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How do I know which functional interface is associated with the method?
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map() is associated with the Function interface. And how can I know which interfaces other methods are associated with, for example findFirst()?
java function java-stream
add a comment |
map() is associated with the Function interface. And how can I know which interfaces other methods are associated with, for example findFirst()?
java function java-stream
1
What doesfindFirsthave to do with functional interfaces? It is just a method ofStream.
– MC Emperor
Mar 9 at 8:55
1
I guess you mean theFunctioninterface. You know what findFirst, and all the other Java methods in the world expect by simply reading their javadoc: map expects a Function (see docs.oracle.com/javase/8/docs/api/java/util/stream/…), whereas findFirst() doesn't take any argument (see docs.oracle.com/javase/8/docs/api/java/util/stream/…)
– JB Nizet
Mar 9 at 8:58
@JBNizet Yes, I was wrong, thanks. This is what I was looking for.
– Anton Sorokin
Mar 9 at 9:01
add a comment |
map() is associated with the Function interface. And how can I know which interfaces other methods are associated with, for example findFirst()?
java function java-stream
map() is associated with the Function interface. And how can I know which interfaces other methods are associated with, for example findFirst()?
java function java-stream
java function java-stream
edited Mar 9 at 8:59
Anton Sorokin
asked Mar 9 at 8:50
Anton SorokinAnton Sorokin
213315
213315
1
What doesfindFirsthave to do with functional interfaces? It is just a method ofStream.
– MC Emperor
Mar 9 at 8:55
1
I guess you mean theFunctioninterface. You know what findFirst, and all the other Java methods in the world expect by simply reading their javadoc: map expects a Function (see docs.oracle.com/javase/8/docs/api/java/util/stream/…), whereas findFirst() doesn't take any argument (see docs.oracle.com/javase/8/docs/api/java/util/stream/…)
– JB Nizet
Mar 9 at 8:58
@JBNizet Yes, I was wrong, thanks. This is what I was looking for.
– Anton Sorokin
Mar 9 at 9:01
add a comment |
1
What doesfindFirsthave to do with functional interfaces? It is just a method ofStream.
– MC Emperor
Mar 9 at 8:55
1
I guess you mean theFunctioninterface. You know what findFirst, and all the other Java methods in the world expect by simply reading their javadoc: map expects a Function (see docs.oracle.com/javase/8/docs/api/java/util/stream/…), whereas findFirst() doesn't take any argument (see docs.oracle.com/javase/8/docs/api/java/util/stream/…)
– JB Nizet
Mar 9 at 8:58
@JBNizet Yes, I was wrong, thanks. This is what I was looking for.
– Anton Sorokin
Mar 9 at 9:01
1
1
What does
findFirst have to do with functional interfaces? It is just a method of Stream.– MC Emperor
Mar 9 at 8:55
What does
findFirst have to do with functional interfaces? It is just a method of Stream.– MC Emperor
Mar 9 at 8:55
1
1
I guess you mean the
Function interface. You know what findFirst, and all the other Java methods in the world expect by simply reading their javadoc: map expects a Function (see docs.oracle.com/javase/8/docs/api/java/util/stream/…), whereas findFirst() doesn't take any argument (see docs.oracle.com/javase/8/docs/api/java/util/stream/…)– JB Nizet
Mar 9 at 8:58
I guess you mean the
Function interface. You know what findFirst, and all the other Java methods in the world expect by simply reading their javadoc: map expects a Function (see docs.oracle.com/javase/8/docs/api/java/util/stream/…), whereas findFirst() doesn't take any argument (see docs.oracle.com/javase/8/docs/api/java/util/stream/…)– JB Nizet
Mar 9 at 8:58
@JBNizet Yes, I was wrong, thanks. This is what I was looking for.
– Anton Sorokin
Mar 9 at 9:01
@JBNizet Yes, I was wrong, thanks. This is what I was looking for.
– Anton Sorokin
Mar 9 at 9:01
add a comment |
1 Answer
1
active
oldest
votes
map() is associated with the Functional interface
No, it is not. For the presence of tag java-stream, it's just another API from the class Stream which has the following syntax :
<R> Stream<R> map(Function<? super T,? extends R> mapper)
Yes, the argument used within i.e. Function is a FunctionalInterface. You can find similar FunctionalInterfaces within the java.util.function package of the java.base module (Java-9 above) of the JDK.
1
Yes, thx. I thought that findFirst() is connected to the Supplier interface, like a map() with a Function
– Anton Sorokin
Mar 9 at 9:04
add a comment |
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1 Answer
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1 Answer
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active
oldest
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active
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active
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map() is associated with the Functional interface
No, it is not. For the presence of tag java-stream, it's just another API from the class Stream which has the following syntax :
<R> Stream<R> map(Function<? super T,? extends R> mapper)
Yes, the argument used within i.e. Function is a FunctionalInterface. You can find similar FunctionalInterfaces within the java.util.function package of the java.base module (Java-9 above) of the JDK.
1
Yes, thx. I thought that findFirst() is connected to the Supplier interface, like a map() with a Function
– Anton Sorokin
Mar 9 at 9:04
add a comment |
map() is associated with the Functional interface
No, it is not. For the presence of tag java-stream, it's just another API from the class Stream which has the following syntax :
<R> Stream<R> map(Function<? super T,? extends R> mapper)
Yes, the argument used within i.e. Function is a FunctionalInterface. You can find similar FunctionalInterfaces within the java.util.function package of the java.base module (Java-9 above) of the JDK.
1
Yes, thx. I thought that findFirst() is connected to the Supplier interface, like a map() with a Function
– Anton Sorokin
Mar 9 at 9:04
add a comment |
map() is associated with the Functional interface
No, it is not. For the presence of tag java-stream, it's just another API from the class Stream which has the following syntax :
<R> Stream<R> map(Function<? super T,? extends R> mapper)
Yes, the argument used within i.e. Function is a FunctionalInterface. You can find similar FunctionalInterfaces within the java.util.function package of the java.base module (Java-9 above) of the JDK.
map() is associated with the Functional interface
No, it is not. For the presence of tag java-stream, it's just another API from the class Stream which has the following syntax :
<R> Stream<R> map(Function<? super T,? extends R> mapper)
Yes, the argument used within i.e. Function is a FunctionalInterface. You can find similar FunctionalInterfaces within the java.util.function package of the java.base module (Java-9 above) of the JDK.
answered Mar 9 at 8:59
NamanNaman
46.4k12104206
46.4k12104206
1
Yes, thx. I thought that findFirst() is connected to the Supplier interface, like a map() with a Function
– Anton Sorokin
Mar 9 at 9:04
add a comment |
1
Yes, thx. I thought that findFirst() is connected to the Supplier interface, like a map() with a Function
– Anton Sorokin
Mar 9 at 9:04
1
1
Yes, thx. I thought that findFirst() is connected to the Supplier interface, like a map() with a Function
– Anton Sorokin
Mar 9 at 9:04
Yes, thx. I thought that findFirst() is connected to the Supplier interface, like a map() with a Function
– Anton Sorokin
Mar 9 at 9:04
add a comment |
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1
What does
findFirsthave to do with functional interfaces? It is just a method ofStream.– MC Emperor
Mar 9 at 8:55
1
I guess you mean the
Functioninterface. You know what findFirst, and all the other Java methods in the world expect by simply reading their javadoc: map expects a Function (see docs.oracle.com/javase/8/docs/api/java/util/stream/…), whereas findFirst() doesn't take any argument (see docs.oracle.com/javase/8/docs/api/java/util/stream/…)– JB Nizet
Mar 9 at 8:58
@JBNizet Yes, I was wrong, thanks. This is what I was looking for.
– Anton Sorokin
Mar 9 at 9:01