</button>';

    – arvie
    Mar 7 at 17:06








1




1





You can use trim() to eliminate whitespaces..

– Vidal
Mar 7 at 16:56





You can use trim() to eliminate whitespaces..

– Vidal
Mar 7 at 16:56













i tried in on after the echo and before the row started, tried on the row it self. Same issue

– Carlos Reyes
Mar 7 at 16:59





i tried in on after the echo and before the row started, tried on the row it self. Same issue

– Carlos Reyes
Mar 7 at 16:59













trim($row['Title']) ? can we see your copyToClipboard javascript function ?

– Vidal
Mar 7 at 16:59





trim($row['Title']) ? can we see your copyToClipboard javascript function ?

– Vidal
Mar 7 at 16:59













added it on edit.

– Carlos Reyes
Mar 7 at 17:03





added it on edit.

– Carlos Reyes
Mar 7 at 17:03




1




1





Maybe it's quote problem, I think you would like to have the param as a string?: echo '<button onclick="copyToClipboard("' . $row['Title'] . '")">Copy TEXT 2</button>';

– arvie
Mar 7 at 17:06






Maybe it's quote problem, I think you would like to have the param as a string?: echo '<button onclick="copyToClipboard("' . $row['Title'] . '")">Copy TEXT 2</button>';

– arvie
Mar 7 at 17:06













1 Answer
1






active

oldest

votes


















0














You are trying to pass #OM2 as agument of the copyToClipboard() function...



There are some quotes missing to make it a string. Actually, #OM2 isn't.



Try to add some ':



echo '<button onclick="copyToClipboard(''. $row['Title'] . '')">Copy TEXT 2</button>';


That should work... But I would suggest a better alternative...

Use a class handle the click event, instead of an inline onclick.



while($row = mysqli_fetch_array($result)) 
echo "<div>";
echo " <p id='" . $row['ID'] . "'>" . $row['Message'] . "</p>";
echo '<button class="copy">Copy TEXT 2</button>';
echo " </div>";



Then your clipboard copy script would simply be:



$(".copy").on("click",function()
var text = $(this).prev("p").html().replace(/<br>/g, "n");
navigator.clipboard.writeText(text);
);





Here is a snippet ;)


$(".copy").on("click",function()
var text = $(this).prev("p").html().replace(/<br>/g, "n");
navigator.clipboard.writeText(text);
);

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<div>
<p id="OM2">some3ohruihrgfijbfgbrfghrgjikbnhjergbnergbg</p>
<button class="copy">Copy TEXT 2</button>
</div>








share|improve this answer

























  • Tried it, and nothing happens. click the button but it not copying it to the clipboard

    – Carlos Reyes
    Mar 7 at 17:27











  • (?) Works on my side...

    – Louys Patrice Bessette
    Mar 7 at 17:28






  • 1





    @CarlosReyes You may need to wrap the JS provided in the infamous $(document).ready(function() { wrapper.

    – Scoots
    Mar 7 at 17:28











  • Holy jesus!!! WAIT Moved my script below >.> the php tags seems to work

    – Carlos Reyes
    Mar 7 at 17:29












  • Working NICE, thank you very much!!!!

    – Carlos Reyes
    Mar 7 at 17:32











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














You are trying to pass #OM2 as agument of the copyToClipboard() function...



There are some quotes missing to make it a string. Actually, #OM2 isn't.



Try to add some ':



echo '<button onclick="copyToClipboard(''. $row['Title'] . '')">Copy TEXT 2</button>';


That should work... But I would suggest a better alternative...

Use a class handle the click event, instead of an inline onclick.



while($row = mysqli_fetch_array($result)) 
echo "<div>";
echo " <p id='" . $row['ID'] . "'>" . $row['Message'] . "</p>";
echo '<button class="copy">Copy TEXT 2</button>';
echo " </div>";



Then your clipboard copy script would simply be:



$(".copy").on("click",function()
var text = $(this).prev("p").html().replace(/<br>/g, "n");
navigator.clipboard.writeText(text);
);





Here is a snippet ;)


$(".copy").on("click",function()
var text = $(this).prev("p").html().replace(/<br>/g, "n");
navigator.clipboard.writeText(text);
);

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<div>
<p id="OM2">some3ohruihrgfijbfgbrfghrgjikbnhjergbnergbg</p>
<button class="copy">Copy TEXT 2</button>
</div>








share|improve this answer

























  • Tried it, and nothing happens. click the button but it not copying it to the clipboard

    – Carlos Reyes
    Mar 7 at 17:27











  • (?) Works on my side...

    – Louys Patrice Bessette
    Mar 7 at 17:28






  • 1





    @CarlosReyes You may need to wrap the JS provided in the infamous $(document).ready(function() { wrapper.

    – Scoots
    Mar 7 at 17:28











  • Holy jesus!!! WAIT Moved my script below >.> the php tags seems to work

    – Carlos Reyes
    Mar 7 at 17:29












  • Working NICE, thank you very much!!!!

    – Carlos Reyes
    Mar 7 at 17:32















0














You are trying to pass #OM2 as agument of the copyToClipboard() function...



There are some quotes missing to make it a string. Actually, #OM2 isn't.



Try to add some ':



echo '<button onclick="copyToClipboard(''. $row['Title'] . '')">Copy TEXT 2</button>';


That should work... But I would suggest a better alternative...

Use a class handle the click event, instead of an inline onclick.



while($row = mysqli_fetch_array($result)) 
echo "<div>";
echo " <p id='" . $row['ID'] . "'>" . $row['Message'] . "</p>";
echo '<button class="copy">Copy TEXT 2</button>';
echo " </div>";



Then your clipboard copy script would simply be:



$(".copy").on("click",function()
var text = $(this).prev("p").html().replace(/<br>/g, "n");
navigator.clipboard.writeText(text);
);





Here is a snippet ;)


$(".copy").on("click",function()
var text = $(this).prev("p").html().replace(/<br>/g, "n");
navigator.clipboard.writeText(text);
);

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<div>
<p id="OM2">some3ohruihrgfijbfgbrfghrgjikbnhjergbnergbg</p>
<button class="copy">Copy TEXT 2</button>
</div>








share|improve this answer

























  • Tried it, and nothing happens. click the button but it not copying it to the clipboard

    – Carlos Reyes
    Mar 7 at 17:27











  • (?) Works on my side...

    – Louys Patrice Bessette
    Mar 7 at 17:28






  • 1





    @CarlosReyes You may need to wrap the JS provided in the infamous $(document).ready(function() { wrapper.

    – Scoots
    Mar 7 at 17:28











  • Holy jesus!!! WAIT Moved my script below >.> the php tags seems to work

    – Carlos Reyes
    Mar 7 at 17:29












  • Working NICE, thank you very much!!!!

    – Carlos Reyes
    Mar 7 at 17:32













0












0








0







You are trying to pass #OM2 as agument of the copyToClipboard() function...



There are some quotes missing to make it a string. Actually, #OM2 isn't.



Try to add some ':



echo '<button onclick="copyToClipboard(''. $row['Title'] . '')">Copy TEXT 2</button>';


That should work... But I would suggest a better alternative...

Use a class handle the click event, instead of an inline onclick.



while($row = mysqli_fetch_array($result)) 
echo "<div>";
echo " <p id='" . $row['ID'] . "'>" . $row['Message'] . "</p>";
echo '<button class="copy">Copy TEXT 2</button>';
echo " </div>";



Then your clipboard copy script would simply be:



$(".copy").on("click",function()
var text = $(this).prev("p").html().replace(/<br>/g, "n");
navigator.clipboard.writeText(text);
);





Here is a snippet ;)


$(".copy").on("click",function()
var text = $(this).prev("p").html().replace(/<br>/g, "n");
navigator.clipboard.writeText(text);
);

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<div>
<p id="OM2">some3ohruihrgfijbfgbrfghrgjikbnhjergbnergbg</p>
<button class="copy">Copy TEXT 2</button>
</div>








share|improve this answer















You are trying to pass #OM2 as agument of the copyToClipboard() function...



There are some quotes missing to make it a string. Actually, #OM2 isn't.



Try to add some ':



echo '<button onclick="copyToClipboard(''. $row['Title'] . '')">Copy TEXT 2</button>';


That should work... But I would suggest a better alternative...

Use a class handle the click event, instead of an inline onclick.



while($row = mysqli_fetch_array($result)) 
echo "<div>";
echo " <p id='" . $row['ID'] . "'>" . $row['Message'] . "</p>";
echo '<button class="copy">Copy TEXT 2</button>';
echo " </div>";



Then your clipboard copy script would simply be:



$(".copy").on("click",function()
var text = $(this).prev("p").html().replace(/<br>/g, "n");
navigator.clipboard.writeText(text);
);





Here is a snippet ;)


$(".copy").on("click",function()
var text = $(this).prev("p").html().replace(/<br>/g, "n");
navigator.clipboard.writeText(text);
);

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<div>
<p id="OM2">some3ohruihrgfijbfgbrfghrgjikbnhjergbnergbg</p>
<button class="copy">Copy TEXT 2</button>
</div>








$(".copy").on("click",function()
var text = $(this).prev("p").html().replace(/<br>/g, "n");
navigator.clipboard.writeText(text);
);

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<div>
<p id="OM2">some3ohruihrgfijbfgbrfghrgjikbnhjergbnergbg</p>
<button class="copy">Copy TEXT 2</button>
</div>





$(".copy").on("click",function()
var text = $(this).prev("p").html().replace(/<br>/g, "n");
navigator.clipboard.writeText(text);
);

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<div>
<p id="OM2">some3ohruihrgfijbfgbrfghrgjikbnhjergbnergbg</p>
<button class="copy">Copy TEXT 2</button>
</div>






share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 7 at 17:24

























answered Mar 7 at 17:16









Louys Patrice BessetteLouys Patrice Bessette

20.4k42345




20.4k42345












  • Tried it, and nothing happens. click the button but it not copying it to the clipboard

    – Carlos Reyes
    Mar 7 at 17:27











  • (?) Works on my side...

    – Louys Patrice Bessette
    Mar 7 at 17:28






  • 1





    @CarlosReyes You may need to wrap the JS provided in the infamous $(document).ready(function() { wrapper.

    – Scoots
    Mar 7 at 17:28











  • Holy jesus!!! WAIT Moved my script below >.> the php tags seems to work

    – Carlos Reyes
    Mar 7 at 17:29












  • Working NICE, thank you very much!!!!

    – Carlos Reyes
    Mar 7 at 17:32

















  • Tried it, and nothing happens. click the button but it not copying it to the clipboard

    – Carlos Reyes
    Mar 7 at 17:27











  • (?) Works on my side...

    – Louys Patrice Bessette
    Mar 7 at 17:28






  • 1





    @CarlosReyes You may need to wrap the JS provided in the infamous $(document).ready(function() { wrapper.

    – Scoots
    Mar 7 at 17:28











  • Holy jesus!!! WAIT Moved my script below >.> the php tags seems to work

    – Carlos Reyes
    Mar 7 at 17:29












  • Working NICE, thank you very much!!!!

    – Carlos Reyes
    Mar 7 at 17:32
















Tried it, and nothing happens. click the button but it not copying it to the clipboard

– Carlos Reyes
Mar 7 at 17:27





Tried it, and nothing happens. click the button but it not copying it to the clipboard

– Carlos Reyes
Mar 7 at 17:27













(?) Works on my side...

– Louys Patrice Bessette
Mar 7 at 17:28





(?) Works on my side...

– Louys Patrice Bessette
Mar 7 at 17:28




1




1





@CarlosReyes You may need to wrap the JS provided in the infamous $(document).ready(function() { wrapper.

– Scoots
Mar 7 at 17:28





@CarlosReyes You may need to wrap the JS provided in the infamous $(document).ready(function() { wrapper.

– Scoots
Mar 7 at 17:28













Holy jesus!!! WAIT Moved my script below >.> the php tags seems to work

– Carlos Reyes
Mar 7 at 17:29






Holy jesus!!! WAIT Moved my script below >.> the php tags seems to work

– Carlos Reyes
Mar 7 at 17:29














Working NICE, thank you very much!!!!

– Carlos Reyes
Mar 7 at 17:32





Working NICE, thank you very much!!!!

– Carlos Reyes
Mar 7 at 17:32



















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