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How do I know which functional interface is associated with the method?


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-1















map() is associated with the Function interface. And how can I know which interfaces other methods are associated with, for example findFirst()?










share|improve this question



















  • 1





    What does findFirst have to do with functional interfaces? It is just a method of Stream.

    – MC Emperor
    Mar 9 at 8:55







  • 1





    I guess you mean the Function interface. You know what findFirst, and all the other Java methods in the world expect by simply reading their javadoc: map expects a Function (see docs.oracle.com/javase/8/docs/api/java/util/stream/…), whereas findFirst() doesn't take any argument (see docs.oracle.com/javase/8/docs/api/java/util/stream/…)

    – JB Nizet
    Mar 9 at 8:58











  • @JBNizet Yes, I was wrong, thanks. This is what I was looking for.

    – Anton Sorokin
    Mar 9 at 9:01

















-1















map() is associated with the Function interface. And how can I know which interfaces other methods are associated with, for example findFirst()?










share|improve this question



















  • 1





    What does findFirst have to do with functional interfaces? It is just a method of Stream.

    – MC Emperor
    Mar 9 at 8:55







  • 1





    I guess you mean the Function interface. You know what findFirst, and all the other Java methods in the world expect by simply reading their javadoc: map expects a Function (see docs.oracle.com/javase/8/docs/api/java/util/stream/…), whereas findFirst() doesn't take any argument (see docs.oracle.com/javase/8/docs/api/java/util/stream/…)

    – JB Nizet
    Mar 9 at 8:58











  • @JBNizet Yes, I was wrong, thanks. This is what I was looking for.

    – Anton Sorokin
    Mar 9 at 9:01













-1












-1








-1








map() is associated with the Function interface. And how can I know which interfaces other methods are associated with, for example findFirst()?










share|improve this question
















map() is associated with the Function interface. And how can I know which interfaces other methods are associated with, for example findFirst()?







java function java-stream






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 9 at 8:59







Anton Sorokin

















asked Mar 9 at 8:50









Anton SorokinAnton Sorokin

213315




213315







  • 1





    What does findFirst have to do with functional interfaces? It is just a method of Stream.

    – MC Emperor
    Mar 9 at 8:55







  • 1





    I guess you mean the Function interface. You know what findFirst, and all the other Java methods in the world expect by simply reading their javadoc: map expects a Function (see docs.oracle.com/javase/8/docs/api/java/util/stream/…), whereas findFirst() doesn't take any argument (see docs.oracle.com/javase/8/docs/api/java/util/stream/…)

    – JB Nizet
    Mar 9 at 8:58











  • @JBNizet Yes, I was wrong, thanks. This is what I was looking for.

    – Anton Sorokin
    Mar 9 at 9:01












  • 1





    What does findFirst have to do with functional interfaces? It is just a method of Stream.

    – MC Emperor
    Mar 9 at 8:55







  • 1





    I guess you mean the Function interface. You know what findFirst, and all the other Java methods in the world expect by simply reading their javadoc: map expects a Function (see docs.oracle.com/javase/8/docs/api/java/util/stream/…), whereas findFirst() doesn't take any argument (see docs.oracle.com/javase/8/docs/api/java/util/stream/…)

    – JB Nizet
    Mar 9 at 8:58











  • @JBNizet Yes, I was wrong, thanks. This is what I was looking for.

    – Anton Sorokin
    Mar 9 at 9:01







1




1





What does findFirst have to do with functional interfaces? It is just a method of Stream.

– MC Emperor
Mar 9 at 8:55






What does findFirst have to do with functional interfaces? It is just a method of Stream.

– MC Emperor
Mar 9 at 8:55





1




1





I guess you mean the Function interface. You know what findFirst, and all the other Java methods in the world expect by simply reading their javadoc: map expects a Function (see docs.oracle.com/javase/8/docs/api/java/util/stream/…), whereas findFirst() doesn't take any argument (see docs.oracle.com/javase/8/docs/api/java/util/stream/…)

– JB Nizet
Mar 9 at 8:58





I guess you mean the Function interface. You know what findFirst, and all the other Java methods in the world expect by simply reading their javadoc: map expects a Function (see docs.oracle.com/javase/8/docs/api/java/util/stream/…), whereas findFirst() doesn't take any argument (see docs.oracle.com/javase/8/docs/api/java/util/stream/…)

– JB Nizet
Mar 9 at 8:58













@JBNizet Yes, I was wrong, thanks. This is what I was looking for.

– Anton Sorokin
Mar 9 at 9:01





@JBNizet Yes, I was wrong, thanks. This is what I was looking for.

– Anton Sorokin
Mar 9 at 9:01












1 Answer
1






active

oldest

votes


















1















map() is associated with the Functional interface




No, it is not. For the presence of tag java-stream, it's just another API from the class Stream which has the following syntax :



<R> Stream<R> map(Function<? super T,​? extends R> mapper)


Yes, the argument used within i.e. Function is a FunctionalInterface. You can find similar FunctionalInterfaces within the java.util.function package of the java.base module (Java-9 above) of the JDK.






share|improve this answer


















  • 1





    Yes, thx. I thought that findFirst() is connected to the Supplier interface, like a map() with a Function

    – Anton Sorokin
    Mar 9 at 9:04











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1 Answer
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active

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active

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active

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1















map() is associated with the Functional interface




No, it is not. For the presence of tag java-stream, it's just another API from the class Stream which has the following syntax :



<R> Stream<R> map(Function<? super T,​? extends R> mapper)


Yes, the argument used within i.e. Function is a FunctionalInterface. You can find similar FunctionalInterfaces within the java.util.function package of the java.base module (Java-9 above) of the JDK.






share|improve this answer


















  • 1





    Yes, thx. I thought that findFirst() is connected to the Supplier interface, like a map() with a Function

    – Anton Sorokin
    Mar 9 at 9:04















1















map() is associated with the Functional interface




No, it is not. For the presence of tag java-stream, it's just another API from the class Stream which has the following syntax :



<R> Stream<R> map(Function<? super T,​? extends R> mapper)


Yes, the argument used within i.e. Function is a FunctionalInterface. You can find similar FunctionalInterfaces within the java.util.function package of the java.base module (Java-9 above) of the JDK.






share|improve this answer


















  • 1





    Yes, thx. I thought that findFirst() is connected to the Supplier interface, like a map() with a Function

    – Anton Sorokin
    Mar 9 at 9:04













1












1








1








map() is associated with the Functional interface




No, it is not. For the presence of tag java-stream, it's just another API from the class Stream which has the following syntax :



<R> Stream<R> map(Function<? super T,​? extends R> mapper)


Yes, the argument used within i.e. Function is a FunctionalInterface. You can find similar FunctionalInterfaces within the java.util.function package of the java.base module (Java-9 above) of the JDK.






share|improve this answer














map() is associated with the Functional interface




No, it is not. For the presence of tag java-stream, it's just another API from the class Stream which has the following syntax :



<R> Stream<R> map(Function<? super T,​? extends R> mapper)


Yes, the argument used within i.e. Function is a FunctionalInterface. You can find similar FunctionalInterfaces within the java.util.function package of the java.base module (Java-9 above) of the JDK.







share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 9 at 8:59









NamanNaman

46.4k12104206




46.4k12104206







  • 1





    Yes, thx. I thought that findFirst() is connected to the Supplier interface, like a map() with a Function

    – Anton Sorokin
    Mar 9 at 9:04












  • 1





    Yes, thx. I thought that findFirst() is connected to the Supplier interface, like a map() with a Function

    – Anton Sorokin
    Mar 9 at 9:04







1




1





Yes, thx. I thought that findFirst() is connected to the Supplier interface, like a map() with a Function

– Anton Sorokin
Mar 9 at 9:04





Yes, thx. I thought that findFirst() is connected to the Supplier interface, like a map() with a Function

– Anton Sorokin
Mar 9 at 9:04



















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