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Expression type '@lvalue String?' is ambiguous without more context when += to UILabel.text
How to enumerate an enum with String type?How to get image from UIImagePickerController and Pass to next VCHow to hide and show label when navigation VC1 to VC2 back and forthSwift 2 iOS 9 animation disappears after button text changedUIAlertController action crashes with error exc_bad_access while performing network oparation of 5 to 6 secsUnable to dismiss MFMailComposeViewController from a separate ViewControllerHow to optimize UITableViewCell, because my UITableView lagsHow do I pass data from a UIViewController to UITabBarController?Swift Error - Use of undeclared type 'cell' - Collection ViewBMI app print result is 0 even with variable being hard coded
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I am trying to add the string "7" to a label when someone tabs the button labeled 7.
But when using += "7", it gives me the error "Expression type '@lvalue String?' is ambiguous without more context", when using the operator = "7" it works fine. Why doesn't += "7" work?
class NumberPadController: UIViewController
@IBOutlet weak var valueLabel: UILabel!
/// set value in main vc and return to that.
@IBAction func doneEntering(_ sender: Any)
guard let valueString = valueLabel.text, let valueDouble = Double(valueString), let presentingVC = self.presentingViewController as? ViewController else
// FIXME: Show error
dismiss(animated: true, completion: nil)
return
presentingVC.valuePassedFromNumPad = valueDouble
dismiss(animated: true, completion: nil)
@IBAction func seven(_ sender: Any)
valueLabel.text += "7" // Expression type '@lvalue String?' is ambiguous without more context
valueLabel.text = "a" // works fine
ios swift uilabel
add a comment |
I am trying to add the string "7" to a label when someone tabs the button labeled 7.
But when using += "7", it gives me the error "Expression type '@lvalue String?' is ambiguous without more context", when using the operator = "7" it works fine. Why doesn't += "7" work?
class NumberPadController: UIViewController
@IBOutlet weak var valueLabel: UILabel!
/// set value in main vc and return to that.
@IBAction func doneEntering(_ sender: Any)
guard let valueString = valueLabel.text, let valueDouble = Double(valueString), let presentingVC = self.presentingViewController as? ViewController else
// FIXME: Show error
dismiss(animated: true, completion: nil)
return
presentingVC.valuePassedFromNumPad = valueDouble
dismiss(animated: true, completion: nil)
@IBAction func seven(_ sender: Any)
valueLabel.text += "7" // Expression type '@lvalue String?' is ambiguous without more context
valueLabel.text = "a" // works fine
ios swift uilabel
what the OP you expect , you want to perform some operation or else
– Anbu.Karthik
Mar 8 at 4:20
You just need to unwrap the optional value before adding up. Just make sureUILabel
text
property it is not nil before incrementing its value:valueLabel.text! += "7"
– Leo Dabus
Mar 8 at 4:37
It is worth saying that you should not use the UI to pass values around. If you need the label string value for future use you should keep a reference to its value.
– Leo Dabus
Mar 8 at 4:42
add a comment |
I am trying to add the string "7" to a label when someone tabs the button labeled 7.
But when using += "7", it gives me the error "Expression type '@lvalue String?' is ambiguous without more context", when using the operator = "7" it works fine. Why doesn't += "7" work?
class NumberPadController: UIViewController
@IBOutlet weak var valueLabel: UILabel!
/// set value in main vc and return to that.
@IBAction func doneEntering(_ sender: Any)
guard let valueString = valueLabel.text, let valueDouble = Double(valueString), let presentingVC = self.presentingViewController as? ViewController else
// FIXME: Show error
dismiss(animated: true, completion: nil)
return
presentingVC.valuePassedFromNumPad = valueDouble
dismiss(animated: true, completion: nil)
@IBAction func seven(_ sender: Any)
valueLabel.text += "7" // Expression type '@lvalue String?' is ambiguous without more context
valueLabel.text = "a" // works fine
ios swift uilabel
I am trying to add the string "7" to a label when someone tabs the button labeled 7.
But when using += "7", it gives me the error "Expression type '@lvalue String?' is ambiguous without more context", when using the operator = "7" it works fine. Why doesn't += "7" work?
class NumberPadController: UIViewController
@IBOutlet weak var valueLabel: UILabel!
/// set value in main vc and return to that.
@IBAction func doneEntering(_ sender: Any)
guard let valueString = valueLabel.text, let valueDouble = Double(valueString), let presentingVC = self.presentingViewController as? ViewController else
// FIXME: Show error
dismiss(animated: true, completion: nil)
return
presentingVC.valuePassedFromNumPad = valueDouble
dismiss(animated: true, completion: nil)
@IBAction func seven(_ sender: Any)
valueLabel.text += "7" // Expression type '@lvalue String?' is ambiguous without more context
valueLabel.text = "a" // works fine
ios swift uilabel
ios swift uilabel
edited Mar 8 at 8:44
AtulParmar
1,374623
1,374623
asked Mar 8 at 4:16
BruceBruce
441215
441215
what the OP you expect , you want to perform some operation or else
– Anbu.Karthik
Mar 8 at 4:20
You just need to unwrap the optional value before adding up. Just make sureUILabel
text
property it is not nil before incrementing its value:valueLabel.text! += "7"
– Leo Dabus
Mar 8 at 4:37
It is worth saying that you should not use the UI to pass values around. If you need the label string value for future use you should keep a reference to its value.
– Leo Dabus
Mar 8 at 4:42
add a comment |
what the OP you expect , you want to perform some operation or else
– Anbu.Karthik
Mar 8 at 4:20
You just need to unwrap the optional value before adding up. Just make sureUILabel
text
property it is not nil before incrementing its value:valueLabel.text! += "7"
– Leo Dabus
Mar 8 at 4:37
It is worth saying that you should not use the UI to pass values around. If you need the label string value for future use you should keep a reference to its value.
– Leo Dabus
Mar 8 at 4:42
what the OP you expect , you want to perform some operation or else
– Anbu.Karthik
Mar 8 at 4:20
what the OP you expect , you want to perform some operation or else
– Anbu.Karthik
Mar 8 at 4:20
You just need to unwrap the optional value before adding up. Just make sure
UILabel
text
property it is not nil before incrementing its value: valueLabel.text! += "7"
– Leo Dabus
Mar 8 at 4:37
You just need to unwrap the optional value before adding up. Just make sure
UILabel
text
property it is not nil before incrementing its value: valueLabel.text! += "7"
– Leo Dabus
Mar 8 at 4:37
It is worth saying that you should not use the UI to pass values around. If you need the label string value for future use you should keep a reference to its value.
– Leo Dabus
Mar 8 at 4:42
It is worth saying that you should not use the UI to pass values around. If you need the label string value for future use you should keep a reference to its value.
– Leo Dabus
Mar 8 at 4:42
add a comment |
2 Answers
2
active
oldest
votes
The text
property is optional. One way to do this safely would be to use append
along with optional chaining:
valueLabel.text?.append("7")
or use +=
with optional chaining:
valueLabel.text? += "7"
If the label is nil
, these would safely do nothing. If you'd like the label to be "7"
if it was nil
, then use @RickyMo's solution.
How can I calculate my foodPrice label value with foodQuantity value?var quantity = 1
andfoodPrice.text *= quantity
. I am getting same error
– Emre Değirmenci
Mar 9 at 11:17
1
@EmreDeğirmenci, you need to take theString
that is infoodPrice.text
, convert it to aDouble
, multiply that byDouble(quantity)
, then convert thatDouble
back to aString
. Something likelet price = Double(foodPrice.text ?? "") ?? 0; let total = price * Double(quantity); foodPrice.text = "(total)"
– vacawama
Mar 9 at 12:58
add a comment |
text
property is optional. To do it safely :
valueLabel.text = (valueLabel.text ?? "") + "7"
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The text
property is optional. One way to do this safely would be to use append
along with optional chaining:
valueLabel.text?.append("7")
or use +=
with optional chaining:
valueLabel.text? += "7"
If the label is nil
, these would safely do nothing. If you'd like the label to be "7"
if it was nil
, then use @RickyMo's solution.
How can I calculate my foodPrice label value with foodQuantity value?var quantity = 1
andfoodPrice.text *= quantity
. I am getting same error
– Emre Değirmenci
Mar 9 at 11:17
1
@EmreDeğirmenci, you need to take theString
that is infoodPrice.text
, convert it to aDouble
, multiply that byDouble(quantity)
, then convert thatDouble
back to aString
. Something likelet price = Double(foodPrice.text ?? "") ?? 0; let total = price * Double(quantity); foodPrice.text = "(total)"
– vacawama
Mar 9 at 12:58
add a comment |
The text
property is optional. One way to do this safely would be to use append
along with optional chaining:
valueLabel.text?.append("7")
or use +=
with optional chaining:
valueLabel.text? += "7"
If the label is nil
, these would safely do nothing. If you'd like the label to be "7"
if it was nil
, then use @RickyMo's solution.
How can I calculate my foodPrice label value with foodQuantity value?var quantity = 1
andfoodPrice.text *= quantity
. I am getting same error
– Emre Değirmenci
Mar 9 at 11:17
1
@EmreDeğirmenci, you need to take theString
that is infoodPrice.text
, convert it to aDouble
, multiply that byDouble(quantity)
, then convert thatDouble
back to aString
. Something likelet price = Double(foodPrice.text ?? "") ?? 0; let total = price * Double(quantity); foodPrice.text = "(total)"
– vacawama
Mar 9 at 12:58
add a comment |
The text
property is optional. One way to do this safely would be to use append
along with optional chaining:
valueLabel.text?.append("7")
or use +=
with optional chaining:
valueLabel.text? += "7"
If the label is nil
, these would safely do nothing. If you'd like the label to be "7"
if it was nil
, then use @RickyMo's solution.
The text
property is optional. One way to do this safely would be to use append
along with optional chaining:
valueLabel.text?.append("7")
or use +=
with optional chaining:
valueLabel.text? += "7"
If the label is nil
, these would safely do nothing. If you'd like the label to be "7"
if it was nil
, then use @RickyMo's solution.
edited Mar 8 at 11:36
answered Mar 8 at 4:30
vacawamavacawama
99.7k15178204
99.7k15178204
How can I calculate my foodPrice label value with foodQuantity value?var quantity = 1
andfoodPrice.text *= quantity
. I am getting same error
– Emre Değirmenci
Mar 9 at 11:17
1
@EmreDeğirmenci, you need to take theString
that is infoodPrice.text
, convert it to aDouble
, multiply that byDouble(quantity)
, then convert thatDouble
back to aString
. Something likelet price = Double(foodPrice.text ?? "") ?? 0; let total = price * Double(quantity); foodPrice.text = "(total)"
– vacawama
Mar 9 at 12:58
add a comment |
How can I calculate my foodPrice label value with foodQuantity value?var quantity = 1
andfoodPrice.text *= quantity
. I am getting same error
– Emre Değirmenci
Mar 9 at 11:17
1
@EmreDeğirmenci, you need to take theString
that is infoodPrice.text
, convert it to aDouble
, multiply that byDouble(quantity)
, then convert thatDouble
back to aString
. Something likelet price = Double(foodPrice.text ?? "") ?? 0; let total = price * Double(quantity); foodPrice.text = "(total)"
– vacawama
Mar 9 at 12:58
How can I calculate my foodPrice label value with foodQuantity value?
var quantity = 1
and foodPrice.text *= quantity
. I am getting same error– Emre Değirmenci
Mar 9 at 11:17
How can I calculate my foodPrice label value with foodQuantity value?
var quantity = 1
and foodPrice.text *= quantity
. I am getting same error– Emre Değirmenci
Mar 9 at 11:17
1
1
@EmreDeğirmenci, you need to take the
String
that is in foodPrice.text
, convert it to a Double
, multiply that by Double(quantity)
, then convert that Double
back to a String
. Something like let price = Double(foodPrice.text ?? "") ?? 0; let total = price * Double(quantity); foodPrice.text = "(total)"
– vacawama
Mar 9 at 12:58
@EmreDeğirmenci, you need to take the
String
that is in foodPrice.text
, convert it to a Double
, multiply that by Double(quantity)
, then convert that Double
back to a String
. Something like let price = Double(foodPrice.text ?? "") ?? 0; let total = price * Double(quantity); foodPrice.text = "(total)"
– vacawama
Mar 9 at 12:58
add a comment |
text
property is optional. To do it safely :
valueLabel.text = (valueLabel.text ?? "") + "7"
add a comment |
text
property is optional. To do it safely :
valueLabel.text = (valueLabel.text ?? "") + "7"
add a comment |
text
property is optional. To do it safely :
valueLabel.text = (valueLabel.text ?? "") + "7"
text
property is optional. To do it safely :
valueLabel.text = (valueLabel.text ?? "") + "7"
answered Mar 8 at 4:23
Ricky MoRicky Mo
1,9771212
1,9771212
add a comment |
add a comment |
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what the OP you expect , you want to perform some operation or else
– Anbu.Karthik
Mar 8 at 4:20
You just need to unwrap the optional value before adding up. Just make sure
UILabel
text
property it is not nil before incrementing its value:valueLabel.text! += "7"
– Leo Dabus
Mar 8 at 4:37
It is worth saying that you should not use the UI to pass values around. If you need the label string value for future use you should keep a reference to its value.
– Leo Dabus
Mar 8 at 4:42